Razavi Electronics 1, Lec 27, Emitter Followers

[@oojikarasuma1]

This lecture series is so underated. I am surprised it isn't more popular than it should be.

[@gwav1a]

You are right. It's certainly by far the best series on analog electronics. I think it's just chance- I only discovered it not more than 6 months ago.

[@mohamedharoual21]

​@@gwav1a me to

[@koushikmaji7998]

The cascaded circuits are really fun to solve!

[@병현박-z2c]

Thanks for your best effort.

[@rezangla1834]

thanks you sir for your time and lots of efforts ,@ from INDIA

[@doob9103]

Amazing lecture. Thanks for your effrorts @ from S.Korea

[@AbdullahElgrew]

You’re the best We are waiting you for a new lectures

[@felipenata8890]

best teacher

[@mdshamsfiroz9074]

Thank🙏💕

[@michaelcostello6991]

Why does total resistance not include the path through the transistor to AC ground

[@gt5490]

For the equivalent circuit used in calculating the output impedance, if we use it to calculate the input impedance, why is there an additional factor of 1/(beta+1) compared to the previously calculated result?

[@xliu2583]

The interpretation of A_v as a voltage divider only gives the ratio of one resistor to the other, but not the absolute magnitude. From the expressions of R_in and R_out for the emitter follower, we know there's a \beta prefactor in front of R_E for R_in but not for R_out. I think the way of using that equivalent circuit to calculate R_out is more like an educated guess.

[@Pedro-gk9og]

This is explained in the next lecture (around min 10)

[@mauriciocarazzodec.209]

pqp esse professor é muito foda kkkkkkk

[@yameixiao2798]

32:00 vout/vx = gm2*Rc

[@coolwinder]

Isn't Rin=rp+(1+B)(Re||1/gm2) ?

[@coolwinder]

Ok, we did it just for emitter follower :).

[@tusharnitharwal]

In calculating output resistance, shouldn't he remove the current source?(he did so when he first taught output impedance in lecture 21)

[@revanthreddy3266]

thats dependent current source. dependent souces cant be deactivated

[@swetha6555]

@@revanthreddy3266 thank you 😊

[@Upgradezz]

Razvi = Ronaldo.

[@yashwinkishore897]

what da fuck?

[@sanjubiswas4418]

Both are G.O.A.T

[@vatsan2483]

#correctionat55.39 The Rin of the emitter follower is actually Rb||(Rin of BJT) and therefore Rb||(rpi+(beta+1)Re))

[@bishwayansarkar6621]

nope