Supermesh

Supermesh

[@Calliboss]

Thank you O.G... I am a community college student in California and my M.I.T. graduate instructor hit us in the head with this one. Spend 7 hours trying to form these equations (we had a dependent voltage source 10Vx instead of your 7 volts) and could not get it crackin'... Thanks again friend...

[@rory1653]

These kids are so lucky to have such a good teacher! I'm jealous!

[@dandyremix2360]

This guy is a freaking legend.

[@neeltej4123]

In the last super node question ,u forgot to consider current in 40 ohms branch during kcl at super node.

[@supriyar3570]

you are the best. thank you so much for the videos.

[@bignnake_family]

Your videos are on point. Teaching skills are very intelligible. Thanks

[@240mains]

Hayt Kemmerly page 69, Engineering Circuit analysis 5th Edition Straight out of the book😀

[@atifbashir7229]

Awesome Job ..... easy to understand .... Thanks for the great video

[@stephenwalker4723]

You are an absolute LEGEND!

[@omniyambot9876]

lol I like his style

[@hajrafarooq2870]

such a good lecture...keep doing such a spectacular job..you're truly a savior.

[@ellavasquez2546]

Thank you.

[@نورةالارقم]

Omg love ya from oman 💓💓 super clever

[@aakash9029]

This person is such a genious man

[@oaksoe188]

If I pass tomorrow exam, it's all because of your explanations..... Super Thanks!!

[@a.nelprober4971]

Did you pass

[@igoralexandrestefan1002]

nice lecture. helped me a lot thank you

[@jhansijanu7210]

Nice teaching sir lam understand clearly

[@jardanijonovich1951]

Where does this guy even teach He is amazing

[@Glozzom]

Does anyone know why he uses the convention of going from + to - adds voltage, and - to + subtracts? It may not matter, but I am used to seeing a voltage source - :| +, and when I do KVL equations I have always treated this as a +V, and every component in its loop facing the current + to - was a drop to that voltage, so I subtract. Are these conventions the same?

[@diags_1109]

As long as you consistently use the polarity of - to + as positive they will result in the same answer.

[@suniln1967]

Tq Sir, I didn't how to solve by seeing urs video I got it....

[@EduTech01]

Perfect

[@mayankrawal6034]

sir will there be no current through 40 ohm resistor ? or you forgot considering it

[@theodor320]

I was thinking the same thing - it got to be a current going into the node through that wire as well.

[@neeltej4123]

yes.. there will be current through 40 ohm resistor,it was a mistake above. v1=38.8 volts is the ans

[@ishaq351]

Neel Tej I got 38.85 volts and I thought I was doing it wrong because he got 45.33333

[@faisalsaddique3323]

yup i got the same question

[@saads5259]

Zahi, did you mean that it equals 8 instead of 3?

[@ضوءالسماء-ل9ب]

😄😄😄😄😄😄😄👍👍👍👍👍👍👍

[@a.nelprober4971]

Habibi

[@nathanielrodway9630]

can i use a matrix instead to solve, i don't have that version of the Ti

[@-wheeling9509]

Nathaniel Rodway yup

[@ضوءالسماء-ل9ب]

شكرا

[@jeanpierreistanbouli2225]

@18:14 how did you get that 3 on the right side?

[@jeanpierreistanbouli2225]

nvm I am impatient and did not see that you corrected it later on

[@ketakirathod]

Sir why we cant take i2= 8 at second loop as we took i1=1

[@nimmmakurikurpa2210]

thank you

[@manmeetsingh5479]

Thankyou !

[@muhannadaltaweel2087]

any one can learn me how i use calculate as he as doing

[@MrOptimusPrime.]

For equation 3 you missed the value of that resistor 2. It should be 2I1 - 2I3= 7.

[@YunusKhanification]

The first 2 equations were (KVL) equations. The 3rd one (KCL equation) was written to find the relation between the currents so he can cancel out one of the currents and solve using first 2 equations.

[@diags_1109]

It does not matter as long as you use 3 equations for 3 unknowns... etc

[@supunimadushani7821]

First one may be wrong it was not super mesh

[@abdualqaderm.aljbory1418]

ﷺ

[@rohithhb4140]

Thanks sir

[@suniln1967]

Tq sir