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@aaronkwizera88453 жыл бұрын
you are best lecturer ever see. keep working hard, we appreciate u sir!!! stay blessed u are loved sir
@EngineeringFunda3 жыл бұрын
When you write this..... it gives lot of motivation to me.
@easwarsendhil21 күн бұрын
You are videos are time less classic which will liked by the current students and also by the future engineering students when they see your video
@EngineeringFunda21 күн бұрын
Your Appreciations, care and share matters a lot to me. #EnginneringLove. Let me give the details of few exciting features of Engineering Funda: 1. A link to more than 30 Courses is given in the Comment Section. 2. Detailed Syllabus of the subject along with chapters is given in the description of videos.
@dakshjain75 жыл бұрын
everything was excellent .. but sir the fact that you used m(t) and you put mx(t) was confusing for people watching this in series .
@skinnythanos68753 жыл бұрын
because A(c) is taken in common?
@akankshagurjar51415 ай бұрын
Here m is modulation index and x(t) is msg signal
@xiaonan2385 жыл бұрын
Thank you very much for your nice explanation in this series.. you save me a lot of time😁😁
@مرتضىالمحمدي6 жыл бұрын
FIRSTLY ..THANK YOU FOR YOUR EFFORTS..sir, I have question please, all previous explanations about ( DSB-LC),What about (DSB-SC)?
@EngineeringFunda6 жыл бұрын
You just go through my playlist you get your answer.
@marcofoschi54792 жыл бұрын
Thanks for this video. I've a question at 8:49minute you says there is no carrier signal inside mbAc^2x(t) , this is due to the fact that omegac is not present? Thanks
@dushyanthyadav26944 жыл бұрын
Super sir excellently said
@EngineeringFunda4 жыл бұрын
your welcome
@rajunagulancha7706 жыл бұрын
good explanation sir....thank you sir
@مادةالسيطرة Жыл бұрын
very good ..........thank you so much.
@EngineeringFunda Жыл бұрын
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
@ishanagarwal6803 жыл бұрын
nice lectures...very informative
@EngineeringFunda3 жыл бұрын
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
@rikmajumdar29384 жыл бұрын
Thank you so much sir 🙏🙏❤️❤️ It is very helpful 👍
@EngineeringFunda4 жыл бұрын
Thanks and welcome
@rugaremaushe89662 жыл бұрын
Thank you Sir you explained well
@EngineeringFunda2 жыл бұрын
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
@VishalSharma-ri3ih3 жыл бұрын
Great sir.... But I think there is a correction in y(t) value that is AM signal you write :- y(t)=Ac(1+modulating_index*message signal )Sinwc(t) But I think the value of y(t) should be- Y(t)= Ac(1+modulating_index*SinWmt )SinWc(t)...... Please correct me If I am wrong
@nitishadhiman41023 жыл бұрын
The AM equation u're talking about is generalistic in nature... In this lecture sir has shown the demodulation using square law device... He therefore has taken the equation corresponding to the AM signal generated from the square law modulator.
@parthsinha23533 жыл бұрын
sir u explain well...however there tends to b some background noise(wind blowing) in ur videos....if possible try to get rid of tat
@EngineeringFunda3 жыл бұрын
In New setup it is not there, I have just initiated youtube channel with these videos.
@parthsinha23533 жыл бұрын
Gr8
@harim87714 жыл бұрын
Thank you very much sir
@EngineeringFunda4 жыл бұрын
Your positive comments motivates me, Thanks and welcome 🙏
@harim87714 жыл бұрын
Actually i felt difficulties in many topics when my sir took but after i saw this video I don't have any difficulties..sir Thank you soo muchh for the clear explanation...💯❣️
@harim87714 жыл бұрын
Sir can u post a video on Weaver's method sir plz
@mrno3455 жыл бұрын
Is there some logic behind selection of components by lpf and bpf
@sarthaksharma93225 жыл бұрын
Low Pass filter only selects the low frequency stuff, basically it neglects all the powers and higher terms of message and carrier signals, and band-pass filter only selects a range of frequencies.
@swatichauhan21063 ай бұрын
sir is detector circuit and demodulator circuit same ?
@ruman22004 жыл бұрын
Thankyou so much sir...
@EngineeringFunda4 жыл бұрын
Your positive comments motivates me, Thanks and welcome 🙏
@riteshparashar7369 Жыл бұрын
nicee
@EngineeringFunda Жыл бұрын
Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
@061_arsh5 ай бұрын
Is this same as rectifier detector?
@Insanelymoodie3 жыл бұрын
How do we know if term is having the information ? Like for carrier term we know x(t) will be present but what about info part ?
@kokilanagaveti79654 жыл бұрын
Thank you sir
@Ehmedbaz3 ай бұрын
#1 ❤
@EngineeringFunda3 ай бұрын
@@Ehmedbaz Your Appreciations, care and share matters a lot to me. #EnginneringLove. Let me give the details of few exiting features of Engineering Funda: 1. All the subjects playlist of Engineering Funda is available in comment section. 2. Detailed Syllabus of subject along with chapters is given description of videos.
@EngineeringFunda2 жыл бұрын
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@shankysays6 жыл бұрын
Thanks
@475d.saikiran43 жыл бұрын
After lpf their is Ac^2 it is the carrier amplitude but u said that the term consist of only msg signal
@EngineeringFunda3 жыл бұрын
Information is there in frequency, amplitude can be scaled
@ShivanshRajSrivastavaSRS3 жыл бұрын
sir how we are recognising if the term is having information or not
@EngineeringFunda3 жыл бұрын
Based on frequency we do that
@sagnikpaul23884 жыл бұрын
Sir,why you took mbAc²x(t) as the output.Here also carrier signal is present.
@EngineeringFunda4 жыл бұрын
There is no carrier in this
@mohammedshaikhussain49493 ай бұрын
1. Explain how an amplitude modulated signal can be detected using a square law detector sir this question we acn write this answer
@EngineeringFunda3 ай бұрын
Yes
@kapilgupta46746 жыл бұрын
what is this 'm' in the final expression?
@shankysays6 жыл бұрын
Kapil Gupta u meu modulation index Am/Ac
@goravsharma75314 жыл бұрын
It's not modulation index wrongly written
@bharathchandra45315 жыл бұрын
Please try to make the video as shorter as you can by not unnecessarily repeating things again and again
@T.saibharadwaj3 жыл бұрын
My dear sir plz stop the ads middle of the class
@kironpaul75814 жыл бұрын
Sir ap ads bare dalte go... Really annoying sir.. Hope u will fix it 😊
@sourabhpatravale83484 жыл бұрын
Too many advertisements 😔
@kapilgupta46746 жыл бұрын
plz rply fast
@chandrajyothibojjapu95663 жыл бұрын
Thank you so much sir
@EngineeringFunda3 жыл бұрын
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.