PYQs on Uniform Continuous & its Properties CSIR NET 2011 to 2023 Short Cut Tricks #csirnetmaths #csirnetmathematicalscience #csirnet
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@nishajyoti58962 ай бұрын
Your lecture series is make us strong to fight any exam within suitable time
@subratpradhan3581Ай бұрын
One correction on the DEC 2023 question : on 52:30 h(x) = x² is not uniform continuous on [0, ∞) hence the 4th option will be discarded. Sir, himself has mentioned it's not UC on the next question. Its not UC because we have two sequences aₙ=√(n+1) and bₙ= √n on [0,∞) such that |aₙ - bₙ|---> 0 as n--->∞ but |f(aₙ) - f(bₙ)|---> 1
@knowledgefactory332 ай бұрын
Sir your approach to Csir net Questions is Always Unique... ❤❤❤
@aslicodes973626 күн бұрын
great lecture with very useful shortcut methods, thank you sir
@celinfionaj46962 ай бұрын
Sir my another request, can you solve csir problems on singularity topic in complex analysis with short cuts. After completing differentiability topic in real analysis , as these series are very useful for our last minute preparation for csir exam.
@mathematics22792 ай бұрын
Thank you so much sir ❤ you solve csir question like board exam questions you have great skills to solve problems and you teach us for free . thanks again ❤
@aishwaryasaini71962 ай бұрын
Thank you sir for providing this lecture
@imkunalkapoor2 ай бұрын
Thank you so much sir this is too much helpful and exam so near thanks again
@NeelamRani_Mathematics2 ай бұрын
Very help full lecture for preparing net, I shared it among my students preparing net . thanks sir
@pusplatasahu5738Ай бұрын
Superb session.....❤
@professorragavan97832 ай бұрын
Thank you sir ❤
@divakarmaurya95992 ай бұрын
Differentiability ke baad complex analysis (bilinear transformation) ka topic Kara dijiye sir
@subratpradhan3581Ай бұрын
THANKS YOU SIR FOR THE LECTURE IN UNIFORM CONTINUITY 🙏🙏
@kulsoomarashid42662 ай бұрын
50:05, last option doesn't seem correct because then f will also be uniformly continuous.
@ishadevi2071Ай бұрын
Thnku so much sir its really helpful 😊
@chauhanpriyanka98712 ай бұрын
Thnaku sir apke video se ese lgta h jse csir easy h
@techmath89222 ай бұрын
I am really happy sir ... I understand all concepts easily
@himanisingh3784Ай бұрын
Very. Very helpful❤❤❤❤
@deepikasharma44862 ай бұрын
4.4k watch n why you are guys not liking the vedios ? I don't think anyone can explain here on yt history even i went to dips their questions discussions was in the air they didnt wait cz they taught iitians n DU students who were already toppers I never gets why they take choching even after coming from institutions like that. Well its humble request to all of you who are attending lectures series here to like the vedios n share too
@kulsoomarashid42662 ай бұрын
Last question, option b is also correct because if I is compact ( closed and bounded) then f and g are both bounded and hence fg is uniformly continuous
@deepikasharma44862 ай бұрын
I must say your analysis is so strong 🙌
@Justyourkaran2 ай бұрын
Thankyou for this lecture Harish sir, with these videos we are able to analyse that csir is just repeating similar qns year after year. Your approach makes the csir look doable busting all the myths prevailing in Delhi based coachings. PS: sound issue is still prevailing, kindly look into it. As this problem ruins the quality content that you're delivering in lecture.
@kancharlaasritha94942 ай бұрын
Thank you sir
@Justyourkaran2 ай бұрын
Its my humble request to all the aspirants to kindly like the video too it would take just 2 seconds, but it would benefit the reach of this video thru YT algorithm. PS: despite 4.2k views only 200 something likes is non-reciprocation of sir's efforts!!
@sheemanitinsan72352 ай бұрын
Thank you for more supporting sir 🙏🏻♥️
@kumardillip45052 ай бұрын
Your service for us will be remember for ever ❤❤
@habibulislam5262Ай бұрын
very helpful👌
@mathematicslovers28882 ай бұрын
Sir your video lectures are very helpful
@mdsalman7651Ай бұрын
Sir please make a video on Statistical Inference
@anshikathakur7085Ай бұрын
Thanks a lot sir ❤
@anuragpandey49122 ай бұрын
Thank you so much sir 🙏🏻🙏🏻🙏🏻
@professorragavan97832 ай бұрын
Sir I have a doubt in 44:42 ... According to your shortcut, in option c, f(g(x)) g(x) is uniform continuous, but f(x) is un bounded so f(gx) cannot be uniformly continuous. How can I differentiate option 1 and 3?... Please clarify sir... Thankyou ❤
@dhrubajotidas82762 ай бұрын
if that condition holds that only gurantees that..if it not then you can't say anything...apply derivative test
@professorragavan97832 ай бұрын
@@dhrubajotidas8276 Ok thank you
@user-hw4ss4fl5y2 ай бұрын
Sir make video on NBHM pyq
@ChandanKumar-dn9lz2 ай бұрын
Charan sparsh Gurudev....
@positivethoughts64192 ай бұрын
Thank you so much sir 😊
@Hasnainmaths2 ай бұрын
very helpful
@Rawat11082 ай бұрын
Thankyou sir. The session was awesome. I know you are proficient in this field. Sir please check it according to official answer key correct answers for the question (53:00) in 1,2 and 3, forth one is incorrect. Once again thank you.
@anitakaushik-be8mo2 ай бұрын
25:38 que ka ans shi lga kya sbko ...?? f(2π) ki value galat h ..mere hisab s to c option shi hona chahiye ...anyone correct me if m wrong
@dhrubajotidas82762 ай бұрын
galat hya woh
@vahisht12 ай бұрын
53:20 in this question it was asked that which of the following options implies that the function f is UC, it is not already given UC, which you told so :(
@Manish-uq5le2 ай бұрын
Thanks sir ❤
@goutamjana12922 ай бұрын
Sir please upload sequence and series of function pyq video
@DrHarishGarg2 ай бұрын
Already uploaded.... Check my lecture "Uniform Convergence"
@DrHarishGarg2 ай бұрын
kzbin.info/www/bejne/h5qXlHeBiqh6o6s This is the link
@goutamjana12922 ай бұрын
Okk sir . Thank you sir 🙏🙏
@SanchitMehra-mf3rh2 ай бұрын
Again thanks sir,
@rashmimalik97692 ай бұрын
🎉 thanks sir
@mr.chauhan86442 ай бұрын
Thanku you sir❣️🚩
@subratpradhan3581Ай бұрын
For the last question, By Heine Borel theorem, I is not compact since option(d) is discarded.
@marubahamad12362 ай бұрын
Thanks sir
@animeshpramanik7862Ай бұрын
nice sir
@vahisht12 ай бұрын
52:00 Last option is incorrect as x^2 is not uc in R, its graph is parallel to Y axis
@kulsoomarashid42662 ай бұрын
Ya I have the same confusion
@shreya22622 ай бұрын
tysm
@aamath2 ай бұрын
Great 🙏 .. Some mistake I think in ques. Gate 2004?
@professorragavan97832 ай бұрын
For the last question. Option a Since f,g are UC therefore both are bounded. So either f or g us bounded is wrong. So option a is wrong. Option b If we choose I as Real numbers then it is not compact. So option b is also wrong. Is it right sir??...
@dhrubajotidas82762 ай бұрын
real number is not an interval
@Siyagupta52Ай бұрын
@@dhrubajotidas8276 It is an interval
@mathematics22792 ай бұрын
Sir tifr ke last two three years ke real and linear ke questions bhi krwa do if you have time tifr concept are repeate in csir I think . thanks ❤
@aishwaryasaini71962 ай бұрын
Kindly provide lecture on abstract algebra also.
@ronneysaini77632 ай бұрын
Kitne bar bole.. Sit ka domain nahi hbye subject
@king-by1kh2 ай бұрын
Sir f(x) =x and g(x) =1 then clearly h(x) is Uniform continuous on R clearly R is not bounded so how option c is true only option 1 is true sir
@dhrubajotidas82762 ай бұрын
given I is an interval
@king-by1kh2 ай бұрын
@@dhrubajotidas8276 R is also an interval (-infinity, infinity)
@Pbt6562 ай бұрын
(a, infinity) is also an interval
@king-by1kh2 ай бұрын
@@Pbt656 we have to discard the option so we take R other wise it always hold on finite interval
@kanchansharma16752 ай бұрын
🥀
@kulsoomarashid42662 ай бұрын
1:03, f is uniformly continuous doesn't imply f satisfies lipchitz condition
@atamohammad6167Ай бұрын
UC=> lip. But converse need not to be true
@parthibanrajapalayam1865Ай бұрын
Converse is true only if derivative is bounded
@nehasharma-zx5xi2 ай бұрын
Sound quality sahi nhi h😬....
@kajalsoni65972 ай бұрын
A,b,c
@sumathinagarajan19372 ай бұрын
ONLY ANSWER C IS CORRECT
@Ekshivbhakat2 ай бұрын
B and c
@sumathinagarajan19372 ай бұрын
ONLY ANSWE C IS CORRECT
@divakarmaurya95992 ай бұрын
In last pyq it is not compact since not closed and option a is true b is false
@king-by1kh2 ай бұрын
How option c is true bro if f(x) =x and g(x) =1 then clearly h(x) is Uniform continous On R but R is not bounded so how it is correct
@user-lo2qx8ow9e2 ай бұрын
@@king-by1kh Bro h is defined from I to R ...so we need to consider an interval in which f and g are u.c that's why interval must be bounded for h(x) to be u.c.
@king-by1kh2 ай бұрын
But it is not necessary because I is also consider as(-infinity, +infinity) f(x) =x is Uniform continuous on R but R=I is not bounded