Solving An Equation Everyone Thought Was Impossible | Bending The Rules of Mathematics

[@RyanLewis-Johnson-wq6xs]

x= -(7 log(5))/log(5/2) x=-(12+Log[2.5,1.31072])

[@RyanLewis-Johnson-wq6xs]

6^(Log[6,2]+1)=12 x=Log[6,2]+1

[@RyanLewis-Johnson-wq6xs]

2^-(12+Log[25/10,1.31072])=5^(-(12+Log[25/10,1.31072])+7)

[@RyanLewis-Johnson-wq6xs]

9^1.5=27 x=3/2=1.5=1 1/2

[@RyanLewis-Johnson-wq6xs]

(3^2)^1.5=27

[@RyanLewis-Johnson-wq6xs]

9=3^2

[@RyanLewis-Johnson-wq6xs]

2^x=0 x=∅ final answer

[@RyanLewis-Johnson-wq6xs]

2 3=27=3^3

[@RyanLewis-Johnson-wq6xs]

9^0=1 9^1=9 9^2=81

[@titoucarotte5238]

Bro's really bending the rules of maths 😭😭😭

[@titoucarotte5238]

4:40 isn't it if a^b=a^c then b=c The base must be the same

[@titoucarotte5238]

13:28 that's just not true, you can't split a fraction that way, only when you're splitting the numerator with the same denominator For example 2/(3-5)=2/-2=-1 (2/3)-(2/5)=4/15≠-1