Calculating pH from [OH-] hydroxide Concentration - CLEAR & SIMPLE

[@veronicalau2438]

Please don't ever stop making videos I spent hours today trying to comprehend my teachers powerpoint and almost gave up on my exam tomorrow. I immediately understood EVERYTHING just from watching your video just one time. Thank you!!!!!

[@irenewonderful3537]

This video just washed away all the confusion in my head. Thank you 😊

[@Balla2201]

I should link this video to my chem teacher so they could learn a few things from you xD. Thanks for the great informative video.

[@erniebruney7903]

OMG after several weeks I understand this thing in a 9 minute video!! You are really really awesome

[@reneedzielak2446]

Thank you! Thank you! Thank you!!!!!!!!!!!!! Please keep doing this! You have explained this so well!

[@QuyKnight]

thank you very much :) I got it after just 9 minutes watching this.

[@ananyamahato7246]

Thnq so much, have been surfing online for a long time, I wished I found this video long back 😊

[@get_right1373]

I think at 4:47 sir. Think the power of 10 should be -13? I tried 10 to the power of -14 it gave me 13.5

[@elhamamander5038]

That also confused me.

[@d.o.n9249]

I found a short cut to this. Use the simple formula from the beginning of the video pH= -log [the given concentration] then solve. Then subtract your answer from 14 and you will only be about .1 or .2 off it i is a lot quicker, try it! :D

[@Annabelsong108]

i did that too but got a different answer then him.. so confused. did you get the same answer?

[@JacoFreezem]

resoof his way works I think he accidentally put -14 on the second step because I put -13 just to see and got the same thing he got.

[@tabassumjan3271]

Thank you soo much it is great 👍 explanation easy to understand first time

[@varnaite]

Absolutely genius! KZbin videos are the best learning tools. Thanks for this teaching video, finally, I've got this yaaay:-))

[@疯狂鸭嘴兽]

Thanks...This vid helped a lot :D

[@johnthefisherman8226]

Chemistry in plain English! Awesome Dude!!

[@sciencepost]

john venrick LOL. Thanks bro!

[@bahjatmahmood94]

You Are The Man, Great Job

[@laurenkellyg]

Thankyou! Perfectly explained

[@sciencepost]

laurenkellyg Wow, that is a big compliment. I appreciate the feedback. This is a challenging topic, and I am glad it clicked. Please keep on trying and learning!

[@vivekrajrider9173]

Gaandmebarafdaldem

[@nadinelucas7788]

thank you for great explanation.

[@1P2S3D4R]

You are very cool, thanks

[@valeriacruz7143]

On the 3rd example I do not know why I can't get the concentration correct. Not doing it right on my calculator?

[@mrznetra]

I think you meant to put a -13 in the last step because then you come out with 12.5. -14 gives you 13.5

[@sherwingomez7675]

Thnx dude..... it was super helpful!!!🔥🔥

[@nathanjones9619]

i tried two different calculators and still ended up with 2.86x10^20 after dividing.......so confused

[@Sydney432hz]

nathan jones same here and i HAD 12DIFFERENT PROBLEMS ON THE LAST TEST BIG EXPONENT # KEPT SHOWING UP AS THE AWER'!!!

[@sweetgina399]

So did I

[@funvidsincorporated]

Nice video. Next time, could you use sig. figs?

[@derekanderson7644]

awesome video

[@sciencepost]

Derek Anderson So cool to hear!

[@tusharthakur3800]

+sciencepost how did you get [3.33x10^-14]

[@shahab8052]

Thanks this helped so much! :D

[@leelamishra3385]

What is the value of log?

"log" has no value. Log is short for logarithm (of the base 10 in this case). In simple it works as follows: log (10^x) = x e.g. log (1000) = log (10^3) = 3 ^ is mark for upper index

[@lanamido]

Hello,in the first problem i kept trying to calculate the 2 times 5.7 X 10 to the -7th a couple of times and i kept coming up with 1.14 x 10 to the -6th. I put it in like this: (5.7 X shift log-7(2)) =1.14 X 10 to the -6th. I cant see how you got 1.14 X 10 to the -9th,can you plz explain.Thanks!

[@sunnysohalsunny9437]

How is it possible that a base have acid character, third one has ph value 5.95

[@Juju.1919]

THANK YOU!

So the 10^-9M Mg(OH)2 solution is in fact *acidic*???

[@MrDerrickp82]

thank you so much

[@MultiUSAPatriot]

Thanks boss!

[@sciencepost]

You are welcome Bro! Keep up the good work!

If you want to know, how to properly and *correctly* calculate the last example with dilution of base, go to this link: www.researchgate dot net/post/What_is_the_pH_of_very_diluted_for_example_hydroxide#view=5dfc383f2ba3a1661305ce8c Because obviously base cannot have pH lower than 7.

[@egojeniffer8]

you rock!

[@johannalipio4971]

I’m confused with exponents

[@ramzilodge7643]

Example 3 is conceptually incorrect. With a concentration that low of a base how did you end up with a pH of below 7. Makes no sense. There is a another calculation that must be used when concentration is that small. Educate yourself.

[@ericksonhangula8085]

Thats correct. looking at it , mg(oh)2 is a strong and should have a ph greater than 7. can one help me how to calculate that

to see how to calculate the last example go to www.researchgate.net/post/What_is_the_pH_of_very_diluted_for_example_hydroxide

@@ericksonhangula8085 if you want to see how to calculate the last example, go here: www.researchgate.net/post/What_is_the_pH_of_very_diluted_for_example_hydroxide

[@sneill2301]

hey dude

[@cortlove98]

this is literally basic algebra

[@prosperace]

Mistake!!!!!!

[@maxlee4949]

Great video