PYQs on Calculus of Variations | Short Cut Tricks| CSIR NET 2012-2023

[@SADDAMHUSSAIN-mw3cv]

16:35 Correct option is (2).

[@nil9428]

16:45 option (2) is correct P.I = +1/2sinX 18:23 natural Boundary Condition to be applied for whichever condition is not prescribed. Here you have to put at x=2 and not at x=1.

[@Gayanibaba_in_math]

16:46 calculation mistake to write the differential equations so option 2nd is true

[@SADDAMHUSSAIN-mw3cv]

Yes. Correct option is 2nd one.

[@komalkapoor3488]

Yes option 2 is true

[@kungumsraj3026]

Excellent way of explanations for all the questions... Thanks for sharing

[@mr.bhushanbalpande5110]

Dear Sir ..... at 6:40 the question you have discussed is from CSIR NET Dec 2016, Part C, and the correct options are (A) and (C) ..... I think you are making it in a wrong way ....... if it holds for some values then it is weak and if it holds for all then it is strong. In addition to this strong always implies weak ......... Please correct it .....

[@sandipsarkar9719]

Exactly... And if it is strong then imply weak but converse not hold.

[@kumaranand5084]

yes you are absolutely right I check this q ans in different pyq book

[@raghuvd1763]

You said correct. opt a and c are correct.

[@anitakaushik-be8mo]

Correcct

[@yogeshjadhavpatil4120]

Great teaching guruji

[@DrHarishGarg]

Thanks...

[@SOMPALSINGH-ps9gl]

Dear Sir, according to myself the functional J[y] has a strong minimum. So option 3 will be correct. Please check it and clear my doubt.

[@shifakhanam6298]

At 16:04 just an error of negative sign y''-y=-sinx.... So that option 2 is correct

[@artidevi8628]

Thank you so much sir 😊

[@sonaligoud-de1cj]

Thank you so much sir for your short tricks. 🙏🙏🙏

[@jobinbaby8287]

Very helpful lecture

[@RanjangamingYT7477]

6:43 a,c option correct

[@kavitagarg6029]

👍 nice

[@DrHarishGarg]

Thanks

[@anupamsamanta6690]

Very nice 🎉

[@DrHarishGarg]

Thanks... I hope you can share with others.

[@rijudey8718]

16:52 option (1) is correct, I think. after using natural boundary condition.

[@virendrakumar6922]

thank you so much sir

[@ahsanmehmood5875]

Awesome

[@Indigenuos]

Thank you sir 🙏

[@maths310-concept]

Thanks sir😍

[@SouvikDas-rw7rp]

sir in the third problem one boundary conditions are given then why natural boundary conditions use?

[@shifakhanam6298]

Sir please mention the corrections as it is very helpful for us. Thank you❤

[@DrHarishGarg]

Noted

[@mukeshlalit5152]

Yes you told opposite

[@sandipsarkar9719]

Sir at 10:48,there exist some polynomial which is neither even nor odd. How can u say this there does not exist such unique y, please clarify??

[@joymath5588]

Nice

[@savitrikuldeep]

Sir please check question no 4 where you discussed maxima and minima there is some problem please check I think strong and weak minima both the correct

[@pinakroy5928]

Yes you are right

[@factsgenius3333]

No it's alright, strong minimum=> weak minimum but Converse need not be true.

[@pinakroy5928]

Definition wrong for strong and weak

[@kartik3535]

Both strong and weak should be there

[@piyushpandita8016]

Thanks ​@@kartik3535

[@chiragthakur3876]

Sir what is the meaning of x belongs to c^2[0,2]

[@DrHarishGarg]

C^2 means continuously diffrrentiable function twice... [0,2] means interval.

[@chiragthakur3876]

@DrHarishGarg thanks sir❣️

[@nishajyoti5896]

👌

[@ronneysaini7763]

Sir Integal Equation nd Numerical Analysis Also🎉Alsop

[@debajitroy7300]

37:07 Y"-aY solution??? I think not correct

[@asimdas2571]

Probability and statistics pyq solution plz

[@someshnogia2009]

25:55 the option (c) is correct. b is not write ans.

[@januaj5268]

Explain your reason

[@subramaniv6791]

Sir polytechnic trb question upload sir

[@bimlakumari7794]

Last vale me Infimum kse zero se bda huva smj nhi aaya sir pz next video me smjane ki krpa kre🙏🙏🙏🙏👆👆👆👆👆👆👆

[@rishebbarwal6344]

16:03 not sinx its -sinx

[@piyushgupta9072]

Kya yrr bhai glt krwadia

[@critical1306]

Sir please apna address ya whatsapp no de hame advice lena hai

[@sagnikdash9060]

Thank you so much sir 🙏🙏

[@prabhadhatterwal3484]

Thanku so much sir