Signals & Systems - Time Variant & Time Invariant

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[@kcmichaelm]

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[@nivetharavichandran8292]

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[@mustafanaqvi7420]

Mam actually i am little bit confused, how can you relate the equations like you are saying input in not equal to output so it time irrvarient or time varient,

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✨Nicely explain 🙏

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[@Yaduvanshi-x4s]

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[@Biggboss02-e4w]

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[@gururajchavan1695]

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[@AhsanAliUet]

how can we check time invariancy of y[n] = x[n-5] + x[5-n], please explain by arguing, it will be a favor!! Thanks

[@hyperv4758]

it is a time invariant func because the y(n,k) == y(n-k) to check: y(n,k) = T[x(n-k)] = x(n-k-5) + x(5-n+k) : (1) y(n-k) = x(n-k-5) + x(5-n+k) : (2) (1) and (2) are equal

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[@anupamanand3143]

nice mam

[@Lauren-cv6ky]

Thank you!!!!!!

[@nikhil_vemu]

How to do it for y(n)=x(2n) ??

[@Arif_0899]

Y(n,k)=x(2n-2k) Y(n-k)=x(2n-2k) Since y(n,k) = y(n-k),time invariant

[@tharmeekansivarasan5642]

@@Arif_0899 y=x(2n) is time varient.system

[@tharmeekansivarasan5642]

Delay the signal after processing. y(t) = x(2t) Replace t by (t-k). Y = y(t-k) = x(2(t-k)) = x(2t-2k) Delay the signal before processing. Delay the input sample alone. y(t) = x(2t-k) Y' = x(2t-k) Clearly Y ≠ Y' Thus, this is a time-variant system.

[@annollasneha8740]

Super awesome

[@spideymoin8146]

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[@changminpark3173]

thanks a lot

[@donthuladivya0206]

Show that the following systems are nonlinear and time invariant. y(n) - x(n)y(n-1) = x(n)

[@luisafernandamartinezmench823]

graciassss

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Anyonr from SSM college

[@SuperRachit2009]

This is mathmatics... please try to explain the conceptually

[@GyanVarsha94]

y(t) = x(t) + u(t+1) is TV or TIV

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TVS

[@Chaitanya178]

Super super

[@mohammedhamza2060]

Madam the video is not clear.

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Nice explanation

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Super