Solving an exponential equation with different bases

[@bryanbain3509]

Important to note, we are able to divide both sides by 7^x because 7^x will never equal zero since the range of 7^x is all real numbers greater than 0.

[@AMMARZAIMBINAMANFUADMoe-y1z]

I also thought off using logarithms before solving the problem

[@pizzaytcomputer]

It works too We will get ln(3^x)=ln(7^(x+2))=>xln(3)=(x+2)ln(7)=>xln(3)=xln(7)+2ln(7)=>xln(3)-xln(7)=2ln(7)=>x(ln(3)-ln7))=2ln(7)=>x=2ln(7)/(ln(3)-ln(7)) Same solution

[@patriciaceli1536]

Thank you!! ❤

[@simpleeducationaltricks1582]

Given : 3^x =7^(x+2) Solve: taking log both side, we get log 3^x =log 7^(x+2) xlog3 = (x+2)log7 now x÷(x+2) =log7 ÷log3 x÷(x+2) = log4 x÷(x+2) =2log2 x÷(x+2) = 2×0.30 x÷(x+2)= 0.60 x=0.6×(x+2) x-0.6x =1.2 0.4x = 1.2 x=1.2 ÷0.4 x=3 But how 🤔🤔🤔

[@sakutaokami]

If a^x=b you can write it x=log(a)b similarly to that (3/7)^x =49 x=log(3/7)49

[@micahmeneyerji]

log(49)/log(3/7) "simplifies" to (2log(7))/(log(3)-log(7)) but it takes less time to calculate the log of 3/7 than subtract already calcuated values.

[@daviddaasian9685]

all that for nothing, couldve just cut straight to the chase by simplifying (3/7)^x = 49 to x = log_(3/7)[49] and use a calculator to get the final answer from here.

[@HARSHVARDHANSHRIVASTAVA-p1j]

NICE VIDEO SIR👍

[@Communist-j2h]

अबे newton teri wajah se mere kam marks aate hai

[@VenuprasathM-f3f]

Verry good!

[@youssefelyousfi4929]

x=-2ln7/(ln7-ln3)

[@HARSHVARDHANSHRIVASTAVA-p1j]

SIR PLEASE ALSO SOLVE MATH QUESTIONS FROM JEE MAINS AND ADVANCED EXAMINATION

[@sabitadidirani9497]

These are way harder than jee advanced problems.

[@Ashwinmathsclasses]

Very nice🎉🎉🎉🎉🎉🎉😮😮😮

[@0x_min]

3^x = 7^(x+2) 3^x = 7^x * 49 1 = (7/3)^x * 49 (7/3)^x = 1/49 x = log_7/3(7^-2) x = -2 * log_7/3(7) x = -2 * ln(7) / ln(7/3) x = -2 * ln(7) / (ln(7) - ln(3))

[@88kgs]

👌👌

[@ITz_Parth7219]

Op brotherrrr

[@0x_min]

3^x = 7^(x+2) 3^x = 7^(

[@banusenthilkumar9864]

Can do video about trigonometry indentity especially prof

[@pratyushkhandelwal7138]

Noice❤

[@StarkGem]

-4.59 is this right

[@pelasgeuspelasgeus4634]

Next time try to solve x-1=0...

[@JBh-v9b]

I did that in my head in ~5 seconds

[@Delfy9292]

Good boy

[@JBh-v9b]

@Delfy9292 can you?

[@Delfy9292]

@@JBh-v9b no

[@JBh-v9b]

Can you solve it in 5 seconds aswell?

[@Delfy9292]

@@JBh-v9b no

[@aviraljain1802]

x = -(2 log(7))/log(7/3) obviously