Stability in Feedback Amplifier Explained | Stability Analysis using Bode Plot

[@ALLABOUTELECTRONICS]

*_For more information about the Feedback Amplifier, check the following videos:_* *1) Introduction to Feedback Amplifier:* kzbin.info/www/bejne/lZCbl2l3jcqhj9E *2) Effect of Negative Feedback on the Amplifier Characteristics:* kzbin.info/www/bejne/fn3RgHiJfpaYptU *3) Feedback Topologies in Amplifier Explained:* kzbin.info/www/bejne/haCxnah7ard_hMk *4) Voltage Series Feedback Amplifier:* kzbin.info/www/bejne/f6awnYaLYqlpotk *5) Voltage-Shunt Feedback Amplifier:* kzbin.info/www/bejne/r6qpXolrj9V0kMk *6) Current-Series Feedback Amplifier:* kzbin.info/www/bejne/qaHCq2WmpKZ7bqs *7) Current-Shunt Feedback Amplifier:* kzbin.info/www/bejne/hZ_Fpn-eZ81gpNk

[@poojashah6183]

Best ever explanation on this topic, rarely find videos on these topics, continue this series 👍🏻

[@mayurshah9131]

It is always very good to watch your video 🎉🎉

[@urnoob5528]

am i wrong or is this basically just a specific case of what u d have already learnt in control theory? where it is not just about feedback amplifiers but about general systems, even with higher order (u also learn this in a signal and system class) u can determine stability with routh criterion, nyquist plot, and region of convergence

[@ALLABOUTELECTRONICS]

Yes, this is also applicable to other control systems. And the stability can also be found using other methods. Bode plot is one of the methods. And here in analog electronics, since I was discussing the feedback amplifier, so in that respect everything was explained.

[@nktrendings816]

🙂

[@samriddhi0906]

my syllabus mentions " digital logic" i can follow your digital electronics for the same right ?

[@ALLABOUTELECTRONICS]

Yes, absolutely

[@samriddhi0906]

@@ALLABOUTELECTRONICS ok,thanks sir :)

[@sadeghmollaii9873]

Awsome

[@HambeleleniShiviya]

Hello engineer,,, help design for me a logic gate of the following equations...D0=Q3Q0'+Q3Q2'Q2'Q0' D1=Q3'Q1'Q0+Q3'Q1'Q0 D2=Q3'Q2'Q1+G3'Q2Q1'Q0+Q3'Q2Q1Q0' D3=Q3'Q2'Q1Q0'