Solving Another Unknown Using NMR, IR and MS Spectroscopy - Example 3

[@taylorp6141]

This is one of the best spectroscopy videos I've watched. I just purchased the guide from your website - it is GOLD! Thank you!

[@ChemComplete]

Awesome, thank you!

[@mattsoutback59]

I wish my professors added mass spec and DEPT NMR, we did bare bones HNMR and CNMR. Great series! Thanks a million!

[@alejandrobonilla813]

Thank you so much. As a premed, you make ochem UNDERSTANDABLE. You have literally helped me earn a 95% on my first ochem II quiz. Tomorrow 2/28 is exam 1 for me... I will keep you posted

[@ChemComplete]

Fantastic! So many premed students fear organic chemistry, but if you understand the basics it is much more approachable.

[@jajuay.jpeggg]

Your explanations are superb! Thank you for your video😭💖

[@julian444]

Good explanation for sure, our exams are always without chemical formula however, do you have any video's without the formula given

[@mbugrahankilic]

Greetings from Istanbul, Turkiye. Teşekkürler.

[@mildredemegha6276]

Im having my finals soon and this was awesome!!!! I do appreciate you!!!🎉🎉🎉

[@naufahanif1996]

thank you very much Prof! such a brilliant lecture video, sir!

[@ChemComplete]

Many thanks!

[@akinfenwaomolajaakeem9017]

Many thanks. This is eye-openng.

[@jaydenarifpardy2049]

you are a king

[@temangwenizwane336]

very helpful, thank you.

[@fakhrulnawawi9681]

I completely understand this video. Thanks

[@Luong_Nguyen_Dang]

Great lesson! Thanks alot!

[@rtk-j23]

this is a super explanation. thank you so much

[@zeinebkhlifi4343]

thank you very helpful please keep on posting such videos

[@user-be4yc2vr5c]

This was really great thank you. Enjoying this very much and very helpful.

[@ChemComplete]

Thank you for all the support and feedback!

[@sushmitasingh3326]

What will be the compound with molecular formula C6H14O that gives only 2 NMR signals?

[@MrKola09]

Awesome lecture

[@jonathansanchez8802]

great stuff!

[@quitt5371]

Thanks, bro!

[@blessingfava4011]

great. thank you

[@MrPablob160]

thanks!

[@maxwellkeicha9418]

Thank you very much.

[@ChemComplete]

You are welcome!

[@safiabegum6826]

Well done sir.

[@andrewpritchard2863]

So why is the CH3 further up field if it’s near the carbonyl? So wouldn’t that triplet on the H NMR be further down field?

[@ellatimm4297]

Great video 😊

[@ChemComplete]

Thanks for watching!

[@khalidm.gharib4189]

We appreciate it, thanxs alot.

[@riki8426]

Lifesaver!!

[@harrypoutter3224]

How do you determine organic structure if structure formula is not known ??

[@ChemComplete]

When the structural formula is not known you utilize all other spectra to support your argument. The information we get from the molecular formula is the degrees of unsaturation. This information helps us, but the structures can be solved without it. I will agree the process becomes more annoying without it, but still possible.

[@niloofarkh4779]

thank u

[@iqraattiq8812]

Please send solution link of problems 231-240

[@kylecatman7738]

Also the 3 carbons without Hydrogens is accounted for

[@matthiasschwier3875]

did i missed somthing or why there are only 4 doublebounds not 5 ?

[@ChemComplete]

There are 5 degrees of unsaturation, not 5 double bonds. A ring system accounts for one of the degrees of unsaturation, the rest are due to double bonds.

[@matteomarchesi507]

why it couldnt be an amide?

[@Katie-g3u]

Please please could you do the C7H7NO one?

[@ChemComplete]

Hi Katie, C7H7NO is a molecular formula that could have multiple structures. If you send me the spectra (NMR IR, MS) that you have I can look them over and present them as a video on the channel. If not try putting the formula into google and seeing the various structures that come up. I know benzamide is a VERY common organic compound with that formula. If you have aromatic peaks in the HNMR, a carbonyl in the IR and an NH2 in the IR/NMR then it likely could be that.

[@Katie-g3u]

Thank you :) I have emailed the spectra to you

[@shazich9807]

Kindly upload combined spectra problems no 51 52 53 54 55.

[@johnwill400]

Really goood

[@masoudrafee2046]

fantastic! many thanks!

[@HA-fw6lf]

I need th equstion

[@YusufAyman-dh7yk]

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