Superposition Theorem

[@atriburily1810]

Thank you so much. I found this channel two weeks ago. It has literally made my B.tech EE course interesting.Wish me luck, I am doing my first year this year You've made my life easy. THANK YOU SO MUCH

[@bhagyashririi]

Which other channels did you refer to

[@echoboy45]

​@@bhagyashririi hay 👋🏼 how pass circuits and network theory s3🙂

[@jackie_wa_muranga]

How are you doing now

[@Dineshkumar-xv4xz]

Hearing your voice after a long time please complete these lectures :)

[@landonphemister3941]

Thank you!!!! Reviewing these for my FE exam and totally forgot this concept. Hope you’re doing well in 2021 :)

[@RockstarSham]

Hello

[@supremeleader5516]

What is FE?

[@imsomething2144]

​@@supremeleader5516final exam

[@aryandhakad8495]

I can get perfect notes from you, thanks 😊🤗

[@vinayakayj284]

You deserve million subscribers. No one do this for free. Wish you get healthy and peaceful life 🙏

[@qemmm11]

Much appreciated 😊 (v/4)+(v-6)/8=3, 2v+v-6=24,v=10v

[@underratedgamerff714]

I am currently in 11th standard, as taking Electronics as a Bifocal subject I thought that this is going to be a hard subject when I didn't understand some concepts in start. Now, I know that everything needs to be practiced and there should be no doubt about that topic in your mind. Thanks for this video.👍

[@taka-taktak]

Thank you so much. Your channel is a life saver, you helped me through my electronics courses in Bsc.

[@ranasohaib9637]

Respected Sir i listened your voice after a long time but now a time plz to complete the series. i was really shocked by hearing the news of Neso Academy hacked. And Now i am glad it is back i really appreciate your work. Plz complete the whole series Thank you Sir.

[@mohammedisarezwani]

why cant we find the v using mesh theorem?

[@abhishekshukla9005]

now this is called smooth lecture. no need to show off.

[@psnjathin8615]

Thank you!!! Reviewing these for my 2rs Amrita PT-1. LY mera dil ka dhadkan

[@himanshuchaurasia2427]

You are one of the best channel on this youtube platform i have ever seen for the purpose of study , the way you teach is awesome and really very simple .....thankyou for these concepts .... 👍 And good luck for upcoming lectures ...

[@avinashvishwakarma6488]

very good video for concept clarity and understanding problem solving approach

[@swetachaudhary9220]

Thank you so much neso acedemy. Your lectures are literally superbly wonderful. Helping lot to us for understanding any concept. In this stupid theory exam, we can understand concept and write it by your videos. Helping a lot. Can't describe in words.😁😊😊😎🤘

[@MARVELEDITS-124]

Tq my dear sir😊

[@sourabhjoshi7522]

I understood the concept easily, thank you sir

[@yourbestie4138]

bahut badiya sujeet singh ji

[@kmtazwar8077]

You are the only reason I am going to pass my eee exam😍

[@chirantharushka3873]

simply nicely explained thanks sir

[@ruchithahareendra2973]

Thanks so much!! You explained it in such an easy manner

[@abhinavpingali2154]

Thank you!!! Reviewing these for my 2rs Amrita PT-1. LY meri jaan

[@manishahalale1678]

Very good explaination!!!Thanks sir❤

[@vanshbhatia7890]

very nicely explained ( watching 1 day before exam )

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Happy for you.. got you're channel back 🥳🥳👏

[@mercy2258]

Thank you Sir for all your efforts, if possible bring lectures on power Electronics also sir

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Thanks for the video it actually helped me a lot

[@harshitayadav950]

Love from India ❤️🥰

[@pranavJha93]

he is indian

[@LokeshSawarkar-xq7me]

😂

[@pravallikareddynarala940]

Thankyou so much bro, it was crystal clear

[@vinayakagrawal4171]

Thank you so much sir Really helped a lot

[@LoneWolf25701]

Very nice explanation sir

[@arki3134]

This was very well explained. Thank you!

[@akhilakhil2394]

You are awesome . Best teacher with patience .😊

[@Kenneth-iw8jz]

Niceee explanation Sir. Thank youuu ❣️

[@nisargadk3672]

since current source is open circuited for frst case, same current must flow through 4ohm resistor just like 8ohm resistor na?

[@saikrishnathota5972]

Welcome sir Please complete network theory sir

[@DevRK-xq9mk]

Really helpful video. Thankyou!!!

[@engineer5085]

Thank you very much sir.

[@nithiyanandham875]

After a long time, I am hearing your voice......❤Hearty❤ Welcome teaching God.....please complete network theory as soon as possible...

[@madhavkhindri2817]

Can't we use nodal analysis for this? It would be much easy..

[@muhammadsamiullah6614]

Thanks To Allah, I see this Video After seeing thousand of time waste video lectures and Also Thanks alot Dear Sir

[@amanmangukiya9928]

Useful for daiict students

[@sword0825]

this is really helpful thank you

[@rishwanthsaisingirikonda9584]

Thank you bro you made my day........

[@pallavipolisetty888]

So clear to undestand.... Tq

[@sowmyakundeti9966]

Thanq so much sir....love towards Neso

[@pagadalasumanth7969]

Man u r damn damn amazing the way u explain such heavy topics sooo simply just like thanos snap 🔥🔥🔥

[@deboor1141]

How we recognise the Circuit which is linear or non linear ?

[@SanjayS-y3w]

What if , we supposed to find I , do we need to add two current values in the same way

[@mathiaskovendy7292]

Using current divider in the last bit, shouldn't it be (3x4)/(8+4)?

[@irvinmosoenyane4389]

that is also my concern

[@tetestoes5188]

No, because we are calculating the voltage in the 4 ohm resistor

[@AdityaSingh-pd9fj]

@@tetestoes5188 yea sl it should be (3x"4")/(8+4)

[@emmanuelnwabuike9475]

Current divider rules state that when two resistors are connected in parallel, the current of the source is multiplied by the other resistor divided by the sum of the resistors

[@rafayali3643]

When you use cdr, then the current for the resistor you are calculating, you have to take another resistor than that

[@shashikamadushanka4303]

Thank you sir..

[@shauryasaxena5263]

Tq very much sir 🙏👍 for excellent video

[@jamesroy9027]

Sir Please complete Computer Network and JAVA series...

[@nesoacademy]

You will get the lectures daily.

[@jamesroy9027]

@@nesoacademy Thanks...

[@sunkaraugranarasimha802]

Sir please explain another problems in super position theorem

[@aimlessideas1165]

Absolute legend

[@Walirehman16567]

Any diploma student?

[@gkiran931]

Sir please upload network theory chapters from 4th to 10 in neso academy app..

[@lakshay6043]

Welcome back. 758k strong.

[@subhadepdas9619]

Thank you sir , your channel is more helpful for me ❣️

[@prebenhamretollefseb530]

Very good, thank you!

[@gau3463]

Why did you open circuit one and short the other?

[@solosamuraiz1526]

Did not learn current divider yet. Wish u listed the rule.

[@anabildebnath2590]

this is so helpful

[@Kayumov]

7:34 why you didn't divide 4/4+8? You wrote 8/4+8. Please, explain

[@hasanhan900]

same notation here!!! he solved for I2 probably!! i think that is why you get different answers if you change the current source with voltage source and solve for the voltage with respect to the polarity.

[@EVERYTHING-xu7hg]

This is the problem from the book written by Alexander and matheww...fifth edition ❤️

[@princepanjiyar1078]

Thank you 💞

[@newinformationhub2.0]

Thanks a lot sir..🎉

[@chaitanyaborude5980]

Excellent 👍

[@devAzhar]

Where did the 8/ 8+4 come from. I know that I= V/R the R is 8+ 4 .Where did the division come from?????????????

[@adityavarun1498]

current and voltage division rule

[@udaykiranbade7872]

Sir open circuit means resistance is infinite ?

[@lunalovegood2766]

Superb!!!!!

[@bba2035]

Thank you bro

[@m.varunreddy7365]

Thanks a lot

[@shaikabid5311]

Thank You

[@sachinbisht8227]

sir u replaced the voltage and current source by worng internal resistances

[@saadansari4497]

Explaining way❤

[@masked_wolf391]

good job👍

[@shravjally4896]

Is he trying to. “Mimic SIRI” ?!.!?!😹😹👌🏼

[@tuhinsardar6749]

Thanks

[@phasepanther4423]

So is the voltage in the 8ohm resistor 12v?

[@phasepanther4423]

Or do we have to consider the direction of the current source and voltage source to see that they're in opposition, and therefore have a voltage of 4?

[@SkajDhj]

VIT-AP

[@Harikrr]

VIT. TN

[@nishantgautam7627]

In the step 2, if I replace the current source by a voltage source V= 12v in series with the 4 ohm resistor I get a different answer . Why ?? Also the voltage polarity across 4ohm due to both the sources is different , so should it be v1 - v2 when we do the algebraic sum ?

[@gourav7899]

U probably got 2 as answer. Its the voltage drop across the resistor. 12-2 will give you 10

[@vinayakagrawal4171]

Sir i want to make a project on this topic please please help me

[@BeenaChetan]

Can you plzz give me the PDF of this topic

[@ajitkumarpandit9956]

Yes I am RGPV students

[@niteshgogna]

I'm doing a paper on super position theorem and I can't seem to find who discovered this theorem, does anyone have any answers?

[@somethinglyrical5365]

For first time you have open the circuit and for the second one you have short circuit that So ho do we know when to do what??

[@SillyLittleMe]

current sources are oc and voltage sources are sc

[@sahilrana8576]

Puri video dekh love day

[@kiaranicolebaliwagan9363]

Hello I have a question what if there's 2 voltage source? What shall I do?

[@SillyLittleMe]

if there are two voltage sources,v1 and v2,then first sc v2 and find voltage due to v1 then sc v1 and find voltage due to v2. Follow same steps for current source

[@YOHANISDESE]

best one

[@eyestracker8922]

Problem 2 te to dependent source dhorei korchenn??

[@imruljony2630]

Why can't we solve this with mesh analysis?

[@voidash]

can't we convert the current source into voltage source and solve the circuit?? what is wrong with that approach?

[@nishantgautam7627]

Exactly same doubt. I did that, and got a different answer. Don't know what's wrong here. 😭😭 Also the final answer should be v1 - v2. Polarity due to both the sources is opposite. Don't understand why he simply added it if it's algebraic sum.

[@naveengouda6697]

Can l get notes for network theory

[@sourabrao9168]

Any IITRAM students? 😅

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RAM?

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Anyone from IIT/IIIT/NIT ?

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Nit Agartala

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I'm from symbiosis, better than you peasants

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IIT LONGOWAL

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IIT CHENNAI

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Nit trichi

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Any bvrit students

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Bpit

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Mee bro

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Bvc

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Want some B'olofwo'er

[@jbonez69able]

wouldnt I1 be negative though? making V=6v?

[@nishantgautam7627]

Yess, there's something wrong here. Voltage Polarity due to both the sources across 4ohm is opposite. So it should be v1 - v2 when we do algebraic sum.. Also if I replace the corrent source by a voltage source, I get a different answer. Don't know what's wrong here, but something definitely is!

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Super👌

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Current multiplayer rule kya hai yaar

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Hii guys anyone from Gnits

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🔥🔥🔥