If you jump out of an airplane, how does your speed change as you fall?
Пікірлер: 184
@savagewill46505 жыл бұрын
I wish I could write backwards like that
@AkashdeepSingh-qq5fw4 жыл бұрын
if you think he is writing backwards then he isn't. kzbin.info/www/bejne/m4eygXeHarCMqdE kzbin.info/www/bejne/eYirfqeJg7Crj6M&feature=emb_title the teacher is writing normally like everyone. He just somehow flips the video, in this case very likely with video recording. If you do not believe, look at the professor. most of the teachers who write on glass seem to be left handed. But statistically mostly are right handed. So this means that the video has been flipped on the vertical axis, so in this way the words that look opposite look normal. While the teacher image will also be flipped, since he is inside that video or image. This is why a right handed person looks left handed and vice versa.
@jeffakoima95293 жыл бұрын
that's why he's the professor
@alvaroakatico91883 жыл бұрын
@@AkashdeepSingh-qq5fw I learned something today. Thank you.
@lachlanc94593 жыл бұрын
So his class just has to read backwards… unlucky
@joeKisonue2 жыл бұрын
Lol, right???
@deependraverma43825 жыл бұрын
I could feel your passion for physics, & I must say that is beyond words.
@yoprofmatt5 жыл бұрын
Thank you. Love this comment. Cheers, Dr. A
@alvaroakatico91883 жыл бұрын
The fact that he has a PHD before his name gives it away, but I understood your query.
@lilymatthosinhos20862 жыл бұрын
@@yoprofmatt thanks for teaching the subject :) i couldnt find any video that catched my attention and manadged to keep it for longer than 2 minutes in portuguese before realising "oh wait,im bilingual and theres probably more videos in english than in portuguese" so i searched it up and am now seing your video and being able to learn the subject and i hope this will be enough to make up for me distracting myself and falling behind on class :)
@frankdimeglio8216 Жыл бұрын
@@yoprofmatt WHY AND HOW what are OBJECTS MAY FALL AT THE SAME RATE IN FULL CONFORMITY WITH WHAT IS E=MC2: CLEARLY, this is a gigantic breakthrough in physics AND mathematics. WHAT IS E=MC2 IS dimensionally consistent. TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE, AS ELECTROMAGNETISM/energy is CLEARLY AND NECESSARILY proven to be gravity (ON/IN BALANCE) !!! GREAT. WHAT IS GRAVITY is, ON BALANCE, an INTERACTION that cannot be shielded or blocked !!!! MAGNIFICENT ! Consider what is THE EARTH/ground ON BALANCE !!! Consider what is THE EYE ON BALANCE !!! Now, consider what is the TRANSLUCENT AND BLUE sky. CLEAR water comes from what is THE EYE. (THE EARTH is ALSO BLUE.) Fantastic. The stars AND PLANETS are POINTS in the night sky. BALANCE AND completeness go hand in hand. It ALL CLEARLY makes perfect sense ON BALANCE. INDEED, LOOK at what is the orange (AND setting) Sun !!! GREAT !!! Consistent WITH WHAT IS E=MC2 (AND WHAT IS TIME), “mass"/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent WITH/as what is BALANCED electromagnetic/gravitational force/ENERGY; AS ELECTROMAGNETISM/energy is CLEARLY AND NECESSARILY proven to be gravity (ON/IN BALANCE) !!! (BALANCE AND completeness go hand in hand !!!) Great. Gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE (ON BALANCE), AS TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE; AS ELECTROMAGNETISM/energy is CLEARLY (AND NECESSARILY) proven to be gravity (ON/IN BALANCE) !!! This IS consistent with WHAT IS E=MC2 AND F=ma !!! (ACCORDINGLY, ON BALANCE, the rotation of WHAT IS THE MOON matches the revolution.) Indeed, inertia/INERTIAL RESISTANCE IS proportional to (or BALANCED with/as) GRAVITATIONAL force/ENERGY; AS TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE; AS ELECTROMAGNETISM/energy is CLEARLY (AND NECESSARILY) proven to be gravity (ON/IN BALANCE) !!! This IS consistent with WHAT IS E=MC2 AND F=ma !!! GREAT. ❤️❤️❤️ I have mathematically unified physics. FACT. THINK. By Frank Martin DiMeglio WHAT RELATES GRAVITY TO WAVE/PARTICLE DUALITY?: WHAT IS E=MC2 does. TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE, AS ELECTROMAGNETISM/energy is CLEARLY AND NECESSARILY proven to be gravity (ON/IN BALANCE) !!! ACCORDINGLY, ON BALANCE, the rotation of WHAT IS THE MOON matches the revolution !!! The stars AND PLANETS are POINTS in the night sky. WHAT IS GRAVITY is, ON BALANCE, an INTERACTION that cannot be shielded or blocked. CLEAR WATER COMES FROM WHAT IS THE EYE. Consider what is THE EYE ON BALANCE, AND consider what is the TRANSLUCENT AND BLUE sky. Consider what is THE EARTH/ground. NOW, consider WHAT IS the ORANGE (AND setting) Sun ON BALANCE !!!! Great. THE EARTH is ALSO BLUE. Consider what is the BLUE flame. WHAT IS E=MC2 IS dimensionally consistent. Magnificent❤️. That what are OBJECTS may fall at the SAME RATE is FULLY consistent WITH WHAT IS E=MC2 !!! GREAT !!! TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE, AS ELECTROMAGNETISM/energy is CLEARLY AND NECESSARILY proven to be gravity (ON/IN BALANCE !!! Consistent WITH WHAT IS E=MC2 (AND WHAT IS TIME), “mass"/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent WITH/as what is BALANCED electromagnetic/gravitational force/ENERGY; AS ELECTROMAGNETISM/energy is CLEARLY AND NECESSARILY proven to be gravity (ON/IN BALANCE). Accordingly, ON BALANCE, what are OBJECTS may fall at the SAME RATE in FULL conformity WITH WHAT IS E=MC2 !!! Great. I have revolutionized physics. GRAVITATIONAL force/ENERGY IS proportional to (or BALANCED with/as) inertia/INERTIAL RESISTANCE, AS TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE, AS ELECTROMAGNETISM/energy is CLEARLY (AND NECESSARILY) proven to be gravity (ON/IN BALANCE). This is consistent with WHAT IS E=MC2 AND F=ma. Accordingly, ON BALANCE, the rotation of WHAT IS THE MOON matches the revolution. Accordingly, ON BALANCE, what are OBJECTS may fall at the SAME RATE in FULL conformity WITH WHAT IS E=MC2 !!! Great. Gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE (ON BALANCE), AS TIME is NECESSARILY possible/potential AND actual ON/IN BALANCE; AS ELECTROMAGNETISM/energy is CLEARLY (AND NECESSARILY) proven to be gravity (ON/IN BALANCE) !!! This IS consistent with WHAT IS E=MC2 AND F=ma !!! I have surpassed Newton and Einstein. By Frank Martin DiMeglio
@Aditi_13194 жыл бұрын
sir you are straight forward in teaching and this is amazing....
@frostytacos94764 жыл бұрын
1:00 scared the living shit out of me
@yoprofmatt4 жыл бұрын
Connor, Talking to you, Connor! Too funny. I should add more names in randomly. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@mungy277 жыл бұрын
Wish I could get a professor like you just once. (even though I'm not currently studying this, curiosity brought me here lol)
@doenglapitus49864 жыл бұрын
Don’t ya just hate people who say lol ALL the time? Btw, Felix Gonzales, nice profile pic 🙈
@1light4love4 жыл бұрын
my 2nd Remote (Online) Physics exam brought me here! But I was thinking the same thing.....(altho honestly, I'm nust sick of trying to learn Physics online... and we're not even half way thru the semester😭)..... where do you teach, Professor?
@raghabbasnet6479 Жыл бұрын
Same brother
@ThePancakeRenegade2 жыл бұрын
My D&D Group wants to drop a group of elephants on a big bad enemy we encounter and so here I am learning about terminal velocity to see what height we need to drop it from in order to kill the boss. Thanks for the lecture Professor Anderson, I enjoyed learning!
@Leo-sp6cr2 жыл бұрын
make sure to make the elephants as aerodynamic as possible, will increase terminal velocity
@xtrphantom85713 жыл бұрын
Professor Matt ... i really really like your way of teaching ..I really understood well..you explain better than my high school teacher....i wish you were my class teacher. :)
@jaritobruh68853 жыл бұрын
thankyou so much, we watched this while loading into a quick match, it kept us very entertained and we appreciate what you do.
@juanmanuelmillansanchez81655 жыл бұрын
Dr. A awesome videos, you should have a spot in Khan academy. Greetings from Colombia
@elielmurmu4 жыл бұрын
Just a perfect explanation! Thank you very much professor!
@siddharthdyavanapalli46177 жыл бұрын
your students are intelligent
@yoprofmatt7 жыл бұрын
Thanks, I think so too. Cheers, Dr. A
@myakudoyoru Жыл бұрын
Everything from the guitar, the trumpets, the drumbeat, and the level itself show just how great and creative Sonic Colours is- wait a minute...
@Ztvp223 жыл бұрын
Superb explanation sir... Congratulations from sri lanka... 💙
@hafsaabbasi16 Жыл бұрын
Your way of teaching is awesome You clear all the concepts Very well explained
@axeldimblad56204 жыл бұрын
so important and straight forward!
@yoprofmatt4 жыл бұрын
Axel DIMBLAD, Great comment, thanks. You might also like my new website: www.universityphysics.education Cheers, Dr. A
@willoughbykrenzteinburg Жыл бұрын
The most impressive thing about this presentation is his ability to write backwards.
@mdzia-jr2ivАй бұрын
Thank you very much professor!
@MissusGame4 жыл бұрын
This video is old and has a chance of being unreliable, BUT it did help me a lot with science work
@yoprofmatt4 жыл бұрын
FNAJ Development, Thanks for the comment, and yes it could use some updating. You might also like my new website: www.universityphysics.education Cheers, Dr. A
@manuboker13 жыл бұрын
GREAT PHYSICS LECTURES !!! :))
@charles727727 Жыл бұрын
Thank you Matt! So clear! I am ready to jump now :)
@markanthonycacal55636 ай бұрын
This helped me a lot to understand terminal velocity but what I am more interested in now is how he's writing backward for us viewers to understand what he's talking about.
@rangavenkat51045 жыл бұрын
Okay u r writing with left hand and in reverse view that's right there is really impressive
@kn7614 жыл бұрын
That's not what he's doing you moron. Use deductive reasoning.
@kriptos23555 жыл бұрын
Thank you for the lesson
@orlando_2544 жыл бұрын
So interesting Prof.
@samuelmoreira51282 жыл бұрын
Watching from brazil, great video professor!
@kingsleydeng94263 жыл бұрын
flexing the bbackward writing i see
@amaypatel2765 жыл бұрын
nicely explained!
@nafisayo36663 жыл бұрын
nicely explained . thank u ☺
@yvonnejohnson37104 жыл бұрын
Thank you!
@krisitak8 жыл бұрын
Thank you. Very cool video.
@yoprofmatt8 жыл бұрын
Krisitak, You are very welcome. Cheers, Dr. A
@buzyreading4 ай бұрын
"Airplane! Airplane!"
@themeditatingdog64024 жыл бұрын
Prof.Anderson Somewhere around 10:00 you said the bowling ball would hit the ground first. If you were to switch the balloon with a basketball,they would fall at exactly the same rate. Even though their masses are still different.Why is this not true in the case of a balloon? If you could clarify that,it would help me a lot. Many thanks, Aaron.
@yogeshpatel6174 жыл бұрын
asked the same question by mail.. please share ans once you get
@superbart30002 жыл бұрын
I believe it has to do with the Buoyancy of the objects. In a vacuum, they absolutely would hit the ground at the same time, any 2 objects will regardless of mass or shape. They did this experiment in a giant vacuum chamber with a bowling ball and a feather. But in the case of a balloon or basket ball, the air inside it makes it buoyant, which is a force preventing it from falling as fast, as the denser bowling ball. The basic principles of fluid dynamics for water and air are the same, except the density of the environments are different. Imagine then, dropping the bowling ball and the basket ball into a pool, the bowling ball would sink, but the basket ball would float, despite being the same shape and despite the forces of gravity pulling them downward at the same constant force. This is because the basket ball is more buoyant than the bowling ball. The same thing happens in air, but to a lessened degree since air is much less dense than water. This is also the same reason why helium balloons float, despite the fact that both the balloon and the helium inside it have weight and therefore should be affected by gravity. But the buoyancy of the helium compared to air, creates a force greater than the downward force of gravity. Thereby pulling it up, instead of down. Floating, instead of sinking.
@themeditatingdog64022 жыл бұрын
@@superbart3000 Firstly I'd like to thank you for taking your time and answering my question with such detail. I didn't take into account the buoyancy and I also believe it has something to do with that, but something still doesn't add up. You mentioned they'd fall and hit the ground at the same time in a vacuum but they would also hit the ground at the same time in absence of a vacuum (there's a video from Veritasium which shows this, though he is using a medicine ball instead of a bowling ball. Regardless, the priciple is the same). The reason for this is inertia as mention in the video. Is there something I'm not taking into consideration?
@superbart30002 жыл бұрын
@@themeditatingdog6402 hmm, if they have the same drag and buoyancy isnt a factor. Then yes they should hit the ground at same time. On earth all objects fall at a constant acceleration of 9.8 m/s2 regardless of mass.
@imstuckwiththisusernamefor21904 жыл бұрын
So, does that mean, if I am in a vacuum, I could accelerate forever, even reach light speed?
@CPrasannaDarvekar4 жыл бұрын
yes as there is no opposite force to stop ya Newton's First Law of Motion kid
@imstuckwiththisusernamefor21904 жыл бұрын
@@CPrasannaDarvekar i like how you wrote "kid" in the end and yes im kid
@yoprofmatt4 жыл бұрын
-CHARRED -, You will keep accelerating if you still have some sort of propulsion, like a rocket engine. And no you can never reach the speed of light because that would require infinite energy. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@imstuckwiththisusernamefor21904 жыл бұрын
Matt Anderson So, even in vacuum, while I’m infinitely falling down by gravitation force (9,8) I will have some kind of terminal velocity, or I didn’t understand you properly?
@EF-wy3di3 жыл бұрын
@@imstuckwiththisusernamefor2190 You can't fall infinitely. You only fall if you are pulled by gravity. Gravity only pulls towards a large mass. To fall infinitely would mean the space between you and this large mass is infinite. One mass that has an gravitational pull strong enough to pull something from an infinite distance would turn the universe into a singularity, in which time and space wouldn't exist. You can't accelerate without time or space.
@changenoways9555 Жыл бұрын
10:07 the bowling ball does not hit the ground first due to gravity, it hits the ground first due to air resistance acting on it greater than the belon
@changenoways9555 Жыл бұрын
if it were just gravity they would fall together
@perenflo86034 жыл бұрын
I never liked classes where the teacher calls on students by name to answer questions. It made me so nervous I would end up not picking up anything from the lecture. I still got good grades in these type of classes because I just read the textbooks and studied hard.
@yoprofmatt4 жыл бұрын
Per Enflo, The ones in my audience were all volunteer, so they sort of knew I would call on them. But appreciate your comment. You might also like my new website: www.universityphysics.education Cheers, Dr. A
@164emanshahid43 жыл бұрын
An amazing concept
@gravitycube430 Жыл бұрын
I have a questio: it is quite late like 8 years now but you said when we get to the terminal velocity the air drag will be equal to the gravitational force. Doesn't that mean the object making a free fall will be in balance.which I don't understand. And thanks
@changenoways9555 Жыл бұрын
Yo I have been watching these videos for the last 10 years. How do these people write right to left? is the axis flipped in the settings of the camera?
@kevilynx74195 жыл бұрын
I learnt a lot 😀👍
@yoprofmatt5 жыл бұрын
Great to hear. Cheers, Dr. A
@fakephysicsengineer61888 жыл бұрын
in my lecture, air drag is equal bv^2. what the different?
@yoprofmatt8 жыл бұрын
+indra fitriyanto Excellent question. In our model, we are simplifying it to the linear case, which works well for small speeds. For higher speeds, the quadratic is more appropriate. You'll see both versions in different textbooks. Probably for a skydiver we should be using the bv^2 option. Thanks much, keep up with the physics. Cheers, Dr. A
@ruthvick.b4706 жыл бұрын
you are awesome you just helped me with my physics RQ and i hope to get a teacher like you but what is sigma Fy
@yoprofmatt6 жыл бұрын
I don't know, what is sigma Fy? Cheers, Dr. A
@jonnyquezada63445 жыл бұрын
That is the sum (sigma) of all the forces (F) in the vertical (y) direction
@yoprofmatt5 жыл бұрын
Yes. At terminal velocity (no more acceleration), the sum of all the forces in the y direction = 0. Cheers, Dr. A
@ruthvick.b4705 жыл бұрын
Thank you so much sir!
@yoprofmatt5 жыл бұрын
You're very welcome. Keep up with the physics! Cheers, Dr. A
@JenniferPChung9 ай бұрын
I know this is besides the point but can we all just take a moment that he has learned how to write backwards so we can see him AS he's writing on the glass(?).
@hmwehmweqhmwe94687 жыл бұрын
Thanks Sir.Good lecture for me.
@yoprofmatt7 жыл бұрын
You are welcome. Cheers, Dr. A
@jonnyquezada63445 жыл бұрын
Hello Dr. Anderson, I am currently a freshman in college and I am majoring in physics, planning to do research in a field of physics someday, would you have any tips for the aspiring physicist? Thank you so much!
@chemistrypodcasts4 жыл бұрын
Let's say I fire a rifle with a muzzle velocity of 300 m/sec (so that the bullet exits the barrel with an acceleration much greater than g) straight down from the plane? What happens to the bullet's velocity and acceleration on its path towards the ground? (Note that the muzzle velocity is also greater than terminal velocity.)
@kn7614 жыл бұрын
Then it slows down to terminal velocity assuming it has enough time to slow down that much before hitting the ground.
@hassansheikh11283 жыл бұрын
Sir when drag force is equal to mg then why object is moving downward...?? Shouldent it be suspended in the air ??
@cradleblaze87983 жыл бұрын
bro acceleration is constant = 0, therefore velocity will not change it will be constant.
@funsky77 Жыл бұрын
So Aristotle was right when he said the time for something to hit the ground is proportionate to the mass of an object (keeping all else constant)?
@cradleblaze87983 жыл бұрын
ENGAA punched me here!
@sohamsharma7424 жыл бұрын
I have a doubt in the chapter "motion in one dimension ". I fail to understand the relation between acceleration and distance as it seems to be both directly proportional as well as inversely proportional. Pls help?
@yoprofmatt4 жыл бұрын
Soham Sharma, Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@sohamsharma7424 жыл бұрын
@@yoprofmatt thank you sir for such a fast and efficient reply but I still unfortunately didn't get my doubt clear. Please help
@alvaroakatico91883 жыл бұрын
@@sohamsharma742 Go to his website and see if that clears it up for you.
@abdelhakyac7285 Жыл бұрын
does this guy write in reverse? I still cant believe that
@iskandergussenov18805 жыл бұрын
Thank you. What happens if I drop down a balloon and a bowling ball in vacuum? Will they hit the ground at the same time or not?
@willoughbykrenzteinburg5 жыл бұрын
In theory - yes, but one thing to consider is that the balloon has air inside it - so in a vacuum, that balloon would surely burst. Take a feather and a bowling ball in a vacuum - yes they will fall at the same rate. In fact, there is a video right here on KZbin of a feather and a bowling ball being dropped in a giant vacuum chamber and they indeed accelerate at the same rate.
@Curious_NG914 жыл бұрын
Hello Dr. A. Sorry to bother. I wanted to confirm that at 10.26 you confirmed that the gravitational pull for the bowling ball due to its mass is more than the baloon. When we drop a bowling ball from 2nd floor to ground, the drag force will never be more than the gravitational pull (considering the mass of the ball). Which means that the body will be in constant acceleration till it hits the ground. But when we consider a=(w-d)/m acceleration is inversely proportional to mass. So greater mass should then mean less acceleration. I am confused. Please consider me un educated in physics and this curiosity is for a silly dream.
@balakrishnaindla57566 жыл бұрын
If a=0 then velocity at every should be same but as object come down velocity will increase that is what g is.a=0 will only when par chute balance the velocity. If i am wrong correct me....
@annamauroam6 жыл бұрын
a = 0 refers to the net acceleration, it means that g does not accelerate the object anymore because the deceleration due to drag is equal and opposite.
@yoprofmatt6 жыл бұрын
You're correct. Initially after you jump, vertical velocity increases for a while until the air resistance = weight. At that point, a = 0 and the velocity is "terminal" (does not change). Cheers, Dr. A
@noahwood599 Жыл бұрын
My ex and I had a series of notes written backward and upside down.
@PzKpfw5 жыл бұрын
I get placing bV "AS" FDrag,,, but wouldn't it be tenebrous to Log them as either 'attrition/sharing' or catalyst/transport?' Covalent and ionic bonding aside, there's real promise with doing this: LogThermalE- Phi =|= 1.618>KinteticE: 2/1 ----> LogTE - bV =|= FDrag>KE: 2/1 Use this one since it "EQUALS:" LogKinetic- Pi = 3.142 LogKE- bV = FDrag
@alexlaroche53172 жыл бұрын
WHAT IS THIS MAGIC WHITE BOARD IS HE WRITING BACKWARDS????
@kylejorolan9783 Жыл бұрын
That is also used when Kratos fell
@gaingamgangmei78873 жыл бұрын
If you are forget to carry parachute you are entitled to register for cemetery.
@zer976 Жыл бұрын
Came here to learn about terminal velocity, left wondering how this dude writes words backwards.
@ayeshashakeel20947 жыл бұрын
best
@RK-xo1rc4 жыл бұрын
When net force is zero than we open a parachute?
@alvaroakatico91883 жыл бұрын
Unless you have a death wish.
@mosesolatunbosun7100 Жыл бұрын
Good day sir, I so much love this video. Can you please teach me how make a video like this including devices needed for a production like this. Thanks
@harsh02bhatt2 жыл бұрын
Why then a watermelon and an egg thrown from same height hit the ground at same time, they both got different weight so terminal velocity must be different?
@SubjectSigma18 Жыл бұрын
Depends on the height, there is a certain high where weight acts, if you drop those on a height of 2 meters they will fall at the same time
@johnsumner14744 жыл бұрын
so when Galileo dropped a bag of feathers and a bag of coal of similar size of the leaning tower of Pisa why did they land at the same time? thanks
@yoprofmatt4 жыл бұрын
John Sumner, Great point. Somehow air resistance didn't kick in enough for him to tell a difference. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@yogeshpatel6174 жыл бұрын
Thank you for lecture sir.. I have doubt You said Ball will reach ground first... but according to galileo theory of dropping objects both should reach ground at same time... or atleast at same time.. Please help me out with my doubt... 🙏🙏
@cradleblaze87983 жыл бұрын
Galileo assumed it in vacuum, if u drop any object for instance a bowling ball and a feather in vacuum they will fall at exactly the same time. Now in practical world if u drop both u know, I know bowling ball will fall way faster and collide with the ground before the feather does, due to air resistance. By the way if you want to prove Galileo correct (LOL) just take a paper (exactly size of the note book) and a notebook . Place the paper just above the notebook then let it free fall.....AND abrakadabra they fall nearly in the same time. Reason - the air particles are displaced by the notebook for the the paper to freefall. (When I first tried it I was amazed) Just an Enthusiast !
@superbart30002 жыл бұрын
You are right. But you have to taking into account buoyancy. Despite have the same shape and size. The basket ball is more buoyant, meaning because of its density compared to the air surrounding it, there is more of an upward buoyant force acting against it, canceling out some of the acceleration due to gravity. Imagine dropping both of these objects into a pool of water. The buoyancy force in that fluid environment would be so strong that the basket ball would not sink, yet the bowling ball would. Because the ball is filled with air which is less dense than water, and the bowling ball has a very dense center. The same thing happens in air, but to a lessened degree. The same thing also happens with helium balloons that would happen if you placed an air filled balloon at the bottom of a pool of water. The buoyant forces would pull both balloons upward, because of the density difference between the balloons and their environments.
@Zakariah19713 жыл бұрын
So if you free fall in a vacuum like space does that means you accelerate to C?
@Martinchox5 жыл бұрын
so before terminal speed you are in a free fall ?
@willoughbykrenzteinburg5 жыл бұрын
Not really. Free fall is motion free from all forces - except gravity. Perhaps in the first few seconds of a skydiving jump, the drag is negligible and you are very close to free fall, but technically not. Near the Earth's surface, the gravitational acceleration is 9.8m/s², so when you first jump out of a plane, you accelerate at this rate, but almost immediately, drag is acting on you - which is a force in the opposite direction. This counters the force of gravity, so this net acceleration decreases. 9.7 m/s², then 9.6 m/s² and so on. The faster you go through the air, the higher the drag force becomes, so the more and more it counters gravity, so just before reaching terminal velocity, your net acceleration is 0.3 m/s², then 0.2 m/s², 0.1 m/s² and then finally - 0.0 m/s². You are now going so fast that the drag force equals the force of gravity, so acceleration stops. You will no longer get any faster. This is terminal velocity. You don't go from free fall (which is 9.8 m/s²) directly to terminal velocity. Your net acceleration gradually decreases as your speed increases (which is increasing the drag force - until it equals gravity).
@mariaahmed16645 жыл бұрын
But ain’t both balls supposed to hit the ground at exactly the same time because the bowling ball has a greater inertia?!
@lmaoty5 жыл бұрын
The important detail is that there is air resistance. In the absence of air resistance, Fd would be zero and both objects would continue to accelerate at exactly 9.8m/s^2 and hence hit the ground at the same time.
@alvaroakatico91883 жыл бұрын
Inside a vacuum both balls will hit the ground at the same time.
@ssjbevegeta30082 жыл бұрын
Why would initial be -g?
@nurrizzatimohammadzambree95532 жыл бұрын
hi professor,, may i ask you some question regarding the a = -g, can you explain about it a bit more detailed?
@yoprofmatt2 жыл бұрын
If there is no wind, you initially fall at an acceleration a = -g = -9.8 m/s^2. (The negative sign just means "down".) Once you start moving faster, you have to push air out of the way. This drag from the air lowers your acceleration until finally your acceleration is zero, hence terminal velocity. We only looked at the start (a=-g) and the end points (a=0), but the actual curve of your velocity is rather interesting. Hope this helps. Cheers, Dr. A
@alina.m4lina2 жыл бұрын
How does he write like this?
@shahzaibhassan65046 жыл бұрын
Sir why Gravity is negative... The Man is falling downwards and gravity is also acting Downwards... Both are in the same direction.
@oktophlo94556 жыл бұрын
I believe the negative just shows the direction in which gravity acts.
@MLGLife4Reality6 жыл бұрын
You can set any direction to be negative as long as everything is consistent
@casesusa2 жыл бұрын
no terminal speed in a vacuum?
@yoprofmatt2 жыл бұрын
Nope. Cheers, Dr. A
@doenglapitus49864 жыл бұрын
What is the formula for terminal velocity?
@fera51656 жыл бұрын
If accelaration is 0, what is g doing there?
@yoprofmatt6 жыл бұрын
Good question. Remember that mg is a force. What this means is gravity is pulling on the object with a force equal to mg. If no other forces are present, then the mass m will accelerate at g because ma=mg. This is what happens when the skydiver first jumps out. However, with other forces present, the acceleration can be very different, since ma = mg - Fdrag. Thus if mg = Fdrag, then the acceleration is zero. This is when the skydiver reaches terminal velocity. Cheers, Dr. A
@willoughbykrenzteinburg6 жыл бұрын
g is what it always was. a = 0 because F = 0. It's important to understand that this does not mean that there are no forces acting - it just means no *net* forces are acting. In other words, all forces cancel each other. Particular for something at terminal velocity, a = 0 because Fnet = 0. Fnet = Fgravity + F drag. If the two are equal, then the net force is zero - because they act in opposite directions. If the force of gravity is 50 Newtons (downward), then the force of drag is 50 Newtons (upward). The net force is therefore zero, so a = 0.
@ahmedrajab78955 жыл бұрын
Why is a not zero at the very start?
@willoughbykrenzteinburg5 жыл бұрын
why would it be?
@zainab713 Жыл бұрын
@@willoughbykrenzteinburg deep.
@madikoorynbay91985 жыл бұрын
So when man is falling, the drag force acting on him is positive? Or as i think the gravitational force is in the same direction as the initial velocity so ‘g’ is positive and drag force opposite of initial velocity and is donated as negative. So what version is right ?
@willoughbykrenzteinburg5 жыл бұрын
Positive and negative doesn't matter really. You just need to be consistent with it. For a two-dimensional problem, where there is only up and down. Just make sure if you use a positive number for the "up" direction, any other vector which points upward is also positive - and anything downward is negative. Or vice versa. Acceleration due to gravity is downward. Drag is upward. Initial velocity is zero, but will obviously be downward immediately after the initial state.
@nuzrathrafiqbaloch77036 жыл бұрын
When The g=F(drag) Then The Net Force Is 0,if The Net Force Is Zero Then A Body Can Be Displaced Without Force? But The Body Is Still Coming Downward When The g=F(drag)....!confused
@yoprofmatt6 жыл бұрын
Remember that if the net force = 0 then there is no acceleration. But of course there can still be velocity. Remember that acceleration = change in velocity. When mg = Fdrag, the acceleration is zero which means the velocity must be constant. You're still falling down, but at a constant speed (and direction). This is what we call terminal velocity. It doesn't change. Hope this helps. Cheers, Dr. A
@Saurav.nittian5 жыл бұрын
a man of 80 kg.falls freelly from height1000m. upto 500m.he falls freely then retarding and reaches at earth with velocity 10m/ s .calculate work done by resistive force
@lalji21855 жыл бұрын
I have also the same question. Mr. Anderson, Would you please help us.??
@muhammedakram71674 жыл бұрын
It would be a silly question but I can't get a point that how does a=-g when it is moving downwards in the direction of gravitional force?
@yoprofmatt4 жыл бұрын
muhammed akram, Remember that + and - signs just indicate direction and that direction depends on your coordinate system. If you draw your coordinate system with +y going up, than a = -g. If you draw your coordinate system with +y going down, then a = +g. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@engr_chie3 ай бұрын
he writes backwards?!
@arthurbosquetti4 жыл бұрын
why is a= -g? shouldn't it be a= g?
@RoBoMaSteR_MK52 жыл бұрын
wait this isn't sonic colors
@myakudoyoru Жыл бұрын
Oh wait, it's not? No wonder the graphics seemed really good today...
@agriarga15212 жыл бұрын
come here because Terminal Velocity by J Petrucci :D
@yknott.14933 жыл бұрын
This is false. -g isn't a negative. You would have the velocity on the hypotenuse of the airplane and the vertical of gravity. In a parabolic towards the ground ... Conservation of energy!
@yknott.14933 жыл бұрын
Are you trying to say that acceleration isn't speed?
@cradleblaze87983 жыл бұрын
what>?
@SubjectSigma18 Жыл бұрын
Nope, it's not the same
@maimoonaqamar6937 Жыл бұрын
Why negative g?
@willoughbykrenzteinburg Жыл бұрын
It doesn't really matter. It's just the designation given. If all values that are presented as positives were negatives and all values that were negatives were positives, you'd arrive at the same result, so it's arbitrary. But generally, down is negative and up is positive. g is an acceleration in the downward direction, ergo it's generally represented as a negative.
@sanfoura19685 жыл бұрын
what about this law ? fd = 1/2*C*ρ*A*v²
@cradleblaze87983 жыл бұрын
Stokes law only valid for spherical objects, in fluids..............It is similar to air drag but not air drag
@grenadeninja30506 жыл бұрын
Wasn't till 7 minutes in it hit me he was writing backwards.
@yoprofmatt6 жыл бұрын
Good catch, but not true. Check us out here: www.learning.glass Cheers, Dr. A
@grenadeninja30506 жыл бұрын
Wow that's really cool. Always fascinated by things like that.
@aizaimran9476 жыл бұрын
shouldn't g be positive?
@hello-go4sy4 жыл бұрын
Depends on coordinate system we choose
@muhammadhabibannajar11156 жыл бұрын
You write backward?
@yoprofmatt6 жыл бұрын
Nope. Secrets here: www.learning.glass Cheers, Dr. A
@ytkartik5 жыл бұрын
how to find the coefficient of drag?
@uraniumstudio12444 жыл бұрын
This Video inspired John Petrucci
@yoprofmatt4 жыл бұрын
Uranium Studio, Great to hear. Who's John Petrucci? Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@weer49804 жыл бұрын
Are you a good person or not to be the one that has to do that to help him out with you and I will be there to do you I will die I will get him a little more and he can help me out with you and him to do it
@shahabdallah94072 жыл бұрын
we learn like this in grade 4.. nice teaching but i think it's kinda childish
@buzz_Baby_d_1st Жыл бұрын
Writing backwards 🧠🧠🧠🧠🧠🧠🧠🧠🧠😔😔
@MrREDVANS3 жыл бұрын
I think either way your going to land on earth dead or alive anymore brain busters
@Sara-ib1eh4 жыл бұрын
I HATE PHYSICS!!
@patrickbooth50914 жыл бұрын
Totally worthless. Doesn’t actually tell us how to figure out terminal velocity
@yoprofmatt4 жыл бұрын
Patrick, I completely agree. There is much more to this story that we need to develop. We're working on it. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A