Signal Flow Graphs (Solved Problem 2)

Control Systems: Signal Flow Graphs (Solved Problem 2)
Topics discussed:
1. Solved GATE Problem (EC 2003, IIT Madras) based on the calculation of overall gain of a Signal Flow Graph by using Mason’s Gain Rule.
2. Homework problems based on the calculation of overall gain of a Signal Flow Graph by using Mason’s Gain Rule.
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#ControlSystemByNeso #ControlSystems #MasonsGainFormula #SignalFlowGraphs

[@sahanasingh8580]

Your channel is serving a lot of purpose for students pls continue uploading lecture videos!

[@siddharth7261]

1. 100 2. Option b

[@theone7550]

I had a wrong concept about these, you just helped me to correct it.

[@halaimam4147]

2. Option (b)

[@gunjankumar240]

1.Ans 1800/18=100 2.Ans B.

[@kirtikansal7388]

a) 1800/18= 100 b) 1/s

[@Rising_sun_408]

2Q. Option B.

[@helenamartinsmariano1591]

I think that when calculating the associated path factor, the 2 remaining isolated loop touch, because they have one node in common

[@PunmasterSTP]

Solved problem 2? More like "These videos are great, through and through!" Thanks again for making and sharing such amazing content.

[@ss-tp6mz]

For question 1.) P1=400; DEL1=2 P2=200; DEL2=5 DEL=18

[@chandruloki6900]

right , so answer will (800+1000)/18=100

[@abhishekrai9607]

how to get dell1 and dell 2 pls tell

[@ano26g]

how did you get del=18? i got it as 14

[@ss-tp6mz]

@@abhishekrai9607 I solved it 2 years ago, now I don't remember sorry.

[@ano26g]

@@ss-tp6mz oh its okay

[@3dgiftz]

Informative video

[@mohdfahad4343]

thanks a lot its really been a big help, keep doing...

[@Azakadune]

“It is equal to 2 right?” “No” Cheeky bugger… my heart dropped lol.

[@Azakadune]

Question 2? It’s 1/s. Idk why people saying it’s B, but I know for a fact all (3) loops touch. They share the inner two nodes.

[@DiyExperimento1]

You know the right answer then tell me bro

[@bethel5414]

There’s only two loops in total, not three

[@Abrar_Jamil_4323]

​@@bethel5414 isn't there three loops? I think we all are missing that? R(s) >node 1>follow the top path>go left using bottom path>go right > go left using bottom path> node 1 So isn't that a loop? Yoy

[@snehashrivastav1630]

Homework Answers: Ans 1: 100 Ans 2: Option B

[@kanpurunplugged9970]

More please

[@rraghavendra]

1. 100 2. 1/S

[@power4436]

Sir , are you uploading videos for all the syllabus

[@ANIMALSBIRDSWORLD.9357]

Really I waiting for this chaneel updated ...when it's come then I will be open must it to see

[@LIVE_LIVELY]

Homework Problems Answers 1) 100 2) Option B

[@debolinasardar1438]

For 2nd qs op B but , the value of ∆={(2^4+2.s^2+1)/s^4}, is it ?

[@Rising_sun_408]

1Q. C/R=100

[@sanskarkumar6484]

thanks Sir🙏❤

[@arintiwari3150]

for 1, ans=100 for 2,ans=b option

[@chetan8577]

Plz make a course on DSA using C++

[@arifmp3284]

4:10 there is one more loop right? a-b-c-d-b-a

[@chandangupta4226]

that's what I too think

[@tarunjangam7159]

@@chandangupta4226 b is touching twice

[@simomohamed4191]

that is not a valid route because b appears 2 times

[@3dgiftz]

I like EEE but because of this corona situation I wasn't able to join college😔

[@PunmasterSTP]

I am very sorry to hear that, and I hope that you can pursue your studies soon!

[@saipranathi7206]

1. 900/7 2.B

[@venkatalokesh1117]

I think 1st might be wrong

[@narendrap7437]

Can you tell how it came 1st question answer

[@sahilyadav5662]

both are wrong ....i think

[@nimitgarg2531]

@@venkatalokesh1117 1 st ka answer 100 aa rha h

[@mk.17-t9y]

100 and 1/S

[@eee_29_rahul49]

For question 2 ) p1=1/S^3 ;p2=1/s Del1=1 ; del2=1 del=s^2+2 / s2 Since there is one " two non touching loops" L1 L2

[@the_math_tutor]

But the answer is not there

[@cgopalreddychitimi6189]

thereis no non touching loop ans is 1/s

[@sameermeshram3062]

Upload control system more videos

[@dmaxvel]

What if we weren't given the graph, just equations

[@kirankumar3768]

There are total 5 individual loops right

[@PunmasterSTP]

How so?

[@aneetakushwaha9058]

Ans 1: 1800/11 Ans 2: (s^2+1)/s(s^2+2) Is it right?

[@sahilyadav5662]

nope both the answers are wrong

[@ginnasomeshwar5068]

@@sahilyadav5662 🤣🤣

[@harshsiddhapura487]

@@sahilyadav5662 400/9 is the answer of first one. Is that correct ?

[@prithamaitha4670]

2nd answer option 1

[@khookengsuen1428]

6:48 why isn't L1 and L3 two non-touching loops?

[@ginnasomeshwar5068]

Because we removed forward path so the 1 node of L1 was removed So we didn't take that loop

[@FredsFolly]

I think non-touching refers to not touching the forward path

[@anilmeena7349]

non touching means in any condition they can't share any common node.

[@tahamehraj2368]

Plzz upload videos more quickly.

[@nuwanatthanayake]

Great..

[@percy_asaga]

Isn’t there supposed to be a 4th loop with a loop gain of [1/s*6*1/s*(-4)*(-2)]?

[@aaqibrashidle6655]

Yes

[@132saqibmaqbool5]

Can anyone please solve the ∆ in prob 2

[@kalyanigawande4061]

There is fourth loop may be possible.

[@swastikdey7498]

Yes, shouldn't there be a fourth loop ? The gain of which would be (1/s) × (1/s) × -2 × -8 = 16/s^2 ?

[@chandangupta4226]

​@@swastikdey7498there will be a fourth loop but you wrote the wrong gain it would maybe (1/s)*6*(1/s)*(-4)*(-2)

[@sibanshmohapatra1406]

7.15 doubt

[@sameermeshram3062]

Ques. 2) gate 2006, IIT Kharagpur Ans:- option B = (S2 + 1)/S(S2 + 2)

[@nandyalanaveenreddy7598]

In second home work question can we take a-d-b-c-a as one loop (consider a,b,c,d as nodes from starting)

[@sameermeshram3062]

@@nandyalanaveenreddy7598 Individual loop :- L1= a - b - c -a L2= b - c - d - b Then, Compared to both the loops there is b and c are common node ..so hence it is Touching loop and here not any Non - Touching loop present.

[@nandyalanaveenreddy7598]

@@sameermeshram3062 I was asking can we take L3 as a-d-b-c-a as it starts and end at "a" if we can't take it as L3 I want to know reason

[@sameermeshram3062]

@@nandyalanaveenreddy7598 yes, option (a) is correct....L3= a - d - b - c - a also consider... thanks bro

[@nandyalanaveenreddy7598]

@@sameermeshram3062 yeah bro Even I got option A ,do u have any idea when will they provide remaining lectures

[@alinedelacruz8957]

Answer to Question 1 : P1 = 200 Delta 1 = 2 P2 = 400 Delta 2 = 5 Delta = 18 200x2+ 400x5/18 = 2400/18 C(s)/R(s) = 133.33

[@arintiwari3150]

u might have made some mistake

[@sudhanshupatil7439]

p1 is 400 and p2 is 200