Mathematical formalism in quantum mechanics

[@albertliu2599]

It is now 2024... I already forgot how much difference you can feel between 480p and 720p. This video is much sharper than the previous one.

[@sophiac.700]

on the second page, there is a small typo. you said sqrt{n} but wrote down sqrt{2} on the denominator

[@user-rg1nt9lf4s]

very good content sir. thank you .. sir kindly make a video on Bound States for Potential Wells with no rigid walls.(wkb approximation )

[@mathfreak2521]

Isn't it the coolest thing ever 🤗 ??( Me pretending i understand something in this LABYRINTH )

[@janasandmeyer3406]

A hilbert space can be finite dimensional

[@bhsieh3537]

At 17:40 integration by parts is uv-integral(v*du). Why would you put du*v?

[@biotech1468]

Informative and enlightening

[@erbazkhan266]

Can anybody explain check your understanding problem?

[@turboleggy]

First one I think just means the expected value of x. Since the integral would be psi star * x * psi over the domain and that is what means. (I'm not sure exactly what he is looking for here) Second one would be zero. This is because states of the QHO are a orthogonal basis. X hat is hermitian because xhat = x and it is a real number and therefore it is commutative so =int( psi star * x * psi ) = int(x *psi star * psi) = * means multiplication not star

[@Mr35diamonds]

You read my mind regarding uncertainty principle......

[@hrkalita159]

Thanks for these videos Really helped a lot

[@zairaner1489]

But wouldn't the (impulse) operator still be hermitian without the minus? You wouldn't have a minus at the end, but you would also not need one? Or more general, I would say that for a hermitian operator A -A is also hermitian (because =-=-=)

[@abbashusain6053]

really helpful, thanks

[@carlosmmartinez1408]

thaks this is helpful. I love you

[@synchronicitystudios8217]

Thank you

[@ankitmishra2723]

Thanks sir

[@إحساسفيزيائية]

Thanks 💜💜

[@andrevlok9932]

But can it run X

[@Maxwell_Integral]

Because i have an IQ of 23, does this video include determinate states? EDIT: I'm sorry I am so dumb I just found It

[@santino4203]

Who would dislike wth?

[@user-vh4jn4vv8e]

Nice

[@mlungost]

The way you did the momentum operator example is not great for those us attempting to follow what you did., please consult the Griffiths book

[@backupemail6831]

wat

[@jagergaming2281]

ummmmmmmmmm... im trying to find out wtf this guy is talking about, I can do things like calculus, but this, this just gets complicated, and I wanna know how to actually use this, and calculate something out of it, and properly use this.

[@osamaishtiak6135]

Well then you'll need to do atleast a bachelor's in physics. For quantum mechanics first learn linear algebra, fourier transforms and special functions (Mary Boas' book is great for this)[you should also learn how to solve differential equations; partial differential equations are a bonus] . Then start with Quantum Mechanics by David Griffiths which is what this guy is following. Also the math used here is not complicated, if you are comfortable with calculus upto calculus 3 and linear algebra then this math is trivial.

[@Salmanul_]

You can watch his earlier videos and also read the book "Introduction to Quantum Mechanics" by David Griffiths which he is following

[@externitiy3692]

Wtf im just 8th grade and i just understand a bit of this.

[@milk9613]

SunDarating am just 2 grade

[@Oliver-xt5wu]

I'm first grade and I'm already at Phd level

[@milk9613]

O. G Austin Am owen a lott of besnisis. Am new stev job.

[@allanhuang3361]

@@milk9613 I am become death, the destroyer of worlds

[@gamerdude19183]

brain hurtie

[@darkzombie524]

Just copy pasted griifiths, you totally made a mess of the standard deviation formula. Came here to understand it. YOU FAILED SUCCESSFULLY.

[@SumitYadav-mx8bp]

Completely agree with you ! he pretends to explain everything but he's actually failing To explain anything in a coherent manner

[@stefanrolfs419]

The definition of variance in statistics is (X−⟨X⟩)^2 which can be written as ⟨X^2⟩−⟨X⟩^2. This relates to QM with (Q−⟨Q⟩)^2 and in its expanded form is (Q−⟨Q⟩)(Q−⟨Q⟩) = Q^2−2⟨Q⟩Q+⟨Q⟩^2 . Meaning ⟨ψ|Q^2|ψ⟩^2 − 2⟨Q⟩⟨ψ|Q|ψ⟩ + ⟨Q⟩^2. This simplifies to ⟨Q^2⟩ - ⟨Q⟩^2 as -2⟨Q⟩⟨ψ|Q|ψ⟩ = -2⟨Q⟩^2.

[@mkminerals12343]

an inappropriate way of teaching some concepts