Razavi Electronics 1, Lec 41, Source Followers & Summary

[@victrixmortalis7823]

End to a glorious Chapter of MOSFET's By Razavi sir Loved ❤️ the 14 lectures.....Thank you so much Razavi sir for such precious lectures....Thanks is a small word to say though!!.

[@ajazshaik7202]

Many many thanks to professor Razavi 🙏🏻 No one had given this much crystal clear explanation on Amplifiers Thank you Sir❤️

[@samtiny6332]

Many Thanks to Prof. Razavi

[@SHUBHAMKUMAR-qd5fo]

I am loving the starting beats

[@karamany9870]

I got an Internship at ADI from watching your videos. Thanks

[@abhijeetsingh5681]

Hi bro, I also went till second interview round in ADI. Can you please tell me what resources did you follow during your preparation for Analog profile

[@karamany9870]

@@abhijeetsingh5681 bro mine was only one round lol But just revise basic circuit analysis and Razavi’s courses

[@goldfishdoc1999]

Your lectures are so amazing.... I just understand everything just with a single watch... Thank you very much Sir....Extremely grateful 🙏🙏

[@bluewhale-c1j]

thank you for these lectures sir. you are theee best

[@ernestb.2377]

Great lessons Mr. Razavi. One short question: Can we directly drive the load from the source of the transistor and avoid the Rs all together? I am thinking to build this circuit (and use as a buffer) to connect my HF radio and SDR radio to the same antenna. If the 1/gm would be close to 50 Ohm that would be a good match for the input of the SDR. Otherwise it can be lower, but maybe that is not a problem for the SDR input. Side note: I will build another small circuit to disconnect the SDR input from the HF radio output when transmitting.

[@maximecholvy2813]

Great explanations, thank you sir for smart pedagogy

[@gevorggeghamyan1718]

brilliant lecture

[@Sourav_Soumyajit]

What an awesome lecture!

[@AndreaBettati]

@ 41:47 why isn't Rd taken into account? Anyway, great material Dr. Razavi, many thanks.

[@vprakash2471]

Rd is present only in the CG stage of the cascaded amplifier.... It comes into play only for the individual gain of CG stage

[@k.k.skesava7561]

Something Intutive: 14:16 using thevenins equivalent to analyse the ckt instead of all the kcl and kvl that we are used to .

[@giammariacocco5854]

in the minutes 38:08 Why do I consider like resistance on the emitter only the 50 ohms and not also the resistance that I see inside the emitter of M2 in parallel at 50 ohm?

[@sumitasahu329]

your lectures are privilege for many students:) anyone knows source of Electronic 2 lectures?

[@mrpossible5696]

Already uploaded Checkout on YT

[@karamany9870]

we could also use it for level shifting properties, right? like in the cascode current mirror with level shift

[@anamikaraj7663]

In last question why input impedance of common gate is not taken parallel to the Rs

[@k.k.skesava7561]

something funny: @13:58: why dont we use a piece of wire instead of source follower (funny but yeah needed question though) answer is: 38:50

[@amarnathbr3420]

Can anybody please explain how one can decide the resistance offered by a specific configuration as viewed from a point in the circuit for example at 41:30 in this lecture?

[@vprakash2471]

That is the basic definition of input or output impedance. When we connect a source we see some current... This voltage by current is the input impedance. So we can alternatively say that the resistance seen from these terminals is input impedance

[@k.k.skesava7561]

Frontiers of electronics: @48:54: watch/Quartz

[@kishansuthar7620]

Sir talked about "Advanced Courses", anyone knows which "Advanced Courses"????

[@vprakash2471]

They were uploaded last year bro

[@mnada72]

@@vprakash2471 what about circuit theory I & II

[@victrixmortalis7823]

What is circuits 101 any idea ??

[@sabriyilmaz5814]

@38:14 isn't the gm 1/40 ? there is mistake here the gain should be -12,49

[@goldfishdoc1999]

gm is 1/40.... but the gain of source follower is Rs/(Rs + 1/gm).... So value of 1/gm = 40

[@goldfishdoc1999]

So no..... there is no mistake @38:14

[@vamsiakula653]

Why is Rs necessary here? anyhow videos are extraordinary

[@chewwjkful]

Just my own interpretation, it could be wrong. Without Rs, the source terminal shorted directly to the ground which means that the Vout will be equal to 0 volt. Hence, Rs is required so as there is IR drop across the Rs which act also as the Vout

[@schnecke1061]

The input signal is due to the transconductance property of the mosfet converted to a current. Therefore I guess Rs is needed to convert the current signal back to a voltage signal, in other words the output signal is sensed by Rs. The resistor Rs acts like a negative feedback device or degeneration device too and stabilises the whole circuit which is a nice bonus. Please correct me if I'm wrong

[@mohammedabdulhakabdullaabd1121]

you need a DC bias current path to GND otherwise in the absence of a signal ID would be zero which means no gm (circuit is dead).

[@nurlatifahmohdnor8939]

Pepsi = a brand for soft drink.

[@krish2nasa]

Many Thanks to Prof. Razavi