Subnetting, Cisco CCNA, IP Addresses, Netmasks & Binary -Part 4

[@robfitzsimmons8003]

Makes a little more sense now! I've had it explained several times.

[@danscourses]

@routermen yes you are correct there should be 8 digits

[@MrHorizonkid]

I am really looking forward to the CCNP tutorial series from you. Anyway's your vid's rock. A million thanx !!

[@mybluemars]

Thank You, GREAT LESSONS !!!

[@myko913]

thank you, it makes so much sense now

[@alfatourist]

Hi Danscourse, could you do examples for class B with bits borrowed from the fourth octet & class A with bits borrowed from third & another example of class A with bits borrowed from fourht octet?

[@konfusionirl]

thanks so much! this was a great help

[@routermen]

how come its 0110011 . thats only 7 digit ? shouldnt it be 01100101 ?

[@eduardkubinec6412]

broadcast adress is 10.10.67.255, last usable is 10.10.67.254

[@When_Disaster_Strikes]

Good video. Perhaps use a monospaced font next time, though. But solid video.

[@in2deep91]

Good job!

[@fazliddin1993]

Thanks!

[@symikea]

probably some good info in these early videos - just can't hear it

[@alvaromoreira2375]

.67.255 is broadcast.... 67.254 is Not.

[@hotaman90]

THANKS mAN

[@ishansoni7869]

how to find subnet mask from ip address?

[@TheDogtag2336]

the subnet mask is all the " network" bits :) so if you got a 192.168.1.0 its called a c class :) if the first octet is between 1 and 127 its called an A class which means the subnet mask is 255.0.0.0 and would be known as a /8:) if its between 128 and 191 its called an B class and the subnet mask world be 255.255.0.0/16 :) if its between 192 and 233. the subnet mask is 255.255.255.0/24 :) it gets a little harder tho since the subnet mask also can have lets sat the number 255.255.255.127 which is /25 so only the first bit in the 4th octet is maked as a subnet or a " 1" where the rest is " o" marking it as posible places for a host :) for every subnet the amount of hosts lets say in the /25 there can be 2^6 (64) host per subnet :) but there is 2^25 subnets :)