TSD Linear Tracks 1 | CAT Preparation 2024 | Arithmetic | Quantitative Aptitude

[@AbhishekGupta-lj8tx]

I watched almost all of your videos sir on every tough looking concept and now all they are very much easy for me... I'm on my last phase of prepration.. solving questions from your videos and just realised that the all the efforts you made aren't just extraordinary.. they are actually money, time & life saving for all of us. They are out of the world both the concepts and the efforts you made for us. Realised and just paused this video to thanking you. Thankyou so much sir ❤️. Now need your blessings for the final day 😄🙏🏻.

[@satyamagarwal298]

Why the sound in your videos is too low Then suddenly the advertisement pops us and i realize i am loosing my ears now😂😂😂

[@prateek7323]

Sir never delete single video bestest Teacher ever

[@icecoldnobody3447]

fun fact!!!!! if u come back to normal speed after listening in 2x or 1.75x ....u feel he is speaking in ultra slow motion in normal mode...which is wayyy wierd

[@sanjayk1286]

true happens everytime lol

[@sonal7928]

I should not complain about anything because you are providing this content for free to us but it's not avoidable to say that sir plz improve sound quality of ur videos

[@Rodha]

It is good in recent videos. Plz use earphone for older ones.

[@shashankkumar6206]

Turn "Stable volume" on, It will improve

[@Endever10]

Hn hn sb chahiye tumko😂❤

[@arunadityarajjain1129]

18:37 Who's this guy you tell everytime to just edit it? He never edits it. LoL

[@ritika9631]

Thought the same 😅

[@aayushdeo9143]

By "edit" I think Ravi sir means "cut" . And he says that to the students only. Or maybe Sir ka video edit karne wale bhaiya is Dhokhebaaz 😂

[@prerakshah8103]

edit karne wale bhaiya pura video nahi dekhte lagta hai

[@restyletime4918]

He edits it himself, and after doing thousands of videos he just let it go

[@NarayananRamanathan07]

Simply every odd time they will meet in M1 and even time they will meet in M2 , I feel this is a more complicated way to find it

[@simrankapoor846]

Best video on concept of linear tracks. With this level of explanation, no one needs hacks of tricks for this concept!

[@Endever10]

Which sem?

[@muskaandatta9233]

I came across a similar question with a very minor tweak as question 15:38 and I realized that the solution told by you sir is a bit incorrect. I found this explanation : A’s speed is more than B. Together they cover 70 km in an hour. So, they take 20 hours to cover the entire stretch of 1400 km. That is, A covers 1000 km and B covers 400 km when they meet for the first time. When A completes 5 rounds he will be at Q. During the same time B completes 2 rounds and he will be at Q. That is to say, both are at Q. On the sixth round A does not meet B and only on the 7th round A meets B for the sixth time! Therefore, after 10 rounds A meets B only 9 times. After 10 rounds A will be at P and B will be at Q. By the same logic, after 20 rounds they meet 18 times and A will be at P and B will be at Q. Now, they are in opposite direction. After 23 rounds, A will be at Q and he has met B for 21 times. During the last 3 rounds of A, B must have covered a distance of 84*20 = 1680 km. That is to say, B is 280 km from P and going towards Q. A is going towards P from Q. The distance between A and B is 1120 km. They take 16 hours to meet for the 22nd time. A covers 800 km from Q. Hence, A is 800 km from Q or 600 km from P.

[@kingkhan-mt7mv]

yes u r right! even my answer is same

[@shauryasharma5554]

Yes this is the correct way to go this ques.

[@mansimainali6145]

@@shauryasharma5554 how is A' speed more than B? . And how come A covers 1000 m and B 400 m ?

[@shauryasharma5554]

@@mansimainali6145 A's speed is more than B. This can be simply deduced from the fact that A travels 60m in the same time when B travels 40m.(Speed is proportional to distance travelled when time is constant) It's given that they meet for the first time at 40m from Q, this means to meet for the first time A travelled 60m from P and B travelled 40m from Q. I hope I am able to clear your doubt.

[@mansimainali6145]

@@shauryasharma5554 how did you got this 60m and 40 m distance covered by A and B respectively? It's not there in the question. In the question it is 400 and 1000m no.!

[@CATPreprations]

Done 👍🏻 30 September 2024

[@LostWizard12]

Sir as A and B are travelling at diff speeds at some point B would overtake A before he ever reached to the end point so that would also be considered as a meeting? or B is stopping at an endpoint till A reaches at the endpoint?

[@hirensoni7636]

Got any solution for it ?

[@himanshugujjar-yx2lc]

Can we not have notes for these sessions as for working professionals it's very much time taking to first see the video & then make the notes?

[@pannux10]

For linear tracks questions what if speed of one of the objects is quite slow such that 2nd meeting or any subsequent meeting happens while both are moving in the same direction? In such cases the combined distance between two meetings wont be 2d but 2*(M1-M2). The general rule wont be valid then ?

[@rishabhpandey2328]

I think it isn't valid for ratios bigger than 2

[@RatnaPatel-g7y]

I am getting intelligent day by day. clearing exam is now the byproduct.

[@purubaranwal8149]

The answer is wrong because it has assumption that at second meeting A will complete 1400 metre round(24:36). But if you will analyse closely you will observe that at second meeting A will be at 1200 from P which is it's first round.

[@vanshlakhina2162]

Bhai, here round means- his own round of 1400m.

[@purubaranwal8149]

Watch at 19:34 where sir is claiming that to meet them for 2nd time A will reach the reach end point and come back again. But when you will apply formula 2x1400x(2/7)=800 means A will cover next 800 after there first meeting. In total it is 1200 which is before the end point of A. So both will meet even before A will reach end point.

[@purubaranwal8149]

And for again any doubt plz refer the comment chat pranjal there I explained it in more detail.

[@competento4024]

Sir is a great teacher, but this concept seems to be wrong. This 2d concept is only applicable when ratio of faster: slower is less or equal to 2:1. In the eg even, B would meet A second time even before A reaches point Q, so how can the distance be '2d' between two successive meeting points?

[@debasishmandal9677]

@Rodha, Sir what about like if after M1, if the speed ratios are such like one overtakes other in the same direction rather than crossing each other in opposite direction? Then I guess the concept of '2d' won't work.

[@siddhichavan99]

I agree with you and I have same doubt

[@sanskarpandey2816]

volume is too low man!! Please get this sorted!

[@rohitbehera4524]

Hello Sir....this solution will only work for face 2 face interactions....Plz explain??

[@shubhamsaurabh7811]

please improve your sound volume. I can't hear properly even at 100% volume. It's really frustrating.

[@commerceworldbydeepesh]

Use headphones buddy 🤷

[@richabhandari6375]

Best series ever

[@tarunverma598]

sir, in the last que. of this video with 400:1000 ratio, for the 22nd time they meet, A should be at Q instead of P, as they met the first time before the completion of 1st round, so they will meet 22nd time before the completion of 22nd round. so the answer would be 400m from Q. please correct me if i am wrong

[@shoumikbardhan8635]

bro.... A is starting from p... therefore to reach q he travels 1400m, then comes back to p i.e, 2800m. his 2d is 2800m nd ends at p. similarly multiple of 2d will make A end at p. therefre at 1400*12 ,he ll end up at p.. (multiple of 2d or even ..he goes nd comes back..2times).. then remaing mtr from 17200 m is 400 which he will travel from P.

[@ramradhakrishnan2351]

@@shoumikbardhan8635 guys we can easily do by without calculation n long process if we gonna use some common sense 43*1000/1400 =1000 remainder means "utna dur from Q"

[@ramradhakrishnan2351]

@@arunadityarajjain1129 haven't u seen it's written remainder .... 42000/1400 is completely divisible but here it's 43000 so 1000 will be the remainder

[@madnessofmunna]

general rule kaise banega sir, in 100 meter track..if A travel 80 and B travel 20 to meet each other.then at second meeting both will be travelling in same direction..and combined distance will be only 66.66m not 200m.

[@Cricketerkwje]

Yes same I am also thinking 😢

[@vanshlakhina2162]

guruji- for '5:3' speed ratio, the 2d concept is not validating. Between M2 and M3 (3rd meeting point) the distance is 'd' units; considering the track length is also 'd'. Please confirm, apke bolne par hi vishws hoga.

[@Rodha]

Ho raha validate

[@VoidThunder-v3n]

Will preparing for CAT will also helpful for preparing for bank exams

[@visuder7412]

No my son

[@business_walleh.]

sir this 2d concept is not valid when speed ratio is more than double, for 2nd meeting . chcek in question 400 and 1400 I am sure its answer should be 466.66

[@rajaswanikar3479]

exactly...

[@vatsalparikh3574]

Best Channel Ever

[@akashsahu2878]

POOR SOUND but quality content in terms of clearing concepts

[@khushikothari5095]

Sir kindly make the video with a little louder voice.

[@lucifergamingtv8849]

where can i find all these questions in text form i.e. pdf or word file?

[@pavithran5515]

How time is const here?? Anyone explain

[@akshatsinghOG]

sir diagram method, I can't understand

[@sahilarora2508]

With all due respect, the solution to last question isn't correct, whenever speed of two individuals is greater than 1:2 or approaching 1:2, we can't apply the distance ratio directly A is faster so A in his own round will always meet the slower one.. Except the round which takes place just after when they are at the same end.. Now when A takes 5 rounds, B takes 2 rounds.. Now they will be same end.. They must have met 5 times.. Now they will be together when faster takes 10 rounds.. Slower will take 4 rounds... They will meet 9 times.. Similarly again A again takes 10 rounds.. B takes 4 rounds.. So Now when A has taken 25 rounds.. they must have met 23 times.. and they are at same end.. now backtrack because we want previous meeting. . They will be at point Q now A must have travelled 2000 just before 23rd meeting.. So 800 from Q..

[@hirensoni7636]

Any method or video for such speed greater then 2:1 ?? Plz help here

[@hirensoni7636]

Thanks for this highlighting this mistake and concept

[@SamarthPandya]

any specific reason for that?

[@rahulgeorge7502]

how m2 to m3 is 2d?

[@BalaSD]

Thank you sir for the video

[@arnabsaha2021]

Awesome Sir

[@aarthisris5103]

Can some one explain me the last step.. Like How 1400* 12 = 16800 + 400 ? I don't understand this step..

[@vasipallianithakumari9664]

He meant.. 17200 he splitted into (1400×12) + 400.. in the video he kept 1400×12= 16800 plus the 400 total gives us the distance travelled by A

[@ishajain5828]

Thank you Sir

[@gaurchirag15]

Thank you sir😊 🎉

[@pranjalverma6241]

Are we only considering face to face meet in this concept...not the one in which one overtakes the other?

[@purubaranwal8149]

Extremely crucial question. Unfortunately sir hasn't mentioned it. The whole calculation is based the condition of face to face meeting. To fulfill the condition of covering 2D distance we will not count instances when one overtake other. This difference becomes important when one has relatively very low speed and the path is very large. Because in this scenario the faster one will overtake slower one multiple times even before the completion of first round for slower one.

[@vikasyadav7893]

This question is language based. Meeting always means face to face. It is not about overtaking but meeting

[@farhakhan5113]

best teacher

[@Shivam_General_Fitness]

Thanku sir

[@icecoldnobody3447]

at what speed do u guys watch his vids???

[@adityaprakash4497]

2x

[@icecoldnobody3447]

@@adityaprakash4497 cmon man.. U got a lot of topics to cover... Or maybe u r just revising 👀💀

[@adityaprakash4497]

@@icecoldnobody3447 completed my syllabus long ago. Now practicing from his videos and mocks. Arithmetic almost completed , will move to next topic soon. Now i am used to watch in 2x

[@AshwajeetKamble]

2.5x

[@icecoldnobody3447]

@@adityaprakash4497 oh yeahh>?? update me with your score/percentile after the CAT ...lets see...

[@aniketsurya4258]

thank u sir

[@hussainpunawala6113]

Is every even round he will be 1000 metre away from Q right?

[@priyasarathimohapatra299]

🙏

[@prateeksahu6197]

What if the ratio of speed comes to be 4:1? In that case not every subsequent meeting would cover 2d

[@aadityadabli]

in every case it will cover 2d , don't take tension

[@LostWizard12]

@@aadityadabli can you please explain how? The same question arose in my mind as he is travelling at diff speeds at some point B would overtake A before he ever reached to the end point so that would also be considered as a meeting? or B is stopping at an endpoint till A reaches at the endpoint?

[@vigneshps397]

No need to think in that way. After we found that A covers 17200m and find how many times he go and come from p to q if that answer is in even number the A will be in P or vice versa. You confused like that is 22nd meeting with B.

[@nikhilniki9333]

The guy with four times the speed just covers 4/5th of 2d. it will be 2d until we are considering face to face meets. What changes is how much they cover of that 2d respectively.

[@rohitbehera4524]

Same doubt....what about the non face 2 face meetings....in which for example A outruns B before B reaches the end....Shouldn't we consider those meetings???

[@shibamsinha3193]

Nothing nothing is audible.

[@Rodha]

plz use earphones. This problem is cleared in later videos

[@secondworld26]

Hi sir. I’m aware of the experience you have in teaching industry, but just a constructive feedback that please try to make your videos less boring.

[@shibamsinha3193]

This is false.

[@Rodha]

What

[@adityaprakash4497]

@@Rodha we are only considering face to face meeting. after some round when they are travelling in the same direction then the faster one would overtake the slower one so they wont cover 2d distance.

[@SamarthPandya]

@@adityaprakash4497 point...have you got ur ans?

[@adityaprakash4497]

@@SamarthPandya yeah long ago but don't remember now 😅

[@angelbeastcoc5893]

@@adityaprakash4497 you cleared cat bro..?

[@VinayKumar-vk3tq]

I had some doubts and spent quite some while figuring them out. The meetings points are only for crossover meetings, and not same directional overtakes. Valid meeting points are: A B | --------------------------------------------|M1|--------------------------------------| a==> & & b==> |------------------------------------------------------------------------------------|M2| A pseudo mathematical proof of why the formulae work: Assume the xth meeting point looks something like this. A B |-----------------------------x units------->|| | --------------------------------------------|M(x)|--------------------------------------| a==> & || | ---------------------------------------|M(x+1)|-----------------------------------------|M(x)|--------------------------------------| ||| a==> & & B ==> M(x) ==> M(x+1) moving leftwards. Distance travelled by A = (d-x) + (d-x) + (x-y) = 2d-x-y Total distance travelled by A and B = 2d. For sub-case P: This is a bit bizzare and we will encounter an overtake in this case. b goes from M(x) to M(x+1) and is moving leftwards at the time of meeting. Distance = x-y. a goes -- M(x) ==> B ==>M(x)==> Overtakes 'b' in between M(x) and M(x+1) ===> M(x+1) ===> A ===> M(x+1) [Meeting point] and is moving rightwards. Distance = d-x + d-x + x-y + y + y = 2d-x+y Total distance travelled by A and B = 2d. The speed of b is pretty low compared to a. (Sa : Sb = 10:1 types). Also, a overtaking b is not a valid meeting point since both are moving in the same direction (leftwards in this case) . Case 2: Assume meeting point M(x+1) is at the any of the corner (here it is corner B). a and b both moving rightwards and meeting at the corner (even though they are moving in the same direction, this is a valid meeting point). A B |-----------------------------x units------->|| | --------------------------------------------|M(x)|--------------------------------------|M(x+1)|

[@adityajoshi6422]

Thanks man.

[@rohitbehera4524]

So this will only work in cases where there are face 2 face meetings???

[@kshitijbalonie4361]

Thankyou sir