Demonstrating and Solving for Drag Coefficient

[@riemanndiy6693]

Dear Flipping, can we have anything about magnetism? Thank You very much for your work

[@suresh__143]

Awesome video and visuals. Lot of fun with learning. Great to see the video

[@andrewjustin256]

Mr. P, I woukd like to incquire you about the difference between the Stoke's and the drag firce equation!

[@williamthompson8740]

I was a physics teacher before I became an art teacher. Your videos are flipping awesome. I want to do art teacher videos. I was thinking I could promote my videos though providing public ed puzzles but noticed the views from edpuzzle don't show on youtube. A google search took me to your video. Wait! What? Anything new on that? Kind regards, Mr. Thompson

[@LC35T]

Great video! I noticed at 6:47 3rd line down, the expression on the right hand side for Cd is missing the g term in the numerator. The answer in blue is correct though. Just thought I'd point that out. Thanks for the content!

[@FlippingPhysics]

Bummer. Wish I could fix it. Glad you enjoyed the video!

[@broysthgaming3877]

why it is a constant velocity? I think the acceleration on the object by the force of gravity is not equal to 0 so the force of drag and the force of gravity are not equal to one another.

[@broysthgaming3877]

if you say the object goes through the water has a constant velocity and 0 acceleration so, why the object goes through the air has the acceleration≠0 and velocity is not constant?

[@adamharoon6021]

What textbook do you base your lessons off of?

[@evidaily9336]

Sir, we'll uses Cd=2mg/rho.phi.r²v² or Cd=Fd/1/2rho.pV²A in case skydiving free fall?

[@FlippingPhysics]

My assumption is that you are referring to terminal velocity. This should help: www.flippingphysics.com/terminal-velocity.html

[@amitrai9101]

Can you guys please make a video on "radial motion without radial acceleration" in polar coordinates. Plzs

[@BHANUPRAKASH-nc8hz]

Dear Sir, Kindly please answer. Sir, my problem statement is to find out the drag coefficient of a small toy boat of 20 cm in length and 10 cm in width. If I place the boat in a stationary position in a small fish tank like yours. How to calculate drag coefficient in the situation. Sir, As my boat is stationary only two forces acting on the boat are FB (buoyancy force) and Fg( gravitational force). How to find the drag coefficient in this situation please enlighten me with the answer... Thank You

[@derrickbecker9856]

Why is drag this equation but jet force is double it? Same equation with no 1/2 assuming Cd around 1

[@forrestberg591]

I’d be interested to see the views v time for this genre of video. I feel like lots of videos see a huge bump in the first 24 hours or so, but these are sort of viewed as a reference. Maybe cyclical bumps every finals season? Thanks for the great content!

[@umarshahzad1154]

the reason of 1/2 in drag equation

[@carultch]

If you are wondering why we include the 1/2 in the drag equation, rather than just embedding it in the drag coefficients, I wondered this too. It has to do with the first principles behind the drag coefficient. This explanation switches the reference frame to consider the solid object stationary, since that's how I'm familiar with describing it. A moving fluid comes to a stop against the solid object, and the fluid's KE is converted into pressure energy, as described by Bernoulli's equation. The KE per unit mass is 1/2*v^2, and the pressure energy per unit mass is P/rho (assuming changes in rho are negligible). Solving for the pressure increase as the fluid comes to a stop (stagnation pressure), we get P = 1/2*rho*v^2. Multiply with frontal area A, to get F=1/2*rho*A*v^2. This gives us the drag force with complete stagnation of the fluid. So what drag coefficients are doing, is comparing the force specific to the body shape, to what the force would be for complete stagnation.

[@nats50]

This laughing hyena ads is annoying.