NOT EASY to Solve this polynomial equation - USE This! (Rational Root Theorem)

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TabletClass Math

TabletClass Math

5 ай бұрын

How to solve a polynomial equation by locating and finding possible rational roots and zeros using the rational root theorem.
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Пікірлер: 15
@GeorgeHChaney
@GeorgeHChaney 23 күн бұрын
John, I have been working your problems for over a year so far. I investigated several other sites that work similar to yours and found them sorely lacking in detail. My original study was all the math's up to and including two semesters of Calculus, but that was 55+ years ago. Currently could not Calculus my way out of a wet paper sack. I am finding your content and explanations most excellent. Thanks.
@charlesmitchell5841
@charlesmitchell5841 5 ай бұрын
Good lesson! 👍
@mollymam7153
@mollymam7153 5 ай бұрын
Thanks for the review. Haven’t used this method in years!
@russelllomando8460
@russelllomando8460 5 ай бұрын
interesting and fun. thanks.
@roger7341
@roger7341 5 ай бұрын
Cubic equations with real coefficients always have at least one real root. Often it is possible to find a real root by inspection, as in this case. x=1 is a real root. If a real root cannot easily be obtained by inspection, Newton-Raphson iteration may be used. Let f(x)=4x^3-13x^2+11x-2 and f'(x)=12x^2-26x+11. Then make a plot to estimate a root and set x to that value. Then iterate x←x-f(x)/f'(x). Once the root has been determined, divide by (x-1) in this case to obtain 4x^2-9x+2=0. The quadratic solution yields x=(9±7)/8=2 or 1/4.
@darkst0rm2
@darkst0rm2 5 ай бұрын
1:49 Brute forced this one again. Waiting for the explanation of the math. 4:03 bummer, I missed the .25 part of the answer :(
@thomasraywood679
@thomasraywood679 5 ай бұрын
I'm going with 4x^3 - 13x^2 + 11x = 2. If that's incorrect, someone please let me know.
@maxinenesbitt4102
@maxinenesbitt4102 5 ай бұрын
1, 2, 1/4
@samswift4921
@samswift4921 4 ай бұрын
I got 2, but not the others
@stevereade4858
@stevereade4858 3 ай бұрын
x=1 by inspection. Took 15 secs.
@mikepearson1057
@mikepearson1057 5 ай бұрын
The answer is 1/4 not -1/4. When you displayed the solutions at the end you had negative 1/4.
@terry_willis
@terry_willis 4 ай бұрын
I noticed that too. What happened? It appeared he caught his mistake and then back tracked and kept -1/4. Which is it?
@leetrask6042
@leetrask6042 5 ай бұрын
Personally I think the best way to solve these equations is to graph them.
@harrymatabal8448
@harrymatabal8448 3 ай бұрын
X-1is a factor. Divide to get a trinomial and factorize the trinomial ans solve for x for less than 20 minutes. Wasting time
@mr.mxyzptlks8391
@mr.mxyzptlks8391 17 күн бұрын
Did not watch yet. But already feel like I will disagree with “must know”, for this problem. Maybe for higher orders it becomes a must 🤓. Because it exists, I would apply the formula for cube polynomials. Not nearly as simple as for squares, but it exists, though I think it is not taught, ever…. 4th powers, I recall, can be solved by applying what I expect is part of the vid to show. 5th powers, and above, are proven to just never have a ‘simple’ (closed form) formula to follow. We’ll see if I get to eat my words …
ONLY those Math students STRONG in factoring can do this easily.
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