Razavi Electronics2 Lec4: Additional Cascode Examples, Cascode Amp with PMOS Input

[@saadqayyum2148]

In the review slide of Lec3 at 2:40, there is a slight mistake. The transconductance in the voltage gain expression should be of the input transistor i.e. gm2 instead of gm1.

[@noth_2]

Yeap!

[@debabrata2137]

@@noth_2 yes

[@allishere5488]

Yes

[@mrkyeokabe]

Agreed. Good catch! To spell it out, the equation on the bottom right should be Av ~= -gm2[(gm1*ro1*ro2)//(gm4*ro4*ro3)]

[@rahultheytv5347]

great teachers like you are sufficient, to teach total world, instead of incompetent teachers in every college

[@coolwinder]

01:25 - Intro and Review 12:22 - Example 1: Change in Cascode Amplifier with Ideal Load when: Bias current is halved, widths are doubled. 18:35 - Example 2: Change in Cascode Amplifier with Non-Ideal Load 27:40 - Quiz: Connecting Input Signal on Cascode Transistor 37:25 - CS Amplifiers with P-Type Input 44:10 - Cascode Amplifiers with P-Type Input

[@kyounghobaik5412]

The GOD of the Electronics...!!!

[@iseeyou2235]

Thank you so much professor you explain so well,so easy to understand and for the amazing book 1 of the best!!!!

[@joydeepdebnath9741]

Thanks a lot I was dying for this.

[@amitgalkin1215]

Thank you so much proffesor! you made my intuition so much etter then before.

[@deepaknagar4331]

Thanks to jio... m watching lecture of a legend in electronics....that too in HD.

[@akssingh8960]

Greetings!!!Welcome back

[@lokeshwar4093]

Much Thnx professor teaching method mind blowing and your book fantastic

[@yasinozbunar8540]

Allah razı olsun

[@mohammedabdulhakabdullaabd1121]

for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?

[@chetanw1676]

Yes bro, i got the same...

[@SumitMukherjee7]

@@chetanw1676 yes you are correct

[@enesog]

Interesting lecture

[@mdkalimullah4207]

Encyclopedia of edc and analog electronics

[@mrpossible5696]

How was Gate this year

[@rahultheytv5347]

please also do lectures on MIXED SIGNALS , please sir

[@dogdogdog2024]

thanks prof

[@srinivasan7790]

since in cascode, as ID is same, gm of pmons and nmos must be same? why he says change is transcondutance.

[@Sourav_Soumyajit]

Explanation ❤

[@armanmanukyan1970]

Thanks dear professor, but I can't find derivation the transconductance of a degenerated transistor Gm = gm1 / 1+gm1*ro2 in Electronics1. Can you help us by saying where it is exactly.

[@saadqayyum2148]

It should not be too difficult to derive using the small signal analysis.

[@amitkumar-sh2lk]

bro as now Vgs= Vin- Iout*r02 thats why Gm is not equal to gm1

[@choco_chanel5377]

@@amitkumar-sh2lk Thanks it helps

[@mutasemwahbeh6954]

From small signal analysis taking a degeneration into account we have 2 equations :KVL gives Vin = V1 + (gm *r02*V1) , KCL gives : Vout = gm*V1*r02 ,,, cancel Vi from both equations and put both equation in AV form yields : Vout/Vin = gm * r02 /(1+gm*r02),,,, and if we rewrite it in a new form Av = - Gm * Rout gives Gm = gm/(1+gm*r02) Hope it helps

[@chinthalaadireddy2165]

@@mutasemwahbeh6954 Thank you so much!

[@AnimationsJungle]

brilliant .....

[@theminertom11551]

Sorry, but am I being ignorant? It seems to me that the big equation for gm for Av in the center of the page should be -gm2 not -gm1.

[@rajamajhi2012]

God

[@raminrajabioskouei781]

Thanks

[@mrpossible5696]

18:31

[@CheeseBurg1203]

at 25:06, Av=1Av , Because 1/sqrt(2) * [4/sqrt(2) || 4/sqrt(2)] = 1

[@ozgunyurutken9485]

the multiplying factors are not in parallel. If R1 || R2 and both of them being multiplied by some factor x, the overall result is multiplied by factor of x, so the answer is 1/sqrt(2) * 4/sqrt(2) = 2

[@CheeseBurg1203]

@@ozgunyurutken9485 oh, I was wrong Thank you very much

[@Specialist_Engineers_Team]

Back music is so irritating 😢

[@histimemanof4954]

I wish youtube add *3 speed

[@-Jayanthkumarreddypalle]

You can add a plugin to your browser.

[@mohammedabdulhakabdullaabd1121]

for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?

[@mrpossible5696]

30:29