Radical Equation

[@Folorunsho3729]

The problem with math is that we introduce stranger to find our way out 😂 Just raise to the sixth power like that!? 😂

[@isjosh8064]

It’s to get to a situation we know. You don’t want fractional powers on your equation so you raise it by 6

[@PrimeNewtons]

6 is the least common multiple of 2 and 3

[@badrishkhanna7800]

We can do without doing power 6 as well. Just use exponential rules on x^1/3 and x^1/2

[@Folorunsho3729]

​@@badrishkhanna7800 buh you know X^1/2 is not really X^1/2 on the RHS

[@BowlDrome]

If it works, it works fine. Although the solution itself is not efficient that it ought to be

[@dianashakeri5869]

Wowww😍🤩

[@treybell40501]

The song choice 🔥

[@cavanipro1138]

I think that is better starting to multipy by 2,and get out the fraction

[@jibblerino]

How did I get here? I don't even remember how to show my work with long division.

[@rakeshkumar-ev1uw]

It can be solved in 1st step when you represent the underroot on the variable

[@gauravbani-lv3yp]

Awesome 👍 sir

[@AstroBrindan]

On 4th step, divide both sides by x^2

[@PrimeNewtons]

Never divide by a variable. Unless you know the variable cannot be zero

[@AstroBrindan]

ooo didn’t know that, thank you

[@tonystone10K]

Yeah, that risks getting rid of possible roots. Ie. If you had x^2 = x, and divided both sides by x, you'd only have x = 1. When in fact, x = 0 is also an answer.

[@sbybill3271]

​@PrimeNewtons Something seriously wrong with this assumption. If x^2=0 then x=+_0 doesn't make sense

[@nebula534]

@@sbybill3271y = x^2 only has one solution at y = 0, which is x = 0. +0 = 0 and -0 = 0. Otherwise would you say that when you substitute in the equation a = b - c, c = 0, a = b - 0 doesn’t make sense because you’re subtracting 0? No of course not.

[@dannyjones4044]

I never could understand algebra and I have 2 College degrees, science awesome, but Algebra, YIKES!!

[@Valerius123]

What part is yikes? Is it the abstraction that loses you? Or is it just remembering the rules?

[@josiahsmith9657]

sees 1/2*x^1/2 *panics in lambert W function*

[@qav_cnzo_]

No that's not how it works 😂

[@LukieReal]

just divide by x^2 on both sides and remember 0 is a solution!

[@PrimeNewtons]

If x=0 is a solution, you can't divide by x²

[@LukieReal]

oh you’re absolutely right! this is why i need ur videos for help, they are so insightful

[@Valerius123]

@@LukieReal Just be careful when you "cancel out" variables. Usually that results in erasing out solutions.

[@potentialofprotonis3]

x^(1/3 - 1/2) = 1/2 x^(-1/6) = 1/2 1/x^(1/6) = 1/2 x^(1/6) = 2 x = 2^6

[@ayomidediekola2505]

x = 0 or x = 64

[@The_Commandblock]

Ok so there is one thing that really annoys me. In another video you said that there is no solution for sqrt(x-1) = -2 because squareroots cant have negative solutions. I just accepted that and continued scrolling. But this video actually contradicts the other video by saying that sqrt(x) = x^½. Powering x to a half is asking "what number do i need to multiply by itself to get x" which is obviously true for positive and negative sqrt(x). The other video however states that squareroots can only have positive results. ... ... ... ... ... ... ... ... ...

[@PY0ME]

no, a third root has solutions

[@Kali-bs7oj]

Square root x is always positive, only because we define it that way. Square root is exactly the same as half power, we need two of the same number that multiply to get x. But we disregard the negative solutions because the square root and half power are operations that we specifically define the solutions for. If you put x^1/2 or sqrt(x) into a graphing calculator, you’ll see the same graph of positive numbers, even though negative numbers multiplied by themselves can get the same value of x. This is because of how we define the operation

[@natevailikit1536]

You didn’t finish… don’t write it as x^2 = 0, or x-64 = 0. You didn’t simplify either factor. It should be x=0, x=64. Do not write “or” that means one of the solutions is correct and one is incorrect. Both solutions are correct.

[@tamirerez2547]

This is how the letter x looks like: ❌ Two straight lines crossing each other in the middle.

[@ARCT1C_S3AL]

It’s a fancy way of writing so that when doing algebra, you don’t mess up the multiplication function with the x

[@maxpie16]

its just x in cursive

[@Kali-bs7oj]

brother is just learning about fonts and handwriting

[@sbybill3271]

Wrong method. There is only one solution. When x^2=1/64x^3 then x=64. why make it so complicated?