Solving a 'Stanford' University entrance exam | c=?

[@alescepe8556]

0 = C^3 - 3C 0 = C(C^2 - 3) 0 = C(C - sqroot 3)(C + sqroot 3) C1 = 0 C2 = + sqroot 3 C3 = - sqroot 3

[@AsadInternationalAcademy]

amazing, thanks

[@AsadInternationalAcademy]

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[@AlbertoGrigolini]

1) C = 0; 2) C = √3; 3) C = - √3. Am I right (or wrong)?

[@AsadInternationalAcademy]

right

[@AsadInternationalAcademy]

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[@boubekerouatouat]

3c=c^3 Log3c=logc^3 Log3 +logc=3logc Log3=2logc e^log3=e^2logc e^log3=(e^logc)^2 3=c^2 lCl=√3 C=√3 ; C=-√3

[@Vadimale]

0 as well

[@AsadInternationalAcademy]

great

[@AsadInternationalAcademy]

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[@AsadInternationalAcademy]

yes

[@AsadInternationalAcademy]

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[@themieljadida4459]

You're very clever !

[@AsadInternationalAcademy]

thanks

[@AsadInternationalAcademy]

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[@davidbrown8763]

I think that this is too easy to be a Stanford University entrance exam question.

[@waltertonelli2174]

I was thinking the same

[@benitoherrero3895]

Even a 7 years old kid could make it

[@AsadInternationalAcademy]

yes, it's easy for exams

[@AsadInternationalAcademy]

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[@AsadInternationalAcademy]

ok

[@HenryBriskin]

3C = C^3 C^2 = 3 C = √3

[@AsadInternationalAcademy]

beautiful

[@AsadInternationalAcademy]

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[@torreyvent9429]

How about zero.

[@AsadInternationalAcademy]

0+0+0=0.0.0

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[@dardoburgos3179]

C= 0.

[@AsadInternationalAcademy]

good

[@AsadInternationalAcademy]

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[@STLesanglier]

3 C = C x C x C 3 = C x C x C / C 3 = C x C C^2 = 3 C = √3 ou -√3

[@AsadInternationalAcademy]

nice

[@AsadInternationalAcademy]

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