TCS-Infosys-IBM Interview Question |Decimal to Binary | Daily Dose -32 | Tamil | code io

[@gowsalyar.s1377]

Binaryl%10 remainder value reverse print in decimal values 😁

[@prithiviraaj5090]

Multiply the digits to 2^N, where N belongs to (0,len (binary)) and find its sum.

[@codeio]

👏👏👏👏 Awesome....

[@prithiviraaj5090]

@@codeio Thank you 🙏 🙌

[@HdjshHdhhhs]

Bro pattern printing solli kudu ya easy ah

[@nithishkumark1644]

Digt(0)*2⁰ + Digit(1)*2¹ +....+ Digit(n)*pow(2,n)

[@codeio]

Awesome na👏👏👏👍

[@KARTHICKRAJKR]

Tcs ninja ku coding varuma??

[@ECKSivakumar]

#include using namespace std; int main() int n=1010; int base=2; int exponent=0; int r: int sum=0; while (n!=0) { int result=1; r-n%10; for(int i=0;i

[@dethia1220]

int n = 100001; int ans = 0; int fact = 0; while (n != 0){ ans += n % 10 * Math.pow(2 , fact) ; fact++; n /= 10; } System.out.println(ans);