What about, for the second example, we have the bounded input Sin(t)? The input is bounded from -1 to 1, and the output (the integral of the function from 0 to t) is bounded from -2 to 2 so we could choose a = 3 for example. Or, are we making an assumption that the signal is being rectified?
@Ensign_Cthulhu12 жыл бұрын
Excellent lecture, concept-wise. However, you seem to be having problems with audio quality = wavering and crackly. Either that or you have the world's biggest frog in your throat, in which case get well soon.
@kedharguhan8 жыл бұрын
why is exp[at] unbounded signal? It IS bounded whenever t is bounded, right?
@burlapsack77598 жыл бұрын
It is BIBO stable only when both the input and output are bounded for ALL t. So you can't consider when t is bounded.
@exile3413 жыл бұрын
How do you plug in u(t) in the integral ?
@exile3413 жыл бұрын
is x(tau) = x(t)? meaning x(tau) the input?
@marisolsolis83699 ай бұрын
Thanks for the explanation!
@AntonisGrr8 жыл бұрын
Very good vids. Congrats and tons of gratitude here, I think that the system at 6:34 computes the algebraic area under x(τ), not the actual area. The parts below the y-axis are being subtracted from the positive ones.
@clintondsilva13748 жыл бұрын
could u teach me cross and auto correlation??? post something on it
@saadurr6 жыл бұрын
that is more like digital signal processing, not control systems.