Structure of Atom - NCERT Solutions (Part 3) | Class 11 Chemistry Chapter 2 | CBSE | 2024-25

[@RadhikaAgarwal-d5r]

53:32 it should b 3p not 3s

[@Varsha_bhadouriya]

Sir,sign mistake nl😊

[@AyushiArya-ve5mp]

well no dude sir meant that n

[@Varsha_bhadouriya]

@@AyushiArya-ve5mp yes I know bro

[@kavyagupta5663]

31:54 23 ii chlorine

[@MagnetBrainsEducation]

Thank you for your positive feedback on our educational school related videos! We're glad you found the video helpful and we hope you continue to use our platform as a valuable resource for your studies.

[@Amrindermehra]

Sir 5th september ki live viedo apke class 11 chemistry live session me nahi hae plzz use dubara upload kar dijiye. plzz🙏🏻

[@BGMI_SANJAY]

Thnxx sir you clear my all concepts

[@MagnetBrainsEducation]

Thank you for watching our videos and taking the time to write a comment! We're glad we could help clear up your concepts and we hope our videos continue to be a valuable resource for you.

[@AyushChoudhary-n1c]

Q-23.iii.C-- 21sc -- scandium

[@AyushChoudhary-n1c]

Q - 23.ii -- 1s2,2s2,2p6,3s2,3p5 = 17cl

[@shibaninath5098]

Sir qn no 21 agar Clacultion solve kava dete to achha hota. Mera solve nahi hua

[@sachingamer9011]

Sir 30 question ke last part mai 3p aayega sir naaki 3s

[@Mahadev_ki_ladli523]

Yess mene bi yehi note kiya

[@nku_creator]

yes bro

[@Ubaidmusic21]

Aray bhi pir correct h

[@missruna4368]

Sir 2.23 ,3p5=1s2,2s2.......3p5 =17chlorine

[@AyushChoudhary-n1c]

Q.19 - 36.33×10^-8 ans.

[@kunal_kumar2101]

A small correction in q 18 we take erg as a cgs system that' why we change all quantities in cgs in when we find lamda but sir forgot to convert speed of light in cgs❤❤❤ Anyway part 1 and part 2 is literally very helpful ❤❤

[@palak8844]

Que 21 0.89 × 10-6

[@HetanshiAmin-q1u]

Sir please upload 4th part as soon as possible because in 2 days i have a notebook checking😅😅😅😅

[@MagnetBrainsEducation]

Thanks for watching our videos! We're glad you're enjoying them and finding them helpful. We'll upload the fourth part of the series as soon as possible. Keep watching and learning!

[@kavyagupta5663]

23 iii c scandium

[@MagnetBrainsEducation]

Thank you so much for your positive feedback! We're so happy to hear that you're enjoying our educational videos. Keep up the good work and we hope you continue to learn and grow with us!

[@Varsha_bhadouriya]

Yes sir my answer is right 👍

[@BGMI_SANJAY]

Achcha

[@BGMI_SANJAY]

Accha

[@SojusPov7]

Sir aap jo bhi H.W dete ho uska next vdo me solution bhi dia kro please

[@palak8844]

Queen 18 answer = 9.47×10-8

[@Staleburger667]

What's the unit?

[@VivekBisht-bt4nr]

Sir question no. 19 answer is 3674Angestron

[@কুরআন_1M]

Thank you 🎉🎉🎉

[@MagnetBrainsEducation]

Welcome! Stay connected with Magnet Brains and Top your exams!

[@lovepreetkaur9631]

Thank you so much 🥰 sir

[@MagnetBrainsEducation]

Thank you for watching our educational videos! We're glad you're enjoying them and hope they're helping you learn!

[@shreyamukeshjain3512]

Q.21 wavelength =11.06×10^-6

[@aditischaudhari]

Sir please start 3rd chapter as soon as possible because my half yearly exams are on the way and my school teacher had already completed 4 chapters

[@MagnetBrainsEducation]

Thanks for letting us know, we'll make sure to upload the next chapter as soon as possible!

[@Aditya_Gamerz_technow]

Thankyou magnet brains❤❤😢😢❤❤

[@MagnetBrainsEducation]

Thank you for your kind words! We're so happy to hear that you're enjoying our videos and that they're helping you learn. Keep up the good work!

[@Rizwan00752]

Que=30,ka f =3P hoga sir

[@palak8844]

Que 19 36.33 ×10-6

[@BGMI_SANJAY]

19:28

[@MagnetBrainsEducation]

Thank you so much for watching our videos and for taking the time to write a comment! We're glad you're enjoying them and finding them helpful. We hope you'll continue to watch and learn with us!

[@nljk6873]

Ques. 21 Kinetic energy= 1/2mv2 V=squre root 1/2mk.E Debroglie lamda= h/ mv Put value of v in debrigli lambda Lambda=h/sq.root(2mK.E)

[@krishbudlakoti9tha41]

Sir in q30 f part l value is 1 so it is p how it can be s

[@MagnetBrainsEducation]

Thank you for pointing that out to us! We have corrected the mistake in the video.

[@princepanwar1016]

Yes bro. Ma bhi yahi soch ra tha

[@shreyamukeshjain3512]

Q.19 36.33×10^-9

[@kavyagupta5663]

17:25 😊

[@MagnetBrainsEducation]

Thank you so much for enjoying our video! We're glad you found it helpful and informative. We hope you'll continue to watch our videos and learn more about your favorite subjects.

[@laxmansingh4126]

Sir please complete syllabus fast

[@MagnetBrainsEducation]

Thank you for watching our educational videos! We are India's No.1 Online Education Platform and we are committed to helping students learn and succeed. We will continue to produce educational videos to help students reach their goals. Thank you for your support!

[@princepanwar1016]

Q 18. Lamda 943×10-¹⁰ approx . Sir i am right

[@MagnetBrainsEducation]

Yes, you are right!

[@Nature_loves_me]

No sir ye galat hai ans 6.8275×10^-8 hoga

[@motivationworld500]

Question no. 21 wavelength= 8.97×10-⁷ 22:01 Please check

[@MagnetBrainsEducation]

Thank you for your comment! We're glad you're enjoying our educational videos and finding them helpful. Keep up the good work and let us know if you have any other questions.

[@Sara-Rubby]

Sir kya exam aane tak chemistry part 1 khatam hoga

[@MagnetBrainsEducation]

Thank you for your question! Yes, you will be able to finish Chemistry Part 1 before your exams.

[@thakurudayrajsingh4715]

sir question no 30 wrong hai 3p hoga

[@P.k_Behera124]

[Ar] 4s² 3d¹ - Sc

[@MohdAkdas-bc6bw]

Question 23 part (ii) Ka (c) ha 17 cl

[@Navniit]

sir in Q.19 we have to find longest wavelength which will be from n=3 then why you have calculated the wavelenght of energy required to remove electron completely please explain.....🙏🙏🙏

[@kavitaagrawal4158]

Same doubt

[@Divesh0007]

Not from n=3 it is from infinity ♾️ to

[@arhamkhan1139]

We have find to longest wavelength which can be used to cause this transition...So, we have calculated the wavelength of energy required of n= 2 shell..!!!

[@Bindasstanu_03]

Slr 6lesson kara do please

[@MagnetBrainsEducation]

Thank you so much for your comment! We're glad you're enjoying our videos and we will definitely keep your request in mind for future videos! Thank you for watching and we hope you continue to enjoy our videos!

[@mangludas1662]

Q20. Answer: Wavelength= 8.9×10-⁷ m

[@azrapary6240]

ITS WRONG

[@padavkar1236]

Sir kal ki video private kyu thi

[@simranKaur-z2u]

Sir 18 question

[@tclhub]

Well done sir ....i think best explanations all the worlds thanks alot sir

[@Varsha_bhadouriya]

Sir,I have doubt q.28-2 is 3d orbital which means n=3,l=2and ml=5

[@KartikThakur-y1g]

17:29 🤙

[@simranKaur-z2u]

36.473*10-7

[@GoluKumar-rm5on]

Sir questions number 18 ka last nahi aa rahi hai sir kar wa dijiye please sir 🙏🙏🙏🙏

[@Fifa_Creed]

Sir question 21 mai doubt aa rha mujhe shayad answer wrong lag rha hai 😢

[@mihir_roy45]

same

[@AyushChoudhary-n1c]

Q.21 - 0.894×10^-6 ans

[@KrishnaKumari-x2n]

Sir physics Start kab se hoga

[@MagnetBrainsEducation]

Thank you for your comment! Our physics videos will be available soon!

[@Shreya_-]

30 ke f me 3p hoga nhh sir ??

[@MagnetBrainsEducation]

Yes! You are right! 30th of September is the date when the third phase of the event will be held!

[@UttamKumar-td6ii]

Sir bio ka class kab se Lenge aap log

[@MagnetBrainsEducation]

We are glad to announce that we will be starting our biology classes from next week! Stay tuned for more updates.

[@watchandsee1410]

Sir ch3 start kar do

[@MagnetBrainsEducation]

Thank you for your valuable feedback. We will start uploading videos for CH3 soon. Keep watching our videos and do let us know if you have any suggestions.

[@shreyamukeshjain3512]

Q.23 3 (c) 3p5=1s2 2s2 2p6 3s3 3p5 = 17 electron =chlorine

[@Sunita_Ranga-ja8tv]

counting mistake 18 hai Ar

[@SurajSuraj-hk8sh]

18 ha Ar

[@qualityentertainment5774]

Your answer is totally wrong s has capacity of max 2 electron

[@nancynarwal7062]

Ch 3 kb start hoga sir

[@MagnetBrainsEducation]

Thank you for your comment! We're glad you're enjoying our videos. Keep up the good work!

[@adishu3776]

Sir please daily class lagiye i am requesting again because monday my exam.। 😢

[@MagnetBrainsEducation]

Thank you for your comment! We will try to upload new videos every day so that you can keep learning!

[@Varsha_bhadouriya]

Q.23 ii-c - F_9

[@ParamjeetSingh-ph8wv]

Sir ehna sre question answer di ik pdf send kr do please 🙏

[@Nature_loves_me]

11:12 18 ans = 6.8275×10^-8

[@shreyamukeshjain3512]

Sir q.20 ka answer 0.3537 aa rahi

[@kokushibo6744]

Kya aa rhi 😂

[@ParamjeetSingh-ph8wv]

Hlo sir

[@P.k_Behera124]

3p⁵- iorn ka atomic number

[@kamaldass8101]

Sir in Q30: f = 3p not 3s. The L is 1 not 0. But the final answer is same.

[@JabedKhan-lb4gt]

Thank u sir❤

[@Varsha_bhadouriya]

Q.23partiii-c-sc_21

[@SanjayAsthana-e3c]

Sir please bataiye kab lacture aata h chapter 2,3&4 ka?

[@MagnetBrainsEducation]

We appreciate your interest in our videos! New lectures are uploaded every week, so be sure to check back often!

[@Divesh0007]

Sir in question no.9 longest wave length come from infinity so why you didn't apply rydberg formula in it explain me please 😢

[@Divesh0007]

@archanadubey6564 tq 🤞

[@studypoint4249]

Sir question 20 me c=lamda *v bhi laga sakta hai kya...

[@HarjinderK-c2f]

Q 18 answer is 0.105 x 10^-8

[@bhanuchasa9892]

2.23 (ii) c . Cl 17

[@padavkar1236]

4 th chapter ki

[@MagnetBrainsEducation]

maths video bahut acchi hai Thank you so much for your positive feedback! We're glad you found our video helpful. We work hard to ensure that our videos are of the highest quality and provide valuable information to our viewers. We hope you continue to enjoy our videos and find them helpful in your studies.

[@riddhima6899]

Sir question number 30 mein 3p ayega shayad se

[@vrsking666ff]

Any free fire lover ❤

[@sufisiddiquee7982]

Abhi 11th ka lover ban bhai😂😂😂😂

[@r-dv1rp]

Padh le bro 😂😂😂

[@AnamikaSharma-u3f]

👎

[@DipaliJaiswal-on9tr]

Cl

[@toyvideos252]

Q 19 =3.63 x 10^-7