Lumped System Analysis

  Рет қаралды 48,613

Sampurna Engineering

Sampurna Engineering

Күн бұрын

Пікірлер: 57
@johnmosheim
@johnmosheim 4 ай бұрын
the clearest step by step derivations that a regular chem eng understands thanks a ton
@SampurnaEngg
@SampurnaEngg 4 ай бұрын
Thank you 🙏 Please go through playlist of Heat Transfer subject - kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@psharma5507
@psharma5507 Ай бұрын
He made mistake brother 10:48
@matharshaik
@matharshaik Жыл бұрын
Good explanation sir thank you sir please continue more heat transfer topics ❤❤
@SampurnaEngg
@SampurnaEngg Жыл бұрын
Thank you 🙏 Please go through playlist of Heat Transfer subject - kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@kaushalsonagra5149
@kaushalsonagra5149 6 ай бұрын
Excellent concept explanation sir . Thanks
@SampurnaEngg
@SampurnaEngg 6 ай бұрын
Thank you 🙏 Please go through playlist of Heat Transfer subject - kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@JitendraPavan-se3fc
@JitendraPavan-se3fc 8 ай бұрын
Great explanation sir
@SampurnaEngg
@SampurnaEngg 6 ай бұрын
Thank you 🙏 Please go through playlist of Heat Transfer subject - kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@kirank7350
@kirank7350 2 жыл бұрын
derive the expression for temperature distribution in a body at time t during a Newtonian heating or cooling is given by T-Ta / Ti-T = e^-BiFo. What is answer for this sir ? Same ansr in your video ?? Please reply sir
@kirank7350
@kirank7350 2 жыл бұрын
Please reply sir. This question asked in engineering heat transfer exam . Yesterday
@annjeena4194
@annjeena4194 4 жыл бұрын
Previous video and this one is very helpful sir
@SampurnaEngg
@SampurnaEngg 4 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@timepass5045
@timepass5045 Жыл бұрын
Are you mechanical engineer
@SampurnaEngg
@SampurnaEngg Жыл бұрын
Yes
@-DanishShafi
@-DanishShafi Жыл бұрын
at 11:13 you have done a mistake, when we take a term on the other side of equal sign it becomes either positive or negative, and in case of multiplication it goes into divide. how had you taken the ln term to divide?
@SampurnaEngg
@SampurnaEngg Жыл бұрын
Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
@psharma5507
@psharma5507 Ай бұрын
10:48 you have made a mistake brother fix it
@SampurnaEngg
@SampurnaEngg Ай бұрын
@psharma5507 Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
@psharma5507
@psharma5507 Ай бұрын
lnA - lnB = ln (A/B) it's correct. But lnA -lnB =lnA /ln B it's incorrect That's the mistake you made brother.
@hanumantigewar9940
@hanumantigewar9940 28 күн бұрын
​@@psharma5507yes brother u r right. And sir I think u should also accept this.
@methodseven6556
@methodseven6556 3 жыл бұрын
very nice explain thank you sir
@SampurnaEngg
@SampurnaEngg 3 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@annjeena4194
@annjeena4194 4 жыл бұрын
Sir...can u plz put video on heat transfer in semi infinite and infinite solids...
@SampurnaEngg
@SampurnaEngg 4 жыл бұрын
Yes, I will do.
@sirftum8913
@sirftum8913 11 ай бұрын
super sir 😘😘😘
@SampurnaEngg
@SampurnaEngg 11 ай бұрын
Thank you 🙏 Please go through playlist of Heat Transfer subject - kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@TonyMontana-yp1lh
@TonyMontana-yp1lh 7 ай бұрын
nmt ln becomes minus not divide at 11:11
@shubhamkamble3187
@shubhamkamble3187 Жыл бұрын
Thank you sir
@SampurnaEngg
@SampurnaEngg Жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@natarajganesan5572
@natarajganesan5572 9 ай бұрын
It can T infinity fluid temperature
@512abrarazadbhat6
@512abrarazadbhat6 Жыл бұрын
Tomorrow is my paper 🥺🥺
@iampravikumarrao5919
@iampravikumarrao5919 11 ай бұрын
Tomorrow is mine 🤣
@Techneet123
@Techneet123 10 ай бұрын
now tomorrow is mine
@Rahulprajapati-rm9xj
@Rahulprajapati-rm9xj 10 ай бұрын
Also mine
@chandramanijaiswar7831
@chandramanijaiswar7831 6 ай бұрын
HMT
@VivekKumar-ui1ro
@VivekKumar-ui1ro 2 жыл бұрын
nice
@SampurnaEngg
@SampurnaEngg 2 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@bluzbucket7908
@bluzbucket7908 4 жыл бұрын
Thankyou sir.
@SyambabuWAOI
@SyambabuWAOI 4 жыл бұрын
super sir
@SampurnaEngg
@SampurnaEngg 4 жыл бұрын
Thank you 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@SyambabuWAOI
@SyambabuWAOI 4 жыл бұрын
Sir boundary layer concept
@mythoughts_sr
@mythoughts_sr 3 жыл бұрын
Tnq
@Chandankumar-qm4nb
@Chandankumar-qm4nb 2 жыл бұрын
Thank you sir 😌
@SampurnaEngg
@SampurnaEngg 2 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@pavanvutukuri7482
@pavanvutukuri7482 3 жыл бұрын
Where is previous video
@SampurnaEngg
@SampurnaEngg 3 жыл бұрын
Previous videio-👇👇 kzbin.info/www/bejne/e4qmoWCphtR1fLs
@SampurnaEngg
@SampurnaEngg 3 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
@Delta_07
@Delta_07 Жыл бұрын
At video 10:35 how is possible the term ln(ti - ta) is positive when it will go to LHS then it will negative then how you place it to denominator
@kales.s.9395
@kales.s.9395 Жыл бұрын
Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms. The step is correct.
@laughingedits2172
@laughingedits2172 2 жыл бұрын
You made mistake in log
@mafiamrkiller1347
@mafiamrkiller1347 4 жыл бұрын
You have done mistake in log it will be difference.
@SampurnaEngg
@SampurnaEngg 4 жыл бұрын
Dear, Complete derivation is correct. Log difference can be written as ratio. For example logX- logY can be written as log(X/Y). Pls check.
@raswin8058
@raswin8058 2 жыл бұрын
@@SampurnaEngg it can be written as log(X/Y) but not logX/logY as you have done in 10:45, kindly look into this!
@shadabpatel5813
@shadabpatel5813 Жыл бұрын
Seems like sir also bunked imp classes like us
@bluzbucket7908
@bluzbucket7908 4 жыл бұрын
Thankyou sir.
@SampurnaEngg
@SampurnaEngg 4 жыл бұрын
Thanks 🙏, Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇 Heat Transfer: kzbin.info/aero/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3
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