Solved Problems for ISOTHERMAL Process | Discussion of Formulas | Step by Step Solution

[@zechae19]

Thank you for the additional knowledge sir. Nakadagdag sa info sa gagawin naming project sa physics.

[@roshniepayas3236]

Thank you po nasagutan ko yung quiz namen ..iniba lang ni sir ng given kaya medyo napacompute parin 😊💓

[@keithrill]

Thank you so much sir❤️

[@gasmenajosuerpalfa.8020]

sir thank you so much

[@Merti758]

The units of entropy are KJ/K, and not KJ/min K. Why was that the answer if the units are wrong?

[@jcamores5099]

Hello Merti. ∆S = Q/T. In the problem, Heat is also the Non-flow Work, and it was a rate, KJ/min. Hence, when Q/T, the unit was KJ/min•K. It really depends on the problem.

[@markoppus9498]

isentropic and polytropic process po 🥺

[@josephboyolmedo5150]

Sir paki solve din po yung number 11 thank you The work required to compress a gas reversibly according to pV = C i s 67,790 J i f there i s no flow. Determine ΔU and Q i f the gas i s (a) air, (b) methane. For the methane, k = 1.321, R = 518.45 J/kg K, c v = 1.6187, c p = 2.1377 kJ/kg K