RC Low Pass Filter Explained

In this video, passive RC low pass filter has been discussed.
What is electronic filter:
The electronic filter is the circuit, which passes some range of frequencies of the input signal and rejects or attenuates the unwanted frequencies in the signal.
Based on the range of frequencies which is being passed by the filter, there are 4 different types of filter.
1) Low Pass Filter
2) High Pass Filter
3) Band pass Filter
4) Band Reject Filter
What is Low Pass Filter:
A low-pass filter is the electric circuit, which passes the low range of frequency signals, starting from 0 Hz (DC) to up to the cut off frequency (fc), and rejects all other frequencies which are higher than cut off frequency.
Now, based on the components used for the design, this low pass filters further can be classified into 2 categories.
1) Active Low Pass Filter:
If the low filter is designed using the active components like Op-Amp and transistors then such filters are known as active low pass filter.
2) Passive Low Pass Filter:
If the low pass filter is designed using the passive components like R, L and C then such filters are known as passive low pass filters.
These are the most common types of Passive Low Pass Filters.
1) RC Low Pass filter
2) RL Low Pass Filter
3) RLC Low pass filter
So, in this video first order RC Low pass filter has been discussed and at the later part of the video, it is shown that how by cascading first order low-pass filters, we can design higher order filters.
The order of the filter can be defined by the number of poles in the transfer function of the filter.
(One simple way to find the order of the filter is to calculate the number of reactive components in the circuit, i.e capacitor, and inductor, but always it is not true. There might be some exceptions)
But in general, this procedure can be followed.
The time-stamped link for the different topics in the video is given below:
0:27 What is an Electronic filter? Different types of Electronic Filter
2:46 RC Low Pass Filter
5:12 Derivation of cut-off frequency expression
8:35 Example on Low Pass Filter
12:28 Higher order filter design by cascading first order filters
This video will be helpful to all students of science and engineering in understanding the RC low pass filter.
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[@debojyotikoley8067]

Two gems of online electronics teaching. All about electronics and neso academy.

[@arpanswain3732]

No doubt!👍

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True

[@muzammilahmedqazi9093]

True, they are really diamonds!!

[@joemiles8402]

instablaster...

[@karthikkotnam6940]

Yes

[@sum1528]

This has to be the best and most straight forward teaching of filters ever. Thanks a ton!

[@israayusuf3712]

I finally understood the filters! Thanks a bunch and please keep making more videos. You are very helpful. Thanks again!

[@tarik1781]

Thanks man this videos made me pass my oral exam in electrical engineering

[@alamjottiwana3650]

whilst i am doing the studying, you have very much blesed me yaar, i would like to thank v much my friend

[@hgaubaul]

Been searching all over yt for a good visually demonstration of what LPF and HPF does, and this was the best one. Thanks.

[@sunildhaka4528]

your way of teaching is very good.please add more and more videos

[@baba00eddy]

You are an amazing human being. Thank you for all of these videos!!!

[@chanchalverma4598]

Thank you soo much sir..... M bahut time s ece k lie lecture dhud rhi thi ... .... thankyou again ❤️❤️❤️❤️❤️

[@laurentdeusdedith8603]

never seen such kind of useful channel, keep making more videos

[@noweare1]

At 7:32 the equation for the angle should be 1/(wCR) as the tangent of the angle is opposite (Xc) over adjacent (R)

[@GDE23]

Very good explanation. Although it took me second to understand that your `7` is not an `F` and your Curls on your `V` was also hard to decipher sometimes.

[@poojashah6183]

Your way to teach is soooooo amazing that make learning easy 👌👌

[@naser3000x]

you saved me, my stupid course gave us a lab about filters and we have to turn in the report before we ever learn what they are even about

[@chasecolin22]

Welcome to the real world. Bitching doesn't help

[@wanderlewis8552]

Good explanation, my only remarks> the phase curve's graph can be done much better--in the negative zone and Xc 's value is in Ohms, not just a number. Keep up the work !

[@venkateshpaidi2720]

You saved my butt with beautiful explanation. Thanks a ton !

[@circuitsanalytica4348]

Yes Mr. Paidi..... really nice explanation....

[@Googleeknowledge1111]

Thank you so much for your valuable information

[@navidahmad78]

it was the most helpful video i have ever watched. thank you so much!! A small favor, if u can provide some notes or the pages you worked on the video in the description of your video, it would be gold and so much appreciated.

[@ganeshm1698]

Hi ji, You are very good technically clarifying the circuit analysis. Can you please make one more video for the pi filter circuit design in a technical way.. i hope you wil be support to my request... Thanks in advance

[@vakhariyajay2224]

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[@aliayan1995]

Why all the good teaching videos are made by the teacher with the dominant Indian accent :D

[@kanchanaramar]

Thank you. Your explanation is direct and easy to understand.

[@circuitsanalytica4348]

Yes Raman, really nice.....

[@stuartmp1974]

Awesome. Really enjoyed your straight to the point explanation

[@QuickishFM]

Thank you for the video, very nice explanation and went into depth about nth order filters and respective roll off.

[@martinsdundurs9497]

Surprisingly clear once you get used to in to's.

[@mrradhafan6005]

Good explanation, keep uploading my dear friend 😊😊

[@aadilsalam7736]

thank you so much. good source to revise and mugg up, keep up the good work.

[@circuitsanalytica4348]

Dear aadil, dont mugg these topics, understand it, you will never forget it....

[@kanhaisharmaacademy3444]

sir i love the way u teach.thank u sir. I'm very happy

[@saikrishnadittakavi6269]

One of the best ways to explain... Thanks a lot

[@akankshapatil5235]

Teaching is best 👍... Continue to new lectures

[@circuitsanalytica4348]

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[@mayurshah9131]

Really very good Narration, keep posting

[@circuitsanalytica4348]

Yes Mr. Shah, really nice....

[@wisnudjatmiko]

Good

[@UECAshutoshKumar]

Thank you sir

[@antoniorebelo9497]

Did someone notice how he says "this"? nice video

[@sangachidam3219]

Great video. I would like to know how a (Vout/Vin) = Xc/(xc + R) suddenly becomes Xc/(sqrt(Xc^2 + R^2). thanks in advance

[@ALLABOUTELECTRONICS]

Vo = Xc * Vin /( Xc +R ) gives amplitude and phase information togather. |Xc / sqrt ( Xc^2 + R^2)| * |Vin| gives the amplitude of Vo. I hope, it will clear your doubt.

[@priyap6242]

Very helpful video Sir. Thanku

[@user-vb1uj3sc4z]

NYC explaination❤

[@shumailakeerio9953]

Thank you so much for this i just enjoyed your lecture...

[@gyandeepbordoloi1035]

really good please make more vedios sir

[@arunavaida5684]

great video.Very clear explanation. Thankyou..

[@pikapool1383]

I just realized that free videos on youtube teach me better than my paid college.

[@BurRun-kt3tf]

Thanks អរគុណ❤

[@godned74]

Thank you for the explanation!

[@chetananam475]

Nice explanations. Simple & to the point.

[@sandeeppinninti3087]

Super explanation thank you

[@rachelstokes1340]

great video, thank you so much

[@qaworlds]

your explanaion tips is toooo good

[@musicvenom3816]

Thank you, this channel is brilliant.

[@user-sw5ee6gj3h]

At 3:16 the output that u wrote was vout=vin*xc/(xc+R) ....But according to my knowledge since this is a A.C circuit, So vout=vin*xc/z...and Z=sqrt(xc^2+R^2)...then in denominator instead of xc+R we should have sqrt(x^2+R^2)...Let me know if I'm missing anything. P.O.V:- I'm a Aerospace Engineer trying to understand filters, for my work.

[@UmerFarooq-zm6po]

your videos are very informative. Plz add how to construct equivalent circuit models of various microwave filters, antennas etc.

[@jameserayburn]

Excellent explanations. Two thumbs up.

[@PetakyahBuckley-ht5iz]

At 9:10 you wrote 2(pi) x 10^3 x 0.1 x 10^-6. PLEASE BEAR WITH ME. If the resistance(R) is 1 kila ohm and the capacitance(C) is 0.1 µF. Why is it not written as 2(pi) x 1 x 0.1 and where did the third power, as well as the six power come from. Why is the sixth power negative? Also is omega a constant. If so, what is the constant value? If you don’t feel like answering all this, I understand can you copy the link to one of your other videos so I can learn where this stuff is coming from?

[@raeedshalabalsham6986]

Thanks..It was very helpful

[@RoyAndrews82]

t's basically how fast the capacitor charges.. There's a resistor there so.. it gives resistance. The charge curve is effected, but there's no load resistor to say how fast the capacitor can discharge. So... a specify threshold frequency is controlled or watched.. The resistor in front of the capacitor is kinda like a regulator valve for how much frequency at a specific voltage is allowed to enter or charge the capacitor. What medication can I take to remember all these equations.. lol.. seriously. I WILL learn.. If it takes me my whole life. I've learned a great deal, but more MUST be learned.

[@venkateshganakallunarasimh5520]

Very nice explanation

[@ahmedkhalaf9556]

Excellent

[@jbgaming6283]

Please explain me the LC FILTER with half wave & fullwave rectifier . I just love Ur explaination.

[@syedwilayathkhadari4403]

excellent teaching thank u

[@munivel9653]

Good explanation sir.. cut off frequency is 120hz, frequency band 20 to 120hz, its for a 200watts subwoofer, that is output from the amplifier sir.. 1) what could be the value of resistor and capacitor for either second order or third order? 2) How to find the resistor wattage? 3)substitute unit in the cut off frequency formula, ex: resistance in ohm or kilo ohm, capacitance value in farad or microfarad or nf etc,, If you help me solve this sir, it could be useful not only for me but also for everyone sir...

[@munivel9653]

We are all waiting for your valuable reply sir

[@qaworlds]

sir pls make a video on1) types of memory and its application2) flop flop 3)type of sensor

[@ALLABOUTELECTRONICS]

I have made a video on different types of memory.

[@sudhanshupawar4543]

Nice

[@srivarshinikillada4942]

Thank you so much :) pls keep going

[@ALLABOUTELECTRONICS]

Thank you. I really appreciate your support.

[@humawaseem576]

amazing explaination

[@vikasgupta-hl9sq]

Best of best

[@sallauddin1]

God bless you thanks for the help.

[@scienceandengineering6999]

thanks for clear concept

[@lalchandburaniya3893]

Best way sir keep it up

[@iamadwait]

at 5:03 the output reduces by a factor of 20 if frequency is increased by a factor of 10

[@ALLABOUTELECTRONICS]

It is in dB. If you convert the dB into normal amplitude then it will reduce by the factor of 10.

[@paulirving3166]

Fantastic! Thank you

[@BlueDattebayo]

From 5:35 to 5:57, May I ask how did you jump from the first equation to the next? Considering that the values will be different (As witnessed in Pythagoras Theorem). Really appreciate anyone's help on this! Have a great ahead.

[@ALLABOUTELECTRONICS]

R+ Xc is (R+1/(jwc)). As Xc= 1/jwc. If you consider the only magnitude, it will be Sqrt (R^2 + (1/w^2*C^2)). Or you can say it is sqrt(R^2 +Xc^2). I hope it will clear your doubt.

[@sudeepsaha452]

Good work. Please explain the Phasor diagrams also w.r.t. the phase differences.

[@ceilingwalker1]

Excellent video! Subscribed.

[@rahatfaruk9747]

Thanks a lot. Would you like to make a documentary on "the propagation constant" that has the term attenuation and phase shift. please.....

[@hawaslianas]

Thank you

[@lopamudragouda4451]

It was really helpful...

[@hiresprosound]

i need this specs circuit preamp, -2 (left and right) input 6 output -working dc 12V -all of outputs must be fullrange ?

[@pythonking_stem1527]

it was super..thank u

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YOU SIR ARE AWESOME

[@ManishYadav-gx8ce]

amazing bro!

[@rushikeshkarande662]

Nice 😘❤️😍

[@496priyamanaswini3]

Thank you sooo much I understood this concept very clearly But one doubt how did we get Vout=(xc/xc+R) ×Vin This equation

[@ALLABOUTELECTRONICS]

Using the voltage divider rule.

[@496priyamanaswini3]

@@ALLABOUTELECTRONICS thank you soo much

[@circuitsanalytica4348]

Hello friend, Vin/(R+jXc) is the current through the circuit. Output voltage is the product of current flow through the circuit and capacitive reactance. So Vo = jXc×Vin/(R+jXc)

[@496priyamanaswini3]

@@circuitsanalytica4348 thank you 😊😊

[@swaritmahalsekar5521]

What concepts from network theory we need to cover to understand frequency response and vo/vin eqn ?

[@ALLABOUTELECTRONICS]

You just need to know how to write the impedance in amplitude and phase form. You should also know what is reactance. That's it. Perhaps this video will help you. kzbin.info/www/bejne/fpKpo4xmprZghLc

[@mariorossi7225]

so..i'm not so dumb..i can understand you :-) ty so much..

[@yomeshyadav3407]

great work

Thanks for shared!

[@zahidhassantushar6821]

Thank you, nice explanation (Y)

[@tahmid1847]

Crazyy good

[@kshitijsingh636]

nicely explained ...thanks

[@asikasik6005]

I didn't understand in 10:14 minutes .. how Vout = |xc|/√(r²+Xc²) ? plz help.

[@awakenedauras11]

Look at the circuit diagram it's similar to voltage divider and therefore r2×Vin/(r2 + r1). Then replace r2 by Xc and r1 by R as given.

[@highwish8510]

there will be a root over in Xc + Rc on the Vout formula

[@jaiminparmar2911]

on 7:12, aren't we taking the phase difference between voltage across resistor and capacitor? Which is clearly 90 degrees.

[@ALLABOUTELECTRONICS]

No, here we are taking the phase difference between the input and the output. The output is the signal across the capacitor.

[@qaworlds]

sir your filter video is very exellant /good

[@indraiahlingampally2900]

Its good Can you please explain about digital electronics .

[@colinwilliams3459]

At 3:13 I’m confused, I’m pretty new to this find of stuff so tell me if I’m wrong. But Vout is Xc•Vin/(Xc + R) which means that multiplying Vin by Xc, then dividing it by Xc, wouldn’t that just cancel out?

[@ALLABOUTELECTRONICS]

Vin is not just divided by Xc, it is getting divided by (Xc + R). So, Xc will not get canceled out.

[@circuitsanalytica4348]

Dear Collin, it is the application of voltage division rule. Vin/(R+jXc) is the current through the circuit and product of this current and capacitive reactance will give output voltage......

[@ahmedismail1018]

wonderful

[@ric8248]

How can you obtain Vout when the input signal's frequency is not constant (like in an audio signal)? In other words, is there a way to calculate Vout(t) in terms of Vin(t), R, and C, for any arbitrary instant t?

[@mrafayshams3089]

Good job explaining. Appreciate it. Can you kindly explain to me that is it possible to use one of these filters to chop down frequency coming out of a high frequency (HF) transformer @220v, to 50 Hz @220v +- 5%?

[@ALLABOUTELECTRONICS]

Filter selectively passes certain frequencies and removes the unwanted ones. In your case, if HF transformer does not contain the 50Hz frequency component then it certainly cannot be filtered out using filters. Filters cannot perform the frequency conversion, it can only select or reject the band of frequencies from the input. I hope you understood what I mean to say.

[@salovamrani2084]

Why when I calculate Vout at a cutoff frequency I get 0.5 of Vin, not 0.707. for example lets say R = 1k, C = 1uF l, fc = 150. Xc = 1061. Vout = Vin*1061/R+1061, R is 1000. Vout = Vin*1000/2000 = 0.5 Vin

[@vivekkumaryadav9170]

its helpful to understand LPF thank you so much... tell me about how to solve question opAmp

[@ALLABOUTELECTRONICS]

I have made video on active filters using OP-AMP. so, you can check that video. Here is the link: kzbin.info/www/bejne/nXbId2uperaHe8U

[@circuitsanalytica4348]

Dear Vivek opamp based filters provide some gain. Basically it is same, one non inverting amplifier extra. Filter + Non inverting amplifier = active filter....

[@ankitpandey3774]

Buddy ur work is great.I m big fan of urs buddy Really.I want to ask query, please explain what is the meaning of slope in frequency response? Kya iska matlab ye he k frequency badhega but gain 0 hota jayega? smjha nai pls explain bro.

[@ALLABOUTELECTRONICS]

It means how the fast the amplitude will decay with frequency. Steeper the slope, faster the amplitude will reduce as frequency increase. I hope now it will clear your doubt. :)

[@ankitpandey3774]

Thanx a lot bro... Now I get it.. I have one more query slope Banega hi? Kya esa nai ho skta LPF me fc cutoff frequency k Baad usse next wali frequency Ko reject krna shuru krde!? jaise ideal case m hota h wese!

[@ALLABOUTELECTRONICS]

Yes, Slope will remain. But you can make it steep by increasing the order of the filter. For the first order filter the slope is -20dB/dec, for second order it's -40 dB/ dec, and for the nth order filter is -20n dB/dec. So, by increasing the order of the filter, we can get close to the ideal filter response. But at the same time complexity of the circuit will also increase.

[@ankitpandey3774]

Thanx yaraa... Sara concept clear ho gya thanx bro.. khoob aage badho.. tarakki karo..