Finally found a satisfying explanation. Thanks a lot, my friend. I will recommend this channel to my friends too. Subbed!
@terachad30002 жыл бұрын
@@Elucyda you are very good but I didn't understood why is the internal energy (change) is zero.
@larryzdanis5377Ай бұрын
Nice.. since I knew that the enthalpy and internal energy of a gas are only a function of its temperature.. I was struggling to understand how the MechPE manual had an expression for reversible work for an isothermal process - my ?? was, where is the energy coming from to do work.. now I realize I was thinking of a closed system, and that was the error.. with an open system, work can be done or absorbed or by addition or subtrataction of heat through a heat sync .. certainly one of the more subtle/tricky concepts in thermodynamics (which is probably rarely utilized in practical applications) and your video cleared that up for me, thanks
@dylanbeck36073 жыл бұрын
You explain scientific concepts in such a brilliant and succinct way! I'm happy to have discovered your channel and I wish I had the pleasure of you teaching my classes :) Keep being awesome^^^
@deepanshinandal89612 жыл бұрын
I am from India I am a student of class 11th To which classes thermodynamics is most appropriate to teach in your country?
@tarcisiomenezes3318 Жыл бұрын
Finally found a good explanation. Thanks man!
@happyfrezar28135 ай бұрын
Your explanations are amazing bro❤👍🏼 You know what you are saying 😂
@ericsi50323 ай бұрын
Thank you so much for explaining it so clearly, i was very lost until I found your video. Thank you very much!!
@heyyo1622 жыл бұрын
If I compress the piston, my work is converted into thermal energy inside the box. Then the heat sink takes that energy away. how can then the piston go back up, the energy should have been lost ?
@putzak2 жыл бұрын
Your'e a great teacher!
@shrutidodiya71173 жыл бұрын
I am indian but your explanation is so better
@Washingmachine38326 Жыл бұрын
???
@andriyivanov4810 Жыл бұрын
Hi matey, thanks for the explanation what problem completely doll I cannot understand basic sing why if you’re applying heat temperature remain constant this I believe this is basic stink of iso thermic process but I cannot understand could you please explain
@איתימטייב2 ай бұрын
Very clear and informative thanks!
@graceoffeibeaacquah8996 Жыл бұрын
Akoa aben😂. (Very intelligent)
@PureQuotes4 жыл бұрын
Thanks
@iskandar10232 жыл бұрын
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air. A. -80.35 J B. 80.35 J C. -811.93 J D. 811.93 J (please show calculation) can use this formula W=nRT ln(p1/p2) Can you help me..everyone doesnt know how to solve this..i must present this question to my lect..please notice me
@smitagravat10633 жыл бұрын
I know this every thing but i still can't understand how we can apply heat if temperature is constant
@mahimachoudhary81383 жыл бұрын
Thank you. Sir
@danielsantslv45652 жыл бұрын
what if I want to do the isothermal curve on a P - v (specific volume) diagram? I don't know in witch table I should seek for the values to do the curve.
@Gruntol53 жыл бұрын
Can you help me? How much heat needs to be rejected during a true isothermal compression of 3,000 cubic feet of air, when compressed from 15 psi to 4,500 psi using a 3-stage compressor?
@zinc67482 жыл бұрын
Here,∆U=0. Explain further.
@florencejaynepalma84663 жыл бұрын
Hi! I'm a new fan.. Thank you for your lectures. I like the way how you explain things. Your voice is also very calm.
@Vinicius-gr3it Жыл бұрын
Eu tentando estudar para termoquimica e voce apareceu kkk
@arunprayog79862 жыл бұрын
U r awesome
@fehmidasalam20362 жыл бұрын
Thank you, I was having a confusion in that! You are amazing! Subscribed
@tacticalmistress2 жыл бұрын
Baby brother of AK lectures.
@raimazaman1284Ай бұрын
thank uuuuu
@muhainifahemahmasjuktoc75884 жыл бұрын
Great video!
@anonymously7__2 жыл бұрын
❤️
@pokihoki86992 жыл бұрын
Amazing!! helps me to understand easily😄
@harshass76523 жыл бұрын
Bro but in google Δu= Q-W so, when internal energy is zero, it becomes Q=W
@Elucyda3 жыл бұрын
Both sign conventions are correct as long as they are used consistently.
@mandavasasank38622 жыл бұрын
nice .great explanation sir ,thank u .
@aanchal60452 жыл бұрын
Thanku for teaching us in such a easy way..
@shivanshguleria11982 жыл бұрын
Nice video bro👍 well understood keep going 🙏
@lilykangai15983 жыл бұрын
You speak so clearly thanks. .well understood
@jeonjungkook14132 жыл бұрын
Nice explanation You keep nice going 👏
@vasconoronha7676 Жыл бұрын
Bro ur an amazing teacher ! Keep it up
@Nick2014B2 жыл бұрын
you're an angel thanks bro
@certezxgirl2 жыл бұрын
Ooh thankyou so much 😍👍
@cherryrosedaclitan20893 жыл бұрын
Thank you for this.. 😊
@milagros0707283 жыл бұрын
Thank you so much!!!
@saumyaelchatwar19673 жыл бұрын
Now I understood the concept
@наукажизнь-м9б2 жыл бұрын
Good men
@djay101016 ай бұрын
Definitely deserves more subscribers
@theboyplays1x4 ай бұрын
0:06
@SMAN03 жыл бұрын
Why not 𝑊=𝑛𝑅𝑇 ln (𝑉f/Vi)? Why have negative?
@Elucyda3 жыл бұрын
The negative sign comes from a sign convention for the work done. It is fine to use a different sign convention as long as you are consistent.