Solution Midpoints of a Quadrilateral forms Parallelogram Q24

[@ebstar511]

saved me for my exam tomorrow good sir, thank you

[@sansamman4619]

i was saved! my exam is a year and 3 months from now, thank you very much

[@naomibernard155]

I STILL HAVE CPT WORTH 30% OF MY GRADE THO

[@georgemorge6776]

thanks

[@alwysrite]

nicely explained

[@cja.chris.1996]

PS/PD = PQ/PA = 2/1. You can’t say that if two sides from two triangles are proportional, then they are similar. You pointed only two sides there. It is not sufficient to say that triangle SPQ and triangle DPA is similar. We do not have SS Similarity. You forgot to mention at angle DPA and angle SPQ are congruent by reflexivity. Then by SAS similarity theorem, the two mentioned triangles are congruent.

[@dipeshgiri4211]

Thanks

[@ksarakan1290]

Thank u my exam is tomorrow kind of I will really cheat half of it

[@basharakeel3944]

Very nice

[@MathematicsTutor]

Thanks for appreciation

[@chetana_pd]

Sir..how to solve this same question using vectors. Please explain me as soon as possible.

[@steveworldwar2]

He did it with vectors in another video. Look at his channel.

[@masterspark9880]

Let the 4 points of a quadrilateral be the origin, ai + bj, ci + dj, and ei + fj, with ei + fj being opposite the origin. Draw a diagram of this. Then the midpoints are (a/2)i + (b/2)j, (c/2)i + (d/2)j, (e + a)/2 i + (f + b)/2 j, and (e + c)/2 i + (d + f)/2 j. We’ll name these A, B, C and D respectively. For ABCD to be a parallelogram, the vector DC must equal BA, and the vector AC must equal BD vector DC = C - D = (e + a)/2 i + (f + b)/2 j - (e + c)/2 i + (d + f)/2 j = (a - c)/2 i + (b - d)/2 j BA = A - B = (a - c)/2 i + (b - d)/2 j, so they’re equal AC = C - A = (e/2)i + (f/2)j BD = D - B = (e/2)i + (f/2)j Therefore, ABCD is a parallelogram

[@pokhrelyadav]

Sir, Please can you tell me how DA and SQ are Parallel ? Sir please reply me as fast as you can The triangles are only similar

[@MathematicsTutor]

Similar triangle will have same ratio of all the sides as explained. Similar triangles will have same angles. If the corresponding angles are equal then the lines are parallel, Hope that helps

[@jyotibhandari3933]

thank u so much

[@manikantsingh990]

nownsence

[@aneeshiramani977]

You are the best the earth

[@user-yh9re4ny9y]

is it just me or am I the only ten year old girl learning this

[@jacobguerreso675]

Possibly