Integration || Most Likely to Come in IIT-JEE ADVANCE (2022) Last Question of Series.

[@sumitabhattacharjee2327]

Kya mast question hain! Integration ke sawaal mein integrate karna hi nahi pada! Balki differentiate karna pada!!💥👌

[@keshavgupta3698]

Whenever I see your video i discover a new thought process!! Amazed!!!😱😱

[@physicsbyabhijit.6740]

Do check my channel too...i have started with krotov solutions in thermal physics,..will upload many more soon.

[@rudrasharma2297]

Sir plz continue to bring these kind of questions for JEE 2023. Also Best of luck for JEE 2022 aspirants 😊.

[@RZMATHS]

Sure sure full series is coming chapterwise 👍

[@rudrasharma2297]

@@RZMATHS Thank you so much sir!

[@megamewtwoy9316]

@@rudrasharma2297 you must be happy cuz you are not going to give exam tommorow , so lucky🥲

[@SumitKumar-gx1kj]

@@megamewtwoy9316 xbxdxxxdxxddxdxddddddxzg

[@krishgarg2806]

@@megamewtwoy9316 bhai kal nahi de rahe iska matlb ye thodi ki kabhi nahi denge, humari bhi baari aayegi 😔😂

[@animeman4096]

Last month apke jitne video the sab dekhe the maine aur mujhe lagata hai Maths me uski wajhe mere 1-2 questions to pakka extra sahi honge jo iske bina nahi ho pata. Thankyou Sir

[@tarukhandelwal6471]

Thank you sir. Was waiting for your video from long time. 🙏

[@tinywrestler383]

Thanks a lot sir I have never been good is maths..never got much marks..in maths..but from last two months..I have gained a lot of interest in maths..now I don't know where I will make after the jee adv..but I will surely keep studying maths..as I am loving it now very much..🤗 u were among the few channels beocz of which I developed interest in maths..thanks a ton sir..btw I have secured enough score in mains to get IT or CSE branch in NIT kurukshetra(as it is in my state) looking forward for a decent performance in adv too..bless me sir that I can put my best effort

[@shourya3099]

Bhaiya I know ki aap puri series laa rahe ho but please koi update ya ek video daali please, main yaha roz ata hu aur chale jata hu please video daaliye kitna wait karaayenge

[@jaivalchauhan1593]

hey! Why did you stop uploading videos? Your content is very useful. please start uploading videos like you done before. We are waiting!!!

[@aasthaiitbombae5750]

Thank you so much sir You really helped a lot Following since I discovered you randomly on YT yet the best channel Rigorously followed this series of yours Will ROCK TOMORROW 🔥♥️

[@gauravahuja7803]

Got a rank of 8k,, thanks for everything 😊😊

[@RZMATHS]

Made my day ❤️❤️❤️ All the best gaurav Ahuja👏

[@jaishankarmishra7585]

Thanks Sir, seeking your blessing for JEE Advanced 🙏🙏

[@aryanahlawat17]

Thank you so much for everything,dear sir.

[@manasmishra2959]

thanks a lot sir for these type of amazing questions plz continue it for 2023 aspirants 🙏🙏

[@ShivamKumar-go3bb]

Thanku Sir 🙏🙏Pranaam Sir 🙏🙏

[@vijaykg7083]

Thank you sir. Proud to be your student😃😀..

[@harshkumargupta8831]

Thanks sir I will also try my best your channel helped me a lot. Thanks for your wishes.

[@wargodyuvraj1879]

Thank You sir… please give us your blessing so that we do well tomorrow❤️❤️❤️

[@user-dx2tb6zt1c]

Sir please bring similar video series for JEE 2023🙏

[@modulus2360]

Nice question sir.

[@wave7213]

thank you sir for helping till the last day !! thank you so much sir !!!

[@jatainkumar]

And that will be all (last time) thank you so much sir !!!

[@someshpatro2762]

Is there any channel like your that solves special physics questions instead of maths this a good channel

[@studyway9263]

Thank you sir ♡ just keep it up ♡

[@adityaagrawal5407]

thank u sir...becoz of u I got so confident in maths...I'll try my best to crack this exam.

[@sandeepadhikari2973]

Tomorrow will not define you but instead you will define tomorrow IIT aap ka intezar kar raha hai....

[@vivaniitb5723]

Thank you sir keep your blessings with me 🔥🔥🔥👍👍✨✨💚💚💚✌️✌️✌️

[@qwrrty6363]

Thanks sir♥️ you have helped me alot, I even made a separate notebook for all ur questions

[@nuranichandra2177]

Nice problem.

[@ramster111]

Really a nice problem

[@tanavposwal]

Make a video on AOD

[@harsh8377]

Sir pls upload the lectures you were about earlier in a comment i have been waiting for them for so long they would be perfect for a large audience who would like to make their theory part strong ,also the most likely series for 2023 would be even nicer Thanks sir for already uploading many questions to practice from.

[@suchetanachattopadhyay2698]

Sir, please bring more such questions and if possible chapterwise. Your channel is really a blessing sir.

[@rupalikumari8829]

Thank you 😊 Sir!

[@omroy8758]

Sir you are god of mathematics

[@potu6534]

Thank you very much sir 😊😊😊😊😊😊 I WILL GIVE MY BEST FOR MATHEMATICS SECTION...AS WELL AS OTHER SECTION TOO... I will give my BEST TO SELECT FOR COLLEGE THIS YEAR ONLY...

[@sahilrawat-we3de]

Yeh q kal hi aya allen mock test mein...

[@lavanyabhatnagar7412]

This question is also in Allen Module . Thank u for the solution sir !

[@somnath3986]

Sir pls upload more videos 🥺🥺

[@gdviperplayz4079]

Thankyou very much sir ❤️❤️

[@dhruvdengada3490]

thank you sir we would be always gratefull to you for you amazing problem for our jee adv 2022 :)

[@Fighter_Believer_Achiever]

Thank you very much sir 👏

[@srivabhi22]

Sir I solved it I a slightly different manner that firstly I found the integral assuming ax2+bx+1 and then I put the coefficient of log which I got after integration as 0 to make it a rational function and then got f'(0) as 3

[@akhileshnayak4297]

Thank you sir

[@aayushraj477]

This is best....❤️

[@juxtar]

Thanks a lot sir.

[@aayushraj477]

Please continue this series.....

[@ashut0ast23]

Thanks

[@Mbhargavkashyap]

Question looks simple but we people always neglect this rule 😅 thanks btw :)

[@yash7144]

Thank you so much sir. You have truly helped me spark an interest in mathematics and i will do my best in tomorrow's exam no matter what. I hope to see more and more videos from you in the future and to all my fellow aspirants, do your best tomorrow we'll make it!! Edit: made it into IITG :) you all can do it

[@atultiwari9528]

Thank you sir that was needed

[@Kunal78-g5m]

Sir please continue this series for JEE 2023.🙏🙏🙏🙏🙏🙏

[@DreamerAbhi-mj9cp]

I want 1000 of such questions before jee 2023😍😋

[@ayushmanbaruah5832]

Thank you sir!

[@anirbanchatterjee8145]

thank u sir

[@dharmendragupta7301]

Thank you sir ❤️❤️

[@cutegirlakanshabag2449]

Thanks sir.. 😊

[@adityasaha2627]

Thank you so much ❤️

[@mathslover2979]

Sir can you help in this question prove : LHS = integration from 0 to 1 : x^k (1-x)^n-k dx RHS = 1/(n+1)(nCk)

[@Indiananime19]

This question i had seen in my advance batch nice problem .

[@9896535455]

I find this very easy sir and i have done fully sammer bansal book also. But thank you sir

[@harsh8377]

my cousin brother is gonna give this adv and i am gonna give adv next i am so excited about his and mine result ...... sir still waiting for vector questions, as i have practiced enough calculus for now i want to try some good vector question .

[@mrinalkumar6895]

Thank u sir :)

[@rishi-io8io]

Thank you for this series sir

[@vineetkarya1393]

Thank u very much 😁

[@ZAMislive]

thanks a lot sir for ur wishes :)

[@spacecodm8480]

Best of luck seniors Jee 2024 aspirant this side

[@aamer236]

how'd it go?

[@ashneerfrasn9568]

Manoj Chauhan sir class illustration hai yeh to Malik ki jai ho :)

[@__cosmos__4388]

Thank u so much sir your this series help me a lot i will definitely crack advance2022 😼😼

[@GoluKumar-vx6sq]

More videos please

[@kaalmotivate]

Thanks sir

[@kaalmotivate]

Please sir hindi mein explain kiya kro 🙇

[@AdityaKumar-lp6qw]

You should teach generalised method or approach to attempt any questions ,better than solving individual questions,please🙏🙏

[@DepresionnIzzzNotReal]

Please give some strategy for 2024 aspirants

[@tanusingh4454]

Sir i am studying in uptu college jss academy of technical education with electrical branch and i took a partial drop from jss and now i got 51000 rank in jee mains and probably wouldn't get a good rank in jee advanced...also I'm female candidate and my category rank is 14k.

[@priyanshuacharya1016]

Sir why ln x couldn't be a rational function????

[@rishavkumargupta8875]

Sir aap kuch uplofe kyu nhi kar rahe itne din se ?

[@aayushraj477]

Sir please start for jee 2023 .....✨✨

[@Bewithsameer8635]

To be honest maza aaya is question mein

[@seven00007]

Which is the Best book for class 11th , jee advanced 2024 I'm also enrolled in a coaching

[@btslovers7165]

12th in 2021, appeared 1st time in jee advanced 22 , will be eligible for jee advanced 2023 ?????

[@ripadebsharma3268]

This channel is making me fall in love with mathematics, just in love with this channel. It's nothing but pure bliss

[@sskumar5434]

Bro konsi book se sawal late ho jra hme bhi bta do😅

[@Somu_z_]

Plz bring any specific series for all chapters for jee 2023 aspirants like Multi conceptual questions and Most repeated Conceptual questions from that specific chapter And Do cover all the Chapters plz...

[@AdityaKumar-lp6qw]

Ek bhi questions nhi bn rha jee dropper student hu

[@justblank3296]

Sir password bhul gye kya Aa bhi jao aur ache ache questions lekr

[@gaminglegend5535]

If in partial marking two options are correct and if we answer one correct how many marks can we get

[@sourabhhukkeri8286]

1

[@gaminglegend5535]

@@sourabhhukkeri8286 thank you

[@varadthube4851]

@@gaminglegend5535 but if marking scheme is like that of 2016 or 2008 then you will need to mark all correct answers to get Marks i.e no partial marking.... So be careful....

[@snehasishalder7973]

Why B+D =0 ?

[@aryann900]

f(x) is quadratic. At 3:09 , f(x)=B(x+1)³+Dx²(x+1)+ Ex² On simplifying, f(x)= Bx³+(....) + Dx³+(.....) +Ex² =(B+D)x³+.....+ Ex². But since f(x) is quadratic, RHS should also be quadratic=> B+D must me 0.

[@snehasishalder7973]

@@aryann900 Thank you .

[@ronin4923]

Sir I got the answer in another way, but i am not sure whether its correct or not. Assume f(x) = ax^2 + bx +c, since f(0) = 1, value of c=1. Now assume g(x) = the integral given, so g'(x) = f(x)/[x^2(x+1)^3] [applying lebinitz rule, although limits are not specified i think it may not be considered correct]. Hence f(x) = g'(x) * [x^2(x+1)^3]. Now for finding f'(x), differentiate both sides, rhs differentiate using product rule. On observation, we see that each term of rhs differentiation will give = 0 when we substitue x=0, except one term, which is when we differentiate the numerator term of (x+1)^3. Hence only relevant value of rhs differentiation becomes g'(x) * 3(x+1)^2 * [other remaining variables of x (they cancel and give 1)] Hence now putting x = 0, f'(0) = g'(0)* 3 * (0+1)^2 = 1* 3 * 1 = 3 [as g'(0) value is known from f(0)]

[@ishansinha1336]

lol

[@youtubestudies4173]

All the best my seniors I am 2023 aspirant!! And pls don't think of taking drop and increasing our competition 😂

[@varadpanaskar3414]

lmaoo

[@Aedxn]

lol the competition will be high in 2024 when our batch takes a drop xD

[@linxuser897]

For anyone that's looking for a physics channel with similar style, check out physics sir jee

[@sourabhhukkeri8286]

Physics SirJEE, INSP, Akash Goyal sir, Apna Physics...

[@jithinsj371]

Thank you sir. Was waiting for your video from long time. 🙏

[@mr.k9099]

Thanks

[@MartianAries_24]

Thank you sir

[@tarukhandelwal6471]

Thanks

[@nikkhilvlogs]

thank u sir

[@needanime8857]

Thank u sir