Discrete Time Convolution Example

[@lurrehsinigang2073]

One of the best intuitive explanations of convolution so far. Thank you!

[@iain_explains]

Glad it was helpful!

[@itdepends5906]

super helpful. Even if I had to think a little to make sense of the 'breaking up the components and adding them up', it helped me a lot when I got it how algebraically we're doing the same thing as adding up the figures

[@iain_explains]

Great. I'm glad it helped. Perhaps this video may provide more intuition: "How to Understand Convolution" kzbin.info/www/bejne/rmSplZdsi8R7pc0

[@tanatswamandudzo3209]

the last part explained the first part better. thanks for this

[@peka2478]

You got my like about 2 seconds in, for your langauge / pronunciation alone; At some point (I passed long long ago) hearing Indian English becomes tiring, but hearing actual British English (or what sounds to me like that)...

[@LL-ue3ek]

Although some algorithms in the software does the calculation in a straight forward way, the decomposition of x[n] into a sum of its discrete components is a great intuition, which clarifies this concept so much. Algorithms can also be developed based on this method, I think it may not be any slower than the former method, if not faster. Thank you so much for sharing it!

[@iain_explains]

I'm glad you found the video interesting and useful.

[@alphabogeyman7462]

@@iain_explains The steps we were taught by my professor was to first convert x(n) to x(k) and do the same for h(n). Then,we do a time reversal on either x(k) or h(k),afterward, we perform a left hand shift until we get to the zero values. We then perform a right hand shift until we get continuous zero values. This sequence produced gives the convolution sum.

[@dannyruffolo1474]

You helped me figure out graphing convolution 15 mins before my exam! Thank you!

[@iain_explains]

I'm glad you found it useful. And I hope your exam went well.

[@ethanmullen4287]

It's so much easier to understand convolution in the discrete case imo. I think it should be taught discretely first, then continuously - especially if you start with the example of a system's unit impulse response :)

[@iain_explains]

That's interesting. Indeed, I think it's often easier to think in terms of (discrete) summations rather than (continuous) integrals, but on the other hand, the "natural" response of a real (continuous) system can be more motivating (easier to visualise), compared to the "response" of a (non-natural-world) digital system.

[@cinema187]

Watched ~5 vids and this is the best approach

[@iain_explains]

I'm so glad you think so. Thanks for letting me know.

[@mnada72]

This is a great help to understand convolution, thank you.

[@iain_explains]

Glad it was helpful!

[@fikunmiajayi]

I'm embarrassed I didn't realize convolution was a sum till you spelt it out. I see the capital Sigma but somehow it didn't register. Until you. Great work Professor I'm really grateful

[@iain_explains]

I'm so glad I was able to help clear that up for you. Thanks for your comment. It's always nice to hear from people who are finding the videos helpful.

[@alaasefa1118]

wonderful and so simple. you are a remarkable doctor😍

[@iain_explains]

I'm so glad you like the video.

[@fisnikzogaj1442]

Best video on convolution, Thanks a lot !

[@iain_explains]

Glad it was helpful!

[@highwayflammable4212]

thank you so much now i can understand how convolution work ,From Algeria

[@iain_explains]

I'm so glad it was helpful.

[@tuongnguyen9391]

The result of discrete convolution between two signal looks like the coefficient obtain by multiplying two polynomials together. what would be an appropriate to explain this issue ?

[@narayanadhasojuraghavender1478]

Great one.

[@NestorESanchezArriaga]

I continued the maths.... it makes sense 🥺

[@haiannguyen903]

thank you a lots❤

[@iain_explains]

I'm glad you found it helpful!

[@nithinbabu4962]

One confusion here: In the continuous time, we flip h(\tau), shift it by t , multiply with x(\tau), and then find the area to determine different values of y(t). In discrete time, it looks like we shift h(k) by n and then multiply with x(k), then add to get y(n). So, this flipping operation is not done in discrete time. Is my understanding correct?

[@iain_explains]

Many people (basically everyone) talks about "flipping" and "shifting", but I never use these terms. I believe these terms are the cause of most students finding convolution difficult. In these videos on continuous time convolution I use the same approach each time (and it's the same approach as for the discrete time case): "Convolution of Square with Rectangle" kzbin.info/www/bejne/rofFgIGvjqqcprc and "Convolution Square with Exponential" kzbin.info/www/bejne/oqSrnIp8d9JmqdE

[@danielmichielin4342]

Great explanation 👍🏻👍🏻👍🏻

[@iain_explains]

Glad you liked it!

[@mariojariomario3277]

really good and understandable explanation!

[@iain_explains]

Glad it was helpful!

[@equalizer9923]

you are a lifesaver, thank you!

[@iain_explains]

Glad it helped!

[@bugrahankutlu1450]

I better to share this video to my professor to show him how to teach... thank you

[@iain_explains]

I'm glad you found it useful!

[@commissargamer]

Finally, I think I am able to crack convolution quiz going to be happen tomorrow...

[@iain_explains]

That's great to hear. Good luck with your quiz!

[@warrennordyke7718]

Hi Iain, I have been working on a PAM-3 differential code that I have not been able to find any similar code. I would like someone who has worked on Digital Comms research to analyze my ideas. Can I send you a small word document that shows the encoding? I am a senior design engineer who has been working for many years.

[@iain_explains]

Sure, I'm happy to take a look. Feel free to email me.

[@dbharathi2003]

Very good. Thank you so much. But what does convolution say. Any inference would be a value add

[@iain_explains]

I''m not sure what you mean exactly. Perhaps this video will help: "How to Understand Convolution" kzbin.info/www/bejne/rmSplZdsi8R7pc0

[@aitorurciuolo2046]

great explanation

[@iain_explains]

Thanks. Glad you liked it.

[@safeegull22]

Sir really, understand, thanks

[@iain_explains]

Glad to hear that

[@fareehaafzal7958]

That's a very Good method..I really Like It..Thanks:)

[@iain_explains]

Glad you like it!

[@akanyerboluly7796]

Why at the beginnin you put n=-1 at y[n] you get x[0]?

[@anastasiamartinez5862]

Thank you sooooooo much!!!!

[@iain_explains]

I'm glad it was helpful.

[@kalvinsackey1804]

helpful but what if the response is negative ? will this still apply ?

[@iain_explains]

Yes.

[@sh4n940]

Thank you, hi from Bolivia :D

[@iain_explains]

Welcome!

[@Zarar00]

Thankyou : )

[@abdulazizhassan5473]

❤

[@poiuwnwang7109]

super!

[@TeknoTeen0]

wow amazing :) Türkiyeden Selamlar

[@iain_explains]

Glad you liked it.

[@moviemadness-omarelderiny5885]

WHY IS K ZERO AND ONE- HOW DO I DETERMINE THE VALUE I USE FOR K

[@iain_explains]

This video might help: "Discrete Time System Output Example" kzbin.info/www/bejne/i56YZ2d8qdZoqZI

[@peterdisanto5880]

dr andrews if youre seeing this please dont make quiz 3 hard

[@wajdy2620]

but what if x[n] is infinite, x[n]=u[n]

[@iain_explains]

This is a discrete-time example. The values cannot be infinite. Perhaps you mean "infinite energy"? But that's OK, just use the same technique.