Quantitative Description of Isothermal (Constant Temperature) Process with Ideal Gas on P-V Diagram

[@xeno4162]

Finally found a satisfying explanation. Thanks a lot, my friend. I will recommend this channel to my friends too. Subbed!

[@terachad3000]

@@Elucyda you are very good but I didn't understood why is the internal energy (change) is zero.

[@dylanbeck3607]

You explain scientific concepts in such a brilliant and succinct way! I'm happy to have discovered your channel and I wish I had the pleasure of you teaching my classes :) Keep being awesome^^^

[@ericsi5032]

Thank you so much for explaining it so clearly, i was very lost until I found your video. Thank you very much!!

[@larryzdanis5377]

Nice.. since I knew that the enthalpy and internal energy of a gas are only a function of its temperature.. I was struggling to understand how the MechPE manual had an expression for reversible work for an isothermal process - my ?? was, where is the energy coming from to do work.. now I realize I was thinking of a closed system, and that was the error.. with an open system, work can be done or absorbed or by addition or subtrataction of heat through a heat sync .. certainly one of the more subtle/tricky concepts in thermodynamics (which is probably rarely utilized in practical applications) and your video cleared that up for me, thanks

[@shrutidodiya7117]

I am indian but your explanation is so better

[@Schrödinger38326]

???

[@vanvlogs4]

I am Indian but this lecture is amazing 👏

[@tarcisiomenezes3318]

Finally found a good explanation. Thanks man!

[@florencejaynepalma8466]

Hi! I'm a new fan.. Thank you for your lectures. I like the way how you explain things. Your voice is also very calm.

[@lilykangai1598]

You speak so clearly thanks. .well understood

[@deepanshinandal8961]

I am from India I am a student of class 11th To which classes thermodynamics is most appropriate to teach in your country?

[@aanchal6045]

Thanku for teaching us in such a easy way..

[@vasconoronha7676]

Bro ur an amazing teacher ! Keep it up

[@sureshanchan23]

Love from India ❤

[@djay10101]

Definitely deserves more subscribers

[@theboyplays1x]

0:06

[@איתימטייב]

Very clear and informative thanks!

[@CurlyMaiden]

Baby brother of AK lectures.

[@putzak]

Your'e a great teacher!

[@happyfrezar2813]

Your explanations are amazing bro❤👍🏼 You know what you are saying 😂

[@mahimachoudhary8138]

Thank you. Sir

[@mandavasasank3862]

nice .great explanation sir ,thank u .

[@jeonjungkook1413]

Nice explanation You keep nice going 👏

[@fehmidasalam2036]

Thank you, I was having a confusion in that! You are amazing! Subscribed

[@PureQuotes]

Thanks

[@muhainifahemahmasjuktoc7588]

Great video!

[@Nick2014B]

you're an angel thanks bro

[@pokihoki8699]

Amazing!! helps me to understand easily😄

[@shivanshguleria1198]

Nice video bro👍 well understood keep going 🙏

[@наукажизнь-м9б]

Good men

[@danielsantslv4565]

what if I want to do the isothermal curve on a P - v (specific volume) diagram? I don't know in witch table I should seek for the values to do the curve.

[@graceoffeibeaacquah8996]

Akoa aben😂. (Very intelligent)

[@陳允昊]

thanks bro

[@saumyaelchatwar1967]

Now I understood the concept

[@andriyivanov4810]

Hi matey, thanks for the explanation what problem completely doll I cannot understand basic sing why if you’re applying heat temperature remain constant this I believe this is basic stink of iso thermic process but I cannot understand could you please explain

[@anonymously7__]

❤️

[@certezxgirl]

Ooh thankyou so much 😍👍

[@milagros070728]

Thank you so much!!!

[@arunprayog7986]

U r awesome

[@heyyo162]

If I compress the piston, my work is converted into thermal energy inside the box. Then the heat sink takes that energy away. how can then the piston go back up, the energy should have been lost ?

[@cherryrosedaclitan2089]

Thank you for this.. 😊

[@Gruntol5]

Can you help me? How much heat needs to be rejected during a true isothermal compression of 3,000 cubic feet of air, when compressed from 15 psi to 4,500 psi using a 3-stage compressor?

[@raimazaman1284]

thank uuuuu

[@smitagravat1063]

I know this every thing but i still can't understand how we can apply heat if temperature is constant

[@zinc6748]

Here,∆U=0. Explain further.

[@iskandar1023]

As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air. A. -80.35 J B. 80.35 J C. -811.93 J D. 811.93 J (please show calculation) can use this formula W=nRT ln(p1/p2)​ Can you help me..everyone doesnt know how to solve this..i must present this question to my lect..please notice me

[@Abcdej_ha]

Thanks bro🥹

[@Vinicius-gr3it]

Eu tentando estudar para termoquimica e voce apareceu kkk

[@harshass7652]

Bro but in google Δu= Q-W so, when internal energy is zero, it becomes Q=W

[@Elucyda]

Both sign conventions are correct as long as they are used consistently.

[@SMAN0]

Why not 𝑊=𝑛𝑅𝑇 ln (𝑉f/Vi)? Why have negative?

[@Elucyda]

The negative sign comes from a sign convention for the work done. It is fine to use a different sign convention as long as you are consistent.