String Manipulation in Java - Interview questions - Part -7

[@rajatgoyal7155]

I have purchased 2 courses to understand Selenium and Java and i spent almost 13k rupees, they didn't tell me so elaborately even after charging so much. your tutorials are really helpful, one can easily understand and learn, moreover they can get enough confidence in few days to crack any MNC interview. Great job Naveen. Keep it up. please keep these tutorials free in future as well.

[@FitHighFive]

Thank you so much Naveen for this video, really got clear picture on String methods.

[@subhashpatil4286]

Sir, no words for your explanation. You are simply born to teach!!!!

[@yolwasmirzat]

This helps me a lot , thank you so much , this makes my java basic is so clear , and recently have interview , your interview section also helps me a lot .

[@aparnabhosale7483]

so beautifuuly explained..thnku sir

[@harishpandey9003]

very helpful, I used to watch your video, The way you explaining the things is very easy to understand.

[@lisazhou7776]

very good and very helpful. Thanks a lot Naveen!

[@shilpathada5832]

String str = "The rains have started here selenium"; System.out.println(str.indexOf(('s'), str.indexOf('s') + str.indexOf('s')+1));//3rd occurrence of 's'

[@MarkGavrilov]

This one works as well: System.out.println(str.indexOf('s',str.indexOf('s')+str.indexOf('s',+1)));

[@softwaretestingatoz3160]

System.out.println(str.indexOf('s',str.indexOf('s' +1)+1)); its this correct way to find 3rd veriable?

[@shubhtiwari4682]

occurrence of third 's' System.out.println(str.indexOf('s', str.indexOf('s', str.indexOf('s')+1)+1));

[@bharatvarshney2666]

Thanks for your efforts Naveen Sir, it is really worthful for me to clear concept in java

[@tikarobinson9335]

Thank you so much, this helps alot.

[@navathutejomai1038]

Sir I got a doubt as string is immutable how can we concatenate and assign to same string, just read on net that a new string is created and it reference is set to the object reference.

[@ParthKandpal]

Hi Naveen, Please find below the code for 3rd occurence of s String str="The Rains have started here selenium"; System.out.println(str.indexOf("s", str.indexOf("s")+str.indexOf("s")+1)); output will be -->28 Thanks :)

[@softwaretestingatoz3160]

System.out.println(str.indexOf('s',str.indexOf('s' +1)+1)); its this correct way to find 3rd veriable?

[@saig3660]

Awesome lecture...

[@deepikavijay3846]

Hi Naveen. Nice video. Could you please prepare a video for Regex ?

[@venkateshandea1767]

Hey Naveen anna you are doing great job I'm finding these days that everyone suggesting ur videos to others in selenium groups and everywhere though ur channel is quite is new u r reaching aspirants very quickly ....and help me with this I'm not able to print 3rd occurance of 's'...I did this System.out.println(s.indexOf('s', s.indexOf('s', s.indexOf('s')+1))); ...

[@lekhraj4395]

starting index should be 15; String str = "The rains have started here in selenium"; System.out.println(str.length()); System.out.println(str.charAt(5)); System.out.println(str.indexOf("s")); System.out.println(str.indexOf("s", str.indexOf("s")+1)); System.out.println(str.indexOf("s", str.indexOf("s")+15));

[@saranyasanapala1049]

If any one done this plz post here

[@borgjoseph]

public static void main(String[] args) { FindNthIndexOfACharacter('s', "The rains have started here in selenium", 3); } private static void FindNthIndexOfACharacter(char c, String str, int position) { int count = 0; //str = str.replaceAll("\\s", ""); -- uncomment this line if you want to remove spaces for (int i = 0; i < str.length(); i++) { if (str.toUpperCase().charAt(i) == Character.toUpperCase(c)) { count += 1; if (count == position) { System.out.println(i); break; } } }

[@sumirozario904]

@@saranyasanapala1049 String str ="The rain has started here for some reason"; System.out.println("The location of second occurence of 's' is :" +str.indexOf('s',str.indexOf('s')+1)); System.out.println("The location of third occurence of 's' is :" +str.lastIndexOf('s', str.lastIndexOf('s')-1)); System.out.println("The location of last occurence of 's' is :" +str.lastIndexOf('s'));

[@KingRetrixx]

System.out.println(str.indexOf('s', str.indexOf('s',str.indexOf('s')+1)));

[@kishoruprade]

Nice video..

[@devarapallirohini5369]

Hi Naveen, i am unable to print the 3rd occurance in the sentence, tried it in many ways. Google is having some complex code. Could you please provide your inputs.

[@devarapallirohini5369]

Thanks

[@srihari4827]

I think we can use OrdinalIndexOf in StringUtils

[@nandhanamtalkies2332]

str.indexOf(‘s’, str.indexOf(‘s’, str.indexOf(‘s’, str.indexOf(‘s’)+1)+1)

[@kalyanitarawate1141]

The letters are not clearly visible. Explanation is good.

[@Ruchi569]

Thanks a lot ! Please do a few programs on Collections...

[@DaddyPrincess]

Really awesome tutorial!

[@manju1ification]

Hi Naveen can you add program to find (first and last)non repeated character in a string

[@shankarpk89]

package javaPrograms; public class NonRepeatingChar { public static void main(String[] args) { String str = "INDIAFORINDIANSFIRST"; System.out.println("FIRST NON REPEATING CHARACTER IS : " + findFirstNonRepeatingCharacter(str)); System.out.println("LAST NON REPEATING CHARACTER IS : " + findLastNonRepeatingCharacter (str)); } public static char findFirstNonRepeatingCharacter(String str) { str = str.toUpperCase(); char chr = 0; for (int i = 0; i < str.length(); i++) { if (!str.substring(i + 1).contains(Character.toString((str.charAt(i))))) { chr = str.charAt(i); break; } } return chr; } public static char findLastNonRepeatingCharacter(String str) { str = str.toUpperCase(); char chr = 0; for (int i = 0; i < str.length(); i++) { if (!str.substring(0, str.length() - i - 1) .contains(Character.toString((str.charAt(str.length() - i - 1))))) { chr = str.charAt(str.length() - i - 1); break; } } return chr; } }

[@khushbooshah7441]

one doubt Output2.IndexOf("W",Output2.IndexOf("W")+1) how will i get the index of 3rd occruence of W in string

[@surekapandian1075]

Telegram link is expired... Is there new link?

[@arabindamohanty2190]

Thanks a lot

[@buvanapandu]

System.out.println(str.indexOf('s',str.indexOf('s' +1)+1)); //3rd occurrence of s or any occurrence

[@buvanapandu]

is it correct? im getting the correct answer but im not sure whether we can do this way

[@samhitasegar2864]

@buvanan Rajendiran - Is this correct way to get third occurence of s?

[@ujjwalverma7787]

sir, please help me i really confuse between them what is the difference between the "array.length and array.length()" some time array.length will work and some time array.length() will work. is there is any rules for is for using it? with String arr.length() will work but when we use an integer type, its work with array.length.

[@kapilrana2361]

As far as I know you can not use .length( )with array. For find the length of an array you should write array.length. Like if String s = "test", the you can write s.length(). and if you have int numbers[] = {-10,-10,24,50,-88,276435}; the you can write int len = numbers.length;

[@tejastoley6714]

length is use to find the size of the array and length() is use to find the size of the string.

[@kuldeepsikka2722]

@@kapilrana2361 you are right array.length is a variable and array.length() is a method.

[@Testprofile-u8b]

Using new keyword creates memory in heap and SCP . Why is that soo?

[@nazimkhan9080]

Lets take this example String s="_Hello_world_"; String test[]=s.split("_"); System.out.println(test.leangth);// Return 3: Why?

[@aakashkhandekar]

PLEASE MAKE VIDEOS ON ZOOM MODE. I AM NOT ABLE TO SEE YOUR CODES PROPERLY...

[@manishgupta5344]

Hi Naveen! How to find the numbers of ‘L’ in a string “GOOGLLLLLEE”?

[@_abhimanyu.]

we can do this using HashMap

[@romalisasamal7109]

public int lengthOf() { String s="GOOGLLLLLEE"; int first=s.indexOf('L'); int last=s.lastIndexOf('L'); int counter=0; for(int i=first;i

[@shankarpk89]

String s = "GOOGLLLLLEE"; int counter =0; for(int i=0; i

[@shankarpk89]

package javaPrograms; import java.util.HashMap; import java.util.Map; import java.util.Map.Entry; public class CountChar { public static void main(String[] args) { String inputStr = "GOOGLLLLLEE"; Map myMap = countCharacters(inputStr); for (Entry entry : myMap.entrySet()) { System.out.println(entry.getKey() + " : " + entry.getValue()); } } public static Map countCharacters(String str) { Map map = new HashMap(); int counter = 1; for (int i = 0; i < str.length(); i++) { if (!map.containsKey(str.charAt(i))) { map.put(str.charAt(i), counter); } else { map.put(str.charAt(i), map.get(str.charAt(i)) + 1); } } return map; } }

[@GreatStoriesTakeTime]

String a="GOOGLLLLLEE"; int b=(int)a.chars().filter(e->e=='L').count(); System.out.print(b);

[@gautamgkp65]

Awesome

[@marine007]

String str="ae@io#b$u123"; Separate characters,special characters and numbers......this was a interview question. sir,plz answer this

[@nandhanamtalkies2332]

public class StringManipulation { public static void main(String[] args) { String str2 = "ae@io#b$u123"; System.out.println("Characters are : "+ str2.replaceAll("[^a-zA-Z]", "")); System.out.println("Numbers are : "+ str2.replaceAll("[^0-9]", "")); System.out.println("Special characters are : "+ str2.replaceAll("[a-zA-Z0-9]", "")); } } O/P Characters are : aeiobu Numbers are : 123 Characters are : @#$

[@shankarpk89]

String s1 = "ae@io#b$u123"; ArrayList alString = new ArrayList(); alString.add(s1.replaceAll("[^a-z]", "")); alString.add(s1.replaceAll("[a-z0-9]", "")); alString.add(s1.replaceAll("[^0-9]", "")); System.out.println(alString);

[@mesrop6339]

Thank u

[@vishalgaikwad873]

sir where is == i.e s1==s2

[@dadasajad8741]

can somebody write here, how to find the third occurrence of 's' in string. thanks in advance. :)

[@anikamehra928]

System.out.println(str.indexOf(('s'), str.indexOf('s') + str.indexOf('s')+1));