mam for answer is 0 because the rule which u said is, for no ion having ionic compound the oxidation no. is 0. Is it correct mam please replay mam
@premilamuralidharan24 күн бұрын
Which question kanna?
@AdhithyaKhanna044023 күн бұрын
@@premilamuralidharan 7 or 8 th question mam u only said to give the answer in comment
@SubhikshaRamesh-p6q4 күн бұрын
Its 6th question ,K2Cr207→K2CrO4 K2Cr207 : +2+2x+(-2*7) = 2x+2-14 which is equal to 2x-12=0 Solving it we get x=+12/2=6 In K2CrO4, +2+x+(-2*4)=0 X+2-8=0 X-6=0 X=6 Both sides oxdn no. Is 6 so the change is 0. Its not 8 and -10.sorry if I am wrong