Rabin Cryptosystem

[@codingid5470]

a3 and a4 are actually b1 and b2........and we have to calculate plain text like this :- PT1=CRT(a1,b1,p,q) , PT2=CRT(a1,b2,p,q) , PT3=CRT(a2,b1,p,q) , PT4=CRT(a2,b2,p,q) where PT=plain text and CRT = Chinese Remainder Theorem

[@gajulaguruprasd8561]

Can you please share your cryptography notes .....it will help us alot 🙏🙏

[@nasif20051]

What is b1, b2? how to calculate them?

[@nasif20051]

What is b1, b2? how to calculate them? The formula at the end of the page is not making any sense. Please explain them.

[@arunabaligar5674]

Can u explain how to take values for Chinese algorithms

[@vaishalitutorials5127]

kzbin.info/www/bejne/ZpW1fJZ5ot2ErLc

[@vaishalitutorials5127]

You check this,if you are still in doubt I'll explain you live

[@nasif20051]

Why we need to calculate a3 and a4?

[@vaishalitutorials5127]

a1,a2,a3,a4are the four possible answers out of which the receiver need to find the appropriate answer .It can be caluclated by using Chinese remainder theorem

[@guyswapnil]

Mam here a1 a2 a3 and a4 are considered as X

[@guyswapnil]

So that we can apply Chinese remainder theorem

[@arunabaligar5674]

In Rabin cryptography

[@govindjangid6201]

Thanks ma'am 😊

[@sivasankarudayagiri]

Plain text p is 23 but you have taken p as 24 in encryption. why???

[@vaishalitutorials5127]

It was by mistake but explaination is as per p=23

[@jaysatapar007]

ma'am if you're teaching on KZbin or any online platform please use simple words ase words to hmare college ke professor and book ke authors bhi likhte and bolte unka samj ni ata isi lie online ate hai samjne k lie and ap log vi ase pdhaoge to kese chlega nvm m is topic ko skip (aj hi mera University ka exam hai )kia tha but aj socha jldi uth gya hu to pdhlu but skip hu thik tha