Suzuki Mechanism

[@majedbajaber]

Short, informative, and sufficient. The best description in youtube.

[@sarahchem4219]

Majed Bajaber Thank you!

[@imbunche2008]

One of the most important reactions in modern pharmaceutical synthesis!!!

[@Enhydra_l]

This video was super helpful, had no idea how Suzuki worked until I watched this. Way more clear an explanation than anything else I found. Thank You!

[@sarahchem4219]

Thank you Andrew! Glad to hear it was clear :-)

[@thatcurtisbrother]

Ma'am you are a saint, I have been roaming the internet trying to find a straightforward explanation. I found that here, thank you much and great job on the video

[@sarahchem4219]

+Jake Curtis Thank you so much! I appreciate your comment and am really happy to hear that it helped :-)

[@DermBeautyMD]

so helpful thank you!! you explained this so clearly my textbook makes it sound crazy

[@sarahchem4219]

+Kaur Beauty - lol, thank you :-)

[@goldykaran8663]

You are really beautiful kaur beauty

[@kaboose64]

Really useful. Made the whole suzuki reaction process easier to understand. Thank you!

[@sarahchem4219]

+thomas wales Thank you so much - really glad it helped!

[@eysansezer2505]

I'm so glad to find your videos on KZbin! It reealllyy helps me a lot and I can understand at once. Can't thank you enoughhh

[@Officials.iitianschemistry]

SARAH you explain Suzuki reaction mechanism in an impressive way ...thanks for posting this video...& keep posting

[@sarahchem4219]

Thank you! I really appreciate that!

[@arrache1]

Your video helped me a lot with my reactions in laboratory. Best video I've found so far!

[@sarahchem4219]

Guilherme Arraché Thank you! So happy it helped!

[@ishanj777]

Best ever video 🤩 👍 Thank you so much ma'am

[@DEEPAKSIR_IITG]

Love you ma'am to your teaching style

[@sarahchem4219]

Thank you!

[@nokuphiwamadlala8715]

O.M.G. wish you could be my lecturer...thank you

[@sarahchem4219]

Nokuphiwa Madlala So happy that it helped - thank you :-)

[@puretwr899]

I can understand it within 3 minutes!! Amazing Thank yoooou

[@celineblaze3921]

fabulous mechanism taught by you.

[@sabithasangem1134]

Really sweet sis explained in sweet and short way.. Thank you

[@butchfro24]

Very well done. Excellent description

[@sarahchem4219]

Thank you!

[@jacoboaguilera4970]

Really helpful !! thank´s Sarah, you are an excellent teacher!

[@fatbugz2919]

Great explanation! Why is it that guys watching these videos have to comment on looks? Take it easy horndogs, it delegitimizes the work.

[@islamelsheikh7161]

Thank for your simple explanation.. Go on your marvelous work The videos were amazing but it will be better if you have the all steps on your board like songshira mechanism i really liked that Thank you again from egypt

[@sarahchem4219]

Thank you for your feedback; I will definitely keep that in mind!

[@brayanenriquesotomayorospi9249]

God ! ... Thank you.. the description was great.. finally i get this reaction, you were of a lot of help to me.

[@sarahchem4219]

BRAYAN ENRIQUE SOTOMAYOR OSPINA Thank you! I'm happy it helped :-)

[@agustins1401]

I don't speak English, but your explanation helped me a lot. I'm using translator xD. Gracias, por si de casualidad entiendes español :)

[@sandeepjaiswal9467]

Thank you so much, you are explaining very simply

[@Broccoli821]

Good explanation. But you picked a poor leaving group. Iodide is relatively more reactive compared to Bromide. Bromide reacts much slower in comparison. Chloride would be worse. As an update 3 years later - 'R-I' would work perfectly fine. The R-Br was not the best example to set in a coupling reaction like this, especially when Iodide is used actually quite frequently in it.

[@HarshPatel-xn6du]

Greatly explained in just 3 to 4 minute ..thank you😊

[@ajayjakhar4775]

do u have any video about sonogashira cross coupling reaction coz u explain so well .....

[@sarahchem4219]

kzbin.info/www/bejne/g3SqiaeZdrFnbM0&lc=UgxrKqajAXUs3MCaLJB4AaABAg

[@asadzaheer3996]

Excellent way to express. thanks

[@sarahchem4219]

Thank you!

[@sagarpatel7122]

Thanks for this video... Really helpful for me and others. Plz upload more videos...

[@sarahchem4219]

I will keep trying to add to the videos set - thank you! :-)

[@llauren8639]

such a great and clear explanation! thank you very much! it is very helpful!

[@sarahchem4219]

Thank you! Happy to hear that :-)

[@lucyaudrey733]

thank you for your great explanation keep posting

[@sarahchem4219]

Thank you! I definitely will be adding more soon :-)

[@Tnpscremembertricks]

Nice explanation mam... What is the reference books for this topic please tell me madam...🙏🙏

[@Zeppelinpuppy]

Hi, great explanation. What type of board/markers are you guys using? Because I wanna make one for my livingroom. Thanks

[@sarahchem4219]

Thank you! I bought the board on Amazon. I can't recall the name of the board - but I typed in glass blakboard as my search terms. The markers are chalk markers. Hope that helps!

[@ThorirLenvik]

Yes, metals like palladium and relatives, have been changing organic synthesis, dramatically in the last few decades. It's almost become to easy to make new C-C bonds...

[@manoharan1155]

hi really it's a very nice short explanation. all the best.... i have one doubt that in the second step i.e bromine elimination and formation of Pd-OH intermediate. really like that way it is going or it is going as a four member cylic transition state? i don't know really. can you clarify my doubt. thank you....

[@sarahchem4219]

Hi +Mano Haran. I don't see there being a benefit in forming a 4 membered cyclic transition. There is typically a lot of strain in a four membered ring (which is not to say that it won't ever happen in a reaction) but I don't think that it would be favorable (energy wise) to form that ring when there is a way to kick off the bromide (which is a great leaving group). In the video I wanted to show the most energetically favorable reaction - I definitely believe that it would be much easier to replace a bromide with a strong nucleophilic hydroxide than to form a ring. I hope that helps!

[@manoharan1155]

+Sarah Chem thank a lot. I have this doubt long time because some times carbonate kind of bases also can work. I got very clear clarification from you. Thank you so much once again....

[@sarahchem4219]

+Mano Haran Thank you for the question! I'm happy I was able to help!

[@haribo1319]

Amazing video god bless!!

[@quintonwilson8565]

Why isn't the organic substituent on the boronic ester jumping onto oxygen preferentially over Pd? Furthermore, the oxygen is already drained of electron density, making it even more favorable.

[@smartkhan2022]

Nice mam very helpfull

[@sarahchem4219]

Thank you!

[@andywong1706]

Could you please explain a little about why C attach to metal that has an close EN to it during the transmetalation step?

[@nasriqbal5841]

Mam you r good teacher but so gorgious

[@nirvanaselic]

Excellent!!!

[@kindlygentleman]

Thanks so much! Just curious, what does L stand for? Just any R group?

[@Thors0n]

L is the symbol for "Ligand"

[@sarahchem4219]

Exactly Thors0n - L=ligand

[@mistersirisaacnewton]

thank you so much, this is amazingly helpful for understanding the concept!

[@homayounhashimi2125]

thank you, it was so short and so helpful

[@govindaraokonna7901]

U did very well, I need more video s from u😍

[@sidewaysfcs0718]

you could actually show with arrows that the alkyl halide coordinates to the palladium center, which by the way is initially PdL4, usually tetrakis-(triphenylphosphine)palladium(0) or some derivative with bulky ligands.

[@sarahchem4219]

Hi sidewaysfcs0718 - This video is based on the mechanism as described by Paula Yurkanis Bruice - using PdL2 rather than PdL4. As, is often the case with chemical reactions, there are quite a few variations of the catalyst used...in fact, there are some variations that use a Ni catalysts rather than Pd. These two articles linked discuss the reaction using PdL2 catalysts pubs.acs.org/doi/abs/10.1021/jo900178c www.ncbi.nlm.nih.gov/pmc/articles/PMC2645945/

[@benscrafield9575]

Palladium tetrakis is an 18-electron complex, so we would expect it to undergo ligand substitution by a dissociative mechanism. As Sarah has explained, two phosphines are believed to come off to allow for oxidative addition of the organohalide; two co-ordination sites need to be free, and it is a d8 metal, so we expect the complex to be square planar.

[@pavankumargondrala5420]

Thank you so much

[@leehyun6274]

how would you explain quaternarization of boron? I mean the quaternization of boron atom with an anion from base.

[@runningaround2]

Thank you !

[@sarahchem4219]

runningaround2 Happy to help!

[@celesteczarnecki3304]

Could you give any insight on how the suzuki reaction is steroeselective?

[@AB-qo6zt]

Made it so easy, thanks!

[@sarahchem4219]

+Ajay Banga Thank you!

[@navidghorbani1729]

you are fantastic

[@rajeshwaran618]

pls give explanation about stereochemical background

[@prakashbishnoi6593]

Very nice

[@pramodmd2581]

Tow thumbs up 👍👍.. super

[@sarahchem4219]

Thank you!

[@kirubabowneeth3928]

Thank you...really useful

[@chemist7862]

well explained.. 👍

[@anuja_k7946]

Thanks

[@maheshtumkurmaheshkp3903]

Madam ...i love u ....osm concept

[@sarahchem4219]

Thank you! Happy to know it helped!

[@raghavym4964]

Thank you.. you explained it so well... please be my lecturer haha :)

[@sarahchem4219]

Raghavy M :-) lol - thank you!

[@raghavym4964]

Sarah Chem u welcome.. can you do one on the waker process please :)

[@sarahchem4219]

I am away from my recording location at the moment - as soon as I am able I will definitely get one up for you!

[@raghavym4964]

Thank you!

[@sarahchem4219]

Raghavy M I just wanted to let you know that I have been researching some aspects of the Wacker process - the issue is that there are quite a few disagreements among organic chemists as to the exact steps of this very involved mechanism. Do you know which version of the process is preferred by your prof?

[@soplv605]

Hi, I have a question about the reaction shown at 0:59, on the left side you show a halide (X) being pushed out and on the right side we see Br- has been pushed out. Now can this X be any halide or is it typical for the suzuki mechanism to have Bromine?

[@sarahchem4219]

Most often it will be Bromides or iodides because of their favorable reactivity.

[@soplv605]

Thank you :) I had an exam on transition metals yesterday and your video's helped me a lot!

[@rockon1333]

Thanks!!!

[@sarahchem4219]

Happy to help :-)

[@peta890]

This as very helpful!!!! :) THANK YOU!

[@sarahchem4219]

Peter Pham So happy to help!

[@bismarasool8752]

Why only pd catalyst can be used for Suzuki reaction and not any other transition metal catalyst??

[@amarkus8830]

Thank u!!

[@satyakimondal3290]

Why water used in suzuki reaction as co solvent?

[@abdulelahmohammed6645]

great

[@elit3chemist958]

too helpful :)..... please make video about negishi coupling reaction

[@abhishekpednekar8468]

Good

[@sarahchem4219]

Thank you!

[@hareshwarahire6259]

Nice

[@petretudor6122]

but why are aril halides reacting with pd? is there any specific reason , because i used to think that they wouldn t have why to react and things like that , thaaanks in advance :)

[@santiagocardenas41]

idola

[@ishfaqwani9216]

Thanks man

[@nirazit]

isn't R and X trans to each other in Oxidative addition # just asking

[@esthermonari1928]

🎉🎉

[@ouxubiyu2685]

i love u Sarah ^_^ thank a lot

[@sarahchem4219]

+Xu Wangguan So happy to help! :-)

[@CartoBalow]

Nice video ! Subbed :D

[@sarahchem4219]

+Cartoo Thank you!

[@inspirewithitself9522]

Thank s mam i request to you that give some time to note down

[@j.a.7047]

I learned something, and fell in love.

[@sarahchem4219]

lol - glad the video helped!

[@dipzzxx31]

What about the stereochmistry??? Tell me please

[@muhammadasadullah7219]

this is a massive blow

[@mohamedesmael1353]

If you may help me, you said: "the best group to get rid of would be the halide" why ?! cause of its reactivity?

[@sjoerdklomp3931]

Products of strong acids are good leaving groups. So chloride for instance is a good leaving group because it comes from hydrochloric acid.

[@mohamedesmael1353]

sjoerd klomp thanks

[@sleela3926]

Sarah can u plz explain group theory step by step plz

[@sarahchem4219]

I definitely can - but I have to say that my request list has grown a little crazy. I'm not sure I could complete by the time you needed it.

[@sleela3926]

Oh ...thank u for reply...but plz try to ...

[@SandeepRasaily-jq2mp]

What is L here?

[@satadhi]

Mam in which course is this included ??

[@sarahchem4219]

Organic Chemistry :-)

[@satadhi]

no i mean the course !!! level ?? Bcoz i dont have .

[@sarahchem4219]

Satadhi Halder 109B

[@Rudra-db5oh]

2.04min video = Palladium electronegativity is 2.2

[@glyoxalanhidrage5495]

Mathe giye ghass kat ei cheee

[@pankajdahiya5764]

Camera angle is not good