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Quality Factor (AKA: Q) Explained (059)

  Рет қаралды 10,914

Electronics for the Inquisitive Experimenter

Electronics for the Inquisitive Experimenter

Күн бұрын

aaah yes, there is Q which stands for Quality Factor!
In this video I am going to explain what Q is and point out the basic things that can cause the Q to be less than stellar.
What is Q?
How does it relate to components?
How does it relate to resonant circuits?
How do I calculate it?
=========================
Time Markers for Your Convenience
----------------------------
00:05 Introductory Comments
01:05 Q on the Component Level
01:06 What is it?
02:44 Calculating it
04:44 Q and the Resonant Circuit
04:48 What is it?
05:11 The Series Resonant Circuit
06:43 The Parallel Resonant Circuit
08:05 Calculating it
08:17 Finding the Bandwidth of a Resonant Circuit
08:20 EXAMPLE #1
08:23 The Bandwidth
09:47 Calculate the Q
10:29 EXAMPLE #2
10:43 The Bandwidth
11:21 Calculate the Q
12:00 Concluding Comments and Toodle-Oots

Пікірлер: 46
@thed8229
@thed8229 Жыл бұрын
I understand Q better than I did 12mins ago. Mission accomplished!
@eie_for_you
@eie_for_you Жыл бұрын
Woohoo! Good news! 🙂
@RobLudwick
@RobLudwick Ай бұрын
I love your scene transitions, btw. :) "Meet me at camera 2"
@eie_for_you
@eie_for_you Ай бұрын
Thanks! I'm working at trying to develop some more variety for some of my future videos. 🙂
@W1RMD
@W1RMD Жыл бұрын
Best description of 'Q" yet. Thanks for making this so simple and straight forward.
@eie_for_you
@eie_for_you Жыл бұрын
Thank you and you are welcome! 🙂
@tsharathchandra7074
@tsharathchandra7074 7 ай бұрын
This is by far one of the best practical explanations I have ever seen. Thank you
@eie_for_you
@eie_for_you 7 ай бұрын
Thank you and you are welcome! 🙂
@NickFrom1228
@NickFrom1228 Жыл бұрын
So many things make sense now. I learn more in one video on this channel than multiple other sources. Huge thanks!
@eie_for_you
@eie_for_you Жыл бұрын
You are very welcome, Nick! 🙂
@anthonyselby8337
@anthonyselby8337 2 ай бұрын
thank you very good explanation as a novice hobbyist trying to rap my head around electronics this video actually explains it very well
@eie_for_you
@eie_for_you 2 ай бұрын
Thank you! I am so glad that this helped you understand what Q is. 🙂
@nathanherling9836
@nathanherling9836 10 ай бұрын
I appreciate your 'turn to the camera' segues. .. .
@eie_for_you
@eie_for_you 10 ай бұрын
Thanks! (as he turns to the camera and smiles)🙂
@aasm-f4l
@aasm-f4l 22 күн бұрын
Thank you so much it is very easy to understand with practical explanation hoping for more such content 🙏🏻
@eie_for_you
@eie_for_you 21 күн бұрын
Thanks! I'm glad it was helpful. 🙂
@SpinStar1956
@SpinStar1956 9 ай бұрын
Great video! Great use of graphics and clear explanation! Thanks Ralph! 73...
@eie_for_you
@eie_for_you 9 ай бұрын
Thanks! 🙂
@N6WLM
@N6WLM Жыл бұрын
I was thinking about making some of the NVARC “Ugly” Filters DIY bandpass filters. Sadly, the capacitors they recommend in the build are no longer sold. The instructions often referenced component Q when picking parts, so I was very confused how to determine the Q of a part to find replacements. This is very useful information, thank you! The Ugly Filters encompass many topics you've covered on your channel, it would make for a great video!
@eie_for_you
@eie_for_you Жыл бұрын
One way that I got a feel for the relative Q of various capacitors was to set up a quicky representative resonant circuit. I put this series resonant circuit (made with a coil I wound on some PVC pipe + my test capacitor) in series between port 1 and port 2 of my VNA and did a through (S21) measurement. This is not a way to actually measure the Q of the capacitor, but you can try various capacitors and definitively see which one provides the best, high Q, response relative to its cousins. With this you should see a peak in the response as the series resonant circuit becomes a short at resonance. This feels like an interesting possibility for a short video ... you think?
@SeyedAgent47
@SeyedAgent47 Жыл бұрын
Perfect job... Please continue thanks👍
@eie_for_you
@eie_for_you Жыл бұрын
Thanks! That is my plan!😁
@abderraouflalla
@abderraouflalla 8 ай бұрын
Thank you for the clear explaining sir.
@eie_for_you
@eie_for_you 8 ай бұрын
You are very welcome! 🙂
@yt4krist0f
@yt4krist0f Жыл бұрын
Simple and perfect explanation..! Thanks!
@eie_for_you
@eie_for_you Жыл бұрын
Thanks!
@34u90vutjwifjklSFJKJKSDjs9
@34u90vutjwifjklSFJKJKSDjs9 Жыл бұрын
Thank you for the simple explanation! Q finally makes sense. The only thing I am unsure of is whether or not the two definitions for Q are mathematically identical, ie. is X/R = f0 / BW ? Or is this an approximation or generalization.
@eie_for_you
@eie_for_you Жыл бұрын
Well...just thinking about it ... one is used for components and the other for a resonant circuit. At resonance the total effective value for X is zero. So, this raises the question, "What about the 3 dB points? I just did a mathamatical exercise to answer this. A parallel tuned circuit with a Q of 625 per the fo/BW method (fo=50MHz; BW=0.08MHz). If we calculate the Q using X/R at the 3dB point we get a Q of 1.24 (Z=9963.56+12373.65j). Good question! But it doesn't work out that way.
@mrhahmad1
@mrhahmad1 Жыл бұрын
Tqvm...
@eie_for_you
@eie_for_you Жыл бұрын
???????????
@Festus2022
@Festus2022 10 ай бұрын
Nice video. I have a dumb question. Why are you decibel numbers negative? Thanks1
@eie_for_you
@eie_for_you 10 ай бұрын
Glad you found the video helpful. The dB values are all negative because I was talking about a passive circuit where the resonant circuit is the output impedance. Being a voltage divider, the voltage gain will always be a negative dB number. Hope this makes sense. :-)
@Festus2022
@Festus2022 10 ай бұрын
Thanks. I will dwell on that answer. @@eie_for_you
@eie_for_you
@eie_for_you 10 ай бұрын
@@Festus2022 Just to give you food for thought... Vout/Vin = Rout/(Rout+Rin); Rout/(Rout+Rin) is always less than 1. dB = 20*log(Vout/Vin) if Vout/Vin is less than 1, then the log (Vout/Vin) will be negative. Hope that helps the noodling. 🙂
@Festus2022
@Festus2022 10 ай бұрын
Thanks again!! Appreciated.@@eie_for_you
@oldblokeh
@oldblokeh Жыл бұрын
Thanks, Ralph. I'd be grateful if you could say a few words on loaded Q, which is a term often heard.
@eie_for_you
@eie_for_you Жыл бұрын
I've been thinking about this very thing myself, knowing that I did not address it in my video. There is the Q of a resonant circuit when it is just sitting there all by itself, enjoying the influx of energy and minding its own business. But, generally speaking, resonant circuits don't exist floating out in space by themselves. Something is drawing energy from them to, say, and antenna or another circuit. This very action changes the Q of the circuit. This new Q is referred to as "loaded Q." Hope this makes sense.
@oldblokeh
@oldblokeh Жыл бұрын
@@eie_for_you Yes, it does make sense, thanks.
@eie_for_you
@eie_for_you Жыл бұрын
@@oldblokeh I am glad to hear that. 😄
@tahirsongelen7781
@tahirsongelen7781 Жыл бұрын
tnc ur expl and efford BR fm istanbul
@eie_for_you
@eie_for_you Жыл бұрын
Thanks!
@d46512
@d46512 Жыл бұрын
For God so loved the world that he gave his only begotten son, that whosoever believes in him should not perish, but have eternal life. ✝
@eie_for_you
@eie_for_you Жыл бұрын
Best news in the whole world!
@factify2022
@factify2022 Жыл бұрын
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