Spearman's Rank Correlation Coefficient - Problem 1 - Engineering Mathematics 3

Subject - Engineering Mathematics 3
Video Name - Spearman's Rank Correlation Coefficient - Problem 1
Chapter - Correlation and Regression
Faculty - Prof. Farhan Meer
Upskill and get Placements with Ekeeda Career Tracks
Data Science - ekeeda.com/car...
Software Development Engineer - ekeeda.com/car...
Embedded & IoT Engineer - ekeeda.com/car...
Get FREE Trial for GATE 2023 Exam with Ekeeda GATE - 20000+ Lectures & Notes, strategy, updates, and notifications which will help you to crack your GATE exam.
ekeeda.com/cat...
Coupon Code - EKGATE
Get Free Notes of All Engineering Subjects & Technology
ekeeda.com/dig...
Access the Complete Playlist of Subject Engineering Chemistry 1 -
• Engineering Mathematic...
Happy Learning
Social Links:
/ ekeeda_official
/ ekeeda.com
#Spearman'sRank #CorrelationCoefficient #Problem #Correlation&Regression #EngineeringMathematics3 #MechanicalEngineering

[@khaledghonaim7325]

I opened the video to know how I get rank 1 and rank 2 😅😅😅, tysm sir

[@sajanstha6589]

So do i bro i swear

[@mariyakhan6628]

Same here 😅

[@hisanasherin1925]

Same

[@Rodiah01]

Me too

[@bimleshdevi6793]

Me also 😅😅😂😂😂😂

[@mikiyasgetachew77]

The way he is explaining is appreciated

[@Cloud702]

legend one day before exam 😂

[@bisma3819]

And I am that legend 😂

[@Cookwithneeru01]

same😂😅

[@ShashwatS_]

one hour before the exam

[@VighneshBhane-uo3jr]

Same😎🤣

[@Keertishindevlogs]

😅

[@harikatoch7620]

My exam is on 09 December 2024 and you are very valuable to me sir 😢😂😂

[@amargaming546]

Which university

[@Jesuschild-y3p]

Which university

[@Zeshan.511]

Same 😂

[@kachinelson]

You solves and explained the simplest and fastest on yt.

[@sujatanayar2824]

I Can't Thank you enough Sir for this explanation ! God Bless You

[@滴]

You can not thank you sir wdym

[@amishavermaverma1841]

Tommorrow is my geography practical...this is very helpful video thanks 🙏🙏

[@rajeevnayan4472]

so this is where engineering n commerce overlaps, anyways thanks for the video

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@hempeete7863]

For arts economics too

[@khakimwihaki4913]

Ekeeda my all time crush when it comes to stem courses ...

[@036_gauravpatil6]

This calculation is also in agriculture. Subject name Statistics Thanks sir very understandable

[@MathFunHouse]

Thank you so much sir 4:47 This help me a lot

[@deoxlee]

Watching it last minute and still understanding everything,tysm sir

[@Mouniii575]

Thank you soo much...it's very clear n clean explination😊

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@searchandlearnwithasma1185]

Well explained, in a very easiest method sir. Thank you

[@sahidkhansahidkhan1388]

Thank you so much sir❤ for this mind blowing explanation 🤞❤

[@shakshikumari6972]

A time saviour lecture and the best explanation on this topic thanku from the heart ❤

[@MuhammadQasim-id8fi]

I am studying in Inter part 2 Computer science and watching from Pakistan i am surprised to see that it is exactly same as our course👍👍

[@topladtv6560]

Wow, I had to subscribe. You made it very easy. You are a good teacher

[@samrinpatan3300]

Tmrw is my exam this is very useful to me

[@brahmXD]

Thanks for the awesome explanation. Saw this video 20 mins before examination and did it right!

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@mangchinghaokip1771]

💜 i really like this channel Good in English lectures 🙏❤️❤️ thank you sir 🏹

[@Ekeeda]

So nice of you

[@AndyWilliams-b3x]

Thank so much sir, you have made my extraneous work so easy,,🙏

[@soumyasagarsoumya888]

Thanks a lot sir, very useful class.

[@timepass242]

AWS ❤️ thanks for the efforts.. very understandable 🙂

[@b.anjaneyulub.anjaneyulu4488]

Thank you sir

[@vedantsuryawanshi2920]

Thank you Sir for your valuable explanation and crystal clear concept. 💐🍫🥧 Please keep up the Good Work 😄👌!!!

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@arunpalta2427]

​@@Ekeedasir need ur help

[@GamingNE000]

sir bahot achha smile hai aapka , bawal muskurate rahiye

[@geethakannadavlogs4696]

Sir aap humko acche se shikshan dete hai Dhanyawad sir

[@criminalhere4161]

Outstanding explanation❤️⭐

[@lordjesus7257]

I don't know last how he calculated ??

[@nikitamewar24]

Same my answer is becoming 0.4

[@durgamsravani927]

Thank you sir

[@Ekeeda]

Thanks, There is more to explore for you on our Ekeeda Application where you can get access to concepts from basic, practice problems to keep track of your progress, live doubt asking facility from top educators and much more. Download App - ekeeda.com/download.html

[@LakshmanKumari-kh6lv]

48/120=0.4,0.4-1 = o.6

[@gracesalamitv7410]

Understood perfectly. Thanks

[@muskzzz]

You made it so simple to understand sir

[@classifiedytfanclub]

Excellent sir❤👍

[@shwetharkulal4440]

Omg it's soo essy tq soo muchh sir 🥰

[@sayantibasak9490]

Thank you Sir🙏🏻 You help me a lot❤🙏🏻

[@ankitabhuyan9292]

Very helpful...thank you sir

[@techprolitegroup]

Last minute preparation tq so much sir

[@waikhomranita5705]

Thank you so much sir you clear my doubt👍

[@shakiratadeoye5884]

This really helpful Thanks alot sir

[@sahilwadekar9436]

Thank you very much sir

[@khushboo197]

Thanks a lot ❤❤

[@antheaneela9683]

Watching from bangladesh,Thanks sir.

[@LuckyYadav-f8f]

That's right sir , Thank you sir ❤

[@pooja-qt2ct]

Nice explanation 😊

[@Basawat-wm5yf]

Nice explanation sir thank you

[@gulzarahmadgulzarahmad3705]

thankuu sir ❤❤❤❤

[@Aashishghule_2004]

Thank you so much sir........for the explain very easily😊❣️❣️

[@Rohini_Harithsya]

😅thank you sir you are the best

[@pradeep79ff]

It's ok😊

[@Nandiniyadav16]

Super explanation sir tq

[@arunpalta2427]

If there is a question find the correlation cofficient can we solve this with spearman rank or not.. Please help

[@cric_foot_level_99]

It is engineering mathematics but i am in class 11 and it is a chapter of maths icse 11 😮😮

[@baby_pa_panda1489]

A got the ans right thankyou sir ❤

[@streamwithak5428]

Sir I think ans is o.4 is this right

[@jsingh7558]

Nop

[@faizal_khan9]

Yes the answer is 0.4

[@HARISH-jv9fk]

1 - 0.4 =0.6

[@asikreza4375]

thank you i could understand about how opend the rank

[@ogechiedosio100]

thank you for the explanation, However. the formula familiar to me for non-repeated ranking has the denominator as n(n²-1) which gives the same answer.

[@itzme_muskan]

Thank you sir..

[@bushrasami30]

Sir answer smjh nhi aya

[@bushrasami30]

Answer kasy nikala hai

[@InspireWave518]

Thank you so much for the explanation

[@manyatagodara6193]

Thankyou so much sir for this so easy explanation of that method.

[@MadMaxoggy]

Check the answer .First u calculate and wrote direct answer.THE ANSWER IS 0.4.

[@cream46]

My name is Meer as well!

[@coder_soder1]

Thankyou sir 😊 best video

[@TheLittleAddaCompany18]

Legend before 4 hr of exam

[@HonestBacha-h5i]

Yes I'm here 👋😂😂

[@asifabbasi-qf6gd]

Very informative sir

[@asimgujjargujjar4475]

Mashallah zabardast.

[@fennygypsy]

Superb tuition 👌🔥❣️thank you kindly

[@rezwanaassad]

It was really helpful. Thank you

[@swatigupta3852]

Thank you so much sir for very easy explanation

[@kennethamadi4387]

Thank you

[@notysr]

Very simple tysm sir👏

[@AmnaSher]

Thankeww 💗🎀

[@pradeep79ff]

Sir please you check the answer one's your answer is wrong "The correct answer is 5.32

[@SahilMushtaq-d5r]

Plz sir solve are full question answer....yor not solved formula sir yor direct answer in question ❓

[@pokkurisaritha4267]

Very very thank you sir, super explained sir

[@nithinb2580]

Thanks sir you helped me a lot ❤

[@joshphelan6077]

You are a genius! Thank you my friend.

[@kparusharamudu8158]

Thanks for

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@fit_tubes_365]

Thankyou

[@ad_academy]

Very good video

[@poojaspoojas333]

Thanks much sir 2methods am under stand

[@k-61-ri.18]

amazing sir

[@manoj-ky8cs]

Thank you so much sir . 🙏

[@vanshverma7514]

Thanku sir

[@Ekeeda]

We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html

[@tusharthakur2810]

The and is -0.38

[@rajithav9743]

We get same result or different?????

[@Bhawanaacharya-p6y]

Thank u thank u thank u thank u sir.

[@Sourav-Dath]

Why am I getting 0.39 as ans

[@aamirriyaz983]

You Are Doing d2

[@sanchitahangma1464]

Thnk u sooooo mch

[@vishakhamaurya9598]

Bs yhi to smjhna tha ki R1 aur R2 kaise pta krye h 😢..thank u sir ☺️

[@kuicwabad93]

Thanks a lot, sir for the excellent explanation! At least I felt that I have understand something.

[@arabindasamantaray1059]

i have doubt on the formula "n" square or "n" cube.Please clarify.

[@udayss7175]

Love you❤

[@somethinginteresting9650]

highly moderately low corelation ho ta hai ki nahi speamans mein??? karls mein jaisa

[@epicalglory9659]

Tq sir ...

[@Deepanshu_joshi8326]

Kl Mera exam hai thanks 🙏

[@Lost-bn2ig]

god bless you

[@oregongaming5348]

Thanks sir 🙏🏻..pata nahi apko shukriyada kese karu..kabhi ajo sir garpe khana khane..

[@tharallapriyanka3002]

If 2 values are similar then in what order should we rank the numbers

[@bhuvaneshbhuvi7027]

They have uploaded that form also in a video named problem-2

[@Rama_divya]

Legends 1hr before exam 😂

[@nandhukurbha9918]

2 I have exam started now 😅

[@mervin09]

If same numbers will come then how can i solve this problems