Step-by-step single shunt stub matching circuit (First solution) using animation

[@akleshkumar1759]

thanks 100000000009 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! times i got it after wasting 8 hours.

[@Matt.Scientist]

Sir, thank you for the tutorial. I need to ask; why did we use -j1.5 susceptance insted of moving on from j1.5? Thank you.

[@RFDesignbasics]

By adding -j1. 5 in 1+j1.5 it will become 1+j0

[@ykr6910]

fire video, great explanation

[@tomascatalao2961]

veri gud

[@Stekaren]

how is load admittance negative imaginary in the lower part of the SC? Admittance is positive there?

[@xavizeroseven]

Great video, thanks!

[@ckc4366]

Why the 1+jb circle is on the right hand side instead of left? Thank you!

[@RFDesignbasics]

Because 1+jb circle is on the left on Y-chart. Y chart means Z chart is rotated by 180 degree. Eventually it comes at the right hand side only.

[@kennethodung8206]

wow...great!!!!!

[@pensulpusher2729]

This video is saving me

[@ivanxu3481]

where does 1+j1.5 come from? Thx!

[@makoto7275]

thank you so much

[@donrixw9955]

its normalized load impedance not admittance

[@RFDesignbasics]

Check again

[@tahabandrawala7603]

Zl/z0 so 40/50 is 0.8 not 0.3

[@RFDesignbasics]

Invert the zl in complex to get yl.

[@RFDesignbasics]

Zl/Z0 is zl and reverse is yl. For shunt matching we need to start from yl.