Sample JEE main question from India

[@Harrykesh630]

x = 2 (by observation) and that's how I did it in the actual exam

[@airplanedude3103]

Yeah root 3 squared is 3 and root 2 squared is 2. Add em' up and multiply with 2 and you'll get 10. I did the same thing lol

[@brendanward2991]

But you missed the other solution.

[@Harrykesh630]

@@brendanward2991 the options were 2,-2,both or none so as I was going to check 2 I thought about checking the other option and wollah -2 was also correct hence option 3 both was the right answer

[@OFSTAKASH]

​@@Harrykesh630Welp x=±2

[@pokemonerpokemoner3623]

this is an exam for class 12th students. competitive exam .. its first paper is mains which is easier than advance the second paper is jee advanced.. it is the second hardest paper in the world after the one in china. both for 12 th class students. both are for admission to colleges mains- NITs and IIITs adv- IITs

[@Dedicate25]

iisc as well :P

[@HrishikeshGiri]

Bhai Maine toh hag diya mains me 99.359 percentile aaya kisi bhi acche nit me nhi ho raha

[@epikherolol8189]

​@@HrishikeshGiriFlex karne ka tarika thoda casual hai💀

[@Setyourhandle_E]

​@@epikherolol8189Bhai sahi me kuch nahi hota 99.8 se neeche dhang ka meri khud 99.57 hai aur kuch zyada options nahi hain

[@Benzene42]

@@HrishikeshGiri bhai ye toh bohot apko toh nit mil hi tha hoga

[@rithvikarun7112]

Thank you for doing this question please do more I am also preparing for JEE mains and advanced

[@devcoolkol]

Hello sir thank you for explaining, This problem was from the Joint Entrance Examination(JEE) conducted by National Testing Agency of India(NTA), there are two exams JEE Mains for getting admission into National Institute of Technology (NITs) and JEE Advanced for getting admissions into Indian Institute of Technology(IITs), This exam is given after Highschool(yes we learn alot of things that are tought in higher University classes in highschool) to get into the best universities in India. Hence JEE exams are one of the toughest ones on the earth.

[@PrimeNewtons]

Now I see. Thanks for the information

[@joyrichard6971]

It is 2nd toughest. 1st is gao cao held in china

[@Phantom_Reaper_]

​@@joyrichard6971gaokao is easier question difficulty wise, its difficulty comes from the amount of people writing it. Even NEET is harder than JEE if you look at the numbers but JEE is definitely the toughest paper in terms of how hard the questions are for highschool students.

[@mb59621]

Stop yapping... You people are good for nothing actually just cramming stuff doesn't help . How many iitians do research on their own? You people go to iit then end up as cyber coolies for American companies.

[@the_real_nayak]

​@@PrimeNewtons try jee advance problems

[@Subham-Kun]

Sir JEE (Joint Entrance Examination) has 2 levels: Mains & Advanced. If a student passes in both of those, they can enter into a branch of the IITs (Indian Institute of Technology), which is the best chain of colleges in terms of Mathematics, Physics & Chemistry. Passing in those is very, very difficult and prestigious. Clearing those grants a student the 1st priority for any college they apply to. It is my own dream to crack both & enter IIT. Approximately 14 lakh (1.4 million) students participate in these examinations every year.

[@kamra702]

IITs are not the best colleges in term of mathematics, physics or chemistry. They are the best engineering colleges in India. IISER, IISc and ISI are better in terms of math, physics and chemistry.

[@Ephemeral_EuphoriaYT]

​@@kamra702That's exactly what I wanted to say. IITs are well known for CS degrees. Not PCM degrees.

[@epikherolol8189]

​@@Ephemeral_EuphoriaYTYet IIT b stands at top 200 in the world while MIT stands at 2nd

[@isaacbunsen5833]

The first step seems wrong sonce you need to to raise the denominator on the left hand side by x

[@toastdog214]

he corrects it later in the video

[@auztenz]

4:30

[@OffiicalComedyClips]

"Sonce"

[@neevhingrajia3822]

​@@OffiicalComedyClips2024 and you're still out here making fun of typos. Wow.

[@bruh____784]

C'mon that's a funny one ​@@neevhingrajia3822

[@marcgriselhubert3915]

x ---> a^x is strictly increasing on R when a>0, so f: x ---> ((sqrt(3) +sqrt(2)) + (sqrt(3) - sqrt(2)) is strictly increasing on R. A consequence is that if the equation f(x) = 10 has a solution, then this solution is unique. As x = 2 is evident solution, then it is the unique solution of the given problem for x>0. Now we can see that f verifies f-x) = f(x) for any real x, so there is also a negative solution which is -2.

[@pk2712]

The function can be written as f(x)=(square root(3)+square root(2))^x+(square root(3)+square root(2))^(--x) . This can be written as f(x) =2cosh(ax) ( this is hyperbolic cosine not cosine) where a =natural log of(square root(3)+square root(2)) . This function is strictly decreasing for x0 . f(x) is an even function , and its minimum value is 2 at x=0 . f(x) crosses the line y=10 at x=2 and x= --2 .

[@unpredictible1104]

Do JEE Advanced question s which are more though🎉

[@anshgoyal3734]

JEE(Joint Enterance Exam) is a competitive exam in India which is an entrance exam for admission in India’s most prestigious Engineering colleges (IITs & NITs). More than 12,00,000( 1.2 million) students ( of age between 17-20)(of class 12 and 12 pass out) give this exam. It is held in 2 stages JEE Mains (easier) and JEE Advanced (second toughest in the world) out of approx more than 1 million student only 250 thousand qualify JEE Mains and and are eligible to give JEE Advance. And in IIT there are only 15k seats. Students prepare to get into IITs for this exam. But everyone do not get it and there are still smart people left and they go into NITs(having approx 20k seats). Also IITs are one of the top most colleges in the world. The only reason they don’t have their name on top in the list where IVY colleges are at top is because they have set some different kind of standards which are against most Indian and other Asian institutes

[@renesperb]

One has to notice that the only chance to get an integer for the sum are the choices x= 2 or x= -2 . And indeed ,it works after some simplification. It is an interesting result.

[@Jam.shed9]

Sir, i am from India and it's called the Joint Entrance Exam. It's an all india exam given by students who want to pursue engineering courses.😊😊😊

[@runningonempty9980]

I completely forgot about such a neat trick like dividing one radical to another at the very beginning of the video, and tried to write both of them down as sums of binomial coefficients (a+b)^n......Which didn't pay off and I gave up shortly after

[@jensraab2902]

Same. He's right when he says in the beginning that it is (comparably) easy if you know what to do and hard (basically impossible) if you don't.

[@Mathsfighters0707]

Superb

[@hubertpruvost3271]

Do you need a démonstration ? x=2 IS ok x=-2 feel Bad... (a+b)^2+(a-b)^2 = 2a^2 + 2b^2 soit ici 2*3+2*2=10

[@Blindeditss]

I solved in 10 sec This is how I solved Like if you open a+b whole power x and a-b whole power X ALL EXTRA TERM LIKE 2ab or more like term cancel by its negetive term so as observing the pattern it's only remain a square +b square=10 hence by solving it you get 2 and -2 and -2 would be rejected

[@WhiteGandalfs]

Well... :D IF we INDEED assume that "something with squaring will help", we can as well substitute x against 2z and do the whole thing much more simple with the original expression. And immediately land at the same destination. (3+2 + something)^z + (3+2 - something)^z = 10 - from where it is jumping into your face that z must be 1. Or just outright try x = 2 in the first place.

[@sowonkun]

3^x + 2^x = 10 3² + 2⁰ = 10

[@norbertduchting6217]

The original term reminds me to Binets formula for the Fibonaaci sequence. So I constructed a recursion formula to this term and got the result.

[@the_real_nayak]

Hey , JEE is Joint Entrance Examination It has 2 papers JEE Mains for admission in National Institute of Technology JEE Advance for admission in Indian Institute of Technology JEE Mains questions are solvable meanwhile each question of JEE advanced will take up 1 hour of your video

[@gautamchoubey1275]

Please 🥺 solve jee advanced questions

[@maharorand507]

We can't use the quadric formula because it's not a ax2 + bx + c = 0 formula because t isn't squared but raised to the x power

[@epikherolol8189]

We let t=(radical)^x already... So it is in the form of at²+bt+c=0

[@dellagobaikal8205]

Your solution is very interesting. But you also may multiply both parts of the ecequation by ( v3+v2)^x or by (V3-V2)^x and then resolve ordinary second order equation.

[@anitajha3937]

Is right hand side rationalization correct?? As denominator has a power x but numerator has not

[@glorrin]

I wanted to generalise the formula if (a+b)^x+(a-b)^x=c and a^2-b^2 = 1 then (a-b)^x =( c +- sqrt(c^2-4))/2 noted that ( c - sqrt(c^2-4))/2 = 1/ (( c + sqrt(c^2-4))/2) so if r is a solution for x then -r is the 2nd solution By the way, "when you square this guy you gonna get one of these answer" I could be facetious and put 98 instead of 10 in the question and the result would have been 4 and -4 :)

[@glorrin]

just realised this realised this result is generalized to any equation in the form of a^x + {1/a) ^x = c

[@surendrakverma555]

Very good 👍

[@navoniljana2012]

Take JEE advance questions for solving

[@xyz9250]

y = (√2 + √3)^x then as √3 - √2 = (√3 - √2)(√3 + √2)/(√3 + √2) = 1/(√3 + √2) so 1/y = (√3 - √2)^x , y + 1/y = 10 .... solve y and get x.

[@janekch.3204]

Hey math friend❤

[@auztenz]

How can we find the complex answers to this?

[@ProactiveYellow]

Speaking generally, complex solutions come from the complex logarithm: for any number z=re^{iθ}, Log(z)=ln(r)+iθ where ln is the real valued natural number. Using these values, we have that x=±2+2kπi for any integer k

[@auztenz]

@@ProactiveYellow thanks

[@onepiece3mk323]

I did it using the inverse function of cosh(x)

[@raghavkumar4914]

Hey bro can u help me sum this 1/(4k+1) (4k+2) (4k+3)

[@mkmathstutorials6645]

Wow❤

[@dhruvm.s.1103]

Hello I am from India jee is entrance exam for admission in indian Institute of technology (government College) well it has 2 parts jee mains and jee advanced students who qualified in jee mains they can give jee advanced exam And I have sent you a question of jee advanced

[@PrimeNewtons]

Please send only short questions. Questions with long description or instructions do not do well on KZbin

[@dhruvm.s.1103]

@@PrimeNewtons no I have sent you on gmail

[@ShoaibKhan-vm3dz]

​​​@@PrimeNewtonswhere can i send you questions? Let me send you toughest or unsolvable question from JEE ADVANCE 😈

[@chintu4398]

@@ShoaibKhan-vm3dz bhai rehne de sir se nhi ho payega..😁sir ne bola short questions only

[@PrimeNewtons]

@@ShoaibKhan-vm3dz There is no guarantee that I can ow will solve the JEE question you send. So, please don't get your hopes up. Secondly, my work is to help people understand concepts they need, and not to flex my intellectual or mathematical muscle. Just a heads up.

[@griffinf8469]

I love that you include Bible verses at the end of your videos! But could you also include where the verse is in the Bible? For example, the verse at the end of this video is Psalm 23:2, but other people might not know that.

[@Bertin-q3y]

X=2

[@kbreslin7289]

So x=±2?

[@samarbaisoya608]

Where i can send you question

[@biddu2683]

Or if u can see that the reciprocal of root3+root2 is root3-root3 u will immediately get a disguised quadratic

[@panagiotisvlachos6114]

Tricky!

[@epikherolol8189]

Fun fact: We have to do this under 2 mins

[@robert8552]

You lost me toward the end re those products, quotients and squares of conjugates - I won't get admission and I wanted to be teacher like you!

[@AnuragGuptainspired]

From hit and trial, I came up with solution in just 2 secs. X =2 can be found out easily.

[@Kuchnahichannel1234]

Your comment indicates how stupid and immature you are in terms of mathematics. He is trying to solve it rigorously not's doing any "trading trick" of typical Indian coaching institutes....haha...

[@Benzene42]

Abb c**** jee mai bath ke trick lgayega

[@akshatsrivastava1684]

Your first step is wrong bro

[@epikherolol8189]

What is wrong?

[@hafizusamabhutta]

He didn't put the x as power in the denominator.

[@akshatsrivastava1684]

@Shining_Arayavart power X is missing in the denominator in RHS

[@akshatsrivastava1684]

@@hafizusamabhutta you are right bro👍

[@Everythingofphysics]

Again i did it in my head

[@yoyogameryt4557]

Hello sir myself ankit panchal, your big fan from Delhi, india And sir passing JEE exam is the main qualification required to get any engineering college/university in India

[@rare.videos]

Love from kerala

[@ARounDeRoP]

Finally sir you took one question from here I qualified this Jee mains exam and I need your blessings to qualify Jee advanced.❤

[@mathematical902]

vai mere ko vi padhade pass krwade jee me

[@kunal_420.]

​@@mathematical902 mere pass parle tu

[@chintu4398]

Ha mujhe bhi😶😶

[@mathematical902]

@@kunal_420. rank 247 he kyaa?

[@kunal_420.]

@@mathematical902 nhi bro.2 years baad me lane bala hun

[@farzadgolkar8413]

You made way too many mistakes in your solution to this problem bruh!

[@jafecc]

Here, JEE stands for 'Joint Entrance Examination'.

[@Careerhumresource]

I just a had thought What if we have infinite log or maybe even infinte product log how would we calculate it

[@epikherolol8189]

Like?

[@royorange9691]

For a simple and better method: 3½ + 2½ = 1/3½- 2½.. now it would be easy form a quadratic and it's done

[@knupug]

My mind couldn't accept that -2 was an answer. But after cross-multiplying the two fractions to get a common denominator, it worked because the common denominator simplified to 1. That helped me to understand the point you were making about conjugates.

[@Th3OneWhoWaits]

10:58 reciprocal of the positive version but it is negative?

[@CharashGanja]

Again i did it in my head but i get only one solution 😅

[@manojitmaity7893]

I think this is an easier problem...actually the questions are more harder.I hpoe you're gonna upload some difficult ones,please do needful.

[@epikherolol8189]

Yeah The probability questions💀

[@pankajlal1090]

😊

[@tmrapper6378]

Please do more jee mains questions,might be helpful for me

[@epikherolol8189]

Jee mains gaya bhai. Advanced hai Sunday ko😭

[@tmrapper6378]

Good luck

[@ryanwilson9555]

You made a major error when dividing everything by (√3+ √2)^x. You divided 10 by √3+ √2 and not (√3+ √2)^x.

[@srikarjv9072]

He corrected it in next step

[@robertpearce8394]

​@srikarjv9072 Yes, you are correct. PM often makes these little slips, which he quickly corrects. I see it as a way of making sure that I am understanding the explanation.

[@hafizusamabhutta]

He rationalised the denominator without x. How can be that correct?