Q. 4.22: Design an excess-3-to-binary decoder using the unused combinations of the code as don’t-car

[@pranst8483]

Thanks to you, I did my homework well!

[@CellerCity]

Ek like toh banta hai sir aapke explanation ke liye😀

[@hamza9052]

Everyone who is thinking that where the decoder is, In z=D' As A+A'=1 z=D'(A+A') z=D'A+D'A' z=D'A(B+B')+D'A'(B+B') z=D'AB+D'AB'+D'A'B+D'A'B' z=D'ABC+D'AB'C'+D'A'BC+D'A'BC'+D'A'B'C+D'A'B'C'------------(1) So we know the decoder has 4 inputs ABCD and 16 outputs A'B'C'D', A'B'C'D..... so on. So from (1), just add these minterms at output of decoder using or gate. Do the same method with the rest, w,x,y.

[@ApoorvaLN]

thanks!!

[@NikitaNair]

Nice

[@laibanadeem5639]

THANK YOU!

[@ysevanlee7489]

Thanks for the informative video! Incidentally, how come we don't get Z = D' + AB? I may still not be entirely familiar with K-maps, but I thought I was supposed to take don't-cares into consideration here.

[@kAAshishSingh]

sir aap mera paper dene chale jao kal saari arrangement main kar dunga aapke liye

[@umaramin-jb3ne]

what if we have to convert excess 4 to bcd

[@zedworku3897]

Thank you too much !!

[@karthikpadub9527]

Where's the decoder here?

[@satwiktatikonda764]

Same doubt here 🤔 Sir 🙋‍♂

[@madhavrabinbipin2116]

the required decoder 's logic circuit is given by sir

[@unstoppableguy7896]

this is already decoder. Decoder's output is minterm

[@system_out_println0]

я такой в майнкрафте строил, лол