Dear sir.. If u can increase number of questions.... Like 2 to 3 questions, Video thooori se lambi hogi....but will be very helpful. Thanku so much🤗Your efforts are heartily welcomed.😊
@R2NITian4 жыл бұрын
Sir,Increase no. Of Question
@piyushsolanki99874 жыл бұрын
My dream of studying from HOD sir..comes true..
@subodhmohanty24093 жыл бұрын
Fantastic, superb.
@seemasahani66154 жыл бұрын
Very gd concept dimag ki batti khul gae thanku sir
@varuduhero6064 жыл бұрын
good morning sir plzz also provide dpp on topic sir, theory+questions jyada yaad hoga
@swatantrakumarmishra8804 жыл бұрын
🙏Awesome Sir...
@charjan254 жыл бұрын
Sir some sources mention Dibalh reduces aldehyde, ketone. Please clarify. Dibalh is always confusing.
@baishaliagrawal76884 жыл бұрын
Yess nabh4 and dibalh
@Cricketttt6584 жыл бұрын
Sir hume 5 minutes nhi 1 hour chemistry padna hai aapse you are awesome..great legend of chemistry
@sudhanshubaranwal33144 жыл бұрын
Sir but I had studied that we should avoid wolf kishner reduction when given reactant has halide, acid halide,anhydride and ester.. And we should avoid clemmensen redn when reactant has alkene,alkyne,alcohol and ether. Am I right or not??
@shishirmit4 жыл бұрын
Good question. For arguments sake, consider the attack of Alkoxide ion on the given molecule. Please remember, we have alkoxide, not hydroxide. The ring can open up and a new Ester may be formed. But the departing RO- stays on the molecule, can reattack the new ester. They will reconvert to the original one, much more preferably since it is intramolecular attack. The information you have presented is useful and memory-based. The case I have taken is mechanism-based, a lot more interesting
@sudhanshubaranwal33144 жыл бұрын
@@shishirmit Ok sir. Got it. Thank you so much for this beautiful explanation.
@GoluKumar-xb1vt4 жыл бұрын
GM Legends of chemistry
@R2NITian4 жыл бұрын
👍👍👍
@autonomousautonomous50804 жыл бұрын
Amazing video Sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@dhruvmahi5464 жыл бұрын
Sir pahle wala series hi acha tha
@alpenliebeshorts4854 жыл бұрын
#Awesome S.M sir
@varadarajanr82824 жыл бұрын
Zarbadast!
@MaheshSingh-dc6xi3 жыл бұрын
Sir offline me aap kis coaching me padte hai please sir reply
@RitikKumar-zm2yt4 жыл бұрын
Sir, Wolf kishner reduction is avoid to use for compounds which have base sensitive groups like -esters, anhydride etc . So how here we use wolfkischner??
@shishirmit4 жыл бұрын
Good question. For arguments sake, consider the attack of Alkoxide ion on the given molecule. Please remember, we have alkoxide, not hydroxide. The ring can open up and a new Ester may be formed. But the departing RO- stays on the molecule, can reattack the new ester. They will reconvert to the original one, much more preferably since it is intramolecular attack. The information you have presented is useful and memory-based. The case I have taken is mechanism-based, a lot more interesting
@chemphile114 жыл бұрын
Sir, in a book ( Named reactions by Laszlo Kurti) it is given that in wolff kishner reduction hydrolysis of Esters, lactones Amides etc takes place.. And base catalysed hydrolysis is irreversible... So I think ans should be clemensen or none of them.
@Anshukumar-wi3vj4 жыл бұрын
Sir in hydrocarbon specially alkenes part I have a bit confusion on Hoffman product and cope elimination
@Anshukumar-wi3vj4 жыл бұрын
Basically on mechanism as how the less stable get as product
@Lucifer33085 Жыл бұрын
Good lecture
@aryanbajpayi1734 жыл бұрын
Super sir 👌👌👌👌👌 Good morning sir🙏🙏🙏🙏🙏
@atul50334 жыл бұрын
Sir thank you for this video But sir plzz make one video on .....reducing and non reducing sugar
@abhibhatnagar40664 жыл бұрын
sir do DIBAL H react with acids??? Having this doubt since long back :/
@shishirmit4 жыл бұрын
yes
@abhibhatnagar40664 жыл бұрын
@@shishirmit sir I was told that at normal working temp of Dibal H (ie -78℃ ) acids are not reacted ...They need high temp ??
@deepakumari67744 жыл бұрын
Very helpful content u r providing sir
@nirupamchatterjee804 жыл бұрын
Will u pls tell me about the board in which u write viz the company which arranged it... A brief consultation help me a lot..
@manushukla71364 жыл бұрын
Inorganic aur physical ka revision course available hai kya sir?
@palashsinghal7994 жыл бұрын
Sir please make video on oxidation also
@archanasolaw57574 жыл бұрын
Great video
@kartikeymishra31494 жыл бұрын
a great chemistry sir
@techprogramer18884 жыл бұрын
Good Morning sir Ji Awesome sir
@sarthaksharma2134 жыл бұрын
Oxidation and reduction of H2O2
@kartikgarg4414 жыл бұрын
Sir clemmeson mein to phir bhi conc.hcl hai wolf kishner mein zyada possiblity nhi hai Kya hydrolysis ki??
@shishirmit4 жыл бұрын
Good question. For arguments sake, consider the attack of Alkoxide ion on the given molecule. Please remember, we have alkoxide, not hydroxide. The ring can open up and a new Ester may be formed. But the departing RO- stays on the molecule, can reattack the new ester. They will reconvert to the original one, much more preferably since it is intramolecular attack.
@anishamohapatra58174 жыл бұрын
Sir do these type of questions only no theory sir please
@abhishekanand58984 жыл бұрын
Great!
@mdataullah68784 жыл бұрын
Sir you are great
@siddharthakumarsingh82514 жыл бұрын
Sir but while using wolff kishner base sensitive group should be absent
@shishirmit4 жыл бұрын
Good question. For arguments sake, consider the attack of Alkoxide ion on the given molecule. Please remember, we have alkoxide, not hydroxide. The ring can open up and a new Ester may be formed. But the departing RO- stays on the molecule, can reattack the new ester. They will reconvert to the original one, much more preferably since it is intramolecular attack. The information you have presented is useful and memory-based. The case I have taken is mechanism-based, a lot more interesting
@rahulbansal44584 жыл бұрын
Sir but hydrolysis of ester also take place in basic medium and that too irreversible so how can we use wolf kishner reduction ??
@shishirmit4 жыл бұрын
Good question. For arguments sake, consider the attack of Alkoxide ion on the given molecule. Please remember, we have alkoxide, not hydroxide. The ring can open up and a new Ester may be formed. But the departing RO- stays on the molecule, can reattack the new ester. They will reconvert to the original one, much more preferably since it is intramolecular attack.
@rahulbansal44584 жыл бұрын
@@shishirmit thank you sir, I get it
@parhisanjaya4 жыл бұрын
Sir, why you always targeting reduction, cover other topics in physical chemistry or inorganic
@golumaratha32974 жыл бұрын
thank you sir
@sriramsrungaram77674 жыл бұрын
Sir is there a crash course available for Physical Chemistry for 2020 aspirants?
@shishirmit4 жыл бұрын
Yes. After 2 weeks
@sriramsrungaram77674 жыл бұрын
@@shishirmit Thank you sir. Looking forward to joining it.
@shivanipatidar19024 жыл бұрын
kya ye crash courses free he
@sriramsrungaram77674 жыл бұрын
@@shivanipatidar1902No. These are paid crash courses.
@shivanipatidar19024 жыл бұрын
@@sriramsrungaram7767 OkThanks for this information
@PrashantKumar-cy5lr4 жыл бұрын
sir please launch crash course of inorganic and physical also🙏🙏🙏
@shivamverma94474 жыл бұрын
💛💚💙
@rahulraghavendrachoudhury96624 жыл бұрын
Sir plz mechanism based questions karaye . Although the lecture was very helpful
@satyvachan39284 жыл бұрын
Sir 5 minutes theory aachha tha
@abhishektomar36644 жыл бұрын
Maja aa gya sir
@expansion_forever4 жыл бұрын
Sir increase important theory
@quantumclasses22824 жыл бұрын
Sir good morning
@rohitdas6444 жыл бұрын
🤩🤩🤩🤩
@Ranjankumar-fc1fv4 жыл бұрын
🙏🙏🙏
@RAHULYADAV-de3ef4 жыл бұрын
New series best h
@sarthakagarwal7804 жыл бұрын
ISOMERISM IN CO ORDINATION COMPOUNDS
@jaygadage54744 жыл бұрын
Sir seo2 please IT is confusing 🍊
@shishirmit4 жыл бұрын
...and useless. Do not waste your time
@jaygadage54744 жыл бұрын
Thanks sir but it was asked in jeemain
@ShortBrainOfficial4 жыл бұрын
Gm..sir.. away some content..
@shabban38964 жыл бұрын
Sir b and d
@rishabh38564 жыл бұрын
Guys Red P +I2 aur RedP +HI.....same hee hota hai na!?
@lemonlemon44354 жыл бұрын
Yup
@varadarajanr82824 жыл бұрын
But Red P + Br2 or Red P + Cl2 with give HVZ in Carboxylic Acids.