Superposition Theorem with Dependent Sources

[@divyatripathi4439]

This is the best channel for an engineering college student. Simply the best!

[@voiceofjd5901]

Exactly 💯💯

[@nitianhostellife.ShivaGupta]

kaha se ho??

[@qemmm11]

I think so 😊

[@abdoolsattarcassim6717]

This youtube channels layout of teaching is excellent. I love this.

[@SK-rc7ey]

Voice clarity and quality is absolute. Thank you.

[@richardfuchs8865]

Your explanations are very clear. I will refer my students to your channel.

[@sandeeptiwari3655]

Long live sir...... Love you NESO academy......by heart😇😇😇... please keep on uploading network theory lectures

[@azultarmizi]

You have a very beautiful handwriting, it helps with the understanding

[@mihirmishra289]

Jab NESO hai sath toh darne ki kya baat😍

[@girirajyadav3206]

Dependent source voltage Must be |vx2/2| otherwise there will be confusion in polarity

[@nagachaitanyanagachaitanya593]

This is best channel for engineer student but i hqve one dought in circuit their is voltage, current and independent voltage source controlled by current source by using super position theorem

[@sammsamm4034]

Your explanation is very easy to understand. Thank you

[@suheabkhan2546]

Amazing lecture sir....sir when can we expect datastructures

[@nesoacademy]

The work is in progress, chances are there to start DS from the next month.

[@ziakamran1692]

@@nesoacademy love u ustad g

[@nitianhostellife.ShivaGupta]

best video ever i've got

[@PRAVEENTAMMINAINA]

You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

[@somdebsar7378]

Thank you sir for your nice explanation 😊

[@aravind9054]

How can u find dependent and independent source

[@snehshah4973]

What does v_x=0 exactly mean? What does it signify in this circuit?

[@sanishishakhyriemmujat4777]

For finding V2 why cant we use KVL?

[@preetichaudhary732]

According to me Vx2 will be -2/3

[@250eeejagadeesh4]

sister, i have doubt ,due to1A ,why V=-Vx2

[@palkisachdeva8246]

Yesss

[@41.safwansafu85]

@@250eeejagadeesh4 the node have -ve polarity according to the resistor voltage drop i.e Vx

[@Khushi-io7ey]

Sir for finding vx2 can we use current division rule for 1ohm

[@mondalaritra]

Thank you sir..

[@dikshaseth862]

Vx1 should be equal to -i1 because the sign of vx1 is negative. See the first ckt of the solution when we are considering only the voltage source. Correct me if I am wrong.

[@omkarsapte4119]

see the polarity of Vx1 it is same along the current tressing direction... If polarity of Vx1 will interchange then you will get Vx1 equals to -i1

[@guillaume6373]

Thank you for this video!

[@adekunleafolabi1040]

Awesome video

[@krishnakumarmishra3580]

Great job... 🙏🙏🙏

[@Preethi-z1s]

Sir how to know wheteher it is independent or dependent source

[@harshdadwal3088]

Good to see u back

[@pramodkeshari975]

Sir here in nodal analysis why v=-vx2

[@sudhanshukumar3770]

Sir in how many days network theory will be completed so that it will be benefacial for us in gate 2021.sir please reply as it make us comfortable for plannig purpose🙏

[@nesoacademy]

It is not possible to predict the exact number of days but it will be over before GATE exam. Now we’re more committed to complete the ongoing subjects as soon as possible.

[@pasvinay]

@@nesoacademy Sir, the Network Theory course is still ongoing. Kindly could you let us know when the course would be completed? Thank you, Sir

[@qemmm11]

Much appreciated Sir🫡 (V-1)/1-(1)+(V-0.5Vx)/1=0....(1) V-1-1+V-0.5Vx=0...(1) 2V-2-0.5Vx=0....(1) 2(1-Vx)-0.5Vx=2..(1) 2-2Vx-0.5Vx=2..(1) -2.5Vx=0, Vx=0 V+Vx=1.....(2) V=1-Vx...(2) (One minute)

[@NanaBaffour-h1l]

Please, how do you locate the independent source

[@AKSHAY-kx3ln]

Sir can you please add operational amplifier in analog electronics series.

[@himanshusingh8693]

U r amazing.. Sir..

[@64.preranakumbhare5]

Thank you so much sir....

[@nagachaitanyanagachaitanya593]

Hlo. Sis independent voltage source controlled by current source what will. Do

[@madhavkhindri2817]

By nodal analysis I am getting 4/3 volts

[@dikshaseth862]

Same

[@scienceaffairs2919]

Same

[@shitposting2234]

i did it using super mesh

[@QuranTilwatAndTranslation]

Nice method

[@an_archy]

sahi bole sir.

[@simence13]

Can we apply Super Mesh analysis here to find Vx2 ?

[@omkarsapte4119]

Sir can we apply mesh analysis for vx2

[@AndrewKiethBoggs]

We don't know the voltage across the current source, so we could use super mesh analysis instead.

[@shitposting2234]

@@AndrewKiethBoggs but us se answer nnahi aa rha mera

[@rudrakshmaurya1061]

Can't we apply voltage divder rule when we consider 1v source

[@baringkiron5375]

yes!

[@biuhalchatterjee2775]

Sir in case 2 why V= -Vx2/2? I didn't get the reason of negative sign. Kindly explain. 🙏

[@nannubedi7773]

because current direction is opposite

[@leminh3482]

You can think of it as going from the positive terminal (higher voltage) to the negative terminal (lower voltage) you have a voltage drop of V = -Vx2/2 (the current in this case goes from the positive to the negative terminal). If you have the current goes in the opposite direction V = Vx2/2. Hope this will help.

[@sahil-of4jb]

Wrong method in nodal .. practically not possible all outgoing current in one node

[@yash1152]

what does the diamond symbol mean?

[@AaronLAB]

It's an dependent voltage source

[@yash1152]

@@AaronLAB ohkay, i don't know about them... > _"It's an dependent voltage source"_

[@monicaarmin1508]

How would i know which source is dependent and which is independent?

[@kalendemercy1651]

Dependent sources always have a standing rhombus with + - sign for a voltage dependent source and an arrow for current dependent source

[@continnum_radhe-radhe]

🔥🔥🔥

[@raisasultana2077]

5:41

[@manish2747]

1:57 Does someone hear the sound of dogs barking in the background??

[@nannubedi7773]

where?

[@manjeetsingh2841]

sir how V=-Vx2

[@PRAVEENTAMMINAINA]

You

[@uhhbby_07]

did all this just too find v=0 -_-

[@akhilkrishnan3410]

😌😌❤️

[@digital-zm]

It was nice if you didn't use video animation. It distracts attention

[@PRAVEENTAMMINAINA]

You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

[@PRAVEENTAMMINAINA]

You are contradicting what you said in nodal analysis sir, when there is a voltage source between a reference and non-reference node it becomes the voltage of that node then we don't do it any further

[@davidalbigensechilengi]

You're right he said that but he actually meant , of which he was correct, that it only becomes the voltage of the node if there's no other branch (resistor for instance) between a nonreference node and the reference node. If there's only a voltage source between a nonreference node and the reference node then the voltage is equal to the voltage of the nonreference node. I hope that will help..

[@davidalbigensechilengi]

But for this question there's a resistor as well as a voltage source between a nonreference node and the reference node.

[@davidalbigensechilengi]

This is because there's voltage on the source as well as on the resistor. That's how I understood.