Basically while the size of model aircraft and their control surfaces changes, the density, inertia (or force needed to move) and viscosity of air stays around the same, so model aircraft and the way that they fly doesn't scale linearly with respect to the properties of air and this has to be factored in when building model aircraft at different scale sizes.
@WalkerWeathers7 ай бұрын
I took an aerodynamics class in college and still did not understand the Reynolds number. All I can remember is my professor essentially saying "always go with 1,000,000" since we were dealing with small real airplanes like the Cessna 172 and Piper Cherokee. You explained this significantly better. Thank you
@miguelmouta53727 ай бұрын
Above this number, Reynolds number, turbulence happens, then it affects the fluid pressure at the measuring space, and also can cause vibrations that affects the surrounding material microstructures. ( Arthur Guyton’s Medical Physiology). Best Whishes from Rio.
@voornaam31917 ай бұрын
These "small planes" are not small at all. Thanks to that heavy engine and the gas tanks, these monsters are two or three times the weight of a two seater glider, that does not need such a huge metal blob up front. And try parking such a "small plane" in a parking lot, you'll see it is far larger than a car. Even those ridiculous large American cars are dwarfed by what you call a "small plane". You are confused by the size of airliners. You think a 200 person plane is the normal size, well, it is close to the size limit. Any larger and it will break in two. Small planes are half the weight and size of the planes mentioned. Do check the Rutan designs, the smallest EZ's are twice as fast and burn way less fuel (mileage) than the giants you named. Because they are way smaller and way smarter designed. That tail in the back is pulling a plane to the ground! Did you ever think about that? It is safe, it is as stable as a badminton shuttle, but it is pulling you DOWN. And causing extra drag. Why do people keep using such fuel burners? I don't get it. Get out more. Do a conversion to an EZ. That does not imply you must buy one, but I bet you will want one. Because of the Reynolds number, maybe.
@WolfeSaber6 ай бұрын
I kinda learned about it in numerical methods class without knowing what it really was. We were running simulations with particles that are sneezed out.
@josega63386 ай бұрын
Reynolds number is an adimensional number, has no units, that indicates relationships between inertia and viscosity forces inside a moving fluid
@DumbledoreMcCracken6 ай бұрын
Rutans are not good concepts, at least the first 20 years worth@@voornaam3191. No one in his right mind would put the engine in back, and the tail up front. The Wrights were equally misguided!
@saltyroe31795 ай бұрын
Discovered Reynolds analogy in 1971 when I tried to design a paper airplane for the UCLA Engineering week paper airplane contest. It can be discussed without numbers. Basically as airfoil get smaller, the viscosity of the air becomes more important than inertial forces like lyft. That led me to use an auto gyro design that was very small with no camber. This about 3 inch tall auto gyro flew 3 times longer than 2nd place. Latter I made 1/2 inch tall auto gyros from vellum using surgical tools. These stayed aloft very long. The problem was they had to be handled with forceps and were easily lost.
@pabloetchepare71605 ай бұрын
You know what you are talking about. And when you learn something deeply, you will never forget. :) Thanks !.
@TeleportingBread1617 ай бұрын
I am very glad youtube recommended me this. You did a good job explaining the topic it in a short timespan.
@heydonray7 ай бұрын
I asked two aero-e’s to explain this. Neither could dumb it down to my level. Thanks!
@Canzandridas7 ай бұрын
KZbin has made a great service for me today by showing me this channel lol
@OnerousEthic7 ай бұрын
Dude you are awesome! Excellent content and droll, over serious tone and demeanor! Excellent!
6 ай бұрын
It is indeed the case that parasitic or induced drag decreases with increasing Reynolds number (Re), but at the scales in question, it is not the Re that causes this decrease; rather, it is the design of the wing, especially the tips and the airfoil, that plays a role. Despite this minor detail, the video is of a high standard, the explanation is very intuitive, and the author explains it very well. I am a university professor and I teach in a Master of Drones programme. I would like to express my admiration for the author's ability to explain this topic so clearly and effectively.
@DanielDuhon6 ай бұрын
Re number is also very important in measuring if a model will behave like the full size version (assuming you’re trying to compare a model with a real plane). To be able to compare, you need to have the same Reynolds number
@AlJay00325 ай бұрын
But how would you do that when the number is in the millions for large planes?
@AlJay00325 ай бұрын
Thank you, well explained. I asked many people who studied aeronautics at the university and so far no one was able to explain it to me so that I could understand it. Now you did that in 5 min. You did a great job. Now I got it.
@nikolatasev49487 ай бұрын
Short and to the point - a great video!
@surfcello7 ай бұрын
The point of Re is that different craft with the same Re behave the same way. This means that you can model a full size plane at a smaller scale by increasing the viscosity of the fluid.
@wolfie543217 ай бұрын
Your pronunciation is Reynolds is something I've never heard, as far as I'm aware the y is silent, so it sounds like Renolds. But I think the best way to describe Reynolds number is that it is the ratio between inertial force effects and viscous force effects. Inertia = velocity, size, density. And viscous force effects = viscosity. So all the inertial terms are in the numerator, the viscous term is in the denominator. So at low Reynolds number, viscosity starts to become more dominant and viscosity tends to act to dissipate. In a high Reynolds number flow, the inertia of the air is more dominant and the flow tends towards more turbulent states because viscosity has a stabilising effect, so when Reynolds number is high, the flow is less stable and more prone to turbulence, but turbulence can have positive or negative effects depending on the situation. For very small aircraft (micro-aerial vehicle scale, or the scale of insects) conventional wings we use on large aircraft tend to not work very well, which is why insects get away with having non-aerofoil type wings, but on the flip side at low Reynolds number things like leading edge vortices can promote high lift (the mechanism used by many insects to achieve high performance).
@rohanbaty31557 ай бұрын
Wow you made it so clear. Thx
@senseisecurityschool93377 ай бұрын
Great video. It's worth noting the "knee" in the curve at about 4500. For best performance, you want your Reynolds number to be above about 5000. After that, the benefit drops off significantly. And we know drag increases greatly with velocity in general. So it's not so much "fly faster to go further", but "fly fast enough to get your R above 5000". This also means that small, slow indoor planes, with R below 4500, can have very different design characteristics from larger, faster outdoor planes. Slow park flyers can be stuck in the middle, halfway in between the viscous regime and the inertial regime. Anyway yeah fly faster or have a longer chord IF you're flying a tiny plane really slow, so your R is below 5000. Once you get above 5,000, increasing your speed gets costly because parasitic drag is proportional to airspeed SQUARED.
@gibbb25017 ай бұрын
What really helped me in school to understand what the Reynolds number is telling you is that it compares the pressure forces to that of the sheer forces, when the pressure forces far exceed the sheer you have a high Reynolds number!
@wolfie543217 ай бұрын
Not quite right. Reynolds is defined as the ratio between inertial force effects and viscous force effects. Inertia = velocity, size, density. And viscous force effects = viscosity. That means a low Reynolds number is one where viscosity plays a large role at dissipating, a high Reynolds number tends to be one more prone to turbulence because viscosity acts to stabilise turbulence so when inertial forces are much much larger than viscous forces, the flow tends to break down into turbulence.
@rjhinnj5 ай бұрын
Correct. I think of it in a real life exaggeration. A 747 would go through a thick fluid like maple syrup much easier than a small bird. The inertial forces of size weight and all that moment moving fast overcomes the viscous forces much easier than a small bird with little weight and speed, being overcome by the viscous forces. The inertial forces of the fluid rival that of the bird and its motion… but not so much that of the 747!
@fullsendmountainbiker58446 ай бұрын
As someone who has applied for an aerospace course at university, I am subscribed
@techtheguy51807 ай бұрын
Come on man, keep those videos coming! I just discovered you and I am addicted...
@daszieher7 ай бұрын
Neat! I like the format and the calm and technical narration. Reminds me of filming my paper airplanes and later models with my dad's VHS camera. This is, of course, taking it a couple of notches further and supporting it with engineering knowledge. Well done!
@norbert.kiszka6 ай бұрын
3:25 Reynolds number *does* affect lift and drag coefficient. Especially at higher AOA. Most of airfoils with RN at least 2-3 millions will stall at about 15 degrees. At half million stall angle in most cases will decrease to around 10 degrees, sometimes around 7 degrees and that is less than half.
@DumbledoreMcCracken6 ай бұрын
What is your justification for the statement?
@norbert.kiszka6 ай бұрын
@@DumbledoreMcCracken NACA papers, papers about fixed-wing UAVs (especially slow ones) and my own experience.
@DumbledoreMcCracken6 ай бұрын
@@norbert.kiszka quote the title of one. I agree that the viscous effects are negligible at high speeds, and the divergence of the flow from the surface is due to the high ratio of the time integral of static pressure*area to momentum. But, in general, people don't talk about stalls outside of the critical angle of attack. Scaling models seems to be a dubious undertaking because the characteristic length is on the same side of the ratio as speed.
@CaptainSwoop6 ай бұрын
Sixty years ago I struggled with this while studying for my commercial licence. I finally understand what I didn't really need to know. Thanks for the excellent presentation.
@rinsatomi95277 ай бұрын
That was a sweet explanation, man
@SmoochyRoo6 ай бұрын
It's not necessarily due to the reynolds number being better on the larger airplane, but that the smaller airplane is more dense than the larger one when they're compared to scale, if you used a hypothetical growth ray on the smaller one to make it exactly as large as the big one you'd find that it would be heavier than the formerly bigger one. This is the thing with making the same model at different sizes from the same material, the smaller ones are heavier to scale than their larger counterparts.
@maxivy6 ай бұрын
Incredible vid. Please dont stop making these
@josippetkovic3896 ай бұрын
Bro is on point. 10/10 on communication. Perfect!
@pitufouno6 ай бұрын
This is a bit misleading. Flying faster increases the Reynolds Number, and gives a lower coefficient of drag. BUT, for that same fuselage or whatever the drag force increases as the square of the speed. Because it is exerted over a larger distance, the power required goes up as the cube of the windspeed. This more than negates the advantage of the higher Reynolds Number. There are airfoils that work good at lower Reynolds Numbers, and airfoil lift coefficient definitely varies with RN. The BEST OVERALL BOOK on model design is Andy Lennon's R/C MODEL AIRCRAFT DESIGN.
@dwaynemcallister72316 ай бұрын
Interesting!
@DesignYourOwnAirplanes-xd6lz6 ай бұрын
You are correct that putting the glider into a steeper dive to fly faster makes it fly a shorter distance, not longer. Instead, you would need to add more weight onto the glider to make it fly faster, since a glider's weight does not (directly) affect its flight distance.
@ccv32376 ай бұрын
Excellent analysis! Indeed, the Reynold's # is important to be considered.
@joshuacook52806 ай бұрын
Bro is INTENSE!!
@pedtrog64435 ай бұрын
Aspergers
@mitchellreece37113 ай бұрын
This video is very informative, very on point, very useful, and you are looking at the camera like you are very mad. Subscribed! I need to learn how to select an airfoil for a 3d printed aircraft with swept wings. I know the spar dimensions, the expected speeds, and the size. I will continue watching your content.
@truegret77782 ай бұрын
I seem to recall something about "dynamic similitude". Meaning, you cannot linearly scale (your small plane scaled 2x) to get twice the performance - or something like this.
@SimonWallwork6 ай бұрын
Thanks. I have 14,000 hours flying and never really understood about Reynolds numbers- although I knew that they changed with size. I learned a few things today.
@peterboy2097 ай бұрын
Excellent Explanation 👍
@jerry23577 ай бұрын
Reynolds number can actually be used in all sorts of fluid flow situations, not just for designing aeroplanes. The key point is that if the Reynolds number is kept constant for a fixed geometry, then the flow patterns will be the same. As a chemical engineer, I use it in pipe pressure drop calculations, for mixing calculations in agitated tanks, or when considering the flow of fluid around solid particles. It can be used to predict the fluid velocity at which the flow goes from laminar to turbulent (for a pipe, flow is laminar below 2100 and turbulent above 4000, where the characteristic dimension when calculating the Reynolds number is the inside diameter of the pipe). The boundary layer thickness depends on the Reynolds number: the higher the Reynolds number the thinner the boundary layer.
@isaacmarkovitz75486 ай бұрын
How do you handle the transition region between 2100 and 4000? Do you just design away from it or go with whichever f value is more pessimistic?
@jerry23576 ай бұрын
@@isaacmarkovitz7548 If you do the calculations for typical industrial plant using liquids like water, common solvents, gasoline, diesel or jet fuel etc. you will always be a long way into the turbulent regime. You need small diameters (3 mm or thereabouts) to make transitional flow a possibility.
@mosesacerdoti7 ай бұрын
This video is really interesting, thank you so much!
@DumbledoreMcCracken6 ай бұрын
Um, you got that backwards. Efficiency is achieved with impossibly thin wings of high aspect ratio. For a given lift force, i.e. weight, a higher aspect ratio demands a lower induced drag for a given speed. Adding chord adds skin friction drag without providing the efficiency of aspect ratio. Adding weight increases speed because the weight must be balanced by lift, and lift is proportional to speed squared. Add weight to the smaller model to make it cross the distance faster, crossing the entire distance before hitting the ground, possibly.
@roryfiler2145 ай бұрын
Very nicely presented! Clear and understandable.
@rousse1.6183 ай бұрын
Love your approach to the aviation
@Zed86zz5 ай бұрын
thank you airplane sheldon
@253ravuribhargavaram25 ай бұрын
bro where are the next videos?? I am really invested in them.
@dominictarrsailing5 ай бұрын
wow great stuff. I shall now watch every single one of your videos
@labraouimehdi69236 ай бұрын
Am i the only one who thinks that this guy is the real life version of sheldon cooper
@reeceengineering6 ай бұрын
Teach us how to use the Reynolds’s number to select an airfoil
@ewingtaylor54873 ай бұрын
What increases the Reynolds Number? Mostly size. The air is the air. It is a constant. So, the larger the aircraft, the proportionally thicker the air surrounding it is. This is why airliners appear to move laterally so slowly, compared to small model aircraft.
@rjhinnj5 ай бұрын
I always wondered how Reynolds number affected wind tunnel modeling of airfoils. The Wright brothers were the first to empirically study airfoil lift and drag efficiencies through wing tunnel modeling, and as you have stated, lift coefficient is not significantly affected by Reynolds number. This is why their experiments to find the best lift characteristics using extremely small airfoil models in a low velocity wind tunnel were successful.
@martinbruckner21095 ай бұрын
Surprisingly, the type of airfoil the Wright Brothers were using is very uncritical about the Reynolds number because of its sharp leading edge.
@rjhinnj5 ай бұрын
No doubt… especially the actual full size one on the 1903 flyer; blunt to say the least! Terrible stall characteristics. I’m convinced that their idea to control pitch through canard elevators (for safety reasons as the forward structure would absorb crash energies) saved their lives, but not for that reason. The canard configuration minimized/tempered main wing stalls… an added benefit they probably didn’t realize right away.
@jimparsons68033 ай бұрын
Interesting and thanks. Once you set up a spreadsheet, you might be able to figure our and draw useful graphs to predict airplane behaviors?
@Umeshsingh-rq8rt7 ай бұрын
You are doing very well. Nicely explains the basics. Slowly you also add electronics and make remote control plane. Thanks
@ArneChristianRosenfeldt7 ай бұрын
Add electronics to stabilise planes and get reproduce able results. Avoid human error and remote control.
@siyz2505 ай бұрын
Great vid. Thank you. Si, Christchurch, NZ.
@GrooveTasticThang6 ай бұрын
It’s a interesting field how to relate wind tunnel models to the real world by interpreting the RE number ( and wall effects)
@klausbrinck21373 ай бұрын
Great lecture, your knowledge is precious, and very few can explain it so comprehensively. Still, it can either be a Parasite OR a Drag, but not both at the same time... It can anyways be a Drag, with the qualities of a Parasite, thus, a "parasitic Drag" (grammar: an adjective for a noun)
@carlosalbertoandradesilva94427 ай бұрын
..your content very well explained with the two gliders; the same when ducks and geese stop swimming, the geese will go further!
@rodella8293Ай бұрын
? Increasing reynolds number does increase the sectional lift coefficient and hence the overall lift coefficient is also enhanced.
@chengong3883 ай бұрын
The lower the Reynolds number, the more it’s like swimming through thick soup.
@ThatNiceDutchGuy7 ай бұрын
I'm not into this thing, but I liked the content! Thank you.
@joseveintegenario-nisu19286 ай бұрын
El número de Reynolds expresa las relaciones entre fuerzas de viscosidad e inercia en un fluido en movimiento, que pueda ayudar a predecir el paso de flujo laminar a flujo turbulento es un uso práctico del número de Reynolds. Las aves vuelan en un entorno de números de Reynolds bajos
@DumbledoreMcCracken6 ай бұрын
Ja, genau. Leider versteht der junge Mann das nicht. Ein wunderbares Buch, das er lesen sollte, trägt den Titel „Die einfache Wissenschaft des Fliegens“.
@michaelmcgovern81105 ай бұрын
Nicely done. I've been looking for exactly what you're doing. Thanks.
@Formovies-g5n2 ай бұрын
This case is only true when your Reynolds number is high enough that there is turbulent boundary layer over the wing. For low reynolds number the laminar boundary layer will separate quickly and the Cd will increase.
@Skulpture004 ай бұрын
We need more videos, good stuff
@michaelphone87396 ай бұрын
Is there a series of reference books for aircraft design that you recommend? Like Jan Roskam
@BenSoar6 ай бұрын
Bro does not BLINK!! Elite
@Paiadakine7 ай бұрын
How much does ground effect help the larger plane fly across the gym?
@DesignYourOwnAirplanes-xd6lz7 ай бұрын
It does help a little bit, you can see the larger plane pull up slightly when it’s about half a wingspan off the ground. That’s another advantage of making the planes larger.
@michaelrtreat6 ай бұрын
Thank you. Nice explanation of very complicated subjects
@Vlaid657 ай бұрын
the "y" is silent in Reynolds.
@scottnj25037 ай бұрын
I like it. Kinda fun when ya think of how much of his generation is shortening everything.
@redbaron077 ай бұрын
Are we sure we know how Osborne Reynolds said it himself, in 1880s Britain with Irish parents? I like the way he says it here.
@scottnj25037 ай бұрын
@@redbaron07 Could be, likely verifiable. Let us know if you find out.
@Vlaid657 ай бұрын
@@redbaron07 Modern day usage is with a silent 'y". But you can be strange and different and say it anyway you like :)
@spacetomato10206 ай бұрын
There are a lot more of self taught people nowadays. A lot of people learned a word from Wikipedia, but heard it pronounced in real life
@mulveymotorsports694206 ай бұрын
If I didn’t speak English I’d think this was a political rant with a major ultimatum at the end. Very intense and direct. I did like the video and I think you conveyed the information well.
@MarkG-h2y6 ай бұрын
Reynolds number is SO much more than this. It's actually from the field of Chemical Engineering and is used to predict the transition from laminar to turbulent flow in fluids.
@zhubajie69406 ай бұрын
And mechanical engineering
@DumbledoreMcCracken6 ай бұрын
Yes, our guide doesn't understand what he proselytizes.
@rjhinnj5 ай бұрын
…. Waiting for your KZbin video and description of RN… 🙄
@DumbledoreMcCracken5 ай бұрын
@@rjhinnj and waiting for yours
@rjhinnj5 ай бұрын
Dude, I did not disagree with this video instruction. YOU did.
@varshneydevansh2 ай бұрын
Immediately subbed thanks
@varshneydevansh2 ай бұрын
I understand with practical examples mostly. Did CSE by mistake bt this is what I really wanted do.
@heydonray7 ай бұрын
One potential flaw (?) in the glide comparison demo was not accounting for weight. The larger plane weighed more and thus possessed more potential energy launched from the same height as the smaller, lighter unit. For a more pure apples/apples comparison, I’d love to see a comparison between the two gliders with the smaller one weighted to the same value as the larger one.
@nidgem71717 ай бұрын
Interseting thought - Theory suggests the big one WILL still go further but *Speaking as an empiricist* SHOW ME *THEN* I'll be convinced
@DesignYourOwnAirplanes-xd6lz7 ай бұрын
The distance that a glider flies is equal to its lift-to-drag ratio multiplied by its starting height, so weight actually doesn't directly affect the distance it flies (although that's not the case for powered aircraft). Adding more weight to the small glider, however, would have made it fly faster, which would have increased its Reynolds number, decreased its parasite drag coefficient, and therefore made it fly further. In that way, adding more weight to the small glider could indirectly make it a match for the larger glider.
@diveintoengineering60896 ай бұрын
Excellent explanation. Thank you!
@mikecarbone8285 ай бұрын
This is also the reason why a smaller plane has to be much more aerodynamically precise than a much larger plane. Thanks for sharing! Please have an excellent and awesome day! ☀️✨🌟✈️
@elmoreglidingclub30306 ай бұрын
I am a glider pilot. I owned a glider with flaps and shifting to negative flap settings when gliding between thermals substantially increased performance. I had three negative settings, each one representing a different “drag bucket.” Any thoughts about that phenomenon?
@DumbledoreMcCracken6 ай бұрын
May I guess? I'm sure the Soaring Society of America has a magazine article with the answer. Anyway, the thinner the wing, the lower the drag. Ideally, a wing would have zero thickness. That is impossible for structural reasons. Reflexing the flap effectively flattens the profile of the airfoil, thinning it slightly, and reducing drag.
@elmoreglidingclub30306 ай бұрын
@@DumbledoreMcCracken I agree with your statement about effectively thinning the wing. It’s fascinating. And when you click in negative flaps, the nose rises slightly and you sort of automatically achieve an optimal speed. Excellent for cross-country flying. I’ve never seen a “Soaring” (the SSA magazine) article about it, but it’s likely there. I did find a dissertation by a NC State aeronautical engineering student about slow speed aerodynamics but drag buckets and negative flaps were not mentioned.
@norbert.kiszka6 ай бұрын
@@DumbledoreMcCracken that's true (not exactly - I will explain it little later in this comment), but only for very low angle of attack. Slower planes has more thick wings (mostly 12-18% of chord) and faster planes has thin wings (4-12% of chord). That's because of mentioned R. number, air viscosity and in some cases mach speed (thicker airfoil will generate more increase of speed at top layer). If You decrease thickness, then stall AOA in most cases will be lower. Drag will be lower for AOA=0. But at some point (like 1-2 deg.) drag will be higher.
@DumbledoreMcCracken6 ай бұрын
@norbert.kiszka there is no reason for a slow plane to have a thick wing. Modern sailplanes have a very very thin wing. While the usable range of Angle of Attack is narrower for a thin wing, that is not an issue for real airplanes. Aircraft that require a large range of AoA have a bendable chord via leading edge flaps, or fixed or retractable slats. My buddy has let me stall his de Havilland Chipmunk a lot. It has a beautifully gentle stall. I attribute that characteristic to its thick, round, gentle airfoil. The Chipmunk is an aerobatic training airplane, so de Havilland may have wished to give the students a more relaxed plane to fly. However, and in general, most planes are designed for speed and low fuel consumption, and require a relatively thin wing (plus flaps, at a minimum) to achieve those goals. Training prevents stall from being a serious issue. Nobody flies with a high drag AoA unless he wants to lose altitude without gaining speed.
@norbert.kiszka6 ай бұрын
@@DumbledoreMcCracken then try to look at many different airfoils, especially designed for low Reynolds numbers (in most channels links are not allowed). In previous comment I missed a small fact, that most thick airfoils (like a 25% chord) are used in wind power plants. Making airfoil thin at around 4% it will be very good for fast fighter jets, but it will be terrible for slow planes. Changing thickness from (for example) 12 % to 11 or 13 will generate significant change in characteristics at slowest and highest speeds. Try any aerodynamic simulation software and You will see that what Im saying is the true.
@KX365 ай бұрын
try to relax a bit in presentation. it looks like you're trying to blow up my head with your mind. 👍
@quaditz5 ай бұрын
I actually think he already talks in a good speed. Not too fast, just like somebody who is really relaxed :). His "strong looking" face is probably a result of physical training :).
@derekwood81845 ай бұрын
@@quaditz 50% of the problem is the lighting. A strong almost directly overhead light is not kind.
@brucebaxter69235 ай бұрын
Are you picking on aspies?
@KX365 ай бұрын
@@brucebaxter6923 no
@brucebaxter69235 ай бұрын
@@KX36 You sure. Sure looks like it.
@sebastiantomczyk45776 ай бұрын
By the way you look to the camera I feel like this is some serious CIA instructions not a model plane video
@rogerrinkavage6 ай бұрын
This was great, thanks!
@abdelrazzac10153 ай бұрын
Thank you for your nice and informative videos. What about the Cubic Wing Loading WCL? planes with low WCL float in the air, are slow, and have low stall speed. On the other hand, planes with high WCL are fast and have high stall speed. For both airplanes used in your demonstration, what are the WCL? is there any direct relation between the Reynold's number and WCL? I know there is not, but what about an indirect relation?
@DesignYourOwnAirplanes-xd6lz2 ай бұрын
A plane with a higher WCL would fly faster and have a higher Reynolds number.
@jimbrowder21006 ай бұрын
Nice explanation - thanks!
@georgemetaxas92276 ай бұрын
In low R nrs the air appears more viscous. Thus insects appear rather to swim in the air, than to fly.
@DumbledoreMcCracken6 ай бұрын
I think that statement is incorrect. Common misunderstanding. While the non-dimensional Reynolds number ratio is lower for lower velocities, for a constant characteristic length, the viscous force does not contribute to lift in a meaningful way because the viscous force points in the wrong direction. Notice the orthogonality of the statement. If we invert the Re number, it is clear that the viscous force is miniscule to the inertial force. Flight must be the result of the inertial forces. Q.E.D.
@europaeuropa36737 ай бұрын
Thanks for that info.
@H0egaarden5 ай бұрын
Are the weights of those 2 different size planes scaled equal to their size difference?
@martinda74465 ай бұрын
What a wonderful channel. Subscribed. Have you calculated the reynolds number of your tache? (I don't know why I felt compelled to ask that)
@crawford3233 ай бұрын
Did both models of aircraft have the same wing loading?
@DesignYourOwnAirplanes-xd6lz3 ай бұрын
No, the larger one had less and therefore was a little slower than the smaller one.
@gabedarrett13017 ай бұрын
L=1/2 • density • airspeed ^2 • area • drag coefficient so why do you say the drag coefficient depends on airspeed and air density?
@DesignYourOwnAirplanes-xd6lz7 ай бұрын
The air will flow differently around the object and create a different drag force.
@phyarth80827 ай бұрын
airspeed influence drag coefficient that is biggest misconception. Geometry of wing under different airspeeds changes drag coefficient, that is complete nonsense. Many solutions disregard engine thrust (airspeed), which sustain energy conservation condition.
@ricksorensen94807 ай бұрын
Yes, thank you,,distance is scaled up along with size and velocity,,I better understand why my larger models travel farther...
@TheRealStructurer5 ай бұрын
Great video 👍🏻 Relax and smile 😎
@christophmahler4 ай бұрын
"Relax and smile" Hell no. It's perfect composure. Remember, You are building Your own airplane, unironically.
@BillPalmer6 ай бұрын
Thank you. Well done
@kirkglundal42896 ай бұрын
So, would it be true to say... All else being equal, if reducing parasitic drag will increase the Re number? In other words... The smaller the airframe (scale), the lower the Re, the more critical that parasitic drag becomes in design, (if wanting to improve L/D and/or minimum sink)?
@DesignYourOwnAirplanes-xd6lz6 ай бұрын
Yes, I’ve found that below a Reynolds number of about 50,000, the parasite drag coefficient of airfoils increases significantly, which would make streamlining more important. The drag coefficients of other shapes may be affected by the Reynolds number in different ways though.
@yatzeegamingop4 ай бұрын
What about the scaled travel ratios ? If we throw 1x and 2x scaled planes, measure their distance and divide the distance of larger plane by 2, would it give the same result ?
@DesignYourOwnAirplanes-xd6lz4 ай бұрын
The distance a glider flies is determined by the ratio of the lift coefficient to the drag coefficient, multiplied by the height it was thrown from. The small plane was at a disadvantage because it had a higher drag coefficient.
@inoculator3 ай бұрын
You can see in the diagrams, that it is a sort of exponential function. So the answer should clearly be "No".
@totally_lost16023 ай бұрын
If all the structural geometries are identical in scale, the smaller plane is at a disadvantage. However structural strength doesn't scale linearly either, and favors smaller, lighter, stronger structural solutions as you scale down to some degree. Replacing the fuselage surface area with a long soda straw, removes parasitic drag while retaining wing area. Likewise the smaller slower model has smaller control forces, so the tail section can be significantly smaller if positioned farther from the CG or CM, with a larger lever length. Scaling planes up has similar results, often requiring significantly heavier and stronger structural elements.
@arushsingh55927 ай бұрын
Great video. I dont have foam board available in my area so can you please make the next plane with some other material please.And can you also teach us how to make a rubber powered plane. Great videos thank you very much.
@DesignYourOwnAirplanes-xd6lz7 ай бұрын
In a later video I plan on talking about building materials. You can also use pressed or corrugated cardboard, balsa wood, corrugated plastic, thick paper, or insulation foam. I'll consider making a video about rubber powered planes.
@alecsandercimpoeru43556 ай бұрын
I just finished my second year in aeronautical engineering and you just taught me more about Re number in 5 min than in my 2 years, such a shit education system
@Samuel-vm7hn6 ай бұрын
i mean it's not a difficult concept (it's quite literally just a ratio between dynamic and viscous/friction forces) but the application of this figure is much more technical which you will see when you study incompressible aerodynamics. it's hard to introduce such a figure without being able to go in depth on what it actually does so i can see why you might be confused. i'm sure you will learn a lot more over the next year so don't be discouraged. btw, reynolds nuymber is much less important past a certain point as your coefficient of lift is invariant all the way down to your level flight stall speed. this guy just happens to be running a model plane (small and slow aircraft) channel and not a general aviation (much much larger and faster) channel so in this case, it is much more relevant. ig that's why a drones prof has shown up in the comments lol.
@AlJay00325 ай бұрын
All the good stuff is free. Stop paying 10'000s to a stupid liberal university.
@Toomanydays6 ай бұрын
So the ratio of wing length to cord length has nothhing to do with the Re #?
@DesignYourOwnAirplanes-xd6lz6 ай бұрын
You can use any length you want to calculate the Reynolds number, as long as you stay consistent when comparing different Reynolds numbers. The aspect ratio does not directly affect the Reynolds number, but it is possible that changing it could also change the characteristic length and therefore the Reynolds number too.
@Toomanydays6 ай бұрын
@@DesignYourOwnAirplanes-xd6lz Does an albatross wing have a higher Re number than a crows wing?
@DumbledoreMcCracken6 ай бұрын
@@Toomanydaysthe chord length is the determining factor, and speed, when discussing Reynolds number. The wing span is irrelevant. Unfortunately, Reynolds number is described in an algebraically simplified form. The factors are more understandable when the form of the equation is not algebracially simplified.
@respectmyprivacy3 ай бұрын
You keep saying further, but mean farther. (i.e. The gas station is farther from my home is an imperial measurement.) (i.e. He is spiritually further ahead in life than I am, cant not be measured with imperial measurements) I hope this helps.
@matthewlazaric35437 ай бұрын
I think it caused me psychic damage reading Reynolds number out of nowhere on my feed
@OnerousEthic7 ай бұрын
How and why is that possible?
@stuartyablon71847 ай бұрын
very interesting. thank you.
@climatehero6 ай бұрын
Condors vs sparrows
@DumbledoreMcCracken6 ай бұрын
Low wing loading vs. high wing loading
@miguelmouta53726 ай бұрын
Reynolds number formula indicates precisely when where and which factors are causing turbulent flow, no matter the surface, wing, rocket combustion chamber, or even heart valves.
@HerbertTowers5 ай бұрын
Utter bullpoop!
@iFriccicle29 күн бұрын
now, what if you're forced to use a low reynolds number? what to do?\
@iFriccicle29 күн бұрын
nevermind. the stepped airfoils video helped
@FUZE_313Ай бұрын
very helpfull video thanks :)
@southerncross49565 ай бұрын
Yea OK got that, Hmm, yea that too, wow did not think that, but then at 4:47 he said making planes bigger makes them more efficient… What ??!!?
@si.ari.064 ай бұрын
Bigger wings more lift When you increase the size, lift and weight don't always correlate (idk if I'm right, I'm not an aeronautical engineer)
@JonChampion-fb9js6 ай бұрын
I am curious as to your background. The Reynolds Number is the ratio of inertia stresses to viscous stresses. It does affect lift coefficient as well as drag. This requires understanding boundary layer theory.
@DesignYourOwnAirplanes-xd6lz6 ай бұрын
I majored in aerospace engineering. The boundary layer and stresses are beyond the scope of these videos so I didn’t mention these subjects to keep things simple. The main point of this video is that if you make your glider too small and/or too slow, it could reduce your flight distance.
@JonChampion-fb9js6 ай бұрын
My undergrad degree was in aero/astro engineering from Purdue in ‘82. This was followed by graduate degrees in aerospace engineering from a joint program from the University of Dayton and AFIT. My research interests were aero elastic effects at low Reynolds Number. I retired as Aerospace Fellow from Honeywell in 2021. You were wise in selecting Aerospace Engineering as a career. It does not get better than that. Aerospace Engineers rock! Cheers!
@_BL4CKB1RD_6 ай бұрын
This is a spectacular video! You are incredibly informative. Being an airplane builder myself, Reynolds’s number always confused me. Thank you very much, and have a nice day!
@brucebaxter69235 ай бұрын
Brownean motion. That explains Reynolds number.
@georgeolson39963 ай бұрын
Frank Zaic's books contain the results of his extensive experimentation and collect much of the knowledge if ither modellers in North America and Europe from pre WW2 through the early 1950's. Extensive work with Airfoil selection and Turbulator shape and Position. The next step was Herr Doctor Ingeneer Richard Eppler's series from his computer program. His interest was spiked when he observed r/c gliders in the Alps that flew well with airfoils that Were Wrong according to his personal State of the Art wind tunnel verified computer airfoil design High Reynolds program. In digging into this he realized that Viscosity is essentially a Constant which becomes more important in Elastic-Gaseous Fluids as Reynolds drop from 1 million of full size Piper Cub at landing speed (3 foot airfoil Chord Length at about 35 mph to a 2 inch airfoil chord of a gilder tossed at 12 mph across a gymnasium. Chord is a Linear factor and Speed - Velocity is Squared!!!! But Viscosity is a Constant !!!
@mithrandir131327 күн бұрын
At sea level, Rn = 6360 x Velocity (fps) x wing cord (ft) Above 1 million, all the weird phenomena is absent, below 100,000, it just sucks!