Collision Avoidance Radar Plotting 1

[@WaynelovesAchu]

I am a DP instructor at Houston Marine and Capt Bob is a very good instructor. I admire his teaching style.

[@abdulkkhan5095]

A very beautiful , knowledgable , capable and enlightening human being. God be with this man.

[@CaptainKiloHotelFoxtrot]

Capt. Bob, you are SUPERB! Thank you for sharing your knowledge on KZbin. I seek your permission to use the way how you deliver understanding about this material to my students!

[@satyapranay6769]

I recommend this one for anyone trying to learn a radar plot. Must watch all the 3 videos . Absolutely amazing Thanks :)

[@sejalpanda9489]

Hello gesco dude...hows life at seaspan..?

[@animar8234]

Thank You professor for this wonderful lesson and for great gift of sharing with people all over the world. Wish you all the best!

[@rodmacrae1596]

Respect to you from Australia 🇦🇺 Seafarers.

[@Dan_C604]

Very clear and practical. I’m just a recreational sailor but this is just amazing stuff to learn and familiarize with. Thank you captain!

[@jeedremedios6925]

This is very good for us sir.specially for students and for refreshing seafarers out there who forgot this one.thanks sir.godbless you😊

[@Djcookiemonster]

Captain Bob Glover is an OG, I learnt a lot from this video. Thank you!!

[@Ярослав-э8ш3о]

in Russia we don't do so much of work, instead of r - letter you can take 0* because it stands for the zero - observance time. Then you put the point that you name 6' cuz it stand for the Six minutes since the observation yet a good explanation it's always awesome to see how it's done abroad, bravo!

[@ryanhawkins6727]

thank you very much for this video i think i have watched it about 5 times now. pays to brush up on this stuff :)

[@aquaman839]

I got my renewal tomorrow this has been helpful. thanks

[@brownmamba3002]

I'm from Philippines and it helps me a lot, Thanks 👍

[@rocket_on49]

this really helped my studying. Thanks very much Capt Bob

[@Downunderexploring]

nice video Bob, great teaching method, cheers

[@parthdesai7501]

Exellent teaching. I got everything right again by seeing the video. Awesome

[@Scrabenger]

excelente forma de enseñar, a pesar de no ser mi idioma entendi perfectamente, me quedaron claro y mejor los conceptos y a pesar de (la opinión de Marina Matic, no la comparto. Tambien aprendi con WA, WO pero nunca nos dijeron el porque, ahora lo recibo claro...) Los 3 videos son para la biblioteca personal, gracias por la enseñanza, un capo.

[@regend7327]

Thank you for this video it is finally beginning to be clear to me how to properly plot and calculate the CPA's

[@gohoho2946]

Dear channel admins, I really appreciate if you can setup a play list of these very informative videos so that anyone can watch the series form start to end with an orderly manner. Really appreciate the work. :)

[@samitavakoli9914]

I wish I had a teacher as good as him at school!

[@navtikidvanajst1150]

i wish it would be explained to me just like that. my lecture sucks! huge thanks to this man..

[@josephokeme1876]

Many thanks, I quite got back on track

[@theislandfishingtv5197]

Thank you sir, BSMT student here❤

[@Fight.Me.N0w]

This video is so much better than my 2/m instructor

[@anonymouslyanonymous5580]

This lecture really help me a lot considering the fact the my professor in radar don't even teach us what was the purpose of the plotted lines and their roles.

[@anne-marievangeloven726]

brilliant!! well spoken well explained. Thank you for your time Sir!

[@mvicera6]

You sir explain more clearly than my 2/M Instructor

[@joaoluizrudgeencarnacao]

I'll do next month, here in Rio de Janeiro (BR), a Captain license exams.and it iwas a great help.... very clear explanation :) Many thanks !!!!!!

[@benjiegado]

this is very helpful my dream is to study at north east maritime institute to learn more about this navigation and all part of seamanship work thank you for introducing this video.

[@johng8823]

Eloquently explained ...... but I still can't fathom the bearing to the nearest ale house!

[@nurlatifahmohdnor8939]

Page 90 The characteristic "W" of the Queen (Cassiopeia) is low down on the northern summer horizon as summer opens, but by early August, she is higher in the sky, surrounded by the band of the Milky Way.

[@marindamarkloyda.8621]

Thank you captain from my school PMMS manila Philippines.

[@satyapranay6769]

Had come across the video several times but backed off cause the terminology of using r, m and RML etc is not used back here in UK. But once i got past and learnt the terminology its so easy, actually now I prefer using RML,r,m and the other ones described later on in the other videos......makes it way more easier :)

[@RamazMalakmadze]

well explained very useful lesson, thank you very much 👋

[@neempress6544]

Well executed very good tutorial.

[@alexwelland8584]

Very good video, however I was always taught to always take 3 plots not 2, to establish that his motion is linear? if only using 2 it's hard to see if he is turning etc. we were always told minimum of 3 plots?

[@BrunoGreenOfficial]

Same thing on my end (?)

[@waterwaysgreece3184]

Very helpful information and in depth explanation. Thanks for upload

[@rgudduu]

Being from non-marine background, I can see the underlying theory in this Radar plot. Let, with respect to some origin, my ship is at location p vector, moving at velocity u vector (includes both magnitude and direction). Let the target is at r vector and velocity v vector. Of course I will see my ship as static, and the target will appear moving at velocity v-u vector. For example, if v=u, then apparent velocity v-u=0, I.e., if target is moving in same direction and at same speed as my ship, then the target will appear stationary to me. If v=-u, then apparent velocity= v-u =2v, I.e. if target is moving at opposite direction, but same speed as my ship, then it will appear to be moving at double the speed. Similarly, For any other direction of my ship's course and the target's course, vector difference of v and u will give the apparent velocity. The two points in the radar map at 6 minute interval, give us the target's apparent course(the line joining those points) and apparent speed (distance bet the 2 points, divided by 6minute). Thus I know, the apparent velocity vector v-u. I also know my own speed and my own course, so I know my own velocity u vector. So the true velocity v of target is obtained as: u + (v-u), which is exactly what this instructor does in part2 of this lecture.

[@geronimosanjay7605]

Well explained Sir😊

[@enjoycast]

Brilliant didactic! Thanks Captain Bob

[@liquit3178]

Thank you very much Sir for this video discussion it makes me clearly understand the topic. God bless !

[@barryandrew2304]

May God bless you for this upload sir.

[@AZ12555555]

love u sir what a dedication and wat u render was ausm hats off

[@MaritimeAcademy]

Thanks Sir, Great Job!

[@ecmo11]

Why keep switching between minutes & hours? As long as you're consistent, you can use either. For instance, the relative motion speed calculation around 18 minutes works out to 8.9(kts)*6(minutes)/2.5(nmi) = 21.36 minutes, for a CPA time of 14:27:22

[@markdallaire3292]

You're absolutely correct using unit analysis (it was actually 8.9 nm, not kts). There's no point to convert to kts if you are trying to find TCPA. It's always going to be in minutes

[@svakestor7219]

Thanks great video! a quick math to find the CPA time 2.5 NM 6 minutes 8.9 NM X? X = 8.9 *6 / 2.5= 21, 36 minutes

[@hasrulmuhammad8271]

7lm. 9tyrfddex iiijttedfgtuj. ieeewmvfga_s8

[@hasrulmuhammad8271]

Tujn. Bnsd C.. ;_ .... +uiweedss=fdh wa. =/a/2. /f. 4.r V C. B . Y fã. J vãs b N. N

[@hasrulmuhammad8271]

Erws#

[@AbhayKumar-qb4kc]

For a person like me after seeing this think I know something which I can suggest or understand what is being done by navigators inside the wheel houses of Vessels

[@robsonams-2176]

very clear explanation.. thanks

[@wellstone1897]

Hi...firstly, thank you for sharing all this amazing content. Where can I find/get that sheet Capt. Bob mentioned in the beggining of the video? Greetings from Spain!

[@MarinaMatic]

r and m relative motion.... I can see it already how next class my students who find this on YT will say WHY are we using WA and WO (Way of Another Way of Own labels.) This is why I keep telling them I DO NOT CARE how do you label target plots, use Chinese mandarin if you want to, as long as you know what you're plotting, that is all I care for. Every city, every university, every lecturer - his/her own labels. No wonder students get confused. But great video. Love the tools you have to do the lecture, gave me ideas.

[@seikibrian8641]

+Marina Matic "...I DO NOT CARE how do you label target plots, use Chinese mandarin if you want to, as long as you know what you're plotting..." That's true...if you're solo on the boat. If you're part of a team, though, it's better if everyone uses the same symbology.

[@MarinaMatic]

+SeikiBrian Yes, that is my remark as well. I am using WAO O as first plot A as second plot and W as point of own ship and then WA is way of another and WO is way of own ship. I was under impression this is used by all in USA and it is an easy way to remember so I used it in Europe. Only to find this video with brand new concept of labeling the plots. The problem is - when the people from courses around the world come to the one ship what are they going to use "your way" or "my way" r m W A O ABC... In my country my instructor used ABC to mark plots with no logic what so ever. When I was introduced with WAO I switched to that, and I teach that.

[@brecsoks]

@@seikibrian8641 "That's true...if you're solo on the boat. If you're part of a team, though, it's better if everyone uses the same symbology" well said. "r" and "m" do not mean "relative" and "motion". "r" means "reference ship and "m" means maneuvering ship on a vector triangle. By means, my understanding is they are not points but vectors of direction and speed. Reference ship is our own ship in this case, but it could be the guide ship, for example as well. On the relative plot, the first point of the maneuvering ship is m1; the second is m2, etc. shows bearing and range. One may or may not combine the relative plot and the vector triangle as the instructor did it here.

[@alastorlestrange9727]

Marina kada smo upisivali drugu poziciju broda da li nam je ona bila data(9.5 Nm i vrijeme 1406), ili da li mi mozemo da odredimo uz pomoc prve pozicije i vremena i cvorova da odredimo gdje ce biti druga pozocija? Mislim mi na brodu imamo radar pa nam on automatski pokaze promjenu kursa broda ali pitam ovako inace isto za svaki slucaj?

[@pwipolulouise3675]

Excelent work,I need to learn more,nice one

[@giffordfabrolina810]

what will happen if ARML do not pass between point "e & r" , we have an scenario that it passes at the bottom, and the distance of vector "er" is too short, that it can't intersect to ARML , and i can't figure out what will be my new course?

[@itadoridg6093]

THANK YOU❤️

[@brucesinclair2981]

To me something is wrong. When I do this exercise having set the initial location of both vessels. To take the next position since I am in a moving vessel I reposition my vessel along its path and then position the target vessel as per reading taken. This gives a different values. Also at sea my understanding is at sea large vessel are required to have a 2 km distance. Otherwise it's considered a near miss and are required to record in their log book. If I am wrong please let me know.

[@MrLikeke]

What I want to solve is, given this same problem, what maneuver would I make to keep CPA exactly 3.0 nm. (Reduction of my speed not allowed) It seems I used to know this but have forgotten. I use maneuvering board. I once did this when crossing the USS Enterprise for a photography mission.

[@MrLikeke]

Aha! The solution is found in Part 3. Yay!

[@immanupestv23]

Thank you sir..im from Indonesia

[@saniinisan]

This helped me. Thank you sir!

[@zubairhamdani5135]

thanks for the video it was realpy helpfull.. appreciate ur good work😊😊

[@KrakenSpeed]

its very helpful . easy to understand .

[@Sailorpanku]

awsum explained by captain saab

[@asimsparks]

We are gonna go ahead

[@elstondsouza3232]

How can you use only to targets to determine whether Roc exist or how can you use 2 targets to complete your triangle??

[@hippo_nuggets]

Anybody else watching this stuck at home during quarantine?

[@dynamo6246]

Thank you

[@王永和-p5z]

Very thanks sir.

[@yangwasjeremie6689]

Where do you put the .35? Maritime student in philippines 😅

[@rodmacrae1596]

Can i please ask you something mate,which rank are you in?.I have a Family friend in here in Australia 🇭🇲 who got his Master's/Captain Certificate (Merchant Navy) in the Philippines 🇵🇭 by the time he got back to Australia the Australian Maritime Safety Authority (AMSA) wouldn't have a Bar of it,they said it wasn't "Worldly Recognised and missing some units too",so they refused to give him his full STCW for his Certificate and had to complete the So-called Incomplete units at Australian Maritime College (AMC)⚓🌑🍺.

[@patrickopaulo]

yes this is good and understandable. it refreshed my mind. thank you sir :)

[@mortymcfly3188]

God bless you sir

[@bogaret624]

Thank you sir

[@littleoak]

Well taught.

[@marcelrosin1087]

Amazing Cap thks...

[@stevie1463]

where did .35 come from. I've missed something?

[@MrLikeke]

8.9 nm (m to CPA) divided by 25 kts = .356 This is around the 18:10 time stamp in the video.

[@pcgurugary]

Old thread but I just ran across this video, which is excellent. Steve, the .35 comes from measuring the Distance between R and M then dividing by Relative Motion Speed(RMS)

[@capt10001]

I had the same Question . You kinda left out and important part of finding the answer when you left out telling / showing where the .. .35 came from. How would someone that don't know , know where that came from ? Kinda important !

[@causewaykayak]

As others point out, around time 18:10 it is all calculated on the whiteboard. Of of the students provided the 0.35 verbally in response to the Captain's question to class (8.9nM ÷ 25 knots).

[@drakeequation521]

My dad was a navigator in the Army Air Corps during WW2 and continued in the Air Force Reserve later on during the 50s through the 60s during the Gemini Mission. I tried to learn it but still can't get the slightest grasp of this subject matter. It's just way over my head. Astronomy was easier and so is learning Chinese.

[@paulineloba2482]

How did he get the range and bearing of 1406?

[@causewaykayak]

From his radar.

[@cliefordquijano1120]

what is the most appropriate to use, radar transfer plotting sheet or maneuvering board? asap

[@DavidVardanianDeone]

Great!!! from FNB barcelona

[@andrearovin]

Can someone explain why it became 043 in 2nd bearing?

[@chomi6312]

Because the target is moving, that's why its bearing and range is changing

[@oliviermace1523]

Merci, clair et bien expliqué

[@PinacoladaMatthew]

This guy's good

[@marcelbet]

Very good indeed: clear, didactic, makes you want to know more ...

[@robertlindsay9363]

What about the terms BCT and BCR?

[@chomi6312]

That's Bow Crossing Time (BCT) and Bow Crossing Range (BCR)

[@sabelokp4161]

so much help

[@johnteal5014]

How can RML be there when r was 45 & m was 43 degrees. Your RML Is wrong?

[@xienphai7100]

i have a question sir about the 1st plot position (r). Did you put that on your own idea or did you calculate it? (what i mean is the range and the bearing of the 1st plot pos) just thinking it right now.. thanks for the the vids anyway.. its a big help for me ^_^

[@naqibhaikal4509]

Xien Phai the plot is based on your observations on the target

[@naqibhaikal4509]

Xien Phai the plot is based on your observations on the target

[@joshuasagaret194]

thankyou sir :) its very helpful :)

[@nurlatifahmohdnor8939]

CYGNUS 20h Albireo 6960 6826 Sadr Veil Nebula 21h 6992, 6995 Deneb (in Cygnus the Swan) 6960 Veil Nebula 21h 6992, 6995 19h LYRA Vega (in Lyra the Lyre) M57 Ring Nebula From 40 degree N Early June 1 am Late June 12 am Early July 11 pm Late July 10 pm Early August 9 pm *Add 1 hour for DST Alabama, us Malabar, india

[@jba466]

Thank you Sir Bob Glover You sounds like Peter Griffin @ 14:30

[@pogsstv7254]

Good evening

[@mohitbatra3657]

Is this college in uk

[@nmi-edu]

No, Fairhaven Ma, Usa but we have international students as well.

[@gustavoramos8907]

Ótimo vídeo

[@nurlatifahmohdnor8939]

That is Rafflesia.

[@goffredoify]

I don have a radar on my sailing boat

[@WilyMarioMedinaOrosco539]

¿Cómo se desplazan las ondas electromagnéticas de un radar?. ¿Es cierto que se desplazan en línea recta y horizontal pero respetando la curvatura terrestre?. O sea. ¿Una línea recta y horizontal que paulatinamente se va curvando hacia abajo?. Claro que ya dejaría de ser una línea recta y horizontal ¿O no?. ¿Verdaderamente un radar funciona correctamente una tierra esférica?. Tengo entendido que un radar tiene un punto ciego. ¿La tierra es plana o esférica?. ¿Cómo se explica el hundimiento del HMS Coventry?. ¿Un radar puede detectar un avión a 420 kilómetros de distancia en una tierra esférica?. Un saludo cordial.

[@jonathank4278]

0.09 Hours ,or about 6 minutes to move out of the way.

[@pogsstv7254]

Rply mi plsss🥺

[@markrencel]

where did he get that 9 miles

[@MrLikeke]

It's a hypothetical problem 9 nm is the 2nd plot designated by m.

[@rss3781]

why n up heading up

[@pogsstv7254]

Hello

[@rawrbowser]

@RaulBowers

[@carlosttitorodriguez6600]

refresh!!