That last question was brutal. as always thank you. Your videos will be viewed by generations of engineering students to come, because of how clean they are and how clear the explanations are.
@QuestionSolutions3 жыл бұрын
You're very welcome :) I really appreciate your comment, very kind of you.
@denreyes673 жыл бұрын
👍 agreed
@masterblake93 жыл бұрын
Hey man, just wanted to say thank you for your videos. I'm not sure I would have passed my statics class without the examples and the clear way you lay out information. I'm glad to see you are still making videos. If you make videos about stress, strain, and other strength of materials topics I'll be here to watch! Thanks again.
@QuestionSolutions3 жыл бұрын
Thank you for taking the time to write a comment like this, I really appreciate it. I will definitely create videos about stress, strain, and I have been requested multiple different topics to cover, so hopefully, in due time, I can do them all. Truly happy for you, and I wish you the best on your future endeavors! Thanks again.
@WxerxesW2 жыл бұрын
@@QuestionSolutions please sir make videos on mechanics of materials and structural design and even hydrology/fluid mechanics. I will make a gofund me page for this let me know.
@BigSmokeEnthusiast2 жыл бұрын
Always manage to do a better job at teaching me the material than my professor. I recommended ur account to other students cuz of how much of a blessing ur Statics playlist is!!
@QuestionSolutions2 жыл бұрын
Thank you so much, really appreciate the shares! Best wishes with your studies.
@gripenjas39d-anm385 ай бұрын
I cant express my love on how many times this channel helped me, clean and straight to the point!!!!! Btw the 2force member actually really helped turn a lot of the complex questions into easier ones, i hope my prof actually teach this.
@QuestionSolutions5 ай бұрын
I am really glad to hear it! The 2 force member should definitely be in your textbook, and hopefully your professor covers it, but if they don't, you can always ask during office hours.
@MrMakeItRain.Ай бұрын
No way u made it that simple. I am mind blown!!
@QuestionSolutionsАй бұрын
:) Glad to hear!
@devrimeskibina95213 жыл бұрын
THANK YOU! I have my statics mid term tomorrow, and I was really stuck.
@QuestionSolutions3 жыл бұрын
You got this! Best wishes on your mid term.
@PunmasterSTP2 ай бұрын
How'd your midterm go?
@daswimmer6001 Жыл бұрын
Hello, at 9:45 why isn’t the answer for Ay = 9.91 kN in the upwards direction? I’ve done it on my calculator a bunch of times but do not get the same answer. I think the direction on Dy is in the wrong direction, since Cy = 1.52kN in the upwards direction and 7*sin(60) = 6.06kN in the downwards direction, surely Dy should be 4.54kN in the upwards direction to balance out and have net 0 newtons in the y direction … please advise thanks
@daswimmer6001 Жыл бұрын
Also, if you take a look at 9:02, the Dy is in the correct direction, so it must be a simple error.
@QuestionSolutions Жыл бұрын
I am not sure if you have the timestamps correct or if you're asking about the right question? Ay is already shown to be upwards, and I am not sure where you got the 9.91 kN from? Ay is 3.09 kN. Please let me know where you're referring to so I can help you out better. Again, even for Dy I don't know what you're referring to. It's shown to be upwards, we got a positive value, which confirms that it is indeed a force in the upwards direction.
@cerulity32k11 күн бұрын
this actually might save my mechanics mark thank you SO MUCH for this
@QuestionSolutions11 күн бұрын
You're very welcome! I wish you the best in our mechanics course. You got this!!!
@jedjoremmagbanua88742 жыл бұрын
Why should we neglect the reactions at pulley at 6:24?
@QuestionSolutions2 жыл бұрын
Because we are looking at the external forces. The effects of the pully on the pin doesn't help us solve the problem 👍
@chalammiriyala2761Ай бұрын
At 5:30 why did u not take torque or moment at 1250 If taken is by=0???
@QuestionSolutionsАй бұрын
The same reason why we didn't take the 650 N force either. The line of action of both of those forces go through the moment point, so they can't create a moment.
@uzairwajeeh1737 Жыл бұрын
In 1st example (at 3:10) how force at point A produces negative/clockwise torque?
@QuestionSolutions Жыл бұрын
If you push at A, the frame would spin counter-clockwise. Since we assumed clockwise to be positive, that would give us a negative value.
@engSendaza Жыл бұрын
Very informative video. Thank you. I have a question, at 4:45 ,is it that whenever we have such a case( a force applied at a pin joint) and we are considering equilibrium of the two pin jointed members separately, the external forces acting at the joint isn’t included
@QuestionSolutions Жыл бұрын
This is a very rare and specific situation. We only treat it the way we did because of the wording in the question, "The 600 N force is applied to the pin." I just wanted to showcase what needs to be done if such a question arises. Otherwise, you can solve it like any other problem shown on the video assuming the forces are applied to the frame.
@LuisRamirez-wb3ph2 жыл бұрын
On the first question what would the reaction forces be for E? Would Ex be 950N and Ey be 600N. If so, when I drew the FBD of member EDC the forces did not add up. One way I got Cx to be 350 while the video shows 650. I'm confused.
@QuestionSolutions2 жыл бұрын
To find the reactions at E, you would have to write a moment equation about point A and then go through the same process. Also, the question is asking for the components of the force pin C on ABC, not EDC.
@Old0den3 күн бұрын
Thanks for the great explanation, but I have a question. In the first example you said that we should not include external forces when it comes to analyse each member. However, in the last example you have included the force of the spring to the reaction force o the pin C, so how come?
@QuestionSolutions3 күн бұрын
Think of the spring as a member. That's why while on member CB, the spring force is shown down, while on member AB, the spring force is up.
@za36762 жыл бұрын
This video summed up what my professor couldn’t. I am a bit foggy on solving the three equations at the end. I thought B(y) would be the starting point but then there is theta. Idk how to isolate the 3 unknowns there. Or better yet which equation to start with. But still thank you for the video, it helped a great deal. I subscribed and will continue to watch
@QuestionSolutions2 жыл бұрын
So you can use any of the variables to start off the solving process. In general though, exams usually give you easy to solve equations. The process is to isolate for one variable, plug that into the next, then isolate again for the same variable in the next equarion and plug that into the last equation. I really encourage you to revise simultaneous equation solving with elimination and substitution. It's really important for most courses :)
@jaytea34813 жыл бұрын
At 9:43 why is 16(4) negative but all the other ones are positive?
@QuestionSolutions3 жыл бұрын
So take a look at the 16kN force with respect to the purple dot in the middle. If the beam can freely rotate about that purple dot, when we apply the 16kN force, would it turn clockwise or counter clockwise? It would be counter clockwise, so it's negative because we assumed clockwise moments to be positive.
@abotsimandela5688 Жыл бұрын
For the first problem you said the 600N force is not an external force, so why then did you used it to solve for the reactions at A?
@QuestionSolutions Жыл бұрын
It's not external when looking at a specific beam, so for example, when looking at ABC. However, looking at the whole system as a whole, the 600 N force will create a moment about point E. That's why when we look at member ABC at 4:09, we don't include it. I explain the process behind it around that time as well so you can understand how to solve problems with this type of wording.
@CarterRaiche77772 жыл бұрын
Taught this better in 10 minutes than my prof did in 2 hours
@QuestionSolutions2 жыл бұрын
😅Thank you very much. Best of luck with your studies.
@alaybey97717 ай бұрын
GOAT of static channels...
@QuestionSolutions7 ай бұрын
Thank you!
@alaybey97717 ай бұрын
Still got a low grade man ain't no professor using that easy questions... No one in my class could solve our exams man.
@QuestionSolutions7 ай бұрын
@@alaybey9771 Sorry to hear your exam didn't go too well. Hopefully, you can pull your grades up in the next semester!
@ettsoc90183 жыл бұрын
Sir,thank u for your great video, I would like to ask why did you count the tension of the rope at 6:39?isn't it also an external force for the member BC just like the previous example at pin C at 4:32?
@QuestionSolutions3 жыл бұрын
I just want to point out that the first example is a pretty rare and unique problem where we are specifically told a certain force is applied to a pin so we had to look at internal and external forces that are applied to the pin and that are applied to the whole body. In the 2nd example, it's the same as someone applying a random force just a certain small distance away from the body. So we didn't calculate forces applied to a specific pin, rather, each member itself. So the forces at 6:39 are forces applied to the body.
@kuklangaren3 жыл бұрын
At 9:45, why is the moment 0 at B? Why is this not treated as a continuous beam?
@QuestionSolutions3 жыл бұрын
I think you might be misunderstanding. There is no moment, because the beam is in equilibrium, there is no movement. It's pinned so it cannot rotate about point B.
@kuklangaren3 жыл бұрын
@@QuestionSolutions Doesn’t pinned support mean that it’s locked in the x and y axis, but free to rotate? I thought that fixed support was the only support type that prevented rotation. Is there a particular reason why this beam can’t be treated as an overhang beam after the load is calculated at D? Or am I missing something fundamental about frames and machines?
@QuestionSolutions3 жыл бұрын
@@kuklangaren I think for these types of problems, the best way is to try and imagine this beam moving. It's pinned at B, but notice we have a roller at A and C. So let's say we push down at C, can it rotate? No, why? Because the roller at C will prevent it from turning clockwise. Now let's say we push at A. Can it rotate? No, why? Because the roller at A will prevent it from turning counter clockwise. So what that means is, it doesn't matter where we cut this beam, it will be in equilibrium. This principle is so important when we look at trusses. Especially when we make cuts through a member. So while we do have a pin at D, this whole collective beam will be in equilibrium so moment is equal to 0. Another tip you should keep in mind is that if you're doing a statics course, your object is always in equilibrium, it will not be moving. All equations, which means F_x = 0, F_ y= 0, F_z = 0, M = 0 will be zero. When you do a dynamics course, then your object will be moving, and you'll have to think about it differently.
@kuklangaren3 жыл бұрын
@@QuestionSolutions Thanks for the quick replies! What you’re saying makes sense, but I guess what I’m trying to ask is why this beam is calculated differently from a similar looking three support continuous beam? In such a beam, we would still have one pinned support and two roller supports, yet the middle support does have a moment. In order to solve such a beam, you first have to find that moment. Why is that?
@QuestionSolutions3 жыл бұрын
@@kuklangaren Maybe I am misunderstanding you. Are you asking about a single beam that is supported at 3 spots vs 2 beams pin connected?
@苏灿-t4f Жыл бұрын
I still have some doubts about the method of drawing the force on the pin. When I specify a direction, such as the force extending along the positive x-axis, sometimes it is a needle arrow (the arrow at the needle extends outward), and sometimes it is an arrow needle (the arrow extends towards the needle), how do I determine whether to extend outward or towards the needle. For example, at one minute and 30 seconds in the video, the force in the x-direction is an arrow that extends outward (with the pin reversed). If I draw an arrow pointing to a pin, can I?)
@QuestionSolutions Жыл бұрын
So what you're referring to are vectors. Vectors are lines with an arrowhead. We draw them to show a force in a certain/specific direction. Usually, we make an assumption as to the direction. If you get a positive answer, then your assumption was correct. If you get a negative answer, your assumption was incorrect, and it's opposite to your assumed direction. It might be helpful to watch this video: kzbin.info/www/bejne/f6nZYoSPiqaAjc0 and this video: kzbin.info/www/bejne/oIKndoKtp7dni7c
@alcerjohnganancial71146 ай бұрын
How did you solve the 3unknowns in the last problem? Thank you
@QuestionSolutions6 ай бұрын
I think I graphed them.
@nathanmorales8025Ай бұрын
Hi I love your videos! , quick question at 3:04 for the reactions of a pin it is Ex and Ey but how do we determine if Ex goes to the left or right again ?
@QuestionSolutionsАй бұрын
So it's just an assumption. If you end up with a negative value, then you know it goes in the opposite direction. If you get a positive answer, then you know your assumption was right. The magnitude of the answer is always correct though. :)
@nathanmorales8025Ай бұрын
@ thank you so much for your help :)
@QuestionSolutionsАй бұрын
@@nathanmorales8025 You're very welcome!
@bigfacts410Ай бұрын
Hey how do you know what the directions are for each reaction? For example, How would you know if it's the reaction is acting downwards instead of upwards, and why would one go to the right instead of the left. Thanks
@QuestionSolutionsАй бұрын
It's just an assumption. If you get a negative value, then you know it's opposite to your assumption, but the magnitude of that value is correct. So if you get -25 N, then it's saying the direction you picked it not correct, but the force is 25 N in the opposite direction to your assumption.
@knightsilverthesoulsenjoyer8 ай бұрын
This video is goated 🐐
@QuestionSolutions8 ай бұрын
Thanks!
@bnyaminsabah Жыл бұрын
Great video 🌼
@QuestionSolutions Жыл бұрын
Thank you!
@bnyaminsabah Жыл бұрын
@@QuestionSolutions no thank you your videos are so nice and usefull 😊💛
@QuestionSolutions Жыл бұрын
@@bnyaminsabah It's always really nice to read a comment like yours. Thank you for taking the time to write one. I wish you the best in your studies. Keep up the great work!
@hazwelnut. Жыл бұрын
Hi, fr the first question... why there's a moment at point E when it only hve to support reactions namely Ex n Ey?
@QuestionSolutions Жыл бұрын
Please give a timestamp so I know where you're referring to. Thanks!
@hazwelnut. Жыл бұрын
tq fr ure replied!! at 3:04 u said point E only have Ey n Ex ...while in the calculation at 3:15 you use moment about E to find Fa... are we not supposed to use moment about point E ?because point E only has 2 support reactions
@QuestionSolutions Жыл бұрын
@@hazwelnut. Okay, thanks for the timestamps. So I think there is a misunderstanding. There is NO moment reaction at a pin, since at a pin, the member can freely rotate clockwise or counter-clockwise. In other words, a counter moment is not created. What we did was just write a summation of moments about point E. This just means if we are standing at point E, what sort of moments will be felt due to the moments created by other forces. You can write a summation of moments about any point you want, it could even be at the middle of beam, or wherever you please. Please see: kzbin.info/www/bejne/h3-xn4OQa52Giqs
@hazwelnut. Жыл бұрын
@@QuestionSolutions Thanks !! That clears up my confusion. Have a good day sir. Keep it going!
@s.ehsanbamyani45712 жыл бұрын
Excellent job! Thank you!!
@QuestionSolutions2 жыл бұрын
You're very welcome!
@PunmasterSTP2 ай бұрын
Thanks for helping us get in the right *frame* of mind to learn 🙏
@QuestionSolutions2 ай бұрын
I hope these videos help you get in the right frame of mind to learn!
@PunmasterSTP2 ай бұрын
@@QuestionSolutions They definitely do.
@JessicaColin-vc1uf8 ай бұрын
Hello Professor, question about 7:02 where calculating moment at C. Why is the y-component of F(AB) negative? Thank you your videos sure help a lot!
@QuestionSolutions8 ай бұрын
So the y-component would face straight up. Imagine this object is free to spin about point C. If we push up at the location where the y-component was applied, would it turn clockwise about point C, or counter-clockwise? It would turn counter-clockwise. Since we picked clockwise to be positive, and this would cause a counter-clockwise moment, it is negative.
@JessicaColin-vc1uf8 ай бұрын
Great, thank you for the response. I have my test today and you have helped a lot!@@QuestionSolutions
@traveljacknguyen2915 Жыл бұрын
Hi , i have a questions for this lesson! It is how can we know exactly the directions of reactions at pin supports ???
@QuestionSolutions Жыл бұрын
Please watch this video first: kzbin.info/www/bejne/oIKndoKtp7dni7c The simple answer is that you don't need to know, since it's just an assumption. If you get a negative answer, then the direction is opposite to your assumption (the magnitude is the same).
@HashemAljifri515 Жыл бұрын
Hello, could you do a curved frames that have a radius R?
@QuestionSolutions Жыл бұрын
Is it a curve that can be considered a 2 force member, like the one at 1:48?
@HashemAljifri515 Жыл бұрын
@@QuestionSolutionsProbably yes , I encountered a semicirclular frame that has a semicircular distributed load w =sintheta. In statics hibbeler chapter 7. How can I resolve a semicirclular load distribution ?
@tomasenrique2 жыл бұрын
This is such an amazing video! THANKS!
@QuestionSolutions2 жыл бұрын
You're very welcome!
@binuyajohnreniel47303 ай бұрын
In the third question why I can't get your answer in Ay when I use AB for solving, my answer is 8kn
@QuestionSolutions3 ай бұрын
I don't know, it's not possible for me to answer your question since I can't see any of the steps you took, where you made a mistake, or whether you wrote down the proper equations 😅
@binuyajohnreniel47303 ай бұрын
First, I sum the moment at point B, then I assume Ay upward(clockwise) moment arm = 8 Second, the 16 kn pointing downward(counter clockwise) moment arm = 4
@chimchar22002 жыл бұрын
What a helpful video! Sir, I have a question. In 04:27 you describe Cx and Cy each by member of ABC and EDC. Is it correct to understand that they are not the action and reaction, but just internal forces by each member?
@QuestionSolutions2 жыл бұрын
Think of it as the force of each member, like member ABC, and EDC applied to the pin, just broken into components. This is one of those videos where the wording in the question is what sets it apart, because we are told that the 600 N force is applied to the pin. Usually, they are forces applied to members, not pins.
@chimchar22002 жыл бұрын
@@QuestionSolutions Thanks a lot:)
@QuestionSolutions2 жыл бұрын
@@chimchar2200 :)
@eyobderese5021 Жыл бұрын
@@QuestionSolutions this was the best replay for all my confusions. thanks, a lot!
@ranisjohnclienta.18542 жыл бұрын
The best teacher♥️. Thank you very much.
@QuestionSolutions2 жыл бұрын
You're very welcome! ❤
@RutendoMadaka Жыл бұрын
Thank you this is amazing
@QuestionSolutions Жыл бұрын
You're very welcome!
@mohamadkhatib8624 Жыл бұрын
Second question the distance is 0.5 how did you get 0.8 from where did u add sir
@QuestionSolutions Жыл бұрын
So the radius of the pulley is 0.3m. So you get 0.5 m + 0.3 m = 0.8 m. :)
@mohamadkhatib8624 Жыл бұрын
thanks for your feedback sir hope you keep updating more videos appreciate it sir @@QuestionSolutions
@stex177 ай бұрын
you are the best
@QuestionSolutions7 ай бұрын
Thanks!
@ImmortalAJ-r2t Жыл бұрын
In which software you write mathematical equations
@QuestionSolutions Жыл бұрын
I use word with the latex functions. If some of the equations don't look nice, I use online latex generators.
@ImmortalAJ-r2t Жыл бұрын
@@QuestionSolutions sir do you take snapshot of equation or convert it into vector file my AI file looks blurry in AE
@QuestionSolutions Жыл бұрын
@@ImmortalAJ-r2t I don't use snapshots but I think that can work if you use high-res images. Most latex generators can export as a PDF, so I export as pdf. Then you get vector equations. You can use a photo editing program to get it to proper size as well.
@ImmortalAJ-r2t Жыл бұрын
@@QuestionSolutions thanks sir i will try
@jaylut59313 жыл бұрын
Hey, in the last question, at the very last part, with 3 equations with 3 unknowns, how do we actually solve it? I've tried many times before, but wasn't able to manually do it without a calculator😅 You're a great teacher!
@QuestionSolutions3 жыл бұрын
Yes, that one is more tedious, because you will have to use trigonometric identities. Remember that tan θ = sinθ/cosθ. So if you divide everything by cosθ, it will probably help you solve this question easier. If not, another way is to graph it. :)
@fitrizuhairi18982 жыл бұрын
I have question about the first question, why we not consider BD as the two force members?
@QuestionSolutions2 жыл бұрын
It's pinned at B, and it's not bent or anything like that. So it can't be a 2 force member. 👍
@fitrizuhairi18982 жыл бұрын
@@QuestionSolutions thank you for replying! It's more clear now!
@QuestionSolutions2 жыл бұрын
@@fitrizuhairi1898 Glad to hear :)
@KienPhamTrung-hy4uh7 ай бұрын
I have a question, in the third question why we cant take the bar AB to calculate first instead to CD and I got different answer. Ur vid is great keep up the good work !
@QuestionSolutions7 ай бұрын
You can, there might be a numerical error in your answer. As long as proper moment equations and equations of equilibrium were written, you will end up with the same answers regardless of the bar chosen.
@chipomwika6824Ай бұрын
i have come across the same issue i started with AB and took moments about point B to get Ay my equation was (taking anti clockwise moments as positive ) 16(4) - Ay(8) = 0 when i solved i found Ay = 8KN and not 3.09KN I dont know what mistake i made, asking for help
@baharbaharlouie13183 жыл бұрын
Thank you for this 🙌🏻
@QuestionSolutions3 жыл бұрын
You're very welcome :)
@rajamannarsaravana16972 жыл бұрын
Good explanation ,
@QuestionSolutions2 жыл бұрын
Glad to hear!
@benjaminhendrich34173 жыл бұрын
Thank you!
@QuestionSolutions3 жыл бұрын
You're very welcome!
@danielrezkalla26872 ай бұрын
God bless you!!
@QuestionSolutions2 ай бұрын
Thank you!
@easymoney73443 жыл бұрын
THANKS FOR THE VIDEOS BRO really helpful💓💓💓💓💓
@QuestionSolutions3 жыл бұрын
Glad you like them! 💓💓💓💓💓
@EveryEngMechanical3 жыл бұрын
Appreciate your efforts ❤️❤️
@QuestionSolutions3 жыл бұрын
Thank you so much 😀 I saw you didn't upload anything recently, have you been busy?
@QuestionSolutions3 жыл бұрын
@@EveryEngMechanical Prefer not to say 😅
@EveryEngMechanical3 жыл бұрын
@@QuestionSolutions 😂okok
@QuestionSolutions3 жыл бұрын
@@EveryEngMechanical ❤
@jasondinosoccer9 ай бұрын
Helpful video thanks for sharing this information, helps for testing! 🤩
@QuestionSolutions9 ай бұрын
Glad it was helpful! Best wishes with your tests.
@HalaAlmaqadmeh Жыл бұрын
May you plzzzzz explain chapter 9 CENTER OF GRAVITY, CENTER OF MASS, AND CENTROID OF A BODY your explanations is amaazinggggg
@QuestionSolutions Жыл бұрын
Yes, I will add it to my to-do list, not sure when I can get to it though. Sorry! :(
@HalaAlmaqadmeh Жыл бұрын
@@QuestionSolutions thank youuuuuuu
@Michel-kb4xz2 жыл бұрын
from what reference are these questions
@QuestionSolutions2 жыл бұрын
Whatever books I use, I write it in the description 👍
@Oscar-jg9gg2 жыл бұрын
question 2 was clever
@QuestionSolutions2 жыл бұрын
😀😀
@driesvanranst34403 жыл бұрын
In the ABC member of first example, I don't get why we should draw 1250N in the Free Body Diagram, but not the 600N.
@driesvanranst34403 жыл бұрын
Actually I think Cy should be 600N pointing upwards instead of 0N. Could it be you made a mistake here?
@QuestionSolutions3 жыл бұрын
@@driesvanranst3440 I actually go through this in details since students tend to get confused here. It's very important that the question states "600 N force is applied to the pin" so please watch from 4:12. I even draw out the pin diagram to explain this. Also no, it's not 0N, the diagrams are correct 👍 If you still don't understand after re-watching that part, I will do my best to re-explain it the best I can :)
@driesvanranst34403 жыл бұрын
@@QuestionSolutions But at 5:42, you wrote Cy = 0N. Shouldn't that be 600N (upwards)?
@QuestionSolutions3 жыл бұрын
@@driesvanranst3440 No, we solved for Cy, we wrote a moment equation about point B and it turns out, Cy is 0 since no other forces are effecting the beam. What process did you use to get Cy to equal 600N?
@driesvanranst34403 жыл бұрын
@@QuestionSolutions I'm very confused. I used 2 different ways of solving the problem. First time I got Cy = 0N, second time Cy = 600N (up). I solved by using members ABC and EDC. What I supposed: When drawing the EDC and ABC members separately, at least one of the diagrams should include the given 600N (down) at point C. When I put the 600N on the EDC diagram, the result is that Cy = 0N. When put on the ABC diagram, the result is Cy = 600N (up).... Would be easier if I could show you my Free Body Diagrams.
@saulromero02 жыл бұрын
In question 2 how do we know F AB points diagonally up and not down? Great video!
@QuestionSolutions2 жыл бұрын
Please kindly re-watch 1:36. The reason we knew that was because it's a two-force member. It's good to recognize them, so you can have 1 single force instead of having one vertical and one horizontal. Makes the math simpler, but only if it's a two force member.
@tsangcahya91623 жыл бұрын
Thx !!
@QuestionSolutions3 жыл бұрын
You're welcome :)
@27thdimensionmusic2 ай бұрын
Thank you so much man
@QuestionSolutions2 ай бұрын
You're very welcome!
@Hussain-e9z Жыл бұрын
In Q1 why can't we use members EDC and and ABC?
@QuestionSolutions Жыл бұрын
You can use whichever ones you want to get the answer. I just showcase one method of getting to an answer. :)
@Hussain-e9z Жыл бұрын
@@QuestionSolutions Oh okay because in the video you said that you can only use two combinations of members: - ABC and DBF - EDC and DBF So, I wasn't sure if EDC and ABC would be valid. Is it?
@shyamdev6928 Жыл бұрын
Informative !! thank you so much for the video. I have a small doubt. I did not understand why you have not considered the 600N external force while drawing FBD. Can you please clarify
@QuestionSolutions Жыл бұрын
Thank you. Please give me a timestamp so I know where you're referring to. Thanks!
@shyamdev6928 Жыл бұрын
@@QuestionSolutions 4min 32 seconds
@QuestionSolutions Жыл бұрын
@@shyamdev6928 Are you referring to the 600N force applied to the pin? This question is sort of tricky because it specifically states that the 600 N force is applied to the pin only.
@jjjjjjjjj24762 жыл бұрын
Do you have any examples of this topic?
@QuestionSolutions2 жыл бұрын
Sorry, which topic?
@jjjjjjjjj24762 жыл бұрын
@@QuestionSolutions the frames and machines, Do you have more videos about them?
@QuestionSolutions2 жыл бұрын
@@jjjjjjjjj2476 This is the only one, I try to cover 3 to 4 examples per topic. 👍
@jjjjjjjjj24762 жыл бұрын
@@QuestionSolutions I appreciate that, thank you sir
@QuestionSolutions2 жыл бұрын
You're very welcome
@matusalaalemseged55872 жыл бұрын
Amazing video, man! But I didn't quite understand why you ignored the 600KN force at joint C. Is it because if we're dismantling the frame, any force applied at the joints will become an internal force and won't be considered?
@QuestionSolutions2 жыл бұрын
We are told that the force is applied to the pin. This question is actually a tricky one because of the wording and it's quite rare. I just wanted to show it so that if you ever get a curveball thrown at you, you can figure it out.
@matusalaalemseged55872 жыл бұрын
@@QuestionSolutions Thank you very much. I didn't see it that way.
@etch3130 Жыл бұрын
in the first example why is it possible to take moments then completely disregard those forces? How did you decide which joint to take moments about?
@QuestionSolutions Жыл бұрын
I am not entirely sure of your question, since nothing was discarded. We needed to find the reaction forces at A, and the easiest way to do that was to take the moment about point E. So what we want to do is take the moment about a point that eliminates as many unknowns as possible. When we take about it about point E, we can eliminate the reaction forces about that point since their lines of action goes through that point. Please see: kzbin.info/www/bejne/h3-xn4OQa52Giqs if you need a refresh on moments.
@vasanthkumarcroos86053 жыл бұрын
sir please upload rigidbody kinetics and rigid body kinematics i watched already but now I can't find the video. please reply with the exact link sir please.
@QuestionSolutions3 жыл бұрын
Check the dynamics playlist here: kzbin.info/aero/PLXePpKFSUW2ZXw_D5h0TTyac-KGlFRxnS
@michaelokaysin42392 жыл бұрын
can u do more l specific videos on just solving topics on moment , vectors and equilibrium from hibbeler textbook 13 edition
@QuestionSolutions2 жыл бұрын
Everything you mentioned is already covered in the playlist. Look at the moments video if you would like to see problems solved involving moments, look for the equilibrium video if you want to see problems solved about equilibrium 👍 the playlist for statics has it all :)
@trentonstevens6575Ай бұрын
I am getting hung up on problem 1. I am using this video as a reference to a similar homework problem where the force applied to the pin is 680N, I go through and solve the problem the same way this one is solved yet I am told my answer Cx= 676.6N and Cy= 0 is incorrect.
@QuestionSolutionsАй бұрын
Does the question specifically say the force is applied to the pin? Does the diagram look the same? Really hard to say without seeing the problem/ diagram. I encourage you to see your professor during their office hours to get everything cleared up.
@ytpremium39153 жыл бұрын
Sir Why the direction of Fs is downward? Is it known from the question?
@QuestionSolutions3 жыл бұрын
Are you talking about 11:04? If so, it's because the wheel is pulling it down, so the spring force is also downwards. The spring creates tension downwards at the top, and tension upwards at the bottom. 👍
@thejvsgamer328911 ай бұрын
Is this Engineering? I'm wondering because as a 6th grader, I am teaching myself Electromagnetism and Engineering on Edx, and I'm wondering if this is engineering statics. I am also wondering because I've done problems that look similar to this, like finding Tension in ropes. I'm currently learning Trusses right now, and I'm piecing together information. Thanks. And yes, I'm a 6th grader, and yes I'm taking college courses on Edx, and yes, I'm self-teaching myself. I would be grateful in your favor if someone could respond :D
@QuestionSolutions11 ай бұрын
Yes, this playlist includes topics covered in a first year engineering statics course. The dynamics playlist includes first year dynamic topics, and the thermodynamics playlist covers first year topics relating to thermodynamics. All topics are engineering topics, but they also get shared by a few other faculties as well, like physics and chemistry. Awesome job for doing all of this at your age. Keep up the great work!
@abdallajama48322 жыл бұрын
whts the name this book bro?
@QuestionSolutions2 жыл бұрын
Any books used as reference is in the description 👍
@HashemAljifri51510 ай бұрын
Hey do you have fluid mechanics tutorials? I used to watch your videos for engineering dynamics and statics and passed them. I would like to see your videos for fluid and soil mechanics
@QuestionSolutions10 ай бұрын
I don't have fluid mechanics videos. It's on my list to do, but it probably won't be done for quite some time.
@nallapanenisaisuprabhanu75302 жыл бұрын
I was searching for Frames in Image Compression, and found this video in the results, tbh these Frames are more interesting than those Frames 😂
@QuestionSolutions2 жыл бұрын
That's really funny 😅 Really happy you found this even a little bit interesting.
@easymoney73443 жыл бұрын
Bro im kind of confuse on 11:29 on how it was 2 cos and 2sin 😭
@QuestionSolutions3 жыл бұрын
So it's a right angle triangle with a hypotenuse of 2 m. Remember that sin is opposite over hypotenuse, and cosine is adjacent over hypotenuse. Draw out the triangle on a piece of paper, label the angle, and the hypotenuse side as 2 m. You can then write the other sides as functions of sin and cosine :)
@omonypeter-b8hАй бұрын
Plis do engineering mathematics also
@QuestionSolutionsАй бұрын
Thank you for the suggestion. I will definitely add it to my to-do list.
@EveryEngMechanical3 жыл бұрын
❤️❤️
@QuestionSolutions3 жыл бұрын
❤❤
@HashemAljifri5155 ай бұрын
Now I am in statically indeterminate frames 😔 it's something way different than we used to do in structural analysis 1 and statics dynamics and strength of materials
@QuestionSolutions4 ай бұрын
I hope you're still doing well on your courses. Keep up the good work and do your best :)
@chrismarklowitz1001 Жыл бұрын
I completely disagree on the first problem. If this were the case then the pin itself would not be in equillibrium. It's more accurate to distribute the force evenly to both members as an external 300N load and then Cy would be 300N
@QuestionSolutions Жыл бұрын
So this question tends to be a confusing one for a lot of students, but the key is in the wording. "The force is applied to the pin", very few questions you'll encounter will say that. You just have to read problems really carefully and apply your knowledge to solve it. I encourage you to speak with your professor during their office hours and get an insight into this problem if it's confusing so you can clear up any misconceptions. If this type of problem shows up on your exam, you'll have a good foundation to tackle it. Best wishes :)
@chrismarklowitz1001 Жыл бұрын
@@QuestionSolutions I deffinetly will I'm probably wrong and I'm not opposed to being wrong but just looking at the diagram of the pin its clear if Cy is 0 that the pin would be pulled down. Part of the reason I'm confident is I also made a simpler similar problem myself of two two force members With pin supports on either end Creating an isocscles triangle with the bottom angles being 45 degrees and A 100N load being applied at the top vertically down on the pin. Breaking up the Diagram into the two members. The only way for Cy,Cx to be the same for both two force members was if I split the 100N load between Both Two force members so 50N down for both. In which case Cy would be 0 and Cx 50 N to the left for the left Member and the right for the right member. If you Treat the 100N load like it doesnt exist when you break up the two members you get a completely wrong answer. To me this makes sense cause even if you apply a load on the pin. Assuming it's symmetrical Aka Both members are equal distance from where the load is applied the load will be distributed evenly to both of them down.
@QuestionSolutions Жыл бұрын
@@chrismarklowitz1001 One thing you can do is write to Hibbler (author of the book) and directly ask him to get more clarification. But yeah, I definitely would ask your professor or TA and ask this question with a force applied just to the pin. It's a very good question, but often tricky for a lot of students. Good to teach it before it goes on the exam 👍 Also, are you understanding the diagram properly? The pin is between EDC and ABC. It can't fall out because Cy is 0. It's between the two beams. The force is countered at the supports.
@isabelapinzon205510 ай бұрын
I love you
@QuestionSolutions10 ай бұрын
❤️
@wuwu159811 ай бұрын
Didn't get a thing :)
@QuestionSolutions10 ай бұрын
I am sorry to hear that :(
@glennjacksonofficial30014 ай бұрын
This guy sounds Filipino based on his accent, but I could be wrong