Thank you for the great videos! I'm watching this during breaks from reading and working on problems. I'm studying for an analysis qualifying exam. This has been very helpful!
@brightsideofmaths2 жыл бұрын
Thanks! I am glad that my videos can help :)
@anascimentopt2 жыл бұрын
in 6:38 there is a typo in the graph. The sequence S_2l+1 is monotonically "increasing" + bounded instead of "decreasing" as in the label used in the figure.
@brightsideofmaths2 жыл бұрын
You are right. Sorry for the confusion!
@anascimentopt2 жыл бұрын
Ok Sir. No need to ask for sorry! By the way. Are you going to post more videos about linear algebra? Also you mention in your page we can download your book about it (linear algebra I suppose). But I can't find the link. Is it available only for members?
@Hold_it2 жыл бұрын
@@anascimentopt Maybe you have already found it, but if you are still looking, you will find it here : jp-g.de/Skripte/LA-GES-CS-JPG.pdf You should be able to get it even if you aren't a member.
@anascimentopt2 жыл бұрын
@@Hold_it Dear Sir. Thank you very much in allowing me access to the book. Actually I did not find it before. So, once again thank you. All the best for you
@remlatzargonix13293 жыл бұрын
Thank you for doing these videos! Cheers!
@qiaohuizhou69603 жыл бұрын
2:15 alternating series test 3:09 proof
@Deksudo Жыл бұрын
Could you maybe do a Numerical Analysis playlist? There doesn't seem to be much english content on stuff like condition number, stability but german uni courses focus pretty heavily on it from what i see.
@brightsideofmaths Жыл бұрын
Very good idea! I really like to do that.
@ahmedamr5265 Жыл бұрын
Thanks for the great video! Isn't it the case that the theorem requires the monotonic decrease of the sequence of only the absolute values of a_k?
@brightsideofmaths Жыл бұрын
Yes, you can tweak the assumptions like that in some sense. However, you still need that the limit is zero. In general, you need an alternating sum :)
@ffar29812 жыл бұрын
1:49, Is there a reason that use (k+1) instead of k in the exponent as is used in the Leibniz criterion? :-)
@brightsideofmaths2 жыл бұрын
It's just multiplying by (-1). Not really a difference :)
@YumeMiteru Жыл бұрын
I have a question about series (-1)^(n + floor(sqrt(n))) / n. Will it converge by Leibnitz test? Our professor said yes, but I'm not sure
@brightsideofmaths Жыл бұрын
The question is only: can you apply the Leibniz test? :)