TSD Boat Streams 1 | CAT Preparation 2024 | Arithmetic | Quantitative Aptitude

CAT PREPARATION 2024 I QUANTITATIVE APTITUDE PREPARATION for CAT 2024
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How to Prepare for Quantitative Aptitude
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[@nehalsharma2971]

i was going through the comments as there is slight change in ans for last question but wasn't able to get one so here is how I did it 8/3-Sr +8/3+Sr = 6 8 (1/3-Sr + 1/3+Sr) =6 take LCM (3-Sr , 3+Sr) = (3-Sr)x(3+Sr) 8 ( 3+Sr + 3-Sr ) / (3-Sr)x(3+Sr) = 6 8 ( 6 ) / (3-Sr)x(3+Sr) = 6 { for numerator 3 +Sr +3 -Sr = 6 } 8/ (3-Sr)x(3+Sr) = 1 { 6 on both sides cancel out each other } Now (3-Sr)x(3+Sr) can be seen as IDENTITY (a+b)(a-b) = a^2 - b^2 so here a = 3 and b =Sr hence a^2 - b^2 = 3^2 - Sr^2 i.e 9 - Sr^2 8 = 9 - Sr^2 Sr^2 = 9 -8 Sr^2 = 1 and Sr = 1 km/hr Tu = 8/3-Sr =8/3-1 = 8/2 = 4 hr Td = 8/3+Sr = 8/3+1 = 8/4 = 2 hr hence we got our ans (ps - calculation is easy just to make it more clear i have written in elaboration)

[@arvindgupta659]

Useful🙌

[@eshaguha2874]

Helpful! thanks.

[@harman5710]

Thanks a lot !

[@dhruvxkhanna]

Why not SR= root 1? Coz SR^2=1, please explain

[@shubhamthakur7299]

@@dhruvxkhanna if A^2 = 4 then A = root 4 i.e. 2. another example if A^3 = 27 then A = cube 27 i.e. 3

[@mukeshkalal9842]

Data should be interchange 40,60 because Time should be greater in upstream as comparing to down stream

[@Rahularora2611]

True af

[@godisasadist857]

Lol chill

[@Error-oi9ms]

That happens sometime when Math has rivalry with Physics 😂😂

[@surajalwayslight5707]

Bilkul

[@ABCD-qf8or]

Guys you can't believe i spend my 3 hour for thinking how downstream can take long time than upstream with same speed..😂 I thought may be i take it wrong than i saw comment.

[@vaibhavtondak]

In the last ques, we can also take S(b) = { S(d)+S(u) }/2 i.e. 3={ 8/t(d) + 8/t(u) }/2 after solving this eq we'll get t(d) x t(u)= 8; which is possible only when t(d) = 2hrs and t(u) = 4hrs

[@RahulPatel-30]

the answer to the last question would be would be 2hrs downstream and 4hrs upstream

[@rishavkhandelwal9323]

correct

[@ydissidy8112]

Yes

[@supritmal985]

Bhai did you cleared cat ??

[@safar-nama9678]

Kya baat h padhai bhi karta h tu hero

[@RahulPatel-30]

@@safar-nama9678 real I'd se aao 😂

[@aloksingh4244]

A better solution for the last question can be as follows :- Total time = ( T'up) + (T'down) =6 hrs....(i) Time in still water would be 8/3 hrs (according to question) We know that T'up, T'still and T'down are in HM Therefore T'still=2* ( T'up) * (T'down)/ ( T'up) + (T'down) => 8/3 = 2* ( T'up) * (T'down)/ 6 ........(from (i)) => ( T'up) * (T'down) = 8...........(ii) From (i) & (ii) T'up =4; T'down=2 ( as T'up > T'down)

[@anannyapadhi828]

Can you explain how ( T'up) * (T'down) = 8?

[@sudhanshushekhar4710]

​@@anannyapadhi828exactly,why is he multiplying both time taken???

[@anonymousab8455]

​@@sudhanshushekhar4710they r in hm...its the property of harmonic mean (hm)

[@bestshorts2762]

Good Approach, But in the end , you'll end up getting quadratic equation and that will consume more time and makes the answer lengthy.

[@Endever10]

​@@anannyapadhi828same mere wala haal😂❤

[@sujiths4409]

last question : answer it is (9-Sr^2) instead of (9-Sr)^2..?

[@riteshsahu1008]

Ya ya there is little error

[@georgemathew880]

Su cannot be greater than Sd if the speed of the boat is same in both the situations, Su > Sd => Sb - Sr > Sb + Sr => Sr < 0 ( which gives situation where speed of river is less than 0 ? )

[@loknathdas3111]

Sir in 2/7 th km, problem. First we can, determine .....time in still water by HP RULE, =5/21 hr. Then speed = 2/7 ÷ 5/21

[@Skinnywalker01]

Last question can be solved in a much easier way if we take help of HM in time and then solve the quadratic eqn thus formed🌟

[@warrenhasting8442]

I have a doubt in question no1 .. how can a boat take more time in downstream while covering same distance .. as speed is more in downstream. ??? 😄😄

[@buddy9466]

I was going to write the same problem but found your comment. I think they misprinted it.

[@ExamLauncher]

Right, there should be downstream at the place of upstream..

[@kshitijshekhar662]

it's not just for one question but for many! But the content is still the class!

[@vishal9264]

Thats why its recommended to watch the FULL VIDEO .

[@ABCD-qf8or]

Guys you can't believe i spend my 3 hour for thinking how downstream can take long time than upstream with same speed..😂 I thought may be i take it wrong than i saw comment.

[@megawarrior95]

Sir, at 25:17 ratio of time taken to be calculated upstream to downstream right?? so should the ratio be 4:1

[@TMMADHAVPRASADBEE]

yeah, I too have the same doubt? can anyone clear it, please?

[@spidervirus5780]

Yeah it will be 4:1

[@nakulkaushal4473]

Yeah, it's 4:1 he forgot that it's written upstream then downstream

[@avishekgoswami363]

boat will take less time in downstream

[@abhinavsahu6440]

In the first question , how is time taken while travelling downstream lesser than time taken while travelling upstream? Since speed will be greater in downstream , time taken should be less , right ?

[@TMMADHAVPRASADBEE]

sir, at 25:15 ratio of time taken to be calculated upstream to the downstream right?? so should the ratio be 4:1 in the answer?? please clear it!

[@santhwanaprasad8333]

Yep, I was thinking the same there

[@sirirvasist4853]

yes so the ratio of speed of upstream to downstream is 12:48 which is1:4 and the ratio of their time will be 4:1

[@subhammajumdar2214]

can be either of the two

[@purbadas9322]

i was thinking the same

[@safalmittal4226]

When Distance is constant -Speed is inversely proportional to Time So If the Ratio of speed is 4:1 Then time taken is -1:4 Ans.

[@anirudhdas5453]

Sir, I am very grateful to you. I have never understood this concept with such fantastic clarity, especially with a multi-disciplinary set of problems 25:29

[@Samrat-Singh-Maurya]

In first question data is interchanged and another question 4:1and last question time in upstream=4hrs and time in downstream=2hrs 😅I think,I am 💯 correct 😂😅

[@sudhanshushekhar4710]

28:03 i think there should be 9-sr^2 not (9-sr)^2

[@SM-ew1jt]

the last qtz asks u to find Time for upstream & downstream.How is the ans in kmph i.e in terms of speed??

[@RahulPatel-30]

the answer needs to be in time i.e.in hours the answer would be 2hrs downstream and 4hrs upstream

[@Whosthatbaldguy]

In question 1, the boat reaches faster ie in 40 sec when it's travelling upstream but takes more time when it travels downstream? Isn't that wrong formulation of question?

[@aswinkrishnanak3261]

question wrong but answer is correct.just exchange the values of time

[@rohitrohitrohit]

in the last question, (3-Sr)(3+Sr) wont be (9+Sr)^2, it would be 3^2-Sr^2

[@nitinagarwal1611]

In last qus answer is 2 hour and 4 hour

[@ayushiacharya6833]

can someone explain how downstream distance is equal to 3/2 upstream distance in 2nd question ?

[@visheshgupta9326]

In order to remove decimal, sir multiplied both numer. n denom. by 2. 1.5 times can be written as 3/2

[@chetansingh405]

“One half“ means 1/2 “One and a half” means 1.5 or 3/2

[@restyletime4918]

thank you so much @@chetansingh405

[@wonderwoman2949]

In question 1, since the total distance is constant can we do 48-8x=36+4x? where x is the speed of river

[@tannukiller6904]

Answer for last question is 2 hr and 4 hr Since times are in HP therefore Still water time = (2 a*b)/(a+b) > 8/3 = (2 a*b)/6 =(a*b)/3 Since a+b = 6 Then a*b =8 only when a=2 and b=4

[@visheshDalal28]

in Q1 the time is given as 40s and 60s. then why sir has taken speed as 40s and 60s in AP method ?

[@AvinashKapu]

Brother, rewind and see that concept of AP and HP again.. Speeds are in AP as distance is constant. Speed inverse to time.. So time will be in HP..2ac/a+c is formula for hp. So what he took is time only

[@vatsalparikh3574]

Just note that in 1st problem upstream time can never be greater than downstream time

[@NavIK_IAS]

2nd problem also

[@ritujatripathi7959]

Great explanation

[@ankitaawasthi119]

For 1st question...why can't we apply- Sb = Sd + Su/2 ....by this method answer is 50s unlike AM & HM method. Again, in 2nd Last question- Ratio of speed should be Su/Sd na...?

[@venkatesh.b5365]

For 1st question If we apply sb = sd+ su/2 Then the time for boat is 48s. Speed inversely proportional to time.

[@user-cv7de8ht5c]

lot of mistakes in the questions

[@komalrajpal6070]

at 24:59 , ratio of speeds should be 1:4 upstream:downstream as given in question. why is it reversed?

[@sanklan10]

sir has taken downstream:upstream as 4:1, both are samething

[@abonthego]

@@sanklan10 why he didnt take upstream:downstream and then inverse it for time?? please clear

[@pranjalaguptaa]

same question, its probably by mistake

[@yashmittal6663]

Sir u r fantabulous

[@yashmittal6663]

Where i can contact u

[@Rodha]

Unacademy plus .. search Ravi Prakash

[@fadhilu5171]

why not using hp concept? it makes a lot easier, anyway thankyou sir!!!

[@redblazer29]

What is that concept? Can you give link of a video where it's explained or tell me here please?

[@supriyas97]

It is explained in chapter time,speed and distance: part 5

[@sheetaljain4288]

In last question it must be (3^2-Sr^2), mustn't it ?

[@Endever10]

Yeah! You are right😮

[@devanshupadhyay6314]

sir at 12 25 question is asked about the ration of the time upstream to downstream so what was the ratio please clear ??

[@muhammadpp393]

This concept and videos use full of the cat 2024??

[@kajolagarwal8807]

In question one T(u) should be 60 sec instead of 40 sec and T(d) should be 40 sec instead of 60 sec as T(u) should be > than T(d) . Am I correct?

[@anshugajraj]

yes

[@kalpeshkabra3371]

in the last que why cant we take the avg of speed of upstream and downstream and equate it to speed of boat and with that we need to assume one time as X and other side time as 6-X and then solve the equation ?? (why its not working in this case)

[@234puramsettysairam4]

its working

[@-AkhilTej-]

🟠⚪ Great fruitful session ⚪🟠

[@deepakgulia3863]

Su. 4 and sd 2 hrs

[@bhagirathsharma7505]

Good videos sir 🙏🏻

[@rupalichaudhary7128]

Fourth ques mn sir distance downstream=3/2 of distance upstream kese le li?

[@Rodha]

We can discuss on telegram group

[@dashrathliyangi6353]

Its 1 and 1/2 mixed fraction simplified

[@asmitkumar5246]

1+1/2=3/2

[@atishayjain1471]

great sir u r amazing

[@knowyourworld5130]

great videos sir

[@samarthbadar7752]

I think there is a mistake in 1st question.

[@ultimatespectator137]

The data is first ques is wrong wrt time.

[@KhyatiSharma-x1r]

Are these lectures relevant for CAT24?

[@Shaileshhh]

Yes

[@Kapilsharmaashow]

18:05 I didn't get how he write 3/2 instead of 1/2

[@gauribabu8553]

because its one and half

[@therebiliousone6240]

Why doesn't boat goes diagonally?

[@VinayKumar-vk3tq]

The motion studied here is 1-dimensional linear motion. Assume everything moves in a straight line. The velocites of the boat and the river are either parallel or anti-parallel.

[@rpbhaskar56]

Guys saws his logic...

[@harshrawat-es6ej]

bhai neend me video bnata h kya... out of 5 quest 3 you did wrong!

[@ajithkumaar3473]

sir down stream is speed of river + speed of boat.so it should reach the destination faster compared to upstream....then why the destination time in downstream higher than upstream? 11:54

[@sanchayanmondal5068]

I think the question is wrong, it should be time taken for upstream 60s and for downstream 40s.

[@muhammadpp393]

How to get lcm 35 ??

[@Shivam_General_Fitness]

Thankyou sir

[@amishasahoo7376]

Thankyou sir 🙏

[@MSD07205]

Hey are u also preparing for cat 2k24

[@BPH_SharmaTushar-NitHamirpur]

jee😍

[@vatsalparikh3574]

We get Sr as 1 in the last problem. There's as error

[@risingstar807]

Hii folks 🌚

[@deepakgulia3863]

In last que u miss the question to find time of ascent and decent

[@spidervirus5780]

He did find it 2hr and 4hr respectively

[@pranavkokane7822]

There are lots of mistakes in question formation in this video . How canboat take less time when going upstream and more time when going downstream . This is by default an act of misdirecting student who are watching your videos . Look into this matter @Rodha . All other videos of yours are good but this one is having lots of mistakes 😒 ..

[@arunadityarajjain1129]

cut him some slack, ungrateful SOAB

[@pranavkokane7822]

@@arunadityarajjain1129 is that your mother's account . SOAMFB

[@VishalSingh-on4ii]

He knew he made a mistake at 14:28

[@moonchild4960]

Yay, upstream time taken > downstream time taken which is not possible

[@VishalSingh-on4ii]

@@moonchild4960 Shmart

[@shriharisriram2385]

he did not make a mistake the question itself is logically flawed

[@VishalSingh-on4ii]

@@shriharisriram2385 fanboi

[@shriharisriram2385]

@@VishalSingh-on4ii lmao what, he often makes calculation mistakes, like watch the next video at 12:50 streams boats -2 But this time the question is flawed

[@BSbscphysics-yu4cr]

CAT clear hone ke bad yaha jayenge kzbin.info/www/bejne/hnLMdJmsd7t3p9k

[@shorts77471]

Hindi me bolbe mai kya problem hai aap logo ko sharam aati hai kya

[@Rodha]

South Indian ko Hindi ni aati. This is to cater a larger group of audience.

[@AvinashKapu]

If you can't digest the videos in English how are you willing to appear for CAT

[@AvinashKapu]

Is someone teaching you VARC in Hindi? 😅

[@anubhavgupta8726]

Sir Can u plz share your telegram group link or its name:::: !!!!

[@ankushsharma9954]

kzbin.info?event=backstage_event&redir_token=QUFFLUhqa01ZazdlR2JTa2h4SnZuT2ZmMEZObi1sSmFZZ3xBQ3Jtc0trVTFCRWh1c3FPWE5IVGRWWlN3cTVwTzFoNVdSeHNsNEIwMFV1bnN4UHV0VGFTSEhoLUZkSXM3WjhZa00tZGZCeXp1bHg2VnBxc2h3UGN6TE5WekhtRmpvUVF5aDM0UkpDUjNsNnl4LXdxbWhwdlJ6Yw&q=https%3A%2F%2Ft.me%2Fjoinchat%2F6EpWdHLmBbE3ODU9

[@kshitijbalonie4361]

Thankyou sir