Some Basic Concept of Chemistry 13 | Solution and Concentration Terms | Class 11 | JEE | NEET

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[@soguitar]

0:40 👉 Solution 5:50 👉 Components of mixture (solute+solvent) 15:55 👉 %weight by weight 21:21 👉 %Volume by Volume 26:56👉%weight by Volume 30:45 👉 Strength 34:44 👉 Mole Fraction &Mole % 41:51 👉 Molarity (M) 47:11 👉 Effect of Temperature 51:15 👉 Effect of Dilution on molarity 55:00 👉 M1V1 == M2V2 01:00:03 👉 Calculation of molarity 01:03:01 👉 Molality (m) 01:04:44👉 ppm (part per million)

[@saurav8065]

haa bhai copy kar lo comment kisi aur ka

[@nobeldude]

@@saurav8065 bhai esne to accha hi kiya jo koi neche na ja sake wo ese se hi topic padh lenge

[@nilimaambekar3475]

L 2❤0ww3w 3333 3 li 0ww😊😊

[@neetubindlish1162]

Finally we have almost reached the end of this chapter in रसायन लीला style... Thank you sir

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@MayankisG]

When course will complete

[@ayushaansari9791]

@@MayankisG full lecture plan is given in the app

[@desilva5611]

No bro normality and molality remains🙂

[@Krishkeditzone_]

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[@KrishnaSingh-lz9qk]

This person is teaching almost 90% of advance syllabus

[@arpitabanerjee75795]

Nope. ..... Mole concept ka syllabus both mains and advance meh same hai

[@hostelers18]

Or ye to NCERT ke syllabus mai bhi hai

[@onlystudypw115]

@@hostelers18 NCERT KA SYLLABUS HI ADVANCED ME ATA HAI

[@hostelers18]

@@onlystudypw115 not only Ncert bro too many other concepts r also the part of Advance syllabus

[@onlystudypw115]

@@hostelers18 TO BE HONEST THOSE CONCEPTS ARE DERIVED FROM NCERT WITH SOME COMMON SENSE

[@Saurabh.conquers]

Calculating of molarity after mixing of solution Prove that M1V1 =M2V2 M1= N1/V1 N1 = M1V1. 1st eq. M2=N2/V2 N2=M2V2. 2nd eq. N1+N2 = M3V3 Putting N1 and N2 value or from 1 and 2nd M1V1 + M2V2 = M3V3

[@deathslayer6534]

Sahi bhai

[@cooltion9905]

Topper

[@anjalik5038]

stop DON'T SCROLL DOWN GO back to LISTENING the lecture CAREFULLY and making NOTES without shifting your mind to read comments

[@ujp-upamanyujitphukan4321]

1:02:50 M3 = ( M1V1 + M2V2) / (V1 + V2)

[@sukantadebnath4067]

Thanku Sir. Even if you r not in the same platform, we respect you. Your teachings r always with us. Thanku for improving my chemistry class 11 . Thanks a lot

[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@portrait8097]

Calculation of molarity after mixing solution. M1V1 +M2V2 = M3V3 so , M1 = N1/V1 then N1=M1V1 -1 , M2= N2/V2 then N2 = M2V2-2 , M3=N1+N2/V3 then N1+N2 = M3V3 , then putting value of N1 And N2 from 1. And 2. So finally we have M1V1+M2V2 =M3V3 , that's the Ans. Thank you 🤗🌸

[@ayush_1736]

Thank you very much bro....aapke comment ke wajh se mein apna ans cross check kar paaya...

[@tasmiyakazmi3617]

Thank you sm

[@niteshkumaryadav3754]

❤

[@sandeshpatel7203]

Thank you bhaiya 😊😊

[@Kavitasankhla-yj3me]

Thanks dear

[@shankymalewar6819]

# 01:02:06 M3 = [ NO. OF MOLES OF SOLUTE (ALREADY PRESENT IN SOLUTION ) + NO. OF MOLES OF SAME SOLUTE ( WHICH ARE ADDED ) ] / V3 SO , M3 = M1V1 +M2V2 / V3

[@atomhuh]

M1V1 = M2V2 Therefore, 2×M1V1/V3 = M3 Or 2×M1V1/V1+V2 = M3 You can also take M2V2 in exchange of M1V1 Thanks 😊

[@farheenshanilshah7804]

@@atomhuh in this case no moles of are not equal.

[@asheerwad_01]

Let's achieve our lakshay by doing prayas and keeping yakeen on alakh sir and all other teachers with an accelerated pace🔥🔥 Love you Alakh Sir😍

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Op

[@DilipKumarG-qn5zm]

Kyaa baat h bhai ne sir ki saari batch ke naam le liye👍🤔😅😅

[@hardikmaity4489]

Aur usi acceleration ke saath me hume sprint karna hai aur fir Udaan bharni hai 😁 9th and 10th batch Sprint and Udaan respectively

[@asheerwad_01]

@@hardikmaity4489 Work hard Brother I wish you All the very Best.

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[@slcgamer4433]

Kash mai chemistry padna phele chalu kr deta . Outstanding explanation by sir

[@neet_aspirant536]

Finally I had understand everything in this chapter as I had not understood in class thanku sir love u ❤️🥀

[@shaikreshma8613]

mee too

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This channel is really awesome , outstanding.

[@sougatapatra7556]

@@Ayush-tf5jb Not sufficient for jee advanced,but sufficient for jee main and neet,sir himself told it's for main.

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[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@SaturnJupiter-pc4sj]

Who ix watching at 2x speed,,like mardo

[@journeyofmicroworld]

"Kamal h aapka andaaj Padhate h aap bindaas Jo nhi samajh aana wo bhi aa jata Chemistry se bs yu hi pyar ho jata" Do you agree👇👇

[@Dghgtgh]

☺️☺️ always confident after the lecture

[@shivanshmishra2320]

Who is waiting for people live class of alakh sir🙂🙂😞😅😅😅🙄🙄🙄😎😎😎

[@babashowkat23]

Me

[@muhammadnuammir7729]

Kb aainge sir live🙄

[@shivanshmishra2320]

These different emojis represent my mixed emotions

[@nehakumari1251]

@@muhammadnuammir7729 9 bje

[@muhammadnuammir7729]

@@nehakumari1251 thanks

[@RahulYadav-dw4tb]

No view But 800+ likes That's the power of Amit sir 💪💪👍✌️

[@iconicgaming6196]

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[@sarthaktiwari537]

*alakh sir

[@TheAlxxFy11th]

thats the power of your sasta phone

[@Thats_shivam.]

Teachers come and go , But some words will remind you memories of alakh sir at the beginning and end of the lecture..😍😍😘😘😚😚💞💓

[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@shortvideo1768]

Best team of physics wallah on KZbin

[@technicalshiva3095]

Sahi kahe

[@technicalshiva3095]

👍👍👍

[@madhusharma937]

M=M1V1+M2V2/v1+v2 M is molarity of mixing

[@JS15434]

yes sir ...mixing wale ka bhi easily ans aa gya woh bhi aaapne hint dia usse bina dekhe .......thank you sir question solve krne ka confidense dene ke liye

[@ayushmati2691]

1:03:04, yes sir I establish the formula of molarity after mixing solution = M1V1+M2V2=M3V3

[@Patel_Kamlesh]

Kaise solve kiya plz describe

[@ayushmati2691]

Sir already describe all the things in last only u have to do some steps

[@manoj1808]

Yes sir I have stabilised the formula of molarity after mixing solution = M1V1 + M2V2 = M3V3

[@Patel_Kamlesh]

Plz define it

[@rabiyakhan9692]

Sir ne bahtreen andaaz se poora lesson khtm kr diya

[@SOHAMJHA-b2w]

Sir, when I learned this from my teacher I couldn’t understand a word of what concentration terms are. But when I listened to your lecture, this concept became crystal clear. Thank you so much sir. Also, at 1:02:49, I have derived the formula sir : n3 = n1 + n2 n1 = M1V1 n2 = M2V2 n3 = M3V3 So, M3V3 = n1 + n2 Therefore, M3V3 = M1V1 + M2V2 HENCE PROVED Thank you so much sir for imparting such golden knowledge to us in a way which is vey easy to understand. We will make you proud sir

[@supradeep.mukherjee]

Sir, Please start regular exams(or unit tests) also for Class 11(doesn't matter if we have to pay for that) Please Sir Please 🙏🙏🙏

[@anuragbarewar9334]

Yes Sir

[@vanshkhanduri2277]

He is coming live at 9 .

[@swayamhajare845]

I think he will announce about test series for class 11

[@sauravkushwaha8790]

👍👍👍

[@anshul7859]

Yes

[@syedayousuf4850]

Yes sir i get the answer its m1v1+m2v2=m3v3

[@Little89087]

Congrats sir, You have gained 41 lakhs subscribers❤️❤️❤️

[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@ShubhamPathan-x4y]

bilkul samjh gye sirr...❤

[@Goalneet-yl5xr]

No views 548 likes Power of physics wallah

[@anshul7859]

Yes

[@Soniya-q9t]

Finally completed the chapter Satisfaction at next level 😎

[@khushidubey635]

Ab sir 9th aur 10th wlo ke bhi saathi hai!!! JAI HO!! 🙏🙏❤❤❤

[@jasbirkaurgill5]

Humne homework ka solution nikaal Liya hai sir... Ekdam behtreen trike se😄😄😄

[@Patel_Kamlesh]

Plz define it

[@sulabhagrawal6414]

@@Patel_Kamlesh see N1 = m1v1 N2=m2v2 And n3 = m3v3 So if n3 is a mixture of N1+N2 then the answer will be M3V3 = m2v2+m1v1

[@mr.dominic9636]

You are so amazing sir Just because of you I am in love with Chemistry 😍

[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@prabalsingh892]

Sir apka bahatareen andaj is vry nice 👍😁

[@PankajKumar-br8np]

Sir aap bhut mehnat kar rahe ho kyunki apne sardi mein bhi t shirt dali hai thanks 😊

[@itzofficialkirtiporwal2007]

Thank you sir❤ .. Calculation of molarity of mixing of solution... Proved the relation 👍 M1V1 plus M2V2 equals to M3V3

[@kismatsingh3172]

AUR ISI KE SAATH....MAINE BEHTARINE ANDAZ MEIN...YE LECTURE DEKH LIYA...

[@dontknow9143]

Sir class me jab padhai hui to mujhe kuch samajh nahi aa raha tha lekin aapse padhne ke baad mujhe sab samajh aa gaya

[@dontknow9143]

Thank you for this video sir 👍

[@Ramniwasyadav222]

Sir I found the molarity of the M³ is M1.V1+M2V2/V1+V2🤔🤔🤔🤔🤔🤔 May be right

[@lavisingh9197]

same aa rhha hn

[@rudrakshkaila8435]

Yai ha bhai

[@pragati569]

No. of moles in 1st solution , n¹= M¹V¹ No . of moles in 2nd solution , n²= M²V² No . of moles in final solution n³=n¹+n² M³V³=M¹V¹+M²V²

[@dareman45]

Hw ans- I have proved the EQ - m1v1 +m2v2 = m3v3 M1= N1/V1 .......eq 1 M2 = n2 /v1 ...EQ 2 M3 = N1 +n2 /V3 ....EQ 3 By all EQ M3v3 .m1v1 + m2v2 Loved ur session 💙☺️☺️ thank you sir ☺️

[@VinayMishra-yg8ne]

1:00:11 Good evening sir, Homework complete.

[@aniketagrawal9833]

I have stabilised the molarity formula

[@gujjar6193]

Amit sir please take question practise session of this complete chapter after end of this chapter 👇

[@AbhishekKumar-vt2oh]

Sir, PLEASE HUMBLE REQUEST TO YOU, KI AAP NORMALITY AND EQUIVALENT WEIGHT concept per bhi video bana dijiye AUR 1 VIDEO ME Question PROBLEM based on SOLUTIONS CONCEPT per bhi video bana dijiye

[@PW-Unofficial1500]

Yes sir

[@aryanpatel5273]

Waiting for alak sir to came live soooo excited

[@ananyakumarnayak1540]

Sir I got the answer (1)m1v1+m1v1=m3v3 (2)m1v1+m1v1=m3v1+m3v1❤️❤️👍👍✌️

[@Kaidiya]

APKO KON CHAHIYE MOM - like 👍👍💕 G.F - scroll down

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@asheerwad_01]

Kaun ho tum bhai kaha se aaye ho.

[@sciencetanium3216]

mujhe gf chahiye, maa to mere paas hai 😂😂

[@mdateeque3997]

@UCMiDRu6Si-BNbqOXVd57tVA sorry bhai but Hamara content dusro tak nahi pahunchta hai. Isliye karna padta hai. SORRY.

[@salilpal]

Mere paas dono h nahi chahiye kuch bhi

[@Bajrangdaskashyap48]

Solvent and solute makes solution

[@KartikSharma-ln8rz]

Bhagwaan ho sir.......PW team or alkh sirr❤️❤️❤️❤️😘😘😘😘

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS ---- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@ishikarana3783]

Yes sir i establish the result M1V1 + M2V2=M3(V1+V2)..

[@abdstruefan3358]

I can't believe I am in class 8 and after studying from Amit sir I can solve 95% + questions

[@Shubhamkumar-fe8bg]

Ek behtareen andaazz mein samaj aagya...

[@ravinderkaur7313]

Very much understandable🔥

[@Bajrangdaskashyap48]

Welcome and thank you sir 👍

[@sanjaychoudhary2612]

Even KZbin also failed in uploading statistics of sir's vdo No views still 836 likes🔥🔥😂

[@iconicgaming6196]

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[@balajichaitanya9212]

sir i like your content and teaching style

[@adityagoyat6871]

Good evening sir Sir M1V2 +M2V2 = M3V3 homework part

[@hafsaanjum8144]

Bst chemistry lecturer everrr...thanks 2 Alakh sir

[@jyotijha1176]

Sir you make chemistry more easy Thank you sir🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰👏👏👏👏👏👏👍👍

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Love you whole physics wallah team ❤️😘♥️♥️♥️💞💞💞💞💞💖💖💖💖💖💗💗💗💗💗💗💗💗

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Aapke comment ko 300 like the na 😎❤

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Hitler reacting to IIT-JEE RESULTS ---- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

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aaj last lecture hai 🥰 Mann laga ke padhenge 😀

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Thanku sir for your efforts❤❤

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Hello bachho has a separate fan base😇😇😇

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He's teaching perfectly!✨

[@PIY502]

Kesa pdhaya sir ne pura Cover Kraya tha Ky? Matlab aapse Questions bn gya kya Didi plss reply 🙏🏻

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​@@PIY502 ha ho jayega que sir ka video follow krne se

[@anshikaverma5799]

No view 304 likes , 900 comments and 1 min of upload . How is it possible 🤔

[@Stickery]

It's possible, Don't comment it You are here for study not other 🤷🤦🤦🤦

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2020 anything possible 😂😂😂😂😂

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@@nobita2.072 u r right 👍

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@@anshikaverma5799 youtube takes time to count views, it's happening from many years ago, U all are...... 🤦🤦

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@@Stickery Now u have come to study not to reply on my comments .

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I cannot express in words how much this video has helped me 😊

[@hariomshukla7348]

Yes sir I understood everything and also stablished the result.

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All teachers of pace batch are outstanding but Amit sir is my favourite. Who else have Amit sir as the favourite??

[@anjilapokhrel6835]

yes

[@prathmeshsingh9699]

Very beautifully explained sir 👌👌👌

[@kthkings174]

Finally Aya gya ❤❤

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@doordie3933]

@@mdateeque3997 💩🤓

[@shivamarora2969]

1:02:07 Sir is it because total no of moles n(3) = n(1) + n(2) Therefore, As we did before, M(1)V(1) + M(2)V(2) = M(3)V(3). Please tell.

[@crowming]

Yes

[@crafty2704]

Can u elaborate why not M3=M1+M2 they did for volumeV=V1+v2 na?

[@shivamarora2969]

@@crafty2704 See M is a concentration term which varies but volume total will remain always constant here.

[@crafty2704]

@@shivamarora2969 how M varies here because they they mixing both the solution still volume is V1+V2 but why not M

[@shivamarora2969]

@@crafty2704 Good Question . According to me it is because M is a variable term. Whereas V is rarely variable. If you get somewhat better answer, don't forget to share.

[@sizlate4178]

M1V1+M2V2=M3V3 Proved the above equation sir...☺️

[@umasingh4470]

Can you please post the answer

[@atomhuh]

@@umasingh4470 M1V1 = M2V2 Therefore, 2×M1V1/V3 = M3 Or 2×M1V1/V1+V2 = M3 You can also take M2V2 in exchange of M1V1 Thanks 😊

[@umasingh4470]

@@atomhuh thank u so much ☺️

[@haize21]

@@atomhuh hey can you please tell me how u got m1v1=m2v2 as the no.of moles arent equal

[@xm8gamer770]

@@haize21 the proof is the moles of the both the solutions get added hence, n1+n2=n3 therefore, M1V1+ M2V2 = M3V3

[@az-sr2ng]

I understand this from behtarin tarika

[@Khushi_2003-]

Thank you sir for your time...

[@ayushpundir9455]

Everyone will leave this class at 9:00 pm when alakh sir will come live 😂😂😂😂 *Edited* first time 5+ likes 😅😅😂😂

[@MJ_Studio_Cuts]

So I am watching lecture in 2x

[@anime.editz._69]

@@MJ_Studio_Cuts me also😁😁😁😅😅

[@ayushpundir9455]

@@MJ_Studio_Cuts that's cool 🤭🤭

[@RahulKumar-od9wi]

Thanks sir for the wonderful explaination .

[@aayushkumawat3642]

Finally Class Aa hi gyi .🥳🥳🥳🥳 Final Lecture...

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@mohdalam2995]

Amit sir is the best teacher of whole KZbin

[@himstitute9030]

SIR CONCEPT BOOSTER SESSIONS KAB AAYENGE?????

[@clrmdh]

Normality कहा है ? 🥺

[@arzoo9521]

Sir u teach the concepts so well.. but I think u should solve numericals after teaching the concept...so that the concepts are more clear... Thnku ❤

[@TheAlxxFy11th]

tysm sirg

[@cricketforever658]

Sir, your teaching skill is amazing❤️

[@Chemistry_talks]

Hey Chemistry Learner! Watch my videos for prepared chemistry notes.

[@PIY502]

Kesa pdhaya sir ne pura Cover Kraya tha Ky? Matlab aapse Questions bn gya kya plss reply 🙏🏻

[@twosetter5951]

We know, n1=M1V1 and n2=M2V2. After dilution, No of moles will be n3(suppose)=n1+n2. Therefore, n3= M1V1+M2V2 M3V3=M1V1+M2V2.

[@chandigarhgymnastics7050]

Bro but no of moles of solute reamain the same all over as we are adding solvent not solute to first beaker

[@sparshsinha6338]

1:02:05 sir aagya M3=M1V1+M2V2/V1+V2

[@udaiveersingh6276]

more simplified M3=N1+N2/V1+V2

[@RahulYadav-dw4tb]

1:02:50 Ans is -; (n1+n2) \ (v1+V2)

[@paytmfirst6345]

*VERY IMPORTANT QUESTION -ALAKH SIR* Dear sir we were given deadline of 7th december for completion of our chemistry 1st chapter but it got completed today?? We would be able to complete our syllabus till 20th feb ??? please reply i am in tensed sir its a request...please

[@kjsdhaliwal4347]

Yes sir

[@doordie3933]

Tu sir se

[@abkyadav7755]

You are best teacher am listen your lecture after solving more questions .

[@sahil-wk9fx]

Sir aap physical chemistry k liye book batane wale the konsi solve karni chahiye?

[@SatyamSingh-uz4qv]

N.awasti

[@AryanSharma-tk2bm]

Yes

[@NehaSharma-ec2cg]

Ncert 😌

[@santosenani4888]

@@doordie3933 rrr aur pathaan toh bhot achi gayi hai bhai

[@jayeshpathak2656]

this lecture was assome

[@aryanpatel5273]

Finally on perfect time

[@Stickery]

See newest comments 😂😂

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8

[@vloggingmadness]

Kaha se ho Bhai😊

[@aryanpatel5273]

@@vloggingmadness BHOPAL

[@asifmansuriff7208]

shandar tarika he sir apka sab clear ho gaya

[@akshitdogra1870]

1:03:00 YES SIR ESTABLISH KAR LIYA HAI..😅

[@satviksumanbarnwal2506]

behetareen andaz !!!!! bro he said that like 500 times ....

[@ayushmansinghIITIAN]

Sir it's my humble request to upload the concept booster session

[@abhinavkumar6223]

Next level teacher study like alakh sir

[@Hanuman335]

Waiting for surprise.🔥🧡🔥💜💜

[@mdateeque3997]

Hitler reacting to IIT-JEE RESULTS -- kzbin.info/www/bejne/e5rSc2aLgJt8iK8